2. • highly compressible.
• occupy the full volume of their containers.
• exert a uniform pressure on all inner surfaces of a
container
• diffuse (mix) easily and quickly
• have very low densities.
Characteristics of Gases
3. Kinetic Molecular Theory
– Gases consist of a large number of molecules in
constant random motion.
– Volume of individual molecules negligible
compared to volume of container.
– Intermolecular forces (forces between gas
molecules) negligible.
– Collision of gas particles are elastic so no
kinetic energy is lost
– As temperature increases the gas particles
move faster, hence increased kinetic energy.
4. Four Physical Quantities for
Gases
Phys. Qty. Symbol SI unit Other common units
pressure P
Pascal
(Pa)
atm, mm Hg, torr,
psi
volume V m3 dm3, L, mL, cm3
temp. T K °C, °F
moles n mol
5. Temperature
ºF
ºC
K
-459 32 212
-273 0 100
0 273 373
32
F
C 9
5
K = ºC + 273
Always use absolute temperature
(Kelvin) when working with gases.
6. What is the approximate temperature for
absolute zero in degrees Celsius and kelvin?
Calculate the missing temperatures
0C = _______ K 100C = _______ K
100 K = _______ C –30C = _______ K
300 K = _______ C 403 K = _______ C
25C = _______ K 0 K = _______ C
Kelvin Practice
273 373
–173 243
27 130
298 –273
Absolute zero is –273C or 0 K
7. Pressure
area
force
pressure
Which shoes create the most pressure?
Pressure (P ) is defined as the force exerted per unit area.
The atmospheric pressure is measured using a barometer.
8. Pressure
2
m
N
kPa
KEY UNITS AT SEA LEVEL
101.325 kPa (kilopascal)
1 atm
760 mm Hg
760 torr
14.7 psi
•1 atm = 760 mmHg = 760 torr = 101325 Pa.
15. Practice
A sample of chlorine gas occupies a volume of
946 mL at a pressure of 726 mmHg. What is
the pressure of the gas (in mmHg) if the
volume is reduced at constant temperature to
154 mL?
16. A sample of chlorine gas occupies a volume of 946 mL
at a pressure of 726 mmHg. What is the pressure of
the gas (in mmHg) if the volume is reduced at constant
temperature to 154 mL?
P1 x V1 = P2 x V2
P1 = 726 mmHg
V1 = 946 mL
P2 = ?
V2 = 154 mL
P2 =
P1 x V1
V2
726 mmHg x 946 mL
154 mL
= = 4460 mmHg
17. k
T
V
V
T
Charles’ Law
The volume and absolute
temperature (K) of a gas are
directly related at constant
mass & pressure
2
2
1
1
T
V
T
V
19. Practice
2. A sample of gas occupies 3.5 L at
300 K. What volume will it occupy
at 200 K?
3. If a 1 L balloon is heated from 22°C to
100°C, what will its new volume be?
20. 2. A sample of gas occupies 3.5 L at 300
K. What volume will it occupy at 200 K?
3. If a 1 L balloon is heated from 22°C to 100°C,
what will its new volume be?
V1 = 3.5 L, T1 = 300K, V2 = ?, T2 = 200K
3.5 L / 300 K = V2 / 200 K
V2 = (3.5 L/300 K) x (200 K) = 2.3 L
V1 = 1 L, T1 = 22°C = 295 K
V2 = ?, T2 = 100 °C = 373 K
V1/T1 = V2/T2, 1 L / 295 K = V2 / 373 K
V2 = (1 L/295 K) x (373 K) = 1.26 L
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21. A sample of carbon monoxide gas occupies 3.20 L at
125 0C. At what temperature will the gas occupy a
volume of 1.54 L if the pressure remains constant?
V1 = 3.20 L
T1 = 398.15 K
V2 = 1.54 L
T2 = ?
T2 =
V2 x T1
V1
1.54 L x 398.15 K
3.20 L
= = 192 K
V1/T1 = V2/T2
25. GIVEN:
V1 = 473 cm3
T1 = 36°C = 309K
V2 = ?
T2 = 94°C = 367K
WORK:
P1V1T2 = P2V2T1
E. Gas Law Problems
A gas occupies 473 cm3 at 36°C.
Find its volume at 94°C.
CHARLES’ LAW
T V
(473 cm3)(367 K)=V2(309 K)
V2 = 562 cm3
26. GIVEN:
V1 = 100. mL
P1 = 150. kPa
V2 = ?
P2 = 200. kPa
WORK:
P1V1T2 = P2V2T1
E. Gas Law Problems
A gas occupies 100. mL at 150.
kPa. Find its volume at 200. kPa.
BOYLE’S LAW
P V
(150.kPa)(100.mL)=(200.kPa)V2
V2 = 75.0 mL
28. GIVEN:
V1 = 7.84 cm3
P1 = 71.8 kPa
T1 = 25°C = 298 K
V2 = ?
P2 = 101.325 kPa
T2 = 273 K
WORK:
P1V1T2 = P2V2T1
(71.8 kPa)(7.84 cm3)(273 K)
=(101.325 kPa) V2 (298 K)
V2 = 5.09 cm3
E. Gas Law Problems
A gas occupies 7.84 cm3 at 71.8 kPa &
25°C. Find its volume at STP.
P T V
COMBINED GAS LAW
29. GIVEN:
P1 = 765 torr
T1 = 23°C = 296K
P2 = 560. torr
T2 = ?
WORK:
P1V1T2 = P2V2T1
E. Gas Law Problems
A gas’ pressure is 765 torr at 23°C.
At what temperature will the
pressure be 560. torr?
GAY-LUSSAC’S LAW
P T
(765 torr)T2 = (560. torr)(309K)
T2 = 226 K = -47°C
31. The Ideal Gas Equation
The gas laws can be combined into a general equation that
describes the physical behavior of all gases.
11.5
nT
V
P
V
P
1
Boyle’s law
V n
Avogadro’s law
V T
Charles’s law
nT
V R
P
PV = nRT
rearrangement
R is the proportionality constant, called the gas constant.
32. B. Ideal Gas Law
UNIVERSAL GAS
CONSTANT
R = 8.3145 J/mol·K
R=0.0821 Latm/molK
PV=nRT
33. R = 0.0821 liter·atm/mol·K
R = 8.3145 J/mol·K
R = 8.2057 m3·atm/mol·K
R = 62.3637 L·Torr/mol·K or
L·mmHg/mol·K
34. GIVEN:
P = ? atm
n = 0.412 mol
T = 16°C = 289 K
V = 3.25 L
R = 0.0821Latm/molK
WORK:
PV = nRT
P(3.25)=(0.412)(0.0821)(289)
L mol Latm/molK K
P = 3.01 atm
B. Ideal Gas Law
Calculate the pressure in atmospheres
of 0.412 mol of He at 16°C & occupying
3.25 L. IDEAL GAS LAW
35. GIVEN:
V = ?
n = 85 g
T = 25°C = 298 K
P = 104.5 kPa
R = 8.315 dm3kPa/molK
B. Ideal Gas Law
Find the volume of 85 g of O2 at 25°C
and 104.5 kPa.
= 2.7 mol
WORK:
85 g 1 mol = 2.7 mol
32.00 g
PV = nRT
(104.5)V=(2.7) (8.315) (298)
kPa mol dm3kPa/molK K
V = 64 dm3
IDEAL GAS LAW
Editor's Notes
Gases only occupy about 0.1 % of the volume of their containers.