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- 1. Gas Laws Section 3.2
- 2. Boyle’s Law At a constant temperature, the volume of a given mass of any gas is inversely proportional to the pressure of the gas. http://www.chem.iastate.edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/boyles_law_graph_new.swf
- 3. Charles’ Law At a constant pressure, the volume of a given mass of any gas is directly proportional to the Kelvin Temperature. http://www.chem.iastate.edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/charles_law.swf
- 4. Gay – Lussac’s Law of Combining Volumes When a gases react, the volumes consumed in the reaction bear a simple whole number ratio to each other, and to the volumes of any gaseous product of the reaction, if all volumes are measured under the same conditions of temperature and pressure.
- 5. Avogadro’s Law Equal volumes of (ideal) gases, contain the same number of particles, or molecules, under the same conditions.
- 6. All the Law’s Combined Charles’ Law Boyle’s Law PV V T k Ideal Gas Law PV = nRT Combined Gas Law P1 V1 T1 P2 V2 T2 k k
- 7. The Combined Gas Laws Combined Gas Law P1 V1 T1 P2 V2 T2 • • P1, V1, and T1 are the initial pressure, volume and Kelvin temperature. P2, V2 and T2 are the final pressure, volume and Kelvin temperature. • • • Pressure can be in any units as long as it’s the same for P1 and P2. Volume can be in any units as long as it’s the same for V1 and V2. Temperature must be in Kelvin’s for T1 and T2. To convert from degrees to Kelvin’s add on 273. For example 25o = 25 + 273 = 298 K
- 8. A sample of gas exerts a pressure of 83,326 Pa in a 300 cm3 vessel at 25oC. What pressure would this gas sample exert if it were placed in a 500 cm3 container at 50oC? P1 83,326 Pa P2 ? V1 300cm3 V2 500cm3 T2 50 273 323K T1 25 273 298 K P1 V1 P2 V2 T1 T2 83,326 300 P2 500 298 323 83,326 300 323 P2 500 54,189.86 Pa P2 Temperature must be in Kelvin’s
- 9. A sample of gas occupies 250 cm3 at 27oC. What volume will it occupy at 35oC if there is no change in pressure? Note : As the pressure is constant, it can be left out of the equation. V1 300mL T1 27 273 300K V1 V2 T1 T2 250 V2 300 308 250 308 V2 300 256.67 cm3 P2 V2 ? T2 35 273 308K
- 10. S.T.P. (Standard, Temperature and Pressure) • Scientists who first studied gases soon realised that the pressure and temperature controlled the volume observed for a gas sample. • Therefore to compare different gas samples, they defined a set of reference conditions. • These conditions are known as standard, temperature and pressure, or simply STP, and are 273 K, and 101,325 Pa.
- 11. What would the volume of a gas at STP if it was found to occupy a volume of 255 cm3 at 25oC and 101,000 Pa? P1 101,325 Pa P2 101,000 Pa V1 ? T1 273K V2 255cm3 T2 25 273 298K P1 V1 P1 V2 T1 T2 101,325 V1 101,000 255 273 298 101,000 255 273 V1 298 101,325 V1 232.86cm3 S tandard temperature 273 K S tandardpressure 101,325 Pa
- 12. The Kinetic Theory of Gases The kinetic theory of gases was developed by James Clerk Maxwell and Ludwig Boltzmann. This theory assumes that: 1. 2. 3. 4. 5. Gases are made up of particles whose diameters are negligible compared to the distances between them. There are no attractive or repulsive forces between these particles. The particles are in constant rapid random motion, colliding with each other and with the walls of the container. The average kinetic energy of the particles is proportional to the Kelvin temperature. All collisions are perfectly elastic .
- 13. Ideal Gases versus Real Gases • An ideal gas is one which obeys all the gas laws and under all conditions of temperature and pressure. • No such gases exists, but real gases behave most like an ideal gas at high temperatures and at low pressures. • Under these conditions, the particles of a real gas are relatively far away from each other, and the assumptions of the kinetic theory are reasonably valid.
- 14. Why do real gases deviate? • Intermolecular forces are present. (Such as dipole – dipole, Van der Waals, etc.,) • Molecules have volume. • Collisions are not perfectly elastic.
- 15. Equation of State for an Ideal Gas pV nRT Measure Pressure Volume Number of moles Gas constant Temperature Conversions Volume : Temperature : 1L 1 10 3 m3 K o C 273 no. of mols: n actual mass Mr Symbol p V n R T Unit Pa m3 mol JK 1mol K 1
- 16. What volume will 24 g of O2 occupy at 20 o C and a pressure of 89000 Pa. p 89000Pa V ? acutal mass n Mr 24 0.75 mols 32 R 8.3 J K 1 mol 1 T 20 273 293K pV nRT 89000 V 0.75 8.3 293 0.75 8.3 293 V 89000 V 0.0204 m3
- 17. A student collected natural gas from a laboratory gas jet at 25o C in 0.25L flask until the pressure of the gas was 73327.30 Pa. The gas sample weighted 0.118 g at a temperature of 25o C. From this data, calculate the molecular mass of the gas. p 73327.30Pa V 0.25L 0.25 10 3 m3 n ? R 8.3 J K 1 mol 1 T 25 273 298K pV nRT 73327.30 0.25 10 3 73327.30 0.25 10 8.3 298 7.41 10 3 mol n 3 actual mass n 0.118 mass 7.41 10 3 mass 15.92 g Mr n 8.3 298 n

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