DNA is a macromolecule that is critical for life. Much of the functi.pdf

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DNA is a macromolecule that is critical for life. Much of the functionality of DNA lies in itscomplex structure. What are the 2 main forces responsible for holding together the structureof DNA and what does each force hold together? Solution The double helical structure of DNA (deoxyribonucleic acid) is formed by the coiling of two polynucleotide chains, similar to a spiral staircase. Of the two polynucleotide chains, the sugar-phosphate backbones are exposed to the outside of the spiral staircase. While the base pairs (side chains) extend towards inside of the helix. The two strands are connected together by hydrogen bonds and hydrostatic forces. Of the two polynucleotide chains, the sugar-phosphate backbones are exposed to the outside of the spiral staircase. While the base pairs (side chains) extend towards inside of the helix. The two strands are connected together by hydrogen bonds..

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It was noted that excess water can kill plants. If water is not toxic, and if all plants require water, then how can excess water kill plants? What is actually killing the plants? Solution When excess water is present, the roots will be deprived of oxygen because the water fills the pores in the soil. This mostly occurs in clay soils. Also, excess water drain out the nutrients and promote root rot disease, which gradually kills the plant..

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In biology, the roles of transition metal ions can be broadly grouped into two classifications: redox chemistry (catalysis, electron transfer, etc.) and acid-base chemistry (catalysis, structural, etc.). A) List three metal ions that commonly participate in biological redox chemistry, and give examples of how they participate. B) Compare this list to metal ions commonly participating in acid-base chemistry. Discuss the overlap of these two groups of metal ions. (e.g. Why are some used for one of these functions and not for the other?) C) List some common biological ligands of these metal ions. Can you see patterns that would allow you to group these ligands into sets with common properties, or that bind common metals? D) Why are trace metals used for these biological functions, and not other more-abundant elements like C,N,O, etc? Solution (a) iron, copper, cobalt, manganese etc are used in biology redox reactions like molecular di oxygen, superoxide, hydrogen peroxide thus inhibiting the effect or formation of these compound by use of the certain other enzymes.. (c) the ions and the Ligands for them are Ike gluthaione peroxide which can bind to chromium, arsenic etc.. Iron binds to ferrodoxin which is associated with the photosynthesis.. (d) transition metals are used because they have empty d-orbitals in with them due to which they can easily transfer or accept the electrons or exchange the electrons among the metals and enzymes.. Which is not possible in other trace metals like carbon, nitrogen etc...

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Explain how recombination increases the amount of genetic variation in offspring: Explain why it is not possible to have a recombination frequency of greater than 50% (half recombinant progeny): A second pair of Drosophila are mated. The female is Cucu YY (straight wing, gray body), while the male is Cucu yy (straight wing, yellow body). Assuming recombination, perform the cross and list the offspring genotypes and phenotypes. Solution Que-3: The recombination frequency is the measure of genetic linkage at different loci. The value of recombination frequency is 50% if the chromosomal genes are located at different regions on the different chromosome because of independent assortment. If the genes are located closely together on the same chromosome, then those genes considered as genetically linked; because they have not assorted independently due to \"crossing over\", then the recombination frequency value is less than 50%. Linked genes are due to linkage often do not obey Mendel\'s laws of inheritance such as independent assortment because of \"crossing over with reciprocal exchange of hereditary genetic material meticulously in between non-sister chromatids\" at the time of \"synapsis formation\" (propahse -I) in reduction division or meiosis 1. These events are leading to formation of gamete cells with complete different genotypically from diploid parent reproductive cell via meiosis finally induce \"genetic variation\" in phenotype due to \"fertilization\" events between sperm cells & ovum. The recombination of chromosomes enables meiosis process of cell division with the generation of novel recombinant nucleotide -sequences by crossing over during the cell division in both unicellular and multicellular species. Sometimes, double strand breaks in DNA during homologous chromosomal recombination may be produced due to exposure any harmful radiation finally may cause higher genetic variation via duplication followed by fertilization to form a phenotype with higher genetic variation Que-4: Crossing over is somewhat randomly distributed over the length of the chromosome because if the two genes are close together then it is very change to get exchange of chromosomal breaks therefore, if the two genes are located farther apart then there will be higher room for the exchange of genetic material with chromosomal breaks. Therefore, when two genetic are far apart on the same chromosome are more likely to have a crossover between them than two loci that are close together. This recombination frequency is considered as a measure of genetic linkage during the crossover of the homologous chromosomes. Linkage disequilibrium defined as the existence of alleles at different loci with the absence of genetic linkage between them even though there is no equilibrium with allelic frequencies independently. The recombination frequency is the measure of genetic linkage at different loci. The value of recombination frequency is 50% \"if the chromosomal genes are .

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Chapter 7 , book: Health in the Later Years, 5th Edition Give a historical perspective on advocacy efforts for the mentally ill in the U.S. Solution Answer: Though it is not clear what was the student/client really asked for. As per the studies concern making the fact easily understandable is the goal of our company. So, here is the brief of the fact asked for- Mental health services throughout the world are in the midst of unprecedented change. New thinking is emerging about what constitutes \"best practice\" in mental health services. Community mental health treatment and support services are now the primary locus of care for people with serious mental illness in many areas. Fundamental components of mental health service systems such as methods of designing and delivering services, mechanisms for establishing and funding service priorities, methods of ensuring system accountability, and definitions of staff role, needed competencies, and training approaches, and so forth, are undergoing scrutiny and restructuring. Historic distinctions between clinical treatment services and disability support or rehabilitation services are no longer simple and examples of integrated service systems are becoming more common. In this context, traditional psychiatric hospital services are undergoing a parallel process which is re-shaping their role, services, and position as partners with community treatment and rehabilitation services, disability services, and self- help/peer support services in an integrated system. Mental health consumers and their family members are exercising their \"voice\" and are assuming increasingly vital roles in governance, policy formulation, and service design and delivery which is helping to shape how these changes will occur in our thinking and practice.\'.

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Discuss the benefits of event-driven programming. Contrast event-driven programming with procedural programming. Discuss how messages from other programs can be viewed as events. Give examples. Give examples of tasks that require the program to guide the user. Should programs be purely event driven, procedural, or a mixture of both? Why? Solution The benefit of event-driven programming is that it\'s very intuitive and naturally well-suited to applications whose control flow are based, not on its structure, but rather on internal or external events. This is why event-driven programming is so popular with GUI programming. Likweise, SOA and client-server architectures are naturally event-driven as well. We if we find contrast between Procedural and event-based then applications written in procedural languages execute by proceeding logically through the program code, one line at a time. Logic flow can be temporarily transferred to other parts of the program through the GoTo, GoSub, and Call statements, directing the program from beginning to end. In contrast, program statements in an event-driven application execute only when a specific event calls a section of code assigned to that event. Events can be triggered by keyboard input, mouse actions, the operating system, or code in the application. For example, consider what happens when the user clicks a command button named Command1 on a form. The mouse click is an event. When the Click event occurs, Visual Basic executes the code in the Sub procedure named Command1_Click. When the code has finished running, Visual Basic waits for the next event. Messages from other programs/threads can be seen as events, as they trigger some instance of code to execute..

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Before 1900, despite its weaknesses in effective management of workers, manufacturing leadership was well provided by top management. They were technological entrepreneurs, archictects of productive systems, veritable lions of industry. But when they delegated their production responsibilities to a second-level department, the factory institution never recovered its vitality. The lion was tamed. It\'s management systems became protective and generally were neither enterpreneual nor strategic. Production managers since then have typically had little to do with initiating substantially new process technology-in contrast to their predecessors before 1900 (skinner 1985). D) how is Japan (or Germany) different from (or the same as) America with regards to this trend in manufacturing leadership? E) taking the structural charestaristics of manufacturing enterprises (e.g., scale, complexity, pace of technological change) as given, what can be done to revitalize manufacturing leadership? Solution Strategic Windows: their nature. The nature and purpose of strategy and how it is formulated. The nature of marketing strategy and how this should take account of the interests of various stakeholders when involving such things as, product/service development and delivery, promotional mix, support services, manufacturing and production processes, R&D, and material purchasing affect the stakeholders. Other factors in the business environment that influence marketing strategy: political, economic, socio-cultural and technological (PEST). Marketing and competitors: how a firm must be able to position itself competitively in the minds of its customers so that its products and services stand out very favourably in important respects in relationship to competitors. Matching the firm’s products / services with opportunities and threats in the market place. The limited periods during which the fit between the key requirements of a market and the particular competencies of a firm competing in that market are at an optimum. Investment in a product line or a market area should be timed to coincide with periods during which a strategic window is open. Correspondingly, withdrawal should be considered where something which was a good fit, is no longer a good fit. Ways in which a market can evolve and how firms might develop a competitive strategy to take advantage of Strategic Windows. Portfolio Analysis How organisations create their own environments rather than simply adapt to existing ones. How they select the strategic windows of opportunities and threats through which they want to look out into the world and develop and market product and services to meet the needs of what they observe to be required in the face of environmental turbulence. How well the fit between an organization’s products/services meet the needs presented by the windows of opportunities and threats is a fitting start for exploring the subject of strategic marketing. It introduces the many factors t.

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A ship was caught in a storm and driven to a small island in the middle of the South Pacific. For generations, no one encountered this small colony, who despite the odds made a thriving settlement on their island. After many years, what characteristics would be unique about this population? A: The people on the island would no longer be considered humans after evolving independently for many generations. B: The people on the island would all look very different from each other, and they may exhibit abnormally high occurrences of traits that are rare in the general human population. C: The people on the island would all look very different from each other, and they may have evolved some odd characteristics that aren\'t seen in other humans. D: The people on the island would all look very similar to each other, and they may exhibit abnormally high occurrences of traits that are rare in the general human population. Solution There is a small group of population who lived seperately from the human for many many years . In this case, the small population would have bred amongst themselves are continued their colony. This small group say after a thousand years look more like each other than any other human on the earth as they had been isolated from the rest of the world. So the answer should be D)The people on the island would all look very similar to each other, and they may exhibit abnormally high occurrences of traits that are rare in the general human population.

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Among 10 people traveling in a group, 2 have outdated passports. It is known that inspectors will check the passports of 20% of the people in any group passing their desks. The group can go as a whole (all 10) to one desk or can split into two groups of 5 and use two different desks. How should members of the group arrange themselves to maximize the probability of getting by the inspectors without having the outdated passports detected? I do not know how to figure out each probability... The section is on counting rules - i am guessing it is without replacement and order does not matter. Thank you for your help Solution Inspectors would check 20% of people in the group Hence if 10 people, 2 would be checked or if 5 one person would be checked If 10 people go to one desk, p for having outdated passport = 0.2 X - no of people having correct passports in 10 is binomial with p = 0.8 They would be caught only if Inspector selects any one person from the two. Y - no of people having outdated passports and p for Y =0.2 P(Y>=1) = 1-P(Y=0) = 1-(0.8)10 = 0.8926 --------------------------------------------- If goes into two groups then either each group can have one outdated or one group no outdated and other groups 2 outdated. For each group one outdated prob of being caught = P(y=1) in I group + P(y=1 in second group)-P( P(y=1) in I group *P(y=1 in second group) as these two events are independent = {1-(0.8)5}+{1-(0.8)5}-{1-(0.8)5}{1-(0.8)5} =2(0,67232)-0.672322 = 0.8926 (same as the first case) ---------------------------------------------- If one group has both outdated and other has none then prob of being not caught = 1(Prob of atleast one in the group having outdated 2) Here p for good passport =0.6 = P(Y>=1) = 1-P(y=0) = 1-(0.6)5 =0.92224 Hence this is the best method to go. Divide into two groups with 2 outdated in one group.

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1.) The normal eye color of Drosophila is red, but strains in which all flies have brown eyes are available. Similarly, wings are normally long, but there are strains with short wings. A female from a pure line with brown eyes and short wings is crossed with a male from a normal pure line. The F1 consists of normal females and short-winged males. An F2 is then produced by intercrossing the F1. Both sexes of F2 flies show phenotypes as follows: 3/8 red eyes, long wings 3/8 red eyes, short wings 1/8 brown eyes, long wings 1/8 brown eyes, short wings Deduce the inheritance of these phenotypes; use clearly defined genetic symbols of your own invention. State the genotypes of all three generations and the genotypic proportions of the F1 and F2. 2.) When a cell of genotype A/a ; B/b ; C/c having all the genes on separate chromosome pairs divides mitotically, what are the genotypes of the daughter cells? 3.) A presumed dihybrid in Drosophila, B/b ; F/f, is test-crossed with b/b ; f/f. (B = black body ; b = brown body; F = forked bristles; f = unforked bristles.) The results are black, forked 230 brown, forked 240 black, unforked 210 brown, unforked 250 Use the 2 test to determine if these results fit the results expected from testcrossing the hypothesized dihybrid. 4.) In mice, dwarfism is caused by an X-linked recessive allele, and pink coat is caused by an autosomal dominant allele (coats are normally brownish). If a dwarf female from a pure line is crossed with a pink male from a pure line, what will be the phenotypic ratios in the F1 and F2 in each sex? (Invent and define your own gene symbols.) Solution Answer 2. If a cell divides mitotically (equational division), the genetic constitution of the daughter cells remains the same as the parents. So a parent with the genotype A/a; B/b; C/c will give rise to daughter cells with the genotype A/a; B/b; C/c. However, if the cell was to divide meiotically (reductional division), the genetic constitution would be different as only one half of the parental chromosomes goes to the daughter cell. So the genotypes would be as follows: ABC or AbC or ABc or Abc or aBC or abC or aBc or abc Answer 3. For the given cross BbFf X bbff For such a test cross the resultant phenotypic ration obtained is 1 (BF):1 (Bf):1 (bF):1 (bf). For dihybrid cross, the degree of freedom will be 4 – 1 = 3 Chi square test is as follows BF Bf bF bf Totals Observed phenotype 230 210 240 250 930 Expected phenotype 930x ¼= 232.5 930x ¼= 232.5 930x ¼= 232.5 930x ¼= 232.5 930 Observed – expected -2.5 -22.5 7.5 17.5 (Obs – Exp)2 Expected 6.25/232.5= 0.0268 506.25/232.5= 2.1774 56.25/232.5= 0.2419 306.25/232.5= 1.3172 3.7633 Looking at the probability value table for degree of freedom = 3, df .90 .70 .50 .30 .20 .10 .05 .01 3 0.58 1.42 2.37 3.67 4.64 6.25 7.82 11.35 Hence we can deduce that there is more than 20% probability for the occurrence of this event. Answer 4. Let XD = Normal phenotype (tall) Xd = Dwarf phenotype P = Pink coat p = Br.

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29. Code an application program that keeps track of student information at your college. Include their names, identification numbers, and grade point averages in a fully encapsulated, homogeneous sorted singly linked list structure. When launched, the user will be asked to input the initial number of students and the initial data set. Once this is complete, the user will be presented with the following menu: Enter: 1 to insert a new student\'s information, 2 to fetch and output a student\'s information, 3 to delete a student\'s information, 4 to update a student\'s information, 5 to output all the student information in sorted order, and 6 to exit the program. The program should perform an unlimited number of operations until the user enters a 6 to exit the program. If the user requests an operation on a node not in the structure, the program output should be “node not in structure.” Otherwise, the message “operation complete” should be output. in java Solution Dear Asker, Following 3 classes consist the colution to this problem. This will give you an idea to approach this problem: //Student Class package studentinfo; public class Student implements Comparable { private String name; private String id; private double gpa; public Student(String id, String name, double gpa) { this.name = name; this.id = id; this.gpa = gpa; } /** * @return the name */ public String getName() { return name; } /** * @param name the name to set */ public void setName(String name) { this.name = name; } /** * @return the id */ public String getId() { return id; } /** * @param id the id to set */ public void setId(String id) { this.id = id; } /** * @return the gpa */ public double getGpa() { return gpa; } /** * @param gpa the gpa to set */ public void setGpa(double gpa) { this.gpa = gpa; } @Override public int compareTo(Student o) { if (this.id.compareTo(o.id) < 0) { return -1; } else if (this.id.compareTo(o.id) > 0) { return 1; } else if (this.gpa < o.gpa) { return -1; } else if (this.gpa > o.gpa) { return 1; } return 0; } public boolean equals(Student o) { if (this.name == o.name && this.id == o.id && this.gpa == o.gpa) { return true; } return false; } } //Student container class package studentinfo; import java.util.Collections; import java.util.LinkedList; public class StudentContainer { LinkedList studentList; public StudentContainer() { this.studentList = new LinkedList(); } public boolean hasStudent(String id, String name, double gpa) { return this.studentList.contains(new Student(id, name, gpa)); } public boolean insertStudent(String id, String name, double gpa) { if (!this.isValidString(id) || !this.isValidString(name) || !this.isValidGpa(gpa)) { return false; } this.studentList.add(new Student(id, name, gpa)); return true; } public boolean deleteStudentById(String id) { Student toRemove = null; for (Student e : studentList) { if (e.getId() == id) { toRemove = e; break; } } if (toRemove != null) { this.studentList.remove(toRemove); return true; } return false;.

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Write the code for a small function called myStack, which creates a Stack object of String elements, named cities. Add \"Sydney\", then \"London\", then \"New York\" and then \"Beijing\" to cities. Then print each element on the screen, one per line. Print each element in a way that causes cities to be empty (i.e. have 0 elements) afterwards. (6 mks) Solution PROGRAM CODE: package stack; import java.util.Stack; public class MyStackClass { //stack function public static void myStack() { //creating a stack object called cities Stack cities = new Stack(); //Adding cities into the stack cities.push(\"Sydney\"); cities.push(\"London\"); cities.push(\"New York\"); cities.push(\"Beijing\"); //using while loop to loop through the stack till its empty while(!cities.isEmpty()) { // pop function is used to remove elements from the stack // pop() returns the elemets which is printed on the csreen System.out.println(cities.pop()); } } // Main function for the class public static void main(String args[]) { myStack(); // function call to the stack method } } OUTPUT: Beijing New York London Sydney.

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Why does the neutralization of an acid by a base often produce water? Solution Neutralisation refers to a reaction between an acid and a Base. This reaction often results in the production of water. It is due to a fact that an acid liberates H+ ions while as a Base releases OH- ions. These ions combine to form water. For example: HCl(aq) H+(aq) + Cl(aq) NaOH(aq) Na+(aq) + OH(aq) HCl + NaOH NaCl + H2O..

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Which statement about phloem transport is false? It takes place in sieve tubes It requires metabolic energy A high pressure potential is maintained in the sieve tubes At sinks, solutes are actively transported into sieve tube elements The mycorrhizal relationship allows a plant’s roots to ?? increase the amount of soil than can be accessed for nutrients. grow in nutrient-poor soils. avoid direct interaction with the soil. None of the above Solution 1. At sinks, solutes are actively transported into sieve tube elements. (False) Phloem is a vascular tissue in plants that actively transports synthesized food from the source tissue ( photosynthetic) to sink tissue (non-photosynthetic). The sieve tube elements (STEs) are the phloem tissue compartments which help in the transportation of food from source to sink. Phloem transport requires metabolic energy and a high-pressure potential is maintained at the sieve tubes. 2. Increase the amount of soil that can be accessed for nutrients Mycorrhiza is the symbiotic relationship between fungi and the plant roots on which they extensively grow. The network of fungal growth or mycorrhiza helps in increasing the surface area of the roots so that they can access more amount of soil and take up nutrients essential for plant growth..

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Which of the following is not a primitive data type Which of the following is not a primitive data type Solution Hi, PLease find primitive data type list in C: The primitive data types in c language are the inbuilt data types provided by the c language itself. Thus, all c compilers provide support for these data types. The following primitive data types in c are available: Integer Data Type int , short, long Float data Type float Double Data Type double Character Data Type char Void Data Type void.

Which of the following is not a primitive data type Which of th.pdf

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