Copy a String in Reverse Order Write a program with a loop and ind.pdf

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arihantsherwani

Copy a String in Reverse Order Write a program with a loop and indirect addressing that copies a string from source to target, reversing the character order in the process. Use the following variables: source BYTE \"This is the source string\",0 target BYTE SIZEOF source DUP(\'#\') and here is what I have got so far ;reverse INCLUDE IRVINE32.INC .DATA SOURCE byte \"this is the source string\", 0 target BYTE SIZEOF source DUP(\'#\') .code main PROC Call Clrscr mov esi,0 mov edi,SIZEOF source-TYPE source mov ecx,LENGTHOF source L1: mov al, source[edi] mov target[esi] sub edi TYPE source loop L1 exit main ENDP END main Solution program with a loop and indirect addressing that copies a string from source to target MOV SI, source ; Get source address MOV DI, (target + SIZEOF source) ; Get the ending address for target LOOP: MOV AL, [SI] ; Get a byte MOV [DI], AL ; Store a byte INC SI ; Move forward one in source DEC DI ; Move back one in target CMP AL, 0 ; Have we reached the zero termination? JNZ LOOP RET.

Copy a String in Reverse Order
Write a program with a loop and indirect addressing that copies a string from source to target,
reversing the character order in the process. Use the following variables:
source BYTE "This is the source string",0
target BYTE SIZEOF source DUP('#')
and here is what I have got so far
;reverse
INCLUDE IRVINE32.INC
.DATA
SOURCE byte "this is the source string", 0
target BYTE SIZEOF source DUP('#')
.code
main PROC
Call Clrscr
mov esi,0
mov edi,SIZEOF source-TYPE source
mov ecx,LENGTHOF source
L1: mov al, source[edi]
mov target[esi]
sub edi TYPE source
loop L1
exit
main ENDP
END main
Solution
program with a loop and indirect addressing that copies a string from source to target
MOV SI, source ; Get source address
MOV DI, (target + SIZEOF source) ; Get the ending address for target
LOOP:
MOV AL, [SI] ; Get a byte
MOV [DI], AL ; Store a byte
INC SI ; Move forward one in source
DEC DI ; Move back one in target

CMP AL, 0 ; Have we reached the zero termination?
JNZ LOOP
RET

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Create a C program that implements \"The Game of Life\" cellular automata (CA) simulation. A few comments: You will want 2 two-dimensional arrays. One that holds the current state of the \"universe\" and second that is generated from the first using the Game of Life rules, which are given below. After the computations for filling the second array are complete, the contents of the second array can be copied back to the first. You can make the array as big as you want, but you should probably use 20 times 20 as a minimum. As discussed in class, the outside boundary of the \"universe\" can be a bit tricky. To keep it simple for this exercise, you can assume that the outside boundary cells are always \"dead\". You can use whatever character (or number) that you want to represent the \"living\" cells. The dead cells should probably be spaces. The rules for whether a particular cell lives or dies are determined by the 8 surrounding cells. If a particular cell is alive, then: If only 0 or 1 of the surrounding cells are alive, the cell dies. (It\'s lonely.) If 4 or more of the surrounding cells are alive, the cell dies. (Too much competition.) If 2 or 3 of the surrounds cells are alive, the cell stays alive. If a particular cell is dead, then it comes to life if exactly 3 of the surround cells are alive. You will have to pick some starting configuration for the universe. An easy thing to do is fill the array randomly, and then let things go and see what evolves. Write your program as described above and demo the operation to your TA. Then try some modifications. First, try using a different starting configurations. Look here for some ideas:. Gosper\'s Glider Gun is a famous one. Or try a simple spaceship or oscillator. Then try changing the rules determining life and death. A common variation is to include a \"birth\" when 6 neighboring cells are alive in addition to the \"3-cell\" birth. Finally, there will be a short quiz covering 2D arrays. This exercise should be very familiar. Solution #include #include #include #include #include #include #include #define ROWS 60 #define COLS 60 #define OFF 0 #define ON 1 #define BLACK 8, 0, 0, 0, 0 #define scr_width 600 #define scr_height 600 #define cell_width (scr_width / ROWS) #define cell_height (scr_height / COLS) We must hold two copies of the board so that we can analyze board and make * changes to temp when killing/creating cells so that we don\'t cause changes * to the board to affect the following cells. */ char board[ROWS][COLS]; char temp[ROWS][COLS]; SDL_Rect cells[ROWS][COLS]; /* Stores positions of each cell for blits. */ void randomize_board(void); void initialize_grid(SDL_Surface* screen); void blit_board(SDL_Surface* bcell, SDL_Surface* screen); int num_neighbours(int x, int y); void update_board(void); int clear_board(SDL_Surface* screen, Uint32 color); int clear_cell(SDL_Surface* screen, int x, int y, Uint32 color); void initialize_cells_array(void); int main(void) { SDL_Init(SDL_INIT_VIDEO).

Create a C program that implements The Game of Life cellular auto.pdf

Create a C program that implements The Game of Life cellular auto.pdf

Create a C program that implements The Game of Life cellular auto.pdf

arihantsherwani

Compare and contrast prokaryotic cells and eukaryotic cells. Compare and contrast passive transport and active transport. Compare and contrast animal cells and plant cells. Summarize the endosymbiosis theory including the evidence that supports it. Solution 1. Similarities between prokaryotic cells and eukaryotic cells: Differences between Prokaryotic cells and Eukaryotic cells: 2. Similarities between active and passive Transport: Differentiate between Active and Passive Transport:Prokaryotic CellsEukaryotic cellsCells don\'t have nucleus.Cells have nucleus.They don\'t have organelles.They have organelles.They all are unicellular.They may be unicellular or multicellular..

Compare and contrast prokaryotic cells and eukaryotic cells. Compare.pdf

Compare and contrast prokaryotic cells and eukaryotic cells. Compare.pdf

Compare and contrast prokaryotic cells and eukaryotic cells. Compare.pdf

arihantsherwani

Case Study 1 Hotel worker Danny Ruiz was living with his wife and four children in a cramped New York apartment when he saw a television ad promising the family a way out. “Why rent when you can own your own home?” Penn- sylvania builder Gene Percudani asked. The company even offered to pay his rent for a year, while he saved for a down payment. So the Ruiz family fled the cityhe Pocono Mountains, where they bought a three- bedroom Cape Cod home for $171,000. However, when they tried to refinance less than two years later, the home was valued at just $125,000. “I just about flipped,” said Mr. Ruiz. Later Mrs. Ruiz remarked about her husband, “He went nuts.” Percudani, a 51-year-old native of Queens, New York, built a thriving homebuilding business in this market, running folksy television ads offering New Yorkers new homes in Pennsylvania. If they joined Percudani’s program, called “Why Rent,” homeowners would find financing through another of his companies, Chapel Creek Mort- gage, which brokered loans from J. P. Morgan Chase and the company’s Chase Manhattan Mortgage unit. For years, the “Why Rent” program appealed to workers with modest salaries, such as Eberht Rios, a truck driver for UPS. Rios bought a home in the Poco- nos for $140,000. This year, when he tried to refinance, he was told the home was valued at only $100,000. One local appraiser, Dominick Stranieri, signed off on most of the “Why Rent” deals that state officials now say were overpriced, including the Rios and Ruiz homes. Percudani’s firm picked Stranieri as his appraiser because of his quick work and low fee of $250, instead of the typical $300 to $400. In exchange for a steady stream of work, Mr. Stranieri accepted without question valuations from Percudani’s company. Other common methods of creating revenues include investors and others buying distressed proper- ties and then, using inflated appraisals, selling them for a big profit. In order to secure the efforts of a “dirty appraiser,” those involved with the fraud would pay up to $1,500 under the table on top of the appraiser’s standard fee of $400. Another unique twist to the plot is that few of the people involved in making mortgage loans have a long- term interest in them. Traditionally, bankers made loans directly and held them, giving the lenders a strong incentive to find fair appraisals to protect their interest. Today, however, many appraisers are picked by independent mortgage brokers, who are paid per transaction and have little stake in the long-term health of the loans. Many lenders have also lost a long-term interest in their loans, because they sell them off to investors. Appraisers increasingly fear that if they don’t go along with higher valuations sought by brokers, their business will dry up. Do you think a county appraiser would do a lot bet- ter than a private practitioner? Joel Marcus, a New York–based attorney recently had his property valued at $2.2 million by a county appraiser, up fro.

Case Study 1Hotel worker Danny Ruiz was living with his wife and f.pdf

Case Study 1Hotel worker Danny Ruiz was living with his wife and f.pdf

Case Study 1Hotel worker Danny Ruiz was living with his wife and f.pdf

arihantsherwani

Assignment Submission Assignment, you submit answers by question by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Assignment submission is used for your score. The complex number z = -1 + i in polar form is z =. The complex number z = 2(cos(pi/6) + i sin(pi/6)) in rectangular form is z = ___________. The complex number graphed below can be expressed in rectangular form as z = or in polar form as z = _________. Solution a)given z =-1+ 1i r =[(-1)2+12] r=2 =tan-1(1/-1) =-tan-1(1/1) =-(/4) =(3/4) z=2 [cos(3/4) +i sin(3/4)] ==================================== b)z=2 [cos(/6) +i sin(/6)] z=2 [(3 /2) +i(1/2)] z=3 +i1 z=3 +i c) z =(1+ 1i) z=2 [cos(/4) +i sin(/4)].

Assignment Submission Assignment, you submit answers by question by .pdf

Assignment Submission Assignment, you submit answers by question by .pdf

Assignment Submission Assignment, you submit answers by question by .pdf

arihantsherwani

A linear dynamical system can be created for two masses connected by.pdf

A linear dynamical system can be created for two masses connected by.pdf

A linear dynamical system can be created for two masses connected by.pdf

arihantsherwani

A 7 year old female with a history of previous UTI’s suddenly develops painful, dark-orange colored urine, with fever and back pain. Her urinalysis reveals dipstick tests that are positive for protein (2+), blood (1+), leukocyte esterase (4+), and nitrate (4+). The microscopic examination yields 20-25 WBC/HPF, 5-10 RBC/HPF, 5-10 WBC Casts/LPF, and numerous bacteria. The patient has been taking Tylenol and vitamin C supplements daily for the past 24 hours, since the condition began. Based on the results 1) what diagnosis/condition would you surmise at this point? 2) what dipstick/microscopic test support this? 3) is the patient’s history significant? 4) can the medication or vitamin supplement have any impact on the test results? Solution Women often experience urinary tract infections that are often marked by pain in the abdomen or lower back. The urine is dark-orange colored due to blood mixing with dark yellow urine. The infection may be due to bacteria E. coli, (MayoClinic). Leukocyte esterase test dipstick that indicates; the presence of white blood cells either as whole cells or as lysed cells; supports this assumption and the microscopic examination yielding 20-25 WBC/HPF also backs this assumption. Yes with all the medical history and the details of the tests done; one can proceed with the treatment. Yes according to researches; Vitamin C spiking of urine has shown to demonstrate false-negative results at various concentrations, (Ko DH, 2015) in case of Dipstick Test Results..

A 7 year old female with a history of previous UTI’s suddenly develo.pdf

A 7 year old female with a history of previous UTI’s suddenly develo.pdf

A 7 year old female with a history of previous UTI’s suddenly develo.pdf

arihantsherwani

5. Toxco, Inc. emits a noxious gaseous substance as a waste product of its operations. As part of its manufacturing process, it also generates liquid solvent wastes such as toluene. Analyze which if any, of these materials are regulated under RCRA. If there is any additional information that would be needed to answer this question, identify what that is. (15 points) Solution Following the discovery of an illegal meth lab by law enforcement, officers collect samples of the chemicals used in that lab as evidence for prosecution. After all forensic samples are gathered, a Hazardous Materials (Hazmat) Team is summoned to clean up the remaining chemicals and other by-products or wastes. Estimates indicate that for each pound of meth produced, between five and six pounds of highly toxic waste is generated.1 The by-products or wastes removed by the Hazmat Teams are generally treated as RCRA hazardous waste without further analysis, and are sent to a RCRA permitted site for treatment and disposal. State and Federal officials also have found that during the operation of the meth lab, the residue from meth production may enter porous building materials such as wallboard, carpets and furnishings.2 In addition to the potential contamination of the building and its contents, there may be further contamination from the improper disposal of these by-products or wastes by the producers of the meth, which is typically poured into the indoor plumbing drains that flow either into the city sewer or individual sewage treatment systems (e.g., septic systems), or modified to allow drainage directly onto the soil near the meth lab. The other disposal method typically seen at functioning meth labs is a burn or burial pit. The primary environmental concern from drainage of these materials into the soil or from disposal into a burn or burial pit is contamination of ground water by the chemicals, including volatile organic chemicals used in the production of meth, as well as vapor intrusion which involves soil vapor gas from ground water plumes infiltrating, and accumulating in, nearby buildings (residences and nonresidential sites) at dangerous levels.3 In most States, the property owner is responsible for decontamination of the property. In some States, the health department or another agency may evaluate the property for risks from long-term exposure to residual chemicals, including the potential environmental impacts of chemical spills into the environment or improper waste disposal. V. How Does RCRA Regulate Hazardous Waste? The determination of whether a particular waste is a Subtitle C RCRA hazardous waste is a multi-step process that depends on a number of factors, including the chemical character and composition of the waste. The regulations for making the hazardous waste determination are found in 40 CFR part 261.4 The first step is to determine whether the waste in question is a solid waste as defined under RCRA. The RCRA regulations require this determinatio.

5. Toxco, Inc. emits a noxious gaseous substance as a waste product o.pdf

5. Toxco, Inc. emits a noxious gaseous substance as a waste product o.pdf

5. Toxco, Inc. emits a noxious gaseous substance as a waste product o.pdf

arihantsherwani

21. Two fair coins are tossed. Let E be the event not more than one head and F the event at least one of each face. Define the sample space S = {HH, HT, TH, TT) and assign probability ¼ to each simple event. a. Determine the P(E) b. Find the P(F) c. Find the P(E intersection F) d. Are E and F independent or dependent? 23. Three fair coins are tossed. Let E be the event not more than one head and F the event at least one of each face. Define the sample space S = {HHH, HHT, ..., TTT} and assign probability 1/8 to each simple event. a. Determine the P(E) b. Find the P(F) c. Find the P(E intersection F) d. Are E and F independent or dependent? Solution 21. a) E be the Event = { Not more than one Head } = {(H,T) (T,H) (T,T) } b) F be the Event = { atleast one of each face } = { (H,T) (T,H)} = Sample Space = { (H,T) (T,H) (T,T) (H,H) } c. P( E n F) = {(H,T) (T,H)} d. Dependent Note : We are suppose to answer only 1 question in time.

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