Bovine spongiform encephalopathy is a food-borne illness also know as.pdf

•

0 likes•4 views

Bovine spongiform encephalopathy is a food-borne illness also know as: mad cow disease. typhoid fever. Norwalk virus. hepatitis A. Solution The correct answer is :mad cow disease. Reason: Bovine spongiform encephalopathy is also known as mad cow disease.It is a neurodegenerative disease in cattle that is often fatal and results in degeneration of brain and spinal cord..

Education

More from arihantcomputersddn

When H_p is equal to r2, the stable equilibrium is K2 and referred .pdf

arihantcomputersddn

The standard deviation of all possible values is called thea. stan.pdf

arihantcomputersddn

The difference between bipolar I disorder and bipolar II disorder is: Select one: a. the seasonal variation in the episodes. b. the number of depressive and manic episodes. c. the number of depressive episodes. d. the severity of the manic episodes. Solution biolar disorders are mental health problems mainly affects your mood. these disorders mainly characterzied by mania and depression. bipolar disorders are classified as type I and II. in type I is characterized by one or more manic episodes or mixed episodes (mania and depression) but is marked by extreme manic episodes. in bipolar disorders II is characterized by one or more major depressive episodes and at least one hypomania. as see above both types I and II there is occurence of depressive episodes but main difference is the severity of the manic episodes. type I -mania but in type II hypomania.

The difference between bipolar I disorder and bipolar II disorder is.pdf

arihantcomputersddn

solve 6 , quiz 2 link of book :http://www.irccyn.ec- nantes.fr/~martinet/Mobrob/FundamentalsofVehicleDynamics.pdf 122% Document Elements Tables charts Smart Art Review A Home Layout Paragraph Style Cambria (Body) 12 Aa A AaBbc AaBbCcDdE Normal No spacing Heading 1 Heading 2 Tit Problem 6 Propose a currently non-commercially available car mechatronics system. Describe the sensors, ac uators and control system you ntend to use. Explain the purpose of this innovation and specify what the added value is for the user [i.e why would anyone want to buy it?]. Print Layout View Sec 1 Pages: rds: 32 of 45 Search in Document Aa Text Box Shape Picture Themes 22% O Solution COMPUTER AIDED DESIGN OF MECHATRONIC SYSTEMS I Use of advanced computer tools in the product development process is necessary to meet the market needs for fast product development. I These tools allows for the verification of the design in all phases of the development process. I Virtual prototypes, I The main drawback of using the computer tools is that they are mostly limited to specific domains. The main requirement to the computer tools for mechatronic system design I to apply to the systems from various domains. I to simultaneously use different system representations (block diagram, physical model, bond graph) Matuško&Koloni 2 of 43 MECHATRONICS SYSTEMS 2014/2015 CLASSICAL (NON- MECHATRONIC) OPTIMIZATION I Classical approach to the optimization during the design process assumes that the parameters of the process, sensors, actuators are known and constant and only controller parameters are optimized. CONTROLLER PROCESS INTERFACE SENSOR OPTIMIZATION + - yR(t) y(t) Matuško&Koloni 3 of 43 MECHATRONICS SYSTEMS 2014/2015 OPTIMIZATION IN MECHATRONIC SYSTEM I Since the main characteristic of the mechatronic design approach is simultaneous design of all system components, the optimization process is performed, not only on the controller parameters but also on the parameters of the other parts of the system. CONTROLLER PROCESS INTERFACE SENSOR OPTIMIZATION + - yR(t) y(t) Matuško&Koloni 4 of 43 MECHATRONICS SYSTEMS 2014/2015 MODELS OF MECHATRONIC SYSTEMS I Physical models, I Bond graphs I Control oriented models I Block diagrams, I Bode diagrams, I Nyquist diagram, I Sate space models. I Time domain models I Animation I C-code Matuško&Koloni 5 of 43 MECHATRONICS SYSTEMS 2014/2015 PHYSICAL MODELS I Physical models describe the system behavior both on functional and structural level, I Model parameters are real physical parameters, I Generally, physical models are not suitable for the control system design, I Building such models requires a deep insight into a physical behavior of the system. Matuško&Koloni 6 of 43 MECHATRONICS SYSTEMS 2014/2015 BOND GRAPHS I Universal representation of the system behavior, independent of the system nature. I Based on power flow analysis of the system. I Two quantities that define the system behavior and power flow within the system (and with its environment).

solve 6 , quiz 2link of book httpwww.irccyn.ec-nantes.fr~mart.pdf

arihantcomputersddn

Question 6 A wastewater sample was collected after screening and grit removal step from Waterloo WWTP. The sample was analyzed in the lab. The sample was found to have the following properties: Total COD 350 mg/L Soluble COD 200 mg/L BOD, 220 mg/L VSS/TSS ratio is 0.7 Removal efficiency of the primary clarifier in the WWTP is 60% for both VSS (both nbVSS and bVSS) and FSS. Assume that biological activity is restricted in primary clarifier, and all soluble compounds pass through. The effluent from primary clarifier is further treated in active sludge Solution To calculate rb COD we use formula sCOD = rbCOD + nbsCOD Where sCOD is soluble COD = 200mg/L, so rb COD 200 = rbCOD + 50; rbCOD = 150 mg/L Now for calculating sb COD we use formula bCOD = rbCOD + sbCOD However, we don’t have bCOD [Biodegradable COD], to calculate that we use bCOD (1.7) of (BOD) bCOD = 1.6 x 220 = 352 mg/L Now bCOD = rbCOD + sbCOD 352 = 150 +sbCOD; sbCOD = 352-150 = 198 mg/L.

Question 6 A wastewater sample was collected after screening and grit.pdf

arihantcomputersddn

1. Cathy has just given birth to a little girl. When the nurse tried to feed her or bather her, the baby become cyanotic. Physical examination indicates no structural deformities. Blood gas levels show only 60% saturation with oxygen. What may be causing this problem? A. The infant has malformed digestive system B. the lungs are hyperventilating C. the lungs are hypoventilating D. the cardiovascular supply of the lungs is impaired E. the infant is born with only one lungs 2. The most effective long-term protection against pH changes of body fluid is: A. buffer system of plasma B. Renal control of H+/HCO3- C. Presence of dissolved proteins in the plasma D. Presence of electrolytes in the plasma E. None of the above 3. Jean has been vomiting off & on for a few days due to viral enteritis. His doctor orders SMA7 (seven blood chemistries including electrolytes) the serum will show: A. Low chloride level B. High chloride leve C. Ca++ will be high D. High H+ ions E. Plasma pH will be low 4. The process of invasion by malignant cells is dependent on? A. activation of TNM system B. Release of enzymes by invading cells C. Decreasing anaplasia D. Tissue damage by chemotherapy E. Stromal adesion 5. T- Cells classified as CD8 cells are: A. Cytotoxic T-Cells B. Killers T-cells C. Helper T- cells D. Memory T-cells E. Regulator T-cells 6. Herpes viruses are transmitted to humans by: A. Birds B. Fleas C. Rodents D.Rodents D. Carnivories E. None Solution 1. The correct option is d because the baby becomes cyanotic is mainly because of the insufficient supply of oxygen which is due to the impaired cardiovascular supply of the lungs. 2. the correct option is a because the blood plasma is responsible for the pH maintenance and works with lungs and kidney to maintain the pH of the body fluids by maintaining the acid and base ratio. 3. The correct option is a because the low levels of chloride level suggest that the body is losing the ions away during vomiting along wth the food particles. 4. The correct option is b because the level of enzymes that are released by the invading cells for the destruction of the proteins of the extracellular matrix which separates the cancer cells and the adjoining tissue. The level of degrading enzymes is responsible for the proliferation and escape of the cancer cell into the surrounding tissue. 5. The option is b killer t cells. 6. The correct option is e. because the Herpes viruses are transmitted through skin to skin contact in humans. mainly when in contact with infected person..

1. Cathy has just given birth to a little girl. When the nurse tried.pdf

arihantcomputersddn

QUESTION 1-construction financeWhich one has not correctly describ.pdf

arihantcomputersddn

Problem #4 (20 points) a.A bus route having seven scheduled stops has the following number of passengers alighting and boarding the bus Sto Alighting 0 Boarding 20 0 per passenger 1.8 seconds and boarding Passengers board and alight through the front door. Alighting time p time per passenger 3 seconds. Compute the dwell time at each stop and the total dwell time. Assume the clearance ime 5 seconds. Briefly describe the four categories of transit system characteristics. c. Briefly describe the various transit modes of transportation End of Problem #4 Problemi #5 (20 points) Transportation Engineering is a multidisciplinary area of study. It is a profession that carries distinct societal responsibilities. What would a comprehensive training include? Provide examples of each training tem a) b) c) d) Explain the difference between direct elasticity and cross elasticity. Give one example of each What does CBD mean? Give an example of a CBD A transportation network having the following characteristics Travel time (minutes) between nodes Nodes From 10 10 10 0 16 12 Each node represents an activity center, and each link represents travel time in minutes. Draw a link/node diagrams for the travel times and distances, if the average travel speed on all links is 30 miles per hour End of Problem #5 Solution 4. (a). There are 2 ways in general to model the dwell time at a particular stop which depends on whether the boarding and alighting processes are sequential or simultaneous. Assuming in the question given that sequential boarding and alighting takes place since only one front door is available for flow of passengers: Dw = a * A + b*B + td ; where A and B are the number of boarding and alighting passengers respectively a and b are time intervals for boarding and alighting per passenger. td is the average clearance time for opening and closing the doors. Here a= 3 sec, b=1.8sec Therefore, at Stop 1: Dw1 = 3*20 + 1.8*0 + 5 = 65 sec Stop 2: Dw2 = 3*5 + 1.8*3 + 5 = 25.4 sec Stop 3: Dw3 = 3*7 + 1.8*5 + 5 = 35 sec Stop 4: Dw4 = 3*3 + 1.8*6 + 5 = 24.8 sec Stop 5: Dw5 = 3*4 + 1.8*8 + 5 = 31.4 sec Stop 6: Dw6 = 3*2 + 1.8*7 + 5 = 23.6 sec Stop 7: Dw7 = 3*0 + 1.8*12 + 5 = 26.6 sec Total dwell time= 231.8 seconds (b). Transit system characteristics can be classified into four main categories: i. System performance elements: Contains entire set of physical performance related elements which decides the raw efficiency of the central system employed as the primary functional core unit of the transit model. This includes Service frequency, operating speed, reliability and safety measures and line and productive capacities. ii. Level of Service (LOS) is an important service parameter that affects the users drastically due to differential change in its delivery. It is a simple basic most powerful characteristic that can attract the users or provide bad experiences to them if miniscule error occurs in provider’s implementation. The factors that affect LOS are performance.

Problem #4 (20 points) a.A bus route having seven scheduled stops h.pdf

arihantcomputersddn

please read carefully before answering. Thank you. Choose at least two concepts in financial reporting (Intermediate Accounting: Reporting and Analysis) you have learned and explain how you may use them in your present or future accounting position. Make sure you provide details to include how each concept will help you support the financial goals of the company you currently work for or will work for in the future. Solution CONCEPT OF MATERIALITY-THE MOST IMPORTANT CONCEPT IN FINANCIAL REPORTING IS RELATED TO MATERIALITY BECAUSE IT EMPHASISES ON RECORDING OF TRANSACTIONS BASED ON TRANSACTIONS MATERIALITY OR IT\'S IMPORTANCE WITH RESPECT TO THE COMPANY CONCERNED.THE CONCEPT OF MATERIALITY STATES THAT ONLY THOSE TRANSACTION SHOULD BE RECORDED WHICH ARE MATERIAL FINANCIALLY TO THE ORGANISATION OR ELSE SUCH TRANSACTONS SHOULD BE IGNORED.SO IT BECOMES VERY IMPORTANT TO DETERMINE WHAT IS MATERIAL AND WHAT IS NOT FOR THE ORGANISATION FOR A FUTURE FINANCIAL MANAGER AND HENCE WILL REQUIRE PERFECT PROFESSIONAL JUDGEMENT. CONCEPT OF PRUDENCE-IT STATES THAT A TRANSACTION SHOULD BE RECORDED BASED ON IT\'S SUBATANCE FORM RATHER THAN IT\'S LEGAL FORM WHICH MEANS THST IF A TRANSACTION HAS BEEN OCCURED IN SUBSTANCE AND ONLY A LEGAL DOCUMENTATION OR FORMALITIES ARE REMAINING FOR SUCH TRANSACTION THEN SUCH TRANSACTIONS SHOULD BE RECORDED IN BOOKS SO THAT A TRUE AND FAIR VIEW OF ORGANISATION IS GIVEN TO IT\'S USERS.IT IS ALAO A IMPORTANT CONCEPT AS IT WILL LEAD TO RELIABILTY OF ORGANISATION FINANCIAL PERFORMANCE AND THUS WILL CONTRIBUTE TO IT\'S FUTURE GOAL..

please read carefully before answering. Thank you. Choose at least.pdf

arihantcomputersddn

As your reward for saving the Kingdom of Bigfunnia from the evil monster “Exponential Asymptotic,” the king has given you the opportunity to earn a big reward. Behind the castle there is a maze, and along each corridor of the maze there is a bag of gold coins. The amount of gold in each bag varies. You will be given the opportunity to walk through the maze, picking up bags of gold. You may enter only through the door marked “ENTER” and exit through the door marked “EXIT.” (These are distinct doors.) While in the maze you may not retrace your steps. Each corridor of the maze has an arrow painted on the wall. You may only go down the corridor in the direction of the arrow. There is no way to traverse a “loop” in the maze. You will receive a map of the maze, including the amount of gold in and the direction of each corridor. Describe and analyze an efficient algorithm to help you pick up the most gold in this maze while traversing a path from the start to the finish. Solution #include using namespace std; // Returns count of possible paths to reach cell at row number m and column // number n from the topmost leftmost cell (cell at 1, 1) int numberOfPaths(int m, int n) { // Create a 2D table to store results of subproblems int count[m][n]; // Count of paths to reach any cell in first column is 1 for (int i = 0; i < m; i++) count[i][0] = 1; // Count of paths to reach any cell in first column is 1 for (int j = 0; j < n; j++) count[0][j] = 1; // Calculate count of paths for other cells in bottom-up manner using // the recursive solution for (int i = 1; i < m; i++) { for (int j = 1; j < n; j++) // By uncommenting the last part the code calculatest he total // possible paths if the diagonal Movements are allowed count[i][j] = count[i-1][j] + count[i][j-1]; //+ count[i-1][j-1]; } return count[m-1][n-1]; } #include using namespace std; // Returns count of possible paths to reach cell at row number m and column // number n from the topmost leftmost cell (cell at 1, 1) int numberOfPaths(int m, int n) { // Create a 2D table to store results of subproblems int count[m][n]; // Count of paths to reach any cell in first column is 1 for (int i = 0; i < m; i++) count[i][0] = 1; // Count of paths to reach any cell in first column is 1 for (int j = 0; j < n; j++) count[0][j] = 1; // Calculate count of paths for other cells in bottom-up manner using // the recursive solution for (int i = 1; i < m; i++) { for (int j = 1; j < n; j++) // By uncommenting the last part the code calculatest he total // possible paths if the diagonal Movements are allowed count[i][j] = count[i-1][j] + count[i][j-1]; //+ count[i-1][j-1]; } return count[m-1][n-1]; }.

As your reward for saving the Kingdom of Bigfunnia from the evil mon.pdf

arihantcomputersddn

Name 3 openings that are transmitted through the levator ani muscle? Name 3 openings that are transmitted through the levator ani muscle? Solution Levator ani muscle extends through and makes internal floor portion of the pelvis (hip portion). The muscle is arranged such that visceral organs. Levator ani allows horizontal openings on the lower side for passage of the following. 1. Anal opening 2. Urinal opening 3. Genital opening.

Name 3 openings that are transmitted through the levator ani musc.pdf

arihantcomputersddn

Answer the following questions about molecule movement across a membrane. a. How is osmosis similar to simple diffusion of CO_2 across a membrane? How is it different? If an aquaporin is involved, how does this change your answer? b. Compare and contrast carrier proteins and channel proteins. Include information about both structure and mechanism of transport. c. Compare and contrast indirect and direct active transport. Give a specific example for each type of transport. Solution 5a: Osmosis is the movement of water molecules down the concentration gradiant through a semipermeable membrane. Both osmosis and simple diffusion of CO2 across a membrane occur down the concentration gradiant and are passive transport. However, osmosis transports hydrophilic water molecules while simple diffusion transports hydrophobic non polar CO2 molecules. If an aquaporin is involved, the proces would be called as facililated diffusion which refers to transport of polar, charged, hydrophilic molecules down the concentration gradiant with the help of membrane transport proteins. 5b: Carrier proteins are the transporter proteins that are actually the integral membrane proteins serving in transport of ions across the membrane. These proteins have ion binding sites and exhibit changes in shape to transport the ions. Channel proteins are the integral membrane proteins that form the hydrophilic channels for transport of polar, charged and hydrophilic substances across the membrane. They do not undergo the shape change. 5c: Direct active transport couples the exergonic chemical reaction for increasing the solute/ion concentration on one side of the membrane. The indirect active transport includes coupling of favorable downhill movement of one solute to the unfavorable uphill movement of other substance. For ex: sodium potassium pump couples ATP hydrolysis with uphill movement of sodium (direct active transport). Downhill movement of sodium coupled with uphill movement of glucose (indirect active transport)..

Answer the following questions about molecule movement across a membr.pdf

arihantcomputersddn

In how many ways, three indistinguishable Owls, one Parrot and one Sparrow can sit together in a line on a string? (b) How many permutations of the letters are possible from the letters in the word: OOOPS!? (a) How many different letter arrangements can be made from the word \"DINOSAUR\"? (b) How many different letter arrangements can be made from the word \"DRAGON\"? Solution S.7 (a) Let us denote Owl as O, Parrot as P and Sparrow as S. The different ways they can sit together in a line on a string are given below: Case I: All three owls sit next to each other O O O P S O O O S P P S O O O S P O O O P O O O S S O O O P Case II: Only two owls sit next to each other O O P S O O O S P O O O P O S O O S O P O P S O O O S P O O P O S O O S O P O O O P O O S O S O O P P O O S O S O O P O Case III: None of the owls sit next to each other O S O P O O P O S O Therefore, there are (6 + 12 + 2) = 20 different ways they can sit together in a line on a string. (Answer) (b) The given word is OOOPS The objective is to determine the number of permutations of the letters possible from the letters of the word OOOPS. The problem is similar to the earlier problem (a) as we have denoted Owl as O, Parrot as P and Sparrow as S. Therefore the answer is 20..

In how many ways, three indistinguishable Owls, one Parrot and one Sp.pdf

arihantcomputersddn

In a certain year, 86% of all Caucasians in the U.S., 76% of all African-Americans, 76% of all Hispanics, and 77% of residents not classified into one of these groups used the Internet for e- mail. At that time, the U.S. population was 67% Caucasian, 12% African-American, and 10% Hispanic. What percentage of U.S. residents who used the Internet for e-mail were Hispanic? (Round your answer to the nearest whole percent.) ________% Solution.

In a certain year, 86 of all Caucasians in the U.S., 76 of all Afr.pdf

arihantcomputersddn

Hosts A through J have been connected to a switch for some time, with Host A on port 1, Host B on port 2, and so on. A user moves his system and connects Host A to interface 12. Immediately after the connection, Host A sends a unicast message to Host B. Which of the following are true? A. When the frame enters the switch, it is flooded to all interfaces. B. When the frame enters the switch, it is sent directly to interface 2, and no other. C. After this unicast message is sent, frames addressed to Host A will continue to be sent to interface 1. D. After this unicast message is sent, frames addressed to Host A will be sent to interface 12. Solution B and D are correct. Moving Host A to a different port would not affect the delivery of frames with a destination MAC for Host B—still on port 2. As the first message from Host A is received, the CAM table will update to the new port (12). A and C are incorrect. A is incorrect because only three types of frames are flooded by switches: broadcast, multicast, and frames without a matching entry in the CAM table. Since Host B is still in the CAM table, the message would be delivered appropriately. C is incorrect because the CAM table is updated to Host A’s new port number immediately after the frame enters the switch..

Hosts A through J have been connected to a switch for some time, wit.pdf

arihantcomputersddn

I have code written for this problem but I am struggling finishing it so I am hoping to see it done in a perhaps different way than how I approached it. Here is the question: Write a program which implements Huffman Encoding assuming a code alphabet of Z2, ie, binary codewords. Start with a class called HuffmanNode.java, which contains the required fields S, P, C, L, as well as a left and a right child HuffmanNode. The algorithm should proceed as follows: First, the user selects a text file, which is read into your program. Each line of the text file will have a symbol, sk S, and a probability, pk P. Each line should be written to a distinct HuffmanNode, (leaving Ck and lk blank for later). The newly semi-filled HuffmanNodes should be added, in increasing order of pk into a HuffmanNode list: an ArrayList of HuffmanNodes. Then the Huffman tree is created by following the Huffman Algorithm. After the tree is created, the tree is traversed recursively in order that the codewords and lengths may be added to the HuffmanNodes. Finally, print your symbols and codes to the screen or to a file for verification. Also, you should traverse your Huffman Tree in order to compute the average codeword length of your new code, (the ACWL(C)). Solution // C program for Huffman Coding #include #include // This constant can be avoided by explicitly calculating height of Huffman Tree #define MAX_TREE_HT 100 // A Huffman tree node struct MinHeapNode { char data; // One of the input characters unsigned freq; // Frequency of the character struct MinHeapNode *left, *right; // Left and right child of this node }; // A Min Heap: Collection of min heap (or Hufmman tree) nodes struct MinHeap { unsigned size; // Current size of min heap unsigned capacity; // capacity of min heap struct MinHeapNode **array; // Attay of minheap node pointers }; // A utility function allocate a new min heap node with given character // and frequency of the character struct MinHeapNode* newNode(char data, unsigned freq) { struct MinHeapNode* temp = (struct MinHeapNode*) malloc(sizeof(struct MinHeapNode)); temp->left = temp->right = NULL; temp->data = data; temp->freq = freq; return temp; } // A utility function to create a min heap of given capacity struct MinHeap* createMinHeap(unsigned capacity) { struct MinHeap* minHeap = (struct MinHeap*) malloc(sizeof(struct MinHeap)); minHeap->size = 0; // current size is 0 minHeap->capacity = capacity; minHeap->array = (struct MinHeapNode**)malloc(minHeap->capacity * sizeof(struct MinHeapNode*)); return minHeap; } // A utility function to swap two min heap nodes void swapMinHeapNode(struct MinHeapNode** a, struct MinHeapNode** b) { struct MinHeapNode* t = *a; *a = *b; *b = t; } // The standard minHeapify function. void minHeapify(struct MinHeap* minHeap, int idx) { int smallest = idx; int left = 2 * idx + 1; int right = 2 * idx + 2; if (left < minHeap->size && minHeap->array[left]->freq < minHeap->array[smallest]->freq) smallest = left; if (right < minH.

I have code written for this problem but I am struggling finishing i.pdf

arihantcomputersddn

Is VLIW archetecture suitable for desktop computers, or mobile devices. Justify your answer? Solution VLIW architecture: VLIW means Very Long Instruction Word. It is suitable for desktop computers rather than mobiles.Because it is processing architecture of computer where a program instrucction is broken into basic operation by language complier or pre processor. It is an alternative for exploiting instruction level parallelism in programs. It is a successor to RISC. The main function of VLIW is to remove the complicated instruction scheduling and parallel dispatch which causes in microprocessors. VLIW is a processor which is faster and les expensive than RISC chip..

Is VLIW archetecture suitable for desktop computers, or mobile devic.pdf

arihantcomputersddn

A researcher is studying the determinants of state-financed welfare programs in the United States such as unemployment compensation and aid to dependent children. She feels that because states in which average income is high have larger tax revenues, they are better to able to afford welfare programs. Therefore, she hypothesizes that the higher the average income in a state, the more welfare programs the state legislature will have adopted. She obtains data permitting to the average income of the residents of each state (coded low; high) and the number of welfare programs passed by each state legislature (coded; many). These data tied the following cross- tabulation. Average Income Number of Welfare Programs Low High Few 9 16 Many 11 14 In reporting her results of her study, the researcher comments about the above cross-tabulation: \"Because more states in which the average income is high (14) have passed many welfare programs that have states in which the average income is low (11), this table provides support for the hypothesis. High average income in a state tends to lead to the passage of welfare programs.\" Do you agree with the conclusion reached by this researcher? Present evidence to support your answer. Solution here we go for chi-squre test for independency of attributes Ho: there is no relationship between average income and welfare program Ha: there is dependency between average income and welfare program Average Income Number of Welfare Programs Low High total Few 9 16 25 Many 11 14 25 20 30 50 E(9)=25x20/50, E(16)=25x30/50,E(11)=20x25/50, E(14)=30x25/50 chi-square statistic=(O-E)2/E with df=1 here O are 9,16,11,14 and E are 10,15,10,15 chi-squre=0.3333 P=0.5637 since P is more than 0.05 so we say that at 5% level of significance we reject alternative hypothesis and accept null hypothesis that there is no relationship between average income and welfare program. conclusion:High average income in a state does not tend to lead to the passage of welfare programs.\".

A researcher is studying the determinants of state-financed welfare .pdf

arihantcomputersddn

Give two instances of the InsuranceCompany entity in the E-R model of the healthcare database. PersonName Address Phone Gender Person mployerP remium emberPremium nrollmentDat on GroupID ependO PlanName MemberlD 0 ID SSN PlanID mpanyName DateOfBirth Patient Enroll nsurancePlan Offer InsuranceCompany Address ompanyAddress Age Phone Include rocesS PatientID ProviderID ClaimID ateOfVisit Employer Visit E-Name Position Claim E- PhoneEmergencyContac enerate CareProvider ClaimID) Sevice Balance Treatment ceCode S erviceName PatientPaymentInsurancePayment Fill rescriptionID Order Disease Languages har ID Pharmacy Prescription RecoveryTime harmacyNa Schedule StartTime Quant ast PickupDat RefillFrequen Symptoms Specialt AffiliatedHospita Education Address Contain atientName Phone Keep Degree Medicine Year escription nitPrice urrentInvento inimumInvento MedicineIDMedicineName FIGURE 5.19 E-R model of the healthcare database with superclass and subclass entities. Solution Two Instances of the Enroll Relationship Patient ID Plan ID Enrollment Date Group ID Member ID PA5 PL3 03/01/2015 40400 5678900 PA6 PL3 03/01/2015 40400 5678906 _____________________________________________________________________________ ________.

Give two instances of the InsuranceCompany entity in the E-R model o.pdf

arihantcomputersddn

How do government policies and/or regulations factor into changes in economic activity on both a domestic and global scale? Give a specific example of a policy or regulation that has helped economic activity. Give a specific example of a policy or regulation that has hindered economic activity. If you were an economist who was tasked with evaluating this policy or regulation, what are some ideas you would suggest for changing it in a way that would achieve the same goal but not hinder economic activity? Finally, state whether or not you enjoy these types of evaluations and if you would consider these types of responsibilities in a future career. Solution Monetary policy is by far the most powerful weapon in the government’s arsenal. Unfortunately, it is also the most imprecise. The government can do some fine control with tax policy to move capital between investments by granting favorable tax status On the whole, governments tend to go for large, sweeping changes by altering the monetary landscape. Governments are the only entities that can legally create their respective currencies. Interest rates are another popular weapon, even though they are often used to counteract inflation. They can spur the economy separately from inflation. Pumping in money feels good for a while, especially for investors who see corporate profits and share prices shooting up, but the long-term impact is an erosion of value across the board. Savings are worth less, punishing savers and bond buyers Government programs provide valuable \"public goods\" such as education and infrastructure. Inreases in government spending can bolster economic growth by putting money into people\'s pockets. I believe the policy of QE (quantiative easing) during times of recession to bring back a shattered economy in place. An automatic reversal will never happen, and it is imperative on the part of government is follow such prudent measures. I would consider these types of responsibilites in a long-term perspective. *****.

How do government policies andor regulations factor into changes in.pdf

arihantcomputersddn

More from arihantcomputersddn (20)