Round seeds (R) is dominant to wrinkled seeds (r), and yellow seeds (Y) is dominant to green seeds (y). A true-breeding pea plant with round and yellow seeds is crossed to a true-breeding plant with wrinkled and green seeds. The F_1 progeny are allowed to self-fertilize. What is the probability of obtaining a yellow seed in the F_2? 3/4 1/16 9/16 3/16 Solution Answer : P1= RRYY x rryy F1 = RrYy F2 =RrYy x RrYy 12 yellow seeds out of 16 = 3/4.