11) Establish each identity. Start from left side of the equation (LHS), and show that it\'s equal to right hand side (RH a) (sin x + cos x)^2 = 1 + sin 2x b) sin^2x + cos^2x=cos^2 x I c) sin Theta(cot Theta +tan Theta)=sec Theta d) csc Theta- cot Theta=sin Theta/a+cos Theta Solution 1. LHS = (sin x + cos x)^2 = sin^2 x + cos^2 x + 2 sin x cos x = 1 + sin 2x = RHS 2. LHS = sin^2 x + cos 2x = sin^2 x + cos^2 x - sin^2 x = cos^2 x =RHS 3. LHS = sin x (cot x + tan x) = sinx (1/tanx + tanx) =sinx / tan x * [1 + tan^2 x] = sinx * cosx / sin x * sec^2 x = cos x / cos^2 x = 1/cos x = sec x 4. LHS = =cosecx - cotx = 1/sin x - cosx/sinx = (1-cos x ) / sin x =[(1-cos x ) * (1+cos x)] / [ sinx (1+cosx)] = [1-cos^2 x] / [sin x *(1+cos x)] = sin^2 x / [sin x *(1+cos x)] =sinx/(1+cos x) =RHS if you have further query, then ask in comment..