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Discrete Math: How many ways are there for a man to distribute 12 indistinguishable gold coins to his 5 children if each child must recieve at least one coin? Solution Number of indistinguishable gold coins (n) = 12 No. of children (k)= 5 No. of ways of distributing n indistinguishable objects among k children such that each child receive at least one coin is (n-1)! / (k-1)!(n-k)! ie., 11!/4! 7! = 330 ways.

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Discrete Math: How many ways are there for a man to distribute 12 indistinguishable gold coins to his 5 children if each child must recieve at least one coin? Solution Number of indistinguishable gold coins (n) = 12 No. of children (k)= 5 No. of ways of distributing n indistinguishable objects among k children such that each child receive at least one coin is (n-1)! / (k-1)!(n-k)! ie., 11!/4! 7! = 330 ways

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  • 1. Discrete Math: How many ways are there for a man to distribute 12 indistinguishable gold coins to his 5 children if each child must recieve at least one coin? Solution Number of indistinguishable gold coins (n) = 12 No. of children (k)= 5 No. of ways of distributing n indistinguishable objects among k children such that each child receive at least one coin is (n-1)! / (k-1)!(n-k)! ie., 11!/4! 7! = 330 ways