AnswerA.) Different Enzymes in the same tissue always have simila.pdf

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Answer: A.) Different Enzymes in the same tissue always have similar half-lives Because, even some substances may have different half-lives in different parts of the body. Solution Answer: A.) Different Enzymes in the same tissue always have similar half-lives Because, even some substances may have different half-lives in different parts of the body..

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The molecular orbital (MO) theory is a way of looking at the structure of a molecule by using molecular orbitals that belong to the molecule as a whole Figure 1. Combination of two 1s atomic orbitals to form a sigma bonding orbital or a sigma-starred antibonding orbital. rather than to the individual atoms. When simple bonding occurs between two atoms, the pair of electrons forming the bond occupies an MO that is a mathematical combination of the wave functions of the atomic orbitals of the two atoms involved. The MO method originated in the work of Friedrich Hund and Robert S. Mulliken. When atoms combine to form a molecule, the number of orbitals in the molecule equals the number of orbitals in the combining atoms. When two very simple atoms, each with one atomic orbital, are combined, two molecular orbitals are formed. One is a bonding orbital, lower in energy than the atomic orbitals, and derived from their sum. It is called sigma. The other is an antibonding orbital, higher in energy than the atomic orbitals, and resulting from their difference. It is called sigma-starred ( s *). (See the diagram in Figure 1.) The basic idea might best be illustrated by considering diatomic molecules of hydrogen and helium. The energy diagrams are shown in Figure 2. Each hydrogen atom has one 1 s electron. In the H 2 molecule the two hydrogen electrons go into the lowest energy MO available, the sigma orbital. In the case of helium, each helium atom has two electrons, so the He 2 molecule would have four. Two would go into the lower energy bonding orbital, but the other two would have to go into the higher energy sigma-starred orbital. Figure 2. Molecular orbital energy diagrams for (a) H 2 showing both electrons in the bonding sigma MO; and (b) He 2 in which two of the electrons are in the antibonding sigma-starred MO Figure 3. Combination of p atomic orbitals to form (a) sigma MOs by end-to-end interactions or (b) pi MOs by sideways interaction. Bond Order The bond order for a molecule can be determined as follows: bond order = ½ (bonding electrons - antibonding electrons). Therefore, the H 2 molecule has a bond order of ½ (2 - 0) = 1. In other words, there is a single bond connecting the two H atoms in the H 2 molecule. In the case of He 2 , on the other hand, the bond order is ½ (2 - 2) = 0. This means that He 2 is not a stable molecule. Multiple Bonds Double or triple bonds involve two or three pairs of bonding electrons. Single bonds are always sigma bonds, but in multiple bonds the first bond is sigma, while any second or third bonds are pi bonds. The overlap of p orbitals can yield either pi or sigma MOs, as shown in Figure 3. When they overlap end to end, they form sigma orbitals, but when they overlap side to side, they form pi orbitals. Consider now the oxygen molecule. The Lewis structure for oxygen is :Ö::Ö: The double bond is necessary in order to satisfy the octet rule for both oxygen atoms. The measured bond length for oxygen supports the.

The molecular orbital (MO) theory is a way of loo.pdf

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The electrons reach or give off a certain amount of energy and different amounts of energy in the electron changes the color because it jumps to a differrent energy level Hope this helps! rate lifesaver :) Solution The electrons reach or give off a certain amount of energy and different amounts of energy in the electron changes the color because it jumps to a differrent energy level Hope this helps! rate lifesaver :).

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Weak London disperision and dipole- dipoleModerate Hydrogen bond.pdf

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var min =0; var max=10; var tab = {}; var name; var score; var sum=0; while(name=prompt(\"Enter name:\")){ // Get userinput for name do{ score = prompt(\"Enter score\"); // Get Score tab[name] = score; // Create object with name as key and score as value. }while(isNaN(score) || !(score>min) || !(score\"; for(item in tab){ // Create table ui = ui + (\"\"+item+\"\"+tab[item]+\"\"); sum = sum + parseInt(tab[item]); } ui = ui + \"\"; document.write(ui); // Display table document.write(\"Average:\"+(sum/Object.keys(tab).length).toFixed(2)); // Finding average and displaying on the page Solution var min =0; var max=10; var tab = {}; var name; var score; var sum=0; while(name=prompt(\"Enter name:\")){ // Get userinput for name do{ score = prompt(\"Enter score\"); // Get Score tab[name] = score; // Create object with name as key and score as value. }while(isNaN(score) || !(score>min) || !(score\"; for(item in tab){ // Create table ui = ui + (\"\"+item+\"\"+tab[item]+\"\"); sum = sum + parseInt(tab[item]); } ui = ui + \"\"; document.write(ui); // Display table document.write(\"Average:\"+(sum/Object.keys(tab).length).toFixed(2)); // Finding average and displaying on the page.

var min =0; var max=10; var tab = {}; var name; var score;.pdf

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Unfortunately several cancers are not predictable with simple tests rather required much intensive diagnosis. The whole genome sequence in determining the entire DNA in normal cells as well as in tumor cells provide the facility to compare and pin point the mutations occurring in the oncogenes or tumor suppressor genes responsible for causing the cancer seems to be a better approach. But such approaches are highly expensive and require expertise. Though, the whole genome sequencing is carried out pin pointing of specific driver mutations responsible for cancer phenotype would be a question. Some critical mutations can be identified in some cancer genome sequences while others are hard to find among the thousands of possibilities. The mutations like missense, nonsense frameshift, rearrangements may alter the coding sequences of any gene must be checked. The regulatory mutations that increase the transcription of oncogenes or decrease that of tumor suppressor genes are potentially important but are very difficult to find in a whole genome sequence. The catalogs of regulatory elements in human genomes provide list of certain potential sequences to be targeted. But the catalogs are rudimentary or incomplete. Therefore, the whole genome sequencing is not a panacea that will lead to immediate cures of all cancers. Recent studies have shown that the whole genome sequences of cells derived from different regions of same tumor have suggested an important reason for cancer reference. Certain cancers are heterogenous and cells within the tumor have different genomes. Certain mutations in oncogens or tumor suppressor genes are common to all cells in the tumor but some are not. These findings make a sense that accumulation of mutations in clone of cells cause cancer. Therefore, designing drug targeting specific cells protecting adult stem cells cannot be accomplished. Thus, effective cancer treatments would be directed against the common mutations but is difficult to identify the specific mutations without sequencing of genomes of many cells throughout the tumor. Cancer landscape is a large scale cancer genome sequencing project (cancer genome atlas) funded by National Institute of Health (NIH). In this project the whole genomes or exomex of several hundreds of cancer are being characterized. The recurrent patterns of mutations are subdivided cancers in to groups with probable clinical relevance. For example, 4 groups of breast cancers have been identified. Almost 178 lung squamous cell carcinoma’s genomes have been characterized and matched with DNA of normal cells from same patients. Mutations in certain tumor suppressor genes like p53 and certain oncogenes have shown relatively high frequencies among these cancers. The mutations of certain cancers resemble cancers in some other organs. For example, pattern of mutation in breast cancer resembles many ovarian cancers more than other types of breast cancers. These findings may help in designing the drugs .

Unfortunately several cancers are not predictable with simple tests .pdf

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The van t Hoff factor i (named after J. H. van t Hoff) is a meas.pdf

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Polar Bonds and Molecular Shape A polar molecule is a molecule that has a net dipole moment due to its having unsymmetrical polar bonds. There are two factors that go into determining if a molecule is polar or not. To determine if a molecule (or ion) is polar or non- polar, you must determine both factors. The polarity of the individual bonds in the molecule. The shape or geometry of the molecule. First, to determine if a given individual bond is polar, you need to know the electronegativity of the two atoms involved in that bond. To find the electronegativities of all the elements, look at the periodic table (follow the link below this answer under Web Links). If the electronegativity of the two atoms has a difference of 0.3 or less, then the bond is non-polar. If the electronegativity difference is greater that 0.3 but less than 1.7, then the bond is polar. If the two values have a difference greater than 1.7, then the bond is ionic, which is just very very polar. Once you know which bonds in the molecule are polar and which are non-polar, you must use the shape of the molecule. You need the shape because two polar bonds, if oriented correctly can cancel each other out (like two equally strong people pulling in opposite directions on a rope -- nobody moves). The three possible outcomes: If all bonds are non-polar, then the whole molecule is non-polar regardless of its shape. If there is symmetry in the molecule so that the polarity of the bonds cancels out, then the molecule is non- polar. A common example of this is carbon dioxide, or CO2. The molecule is linear, and its Lewis dot structure is like this: O=C=O (this doesn\'t include two sets of lone pairs on each oxygen). The carbon-oxygen bond is a polar bond, but because they are exactly opposed to each other, the molecule is overall non-polar. Another example of this is CCl4, where each carbon- chlorine bond is polar, but the molecule is non-polar. Here, how they cancel out isn\'t as obvious, but they do. CCl4 is a tetrahedral molecule, and the 4 C-Cl polar bonds cancel each other out. If there are polar bonds but there is no symmetry such that they cancel each other out, the overall molecule is polar. Water is a typical example of this. The two O-H bonds are oriented in a V- shape, and so the don\'t cancel out. Similarly, CH3Cl is also polar. It is the same shape as CCl4 (see above), but now it doesn\'t have the same symmetry because there is only one C-Cl bond and the bonds don\'t cancel out Solution Polar Bonds and Molecular Shape A polar molecule is a molecule that has a net dipole moment due to its having unsymmetrical polar bonds. There are two factors that go into determining if a molecule is polar or not. To determine if a molecule (or ion) is polar or non- polar, you must determine both factors. The polarity of the individual bonds in the molecule. The shape or geometry of the molecule. First, to determine if a given individual bond is polar, you need to know the electronegativ.

Polar Bonds and Molecular Shape A polar molecule.pdf

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The good functioning of an economy depends on the proper functioning of the country\'s financial market and financial institutions. Both these are involved in the financial transactions that take place in the economy. Financial transactions take place through exchange of funds. There are two ways in which the exchange of funds can take place. They are: Direct exchange and Indirect exchange. Direct exchange takes place when the buyers and the sellers meet each other directly and exchange their securities.For example: Stocks or bonds Indirect exchange takes place when the buyers and sellers do not meet each other directly. They carry out their financial transaction through a financial institution. For example: Bank The financial market and financial institution have the main function of transferring the funds from people who have excess funds to people who have shortage of funds. Some functions are common for both financial markets as well as financial institutions. They both are involved in the borrowing and lending of funds. They help in transfer of risk of the financial asset from the seller to the buyer. They both help in providing information to the buyers and sellers about the financial assets. However, there are also some functions that are unique to each. Financial markets determine the price of the financial asset based on the demand and supply forces. Financial institutions help to lower the transaction costs and also reduce the assymetry of information about financial assets. The financial institutions also provide specialized services to th buyers and sellers. Thus, it can be said that in the financial system, the financial market and financial institutions have an important role to play. Direct exchange takes place through financial market while indirect exchnage takes place through financial institutions. Solution The good functioning of an economy depends on the proper functioning of the country\'s financial market and financial institutions. Both these are involved in the financial transactions that take place in the economy. Financial transactions take place through exchange of funds. There are two ways in which the exchange of funds can take place. They are: Direct exchange and Indirect exchange. Direct exchange takes place when the buyers and the sellers meet each other directly and exchange their securities.For example: Stocks or bonds Indirect exchange takes place when the buyers and sellers do not meet each other directly. They carry out their financial transaction through a financial institution. For example: Bank The financial market and financial institution have the main function of transferring the funds from people who have excess funds to people who have shortage of funds. Some functions are common for both financial markets as well as financial institutions. They both are involved in the borrowing and lending of funds. They help in transfer of risk of the financial asset from the seller to the buyer. They both help.

The good functioning of an economy depends on the proper functioning.pdf

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The answer is Yes, it is a reduction-oxidation reaction2 HNO2 + 2.pdf

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Stegosaurus dinosaur belonged to the late jurassic period i.e Kimmeridgian to early tithonian, is a large quadriped with unusual posture, heavy back, short forelimbs, spiked tail. Integumentary system is that which is composed of skin and its appendages. Its primary function is to protect the body from external injury, temperature regulation, cushioning and self defense. Stegosaurus skin is made up of dermal plates. They arise from the skin, the largest of them measured 2 ft wide. Their size is largest on hip and smallest on neck region. It helped in selfdefense and regulation of body temperature. The plates were supplied with blood through the blood vessels and the air flow through the plates is hypothesized to have regulated the body temperature. The plates were in double row as per findings in late 1960\'s. Lymphatic system: There is little evidence to clearly understand the lymphatic system although it is hypothesized that they had a 4 chambered heart and were warmblooded with a well functioning circulatory system. They had higher aerobic capacity and higher pressure or higher gas exchange circulatory system. Solution Stegosaurus dinosaur belonged to the late jurassic period i.e Kimmeridgian to early tithonian, is a large quadriped with unusual posture, heavy back, short forelimbs, spiked tail. Integumentary system is that which is composed of skin and its appendages. Its primary function is to protect the body from external injury, temperature regulation, cushioning and self defense. Stegosaurus skin is made up of dermal plates. They arise from the skin, the largest of them measured 2 ft wide. Their size is largest on hip and smallest on neck region. It helped in selfdefense and regulation of body temperature. The plates were supplied with blood through the blood vessels and the air flow through the plates is hypothesized to have regulated the body temperature. The plates were in double row as per findings in late 1960\'s. Lymphatic system: There is little evidence to clearly understand the lymphatic system although it is hypothesized that they had a 4 chambered heart and were warmblooded with a well functioning circulatory system. They had higher aerobic capacity and higher pressure or higher gas exchange circulatory system..

Stegosaurus dinosaur belonged to the late jurassic period i.e Kimmer.pdf

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The answer is d- the hydrogen bonds in iceThe high heat of fusion.pdf

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Solution : Option (a) will qualify as a database as dictionary is a database of different words with their meanings stored in it. Option (b) will qualify as a database as telephone directory contains data regarding people like their name, address, phone number. Option (c) will qualify as a database as rolodex is a file that contains cards holding information about people like names, addresses and phone numbers. Option (d) will not qualify as a database as textbook index only points to the topics in the book, it itself does not store any data in it related to the topic or anything..

SolutionOption (a) will qualify as a database as dictionary is a .pdf

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Tests of Controls in an Audit of Internal Control. The objective of .pdf

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Software Quality Assurance is important because Quality in the software is one of the pivotal aspects of a software development company. quality assurance starts from the beginning of a software project, right from the analysis phase. Software Quality Assurance (SQA) is defined as a well planned and systematic approach to evaluate the quality of software. It checks the adherence to software product standards, processes, and procedures. SQA includes the systematic process of assuring that standards and procedures are established and are followed throughout the software development life cycle and test cycle as well. The compliance of the built with agreed-upon standards and procedures is evaluated through process monitoring, product evaluation, project management etc. Software quality assurance methods The main reason of involving quality in software assurance in the process of software product development is to make sure that the final product built is as per the requirement specification and comply with the standards. SQA encompasses different activities, like : 1) Requirement analysis and definition 2) Design architecture and description 3) Coding and logic analysis 4) Change and configuration management 5) Testing and standard compliance 6) Release management and Release Control Different Functionalities of Quality Assurance are the following: 1. Maintaining the quality of the project as per business requirements and Specifications. 2. Defect Prevention. And formal methods for other defect prevention techniques. 3. Defect Reduction 4. Inspection, formal and informal reviews: Direct fault detection and removal without executing the project scenario. 5. Testing the project for Failure observation and bug removal. 6. Risk identification. 7. Defect tracking techniques and methods 8. Software fault tolerance. 9. Concluding Remarks and maintaining reports. Software quality can be quantified into two major groups such as: 1. Software Functional Quality: It basically shows how well the software product conforms to the basic design, based on functional requirements. The attribute can also be described as the fitness for purpose of a software. 2. Software Structural Quality: It reflects to how well the project meets the non-functional requirements such as usability, accessibility and security that helps in proper the delivery of the functional requirements. It basically defines the degree of correctness of the product. . Solution Software Quality Assurance is important because Quality in the software is one of the pivotal aspects of a software development company. quality assurance starts from the beginning of a software project, right from the analysis phase. Software Quality Assurance (SQA) is defined as a well planned and systematic approach to evaluate the quality of software. It checks the adherence to software product standards, processes, and procedures. SQA includes the systematic process of assuring that standards and procedures are establis.

Software Quality Assurance is important because Quality in the softw.pdf

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Oxygen rich blood leaves the lungs. It travels via the pulmonary vein to the heart. It travels through the aorta to the iliac artery. It then travels through the femoral artery to lower leg capillaries. It leaves the lower leg capillaries through the femoral vein It travels through the iliac vein to the inferior vena cava to the heart Carbon di oxide rich blood reaches the lungs through the pulmonary artery. Solution Oxygen rich blood leaves the lungs. It travels via the pulmonary vein to the heart. It travels through the aorta to the iliac artery. It then travels through the femoral artery to lower leg capillaries. It leaves the lower leg capillaries through the femoral vein It travels through the iliac vein to the inferior vena cava to the heart Carbon di oxide rich blood reaches the lungs through the pulmonary artery..

Oxygen rich blood leaves the lungs. It travels via the pulmonary vei.pdf

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Normal Concept : For colour vision, our normal human eyes have 3 cones and photoreceptors. L cone - sensitive to long wavelength of yellowish green light M cone - middle wavelength of green light s cone - short wavelength to bluish violet light Protonapia - complete absence of red cone photoreceptors.He felt difficulty in identifying the red colour Deuteranopia - complete absence of green cone photoreceptors.He felt difficulty in identifying green colour Red green colour discrimination is called red- green dichromat vision blindness.He can able to see yellow circles sometimes in place of red or green colour, it shows the unstable working colour vision receptors. If one colour dominates the vision, the other will be absent,for instance, if red hue is dominant, it strikes the receptors of green colour and vice versa. Red green dichromat friend will have reduction view in the normally appearing red - green colour.The hues, he perceives was not like normal, it looks fade olive in colour.This is due to specific absence of photoreceptors. If he able to perceive colours, either one of the phoreceptors work in exitatory state and the other in inhibitory state.This is called opponent colour theory. Of all that, he might have some degeneration or improper formation issues with myelin sheath(covering the axon of a neuron) which is responsible for colour determination. Solution Normal Concept : For colour vision, our normal human eyes have 3 cones and photoreceptors. L cone - sensitive to long wavelength of yellowish green light M cone - middle wavelength of green light s cone - short wavelength to bluish violet light Protonapia - complete absence of red cone photoreceptors.He felt difficulty in identifying the red colour Deuteranopia - complete absence of green cone photoreceptors.He felt difficulty in identifying green colour Red green colour discrimination is called red- green dichromat vision blindness.He can able to see yellow circles sometimes in place of red or green colour, it shows the unstable working colour vision receptors. If one colour dominates the vision, the other will be absent,for instance, if red hue is dominant, it strikes the receptors of green colour and vice versa. Red green dichromat friend will have reduction view in the normally appearing red - green colour.The hues, he perceives was not like normal, it looks fade olive in colour.This is due to specific absence of photoreceptors. If he able to perceive colours, either one of the phoreceptors work in exitatory state and the other in inhibitory state.This is called opponent colour theory. Of all that, he might have some degeneration or improper formation issues with myelin sheath(covering the axon of a neuron) which is responsible for colour determination..

Normal Concept For colour vision, our normal human eyes have 3 con.pdf

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LinkedListOperations.java-class Node{ public int item; .pdf

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In Keynesian economic theory, a factor that quantifies the change in total income as compared to the injection of capital deposits or investments which originally fueled the growth. It is usually used as a measurement of the effects of government spending on income, and it can be calculated as one divided by the marginal propensity to save. Average propensity to consume, or APC, is the ratio of total consumption to total disposable income, whereas marginal propensity to consume, or MPC, is the ratio of change in consumption to the change in disposable income. Y= C + S That is, disposable income (income after tax) = Consumption + Savings Think of Bob the Builder who earns a gross income of $1000 per week. After tax (which he legally has no choice but to pay) he brings in $850 dollars. His DISPOSABLE Income is $850. He then has two very simple choices- to save it all (i.e. place it in a financial institution such as a credit union, bank, super fund) or to spend it (consume as economists would say). Realistically, he will probably save a fraction and spend a fraction. The fraction of his disposable income (Y) in which he decides to save (S) is his APS- Average Propensity to Save Therefore- Amount Saved/Disposable Income or S/Y. Very simple maths. Similarly, the amount of disposable income that he uses on consumption (spends) is his Average Propensity to Consume- Consumption/Disposable Income or C/Y. The APC and APS are expressed as fractions of Disposable Income- for example 0.3 and 0.7. As he only has two choices, whether to save or spend, the APC and APS must always sum to give 1. They vary with individuals, particularly with those of different disposable incomes. Surprisingly, the wealthy has a higher APS and a lower APC compared to the poor. This is because APS/APC are proportional things; poor people will spend a larger amount of their income on bills and just general living expenses leaving little to no room for saving. As you get wealthy, your consumption will rise however you can afford to live comfortably plus have a lot more money left over for savings, hence their APS is higher. Extending this, economists have come up with the Marginal Propensity (Tendency) to Save/Consume. This looks at the tendency to save/spend each extra dollar of income that is earned. MPC is the proportion of the next dollar in which someone earns that is spent, and similarly MPS is the proportion that is saved. Eg- I give you one dollar, you spend 80 cents and keep 20 cents, your MPC is 0.8 and your MPS is 0.2. As you can see- MPC + MPS also add to 1. As pointed out above, this concept must be clearly understood, as it is the fundamental of Keynes demand theory and the multiplier which you look at to explain economic growth in year 12. As for the difference between savings and investment. Savings are placed away in a financial institution, the incentive to do so is that they earn interest and hence ‘grow’. If you look at the circular flow of income model (if yo.

In Keynesian economic theory, a factor that quantifies the change in.pdf

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import java.util.LinkedList; import java.util.Random; import java.util.Scanner; /** * author * */ public class LinkedListTest { /** * param args */ public static void main(String[] args) { int M, N, Lower, Upper; Scanner scanner = null; try { LinkedList list1 = new LinkedList(); LinkedList list2 = new LinkedList(); LinkedList list3 = new LinkedList(); Random random = new Random(); scanner = new Scanner(System.in); System.out.print(\"Enter the Lower and Upper bounds:\"); Lower = scanner.nextInt(); Upper = scanner.nextInt(); System.out.print(\"Enter the N value to Insert list1:\"); N = scanner.nextInt(); System.out.print(\"Enter the M value to Insert list2:\"); M = scanner.nextInt(); for (int i = 1; i <= N; i++) { list1.add(random.nextInt((Upper - Lower) + 1) + Lower); } for (int i = 1; i <= M; i++) { list2.add(random.nextInt((Upper - Lower) + 1) + Lower); } System.out.println(\"list1: \" + list1); System.out.println(\"list2: \" + list2); System.out.println(\"Minimum elelment in list1 :\" + getMin(list1)); System.out.println(\"Minimum elelment in list2 :\" + getMin(list2)); System.out .println(\"Count Divisibles by 3 and 5 elelment in list1 :\" + countDivisibles(list1)); System.out .println(\"Count Divisibles by 3 and 5 elelment in list2 :\" + countDivisibles(list2)); System.out.println(\"Common Elements From list1 and list2:\" + getCommonList(list1, list2)); } catch (Exception e) { // TODO: handle exception } } /** * param list * return */ public static int getMin(LinkedList list) { int min = list.get(0); for (Integer integer : list) { if (min > integer) { min = integer; } } return min; } /** * param list * return */ public static int countDivisibles(LinkedList list) { int count = 0; for (Integer integer : list) { if (integer % 3 == 0 && integer % 5 == 0) { count++; } } return count; } /** * param list1 * param list2 * return */ public static LinkedList getCommonList(LinkedList list1, LinkedList list2) { LinkedList list = new LinkedList(); LinkedList listCommon = new LinkedList(); list = (list1.size() > list2.size()) ? list1 : list2; for (int i = 0; i < list.size(); i++) { Integer number = list.get(i); if (list2.contains(number) && list1.contains(number)) { listCommon.add(number); } } return listCommon; } } OUTPUT: Enter the Lower and Upper bounds:1 10 Enter the N value to Insert list1:10 Enter the M value to Insert list2:20 list1: [1, 4, 4, 6, 9, 4, 9, 5, 8, 5] list2: [5, 10, 10, 2, 1, 10, 8, 8, 8, 2, 6, 10, 6, 2, 5, 9, 6, 9, 6, 2] Minimum elelment in list1 :1 Minimum elelment in list2 :1 Count Divisibles by 3 and 5 elelment in list1 :0 Count Divisibles by 3 and 5 elelment in list2 :0 Common Elements From list1 and list2:[5, 1, 8, 8, 8, 6, 6, 5, 9, 6, 9, 6] Solution import java.util.LinkedList; import java.util.Random; import java.util.Scanner; /** * author * */ public class LinkedListTest { /** * param args */ public static void main(String[] args) { int M, N, Lower, Upper; Scanner scanner = null; try { LinkedList list1 = new LinkedList(); L.

import java.util.LinkedList; import java.util.Random; import jav.pdf

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Hi, Please find the answers as follows: Part A: Expected Return = .1*-10 + .2*0 + .4*10 + .2*20 + .1*30 = 10% Part B: Variance = .1*(-10 - 10)^2 + .2*(0 - 10)^2 + .4*(10 - 10)^2 + .2*(20 - 10)^2 + .1*(30 -10)^2 = 120 Standard Deviation = (120)^1/2 = 10.95% Part C: Coeffcient of Variation = Standard Deviation/Expected Return = 10.95/10 = 1.095 Part D: Stand Alone Risk is measured by th Standard Deviation or Coefficient of variation (CV) of returns. Part E: Stand Alone Risk reflects the uncertainty about the cash flows. It is relevant when the the undiversified risk of an individual asset is required to be measured. Thanks. Solution Hi, Please find the answers as follows: Part A: Expected Return = .1*-10 + .2*0 + .4*10 + .2*20 + .1*30 = 10% Part B: Variance = .1*(-10 - 10)^2 + .2*(0 - 10)^2 + .4*(10 - 10)^2 + .2*(20 - 10)^2 + .1*(30 -10)^2 = 120 Standard Deviation = (120)^1/2 = 10.95% Part C: Coeffcient of Variation = Standard Deviation/Expected Return = 10.95/10 = 1.095 Part D: Stand Alone Risk is measured by th Standard Deviation or Coefficient of variation (CV) of returns. Part E: Stand Alone Risk reflects the uncertainty about the cash flows. It is relevant when the the undiversified risk of an individual asset is required to be measured. Thanks..

Hi,Please find the answers as followsPart AExpec.pdf

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