The answer is: Yes, it is a reduction-oxidation reaction 2 HNO2 + 2 H+ + 3 I- => 2 NO + I3- + 2 H2O Oxidation state of N in HNO2 = +3 Oxidation state of N in NO = +2 Thus HNO2 is reduced to NO as oxidation state of N decreases. Oxidation state of I in I- = -1 Oxidation state of I in I3- = -1/3 Thus I- is oxidized to I3- as oxidation state of I increases. Solution The answer is: Yes, it is a reduction-oxidation reaction 2 HNO2 + 2 H+ + 3 I- => 2 NO + I3- + 2 H2O Oxidation state of N in HNO2 = +3 Oxidation state of N in NO = +2 Thus HNO2 is reduced to NO as oxidation state of N decreases. Oxidation state of I in I- = -1 Oxidation state of I in I3- = -1/3 Thus I- is oxidized to I3- as oxidation state of I increases..