MinOfFourNumbers.javaimport java.util.Scanner;public class MinOf.pdf

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If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each. Solution If I assume you meant supply is determined as [q_(s)=3p^2-4p] and demand is determined as [q_(d)=-p^2+24] then I would calculate that the equilibrium is where [q_(s)=q_(d)] and p>0. So I set up the equation [3p^2-4p=-p^2+24] I add [p^2] to both sides of the equation yielding [4p^2- 4p=24] I subtract 24 from each side, yielding the quadratic equation [4p^2-4p-24=0] I factor the equation [(2p-6)(2p+4)=0] so that means [2p-6=0] or [2p+4=0] In the former case 2p=6 so p=3, and in the latter 2p=-4 so p=-2. The economic nature of the question requires p>0, so [p!=-2] and thus the equilibrium price is $3.00 each. Then to determine the equilibrium quantity, we solve either q expression for p=3. [q_(s)=3(3)^2-4(3)=3(9)-12=27-12=15] [q_(d)=-(3^2)+24=-9+24=15] So the equilibrium quantity is 15 items. The price and quantity for market equilibrium is 15 items at $3.00 each..

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MinOfFourNumbers.java
import java.util.Scanner;
public class MinOfFourNumbers {
public static void main(String[] args) {
//Creating an Integer array of size 4
int numbers[]=new int[4];
//declaring the variables
int min;
//Scanner object is used to get the values entered by the user.
Scanner sc=new Scanner(System.in);
/* This for loop will get the values from the user
* and populate into the array
*/
for(int i=0;i<4;i++)
{
//Getting the number from the user.
System.out.print("Enter Number "+(i+1)+" :");
numbers[i]=sc.nextInt();
}
//Store the first element of the array in min variable
min=numbers[0];
//This loop will calculate the minimum of 4 numbers
for(int i=0;i<4;i++)
{
/*Check each element of the array with the value value contained in the min variable.
* If the element of the array is less than min,then assign that element to min variable
*/
if(numbers[i]
Solution

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import java.util.Scanner; public class ArrayData { /* * ARRAY_SIZE variable to decalre the minimum array size */ static int ARRAY_SIZE = 5; /* * ARRAY_ELEMENTS variable to monitor the array elements at present [after user operations] */ static int ARRAY_ELEMENTS = 0; /* * integerArray base array of size ARRAY_SIZE with elements \'0\' */ int[] integerArray = {0,0,0,0,0}; /* * copy\'s the array passed to the base array */ public void copy(int[] from, int length){ for(int j=0;j= ARRAY_SIZE){ doubleArray(); } System.out.println(\"integerArray length\"+integerArray.length); int[] bigger = new int[integerArray.length]; int add = valueInsert; boolean found = false; int indexToInsert = 0; for (int i = 0; i < integerArray.length-1; i++){ if ( !found && add >= integerArray[i]){ found = true; indexToInsert = i; bigger[indexToInsert] = add; i--; } else{ if(found) { bigger[i+1] = integerArray[i]; }else { bigger[i] = integerArray[i]; } } } if(!found) { indexToInsert = integerArray.length; bigger[indexToInsert] = add; } System.out.println(\"integerArray length last\"+integerArray.length); integerArray = bigger.clone(); ARRAY_ELEMENTS += 1; } /* * Displays the base array elements when user gives wrong input */ public void display(){ for(int i=0;i Solution import java.util.Scanner; public class ArrayData { /* * ARRAY_SIZE variable to decalre the minimum array size */ static int ARRAY_SIZE = 5; /* * ARRAY_ELEMENTS variable to monitor the array elements at present [after user operations] */ static int ARRAY_ELEMENTS = 0; /* * integerArray base array of size ARRAY_SIZE with elements \'0\' */ int[] integerArray = {0,0,0,0,0}; /* * copy\'s the array passed to the base array */ public void copy(int[] from, int length){ for(int j=0;j= ARRAY_SIZE){ doubleArray(); } System.out.println(\"integerArray length\"+integerArray.length); int[] bigger = new int[integerArray.length]; int add = valueInsert; boolean found = false; int indexToInsert = 0; for (int i = 0; i < integerArray.length-1; i++){ if ( !found && add >= integerArray[i]){ found = true; indexToInsert = i; bigger[indexToInsert] = add; i--; } else{ if(found) { bigger[i+1] = integerArray[i]; }else { bigger[i] = integerArray[i]; } } } if(!found) { indexToInsert = integerArray.length; bigger[indexToInsert] = add; } System.out.println(\"integerArray length last\"+integerArray.length); integerArray = bigger.clone(); ARRAY_ELEMENTS += 1; } /* * Displays the base array elements when user gives wrong input */ public void display(){ for(int i=0;i.

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Getting Started Create a class called Lab8. Use the same setup for setting up your class and main method as you did for the previous assignments. Be sure to name your file Lab8.java. Additionally, make another file called Arrays.java. This file will be an object, so simply start it off by declaring an Arrays class. You can copy the following skeleton and fill in the appropriate code below each of the comments: public class Arrays { / Instance Variables // Constructors // findMin 1 // findMax // calcSum // calcAverage // toString } Task Overview Your task for this lab is to create a class called Arrays with some array processing methods. This class will maintain an array and the number of elements present in it. Additionally, methods will be available to display the current min and max elements along with the average of all of them. Finally, a toString() method will be available to cleanly display all the array elements. Finally, you will write a simple driver class to test out the above Arrays class. Part 1: Instance Variables for Arrays The first thing to do for the Arrays class is to set up its instance variables. Declare the following (private) instance variables: • An int array called array ? this will be the array we will be writing methods for. • An int called count - this represents the number of valid elements in the array. Part 2: Constructors for Arrays The Arrays class will have two constructors. The first constructor takes the maximum size of the array as input as a parameter and initializes the array instance variable appropriately. It also sets count to size. Finally, it will initialize all of the array elements to some values between 0 and 10, inclusive. To create this constructor, follow these steps: • Import java.util.Random to make use of the random number generator. • Create a constructor with the following header: public Arrays(int size) • Initialize your array variable and set its size to size (see the chart on page 252 for reference on initializing arrays). Be very careful that you are setting the value of your array instance variable, as opposed to creating a new variable called array. • Set the value of the count variable to size because we will be populating the entire array. • Copy the following code to the constructor in order to generate random values between 0 and 10, inclusive: Random rand = new Random(); for (int i = 0; i < count; i++) { array[i] = (rand.nextInt(10)); } Next, create another constructor with the following header: public Arrays(int[] arr). This constructor will initialize the class by using the passed arr argument in order to fill its instance variables. The following things need to be done inside of this constructor: • Set the array variable equal to arr. • Set the count variable equal to the length of the array. Part 3: Displaying the Output findMin() The first method of this class will search the array for the minimum element. Copy the following code for the findMin method. Note how the count i.

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OrderTest.java public class OrderTest { /** * Get an array of specified size and pass it to Order.order(). * Report the results. */ public static void main(String[] args) { if (args.length != 1) {//1 System.out.println(\"Usage: java OrderTest sizeOfArray\ \" + \"\\tor\ \\tjava OrderTest arrayFile\"); System.exit(1); } // create or read the int[] int size = 0; int[] array = new int[0];//5 try { size = Integer.parseInt(args[0]); array = ArrayOfInts.randomizedArray(size); } catch (NumberFormatException nfe) {//8 try { array = ArrayOfInts.arrayFromFile(args[0]); size = array.length; } catch (Exception e) { System.err.println(\"unable to read array from \" + args[0]); System.exit(1);//14 } } System.out.println(\"before:\");//15 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]);//1 } int myNum = Order.order(array); //this is the call we want to measure System.out.println(\"\ after:\");//18 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]); } System.out.println(myNum); } } ArrayOfInts.java import java.io.BufferedWriter; import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.InputMismatchException; import java.util.Scanner; public class ArrayOfInts { /** * Returns an array of consecutive ints from 1 to size. */ public static int[] orderedArray(int size) { int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = i+1; } return a; } /** * Returns a randomized array containing ints from 1 to size. */ public static int[] randomizedArray(int size) { ArrayList aL = new ArrayList(); for (int i = 0; i < size; i++) { aL.add(i+1); } Collections.shuffle(aL); int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = aL.get(i); } return a; } /** * Writes an int[] to a plain-text file with ints separated by spaces. * Useful for creating input files for repeatable tests. */ public static void arrayToFile(int[] array, String outfile) { try { FileWriter fw = new FileWriter(outfile); BufferedWriter bw = new BufferedWriter(fw); PrintWriter outFile = new PrintWriter(bw); for (int i : array) { outFile.print(i + \" \"); } outFile.close(); } catch (IOException e) { System.err.println(\"Could not write to \" + outfile + \"\ \" + e); } } /** * Read ints from a file and return them in an int[] */ public static int[] arrayFromFile(String infile) throws FileNotFoundException, InputMismatchException { Scanner scan = new Scanner(new File(infile)); ArrayList aL = new ArrayList(); while (scan.hasNext()) { aL.add(scan.nextInt()); } scan.close(); int[] a = new int[aL.size()]; for (int i = 0; i < a.length; i++) { a[i] = aL.get(i); } return a; } } Order.java public class Order { /** * Take an int[] and reorganize it so they are in ascending order. */ public static int order(int[] array) .

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Write a method called uniqueNumbers that takes an int array as parameter, and returns a different int array, which only contains the list of unique numbers in the original array. Hint: Use the isPresent method defined below to accomplish your here is the code we need to add too Solution solution package com.mt.classes; import java.util.ArrayList; import java.util.List; public class Lab8e { public static void main(String[] args) { int[] numbers = new int[20]; // Generate random numbers between 0 and 99 and fill up the array for (int i = 0; i < numbers.length; i++) { numbers[i] = (int) (Math.random() * 50); } System.out.println(\"The list is:\"); printNumbers(numbers); // Task 1 System.out.println(\"The smallest number in the list is \" + smallestNumber(numbers)); // Task 2 System.out.println(\"The largest number in the list is \" + largestNumber(numbers)); // Task 3 System.out.println(\"The average of numbers in the list is \" + averageOfNumbers(numbers)); // Task 4: Extra Credit. Uncomment the following // two lines if you complete this task. System.out.println(\"The list of unique numbers is:\"); uniqueNumbers(numbers); } private static void uniqueNumbers(int[] numbers) { for (int i = 0; i < numbers.length; i++) { boolean isDuplicate = false; for (int j = 0; j < i; j++) { if (numbers[i] == numbers[j]) { isDuplicate = true; break; } } if (!isDuplicate) { System.out.print(numbers[i] + \" \"); } } } public static void printNumbers(int[] list) { for (int i = 0; i < list.length; i++) { System.out.print(list[i] + \" \"); } System.out.println(); } // 1. Write a method called smallestNumber that // takes an int array as parameter, and returns the // smallest number public static int smallestNumber(int[] list) { int small = 100; for (int i = 0; i < list.length; i++) { if (list[i] < small) { small = list[i]; } } return small; } // 2. Write a method called largestNumber that // takes an int array as parameter, and returns the // largest number public static int largestNumber(int[] list) { int large = 0; for (int i = 0; i < list.length; i++) { if (list[i] > large) { large = list[i]; } } return large; } // 3. Write a method called averageOfNumbers that // takes an int array as parameter, and returns the // average of the numbers public static double averageOfNumbers(int[] list) { double average = 0.0; for (int i = 0; i < list.length; i++) { average = average + list[i]; } average = average / list.length; return average; } public static boolean isPresent(int[] list, int target) { boolean found = false; for (int i = 0; i < list.length && !found && list[i] != 0; i++) { if (list[i] == target) { found = true; } } return found; } } output The list is: 16 14 11 31 7 8 18 49 27 43 9 39 38 18 6 16 8 30 32 15 The smallest number in the list is 6 The largest number in the list is 49 The average of numbers in the list is 21.75 The list of unique numbers is: 16 14 11 31 7 8 18 49 27 43 9 39 38 6 30 32 15.

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Write a function which return a list of all of the n element subset of a given set Implement in JAVA Question 3 Write a function that returns a list of all of the n-element subsets of a given set. For example, if the given set is [1,2,3] and n is 2, then the returned list should contain [1,2], [1,3], and [2,3]. The order of the elements is not important. Solution The program for this problem is as follows: Comments are included in the program for explaining the steps. A sample output is attached below the program. package com.temp; import java.util.ArrayList; import java.util.List; import java.util.Scanner; /** * Program to find sublists of a list. * @author Rohit Phatak * */ public class subset { /** * This list will contain the resultant sublists. */ static List list = new ArrayList<>(); public static void main(String arg[]){ /** * Input a list comma separated. */ System.out.println(\"Enter a list : \"); Scanner scanner = new Scanner(System.in); String s = scanner.nextLine(); String[] sArr = s.split(\",\"); /** * Input a value of n. */ System.out.println(\"Enter value of n : \"); Integer n = scanner.nextInt(); /** * Check if value of n is greater than entered list. */ if(sArr.length < n){ System.out.println(\"Length of list is less than value of n\"); } else if(sArr.length > 0){ getSubsetList(sArr,n); System.out.println(\"List is as :\"); /** * Printing the sublists. */ for(String[] str : list){ String printVar = \"\"; for(String temps : str) printVar+=temps+\",\"; System.out.println(\"[\"+printVar.substring(0, printVar.length()-1)+\"]\"); } } else { System.out.println(\"Please enter atleast one element:\"); } scanner.close(); } /** * This method calls the recursive function which is used to obtain the sublists. * @param sArr * @param n * @return */ public static List getSubsetList(String[] sArr,Integer n){ List lista = new ArrayList<>(); sublist(sArr, 0, n, new String[n]); return lista; } /** * This is a recursive function. * This function will iterate over itself for finding the sublist. * * Parameters are as follows: * * @param arr -> List entered by the user. * @param n -> Value of sublist entered by user. * @param startPosition -> index to start creating the sublist. * @param result -> resultant sublist */ public static void sublist(String[] arr, int startPosition, int n, String[] result){ /** * Check for the value of n ==0. * If n==0 break from the recursion. */ if (n == 0){ /** * Add the sublist \'result\' in the list. */ list.add(result.clone()); return; } /** * Iterate through for loop starting from startPosition till length of list minus entered value n. */ for (int i = startPosition; i <= arr.length-n; i++){ /** * Here result is a temporary sublist. * This for loop adds an element to the temporary sublist in each iteration. * The element is added from the complete list entered by user. * Location of element is iTh index. */ result[result.length - n] = arr[i]; /** * After adding the element to the temporary sublist, the sublist an.

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/******************* using recursive method **********************/ /** * 1.2.1 Java program to calculate the Fibonacci Number using recursion */ import java.util.Scanner; public class Fibo { public static void main(String args[]){ Scanner scan= new Scanner(System.in); //Scanner object to read from the user int n; System.out.println(\"Enter the value of n\"); n=scan.nextInt(); System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the recursive method scan.close(); } //method to calculate Fibonacci number recursively public static long calFibonacci(int index){ if (index == 1) return 0; if (index == 2) return 1; return calFibonacci(index - 1) + calFibonacci(index - 2); } } /** Outputs * Enter the value of n 25 The 25. Fibonacci number is 75025 */ /******************************using iterative method************************************/ /** * 1.2.2 Java program to calculate the fibonacci number using iterative method */ import java.util.Scanner; public class Fibo2 { public static void main(String args[]){ Scanner scan= new Scanner(System.in); //Scanner object to read from the user int n; System.out.println(\"Enter the value of n\"); n=scan.nextInt(); System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1)); // Calling the iterative method to calculate fibonacci number scan.close(); } public static long calFibonacci(int index){ int first=0; int second=1; for(int i=2;i<=index;i++){ int temp=first; first=first+second; second=temp; } return first; } } /** Output * * Enter the value of n 25 The 25. Fibonacci number is 75025 * */ /**************************************************/ The efficient method is the iterative way of calculating the number Explaination In recursion method we calculate the the numbers from current index till 0. So for each index we do calculate the fibonacci number again and again. Hence it takes a lot time to calculate the answers. Whereas in iterative method we do not rework like recursion. Here we store the previous two numbers(first and second in above code) and calculate the next one. So its a efficient way to calculate the number. The time complexity in this will be O(n). Thanks a lot. Please feel free to ask doubts if you have any. God bless you. Solution /******************* using recursive method **********************/ /** * 1.2.1 Java program to calculate the Fibonacci Number using recursion */ import java.util.Scanner; public class Fibo { public static void main(String args[]){ Scanner scan= new Scanner(System.in); //Scanner object to read from the user int n; System.out.println(\"Enter the value of n\"); n=scan.nextInt(); System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the recursive method scan.close(); } //method to calculate Fibonacci number recursively public static long calFibonacci(int index){ if (index == 1) return 0; if (index == 2) return 1; return calFibonacci(index - 1) + calFibonacci(index - 2); } } /** Outputs * .

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What will be the output from the following code if the user enters 4. int[] list = {1, 4, 4, 2, 5, -3, 6, 2}; int toSearch = input.nextInt(); int location = -1; for(int i = 0; i < list.length; i++) { if(list[i] == toSearch) { location = i; } } System.out.print(location); Solution Program: import java.io.*; import java.util.Scanner; public class Ary { public static void main(String[] args) { int[] list = {1, 4, 4, 2, 5, -3, 6, 2}; Scanner input = new Scanner(System.in); // here we are scanning the input from the user int toSearch = input.nextInt(); int location = -1; for(int i = 0; i < list.length; i++) { if(list[i] == toSearch) { location = i; } } System.out.println(location); // here we are printing the corresponding element in the list based on user input } } //if the user enters number 4 the output of the above code is as follows Output: 4 2.

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For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days Solution For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x)) Where a = initial amount a-x = amount left after time t = a / 10 t = time = ? k = rate constant = 3.43x10 -2 d -2 Plug the values we get t = ( 2.303 /k )x log ( a / (a-x)) = ( 2.303 / 3.43x10 -2 )x log ( a / (a/10)) = 67.14 days.

import java.util.Scanner;public class HornersPolynomial { .pdf

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Direct memory access (DMA) is a function that allows an inputoutput.pdf

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b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements. Solution b) Security requirements Security requirements are the outputs of the risk management activity. Inputs to the risk management and information security strategy include business strategy, business processes, risk assessments, business input analysis, information resources, and regulatory requirements..

Ethanol is miscible in water because of the hydroxyl functional grou.pdf

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the diluted concentration of HCl = (0.120 M x 25..pdf

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Simple Nobody Knows The Answer .pdf

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a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..

AnswerThe net equation of the reaction catalyzed by the protein c.pdf

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A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..

Answer i command.The vi editor always starts in command mode. For.pdf

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A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.

Answer (b) systems security and control.The businesses are now a .pdf

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A. Temeperature of refrigeratorsIntervalB. Horspower of .pdf

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48. The answer is Botulism. Botulism ia an illness that brings about.pdf

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(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..

2) b) Understory is rich in humidity hence supports fungi3) a) can.pdf

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#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).

1.Discuss in detail Emile Durkheim and his contributions to the fiel.pdf

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1) YELLOW FEVERGroup Group IV ((+) ssRNA)Order Unassigned.pdf

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Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki Solution Thermodynamic entropy is a non-conserved state function that is of great importance in the sciences of physics and chemistry. Historically, the concept of entropy evolved in order to explain why some processes (permitted by conservation laws) occur spontaneously while their time reversals (also permitted by conservation laws) do not; systems tend to progress in the direction of increasing entropy. For isolated systems, entropy never decreases. This fact has several important consequences in science: first, it prohibits \"perpetual motion\" machines; and second, it implies the arrow of entropy has the same directionality as the arrow of time. Increases in entropy correspond to irreversible changes in a system, because some energy is expended as waste heat, limiting the amount of work a system can do. In statistical mechanics, entropy is a measure of the number of ways in which a system may be arranged, often taken to be a measure of \"disorder\" (the higher the entropy, the higher the disorder). This definition describes the entropy as being proportional to the natural logarithm of the number of possible microscopic configurations of the individual atoms and molecules of the system (microstates) which could give rise to the observed macroscopic state (macrostate) of the system. The constant of proportionality is the Boltzmann constant. - Wiki.

Thermodynamic entropy is a non-conserved state fu.pdf

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I is oxidized by 6 electrons as the oxidation sta.pdf

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The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method Solution The main difference is that Democritus was not a scientist he was a philosopher as such he only theorized that matter could not be indefinitely divided, that there is a limit (now know to be the atom). Dalton on the other had based his theory of atoms on scientific experimentation and observation. Demeocritus used reason vs. Dalton used scientific method.

The main difference is that Democritus was not a .pdf

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for acidic nature is should give H+ equation H.pdf

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