molarity = 0.252101.1 =0.001236 M percent =0.251002 =12.5 .pdf

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A

If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform Solution If this is not soluble in water, this must be nonpolar, if it si soluble in hexane, this must be nonpolar as well therefore, we are certain this is nonpolar substance with low vap pressure... From the list, nearest BP for that pressure is chloroform with 60ºC (vs 58.) which is ok, since no range is given. CCl4 is nonpolar In order to ensure this, you could use a chromatography with previous data, i.e. use chloroform standard and run chromatography vs. unkown. If they behave the same ( same Rf value, and retention time ) then this is most likely chloroform.

molarity = 0.25/2*101.1 =0.001236 M
percent =0.25*100/2 =12.5 %
Solution
molarity = 0.25/2*101.1 =0.001236 M
percent =0.25*100/2 =12.5 %

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a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]. Solution a) [21]+[19] = [40] = [4] {since 40 when divided ny 12 leaves a remainder of 4 } b) [37][27] = [ 999] = [9] { Since now the remiander will be 9 when divided by 45} c) [33]([83] - [67]) = [33] [16] = [528] = [28] d) [18] + [8] = [26] = [0]. Hence additive inverse of [18] is [8]..

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A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation. Solution A Shareholder of a company is holding a share in the assets of the company. A shareholder is also entitled to the profits which company makes by using those assets. As the basic fomat of company distinguishes the Management function from the ownership, People managing the company may or maynot be the owners i.e share holders of the company. Regulators often require the companies to obtain approval of the shareholders via a resolution in the shareholders meeting, thus the deciding power rests with the shareholders. However the extent of powers are contained in the Legislature governing that corporation. Shareholders have right in the assets of the corporation not in the day to day mangement of the corporation..

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A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps Solution A chemical formula is an expression indicating the atoms and their number in a particular compound. Each element/atom is identified by its symbol and the number of atoms are given in the subscript. For example, one molecule of water contain 2 atoms of hydrogen and one atom of oxygen: H2O Hope this helps.

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(A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity. Solution (A) The answer is b. increases Electricity in the form of electrons are transported through the solution by charged ions of the electrolyte. As the electrolyte concentration increases, so does the number of charge carriers and hence the amount of charge and electricity conducted increases. (B) Acetic acid (CH3COOH) is a weak acid and partially ionizes in water: CH3COOH + H2O => CH3COO- + H3O+ The charged acetate (CH3COO- ) and hydroxonium (H3O+) ions are responsible for electrical conductivity. In 6 M acetic acid, water is in excess and and the ionization proceeds as shown above to give an electrolyte solution with charged ions that conduct electricity. In glacial acetic acid, there is very little water present and ionization is negliglble. Almost all the acetic acid remains in the non-conducting molecular form (CH3COOH) and there are no charged ions present. Thus glacial acetic acid does not conduct electricity..

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#include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)) Solution #include #include #include int check(char*); int k=0; char a[100]; void shift(int,int); int main() { int i,j=0,l=0,m,p,z; do { if(j) cout<<\"Enter the string\"; fgets(a,100,stdin); j=check(a); } while(j); for(i=0;i0 && m!=2;j--) { m=2; if(a[j]==\'+\'||a[j]==\'-\'||a[j]==\'*\'||a[j]==\'/\') l++; } if(m==2) { for(m=j-2,p=1,z=1;z!=2&&m>0;m--) { if(p==1) if(a[m]==\'(\') p=2; if(p==2) { if(a[m]==\'(\'&&(a[m-1]==\'+\' ||a[m-1]==\'-\' ||a[m-1]==\'*\'||a[m-1]==\'/\')) { m--; z=2; } } } j=m; } if(j<0) j=0; else j=j+2; shift(l,j); a[j]=\'(\'; k--; i++; } } if(k) cout<<\"Your putput is\"<<\"\ \"; cout<=0;i--) { if(a[i]==\')\') k++; if(a[i]==\'(\') return 1; } Output: Enter the string 1+2)*3-4)5-6))) Your output is ((1+2)*((3-4)*(5-6)).

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