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the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33
Solution
the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL =
0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33

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the diluted concentration of HCl = (0.120 M x 25..pdf

  • 1. the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33 Solution the diluted concentration of HCl = (0.120 M x 25.0 mL) / (25.0 + 40.0) mL = 0.0462 M [H+] = [HCl] = 0.0462 M pH = -log[H+] = -log0.0462 = 1.33