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ZnS mass ratio = 1.310.642 =2.04 .pdf
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Zn/S mass ratio = 1.31/0.642 =2.04 Solution Zn/S mass ratio = 1.31/0.642 =2.04.
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The three domains of human development are physical, cognitive and psychosocial. Physical development: Individual growth varies according to genetics, gender, culture and socioeconomic status. Physical development starts at infancy and can last till late adolescence. It is generally divided into eight stages being infancy; early, mid and late childhood; adolescence; early adulthood; middle age and old age.Specific physical changes occur at each stage of physical development. Physical development concentrates on gross and fine motor skills as well as puberty which includes developing a control over the body, particularly muscles and physical coordination. Gross motor skills involves moving the large muscles in the body like the arms and legs, consciously and deliberately. It also involves balancing and stability with movements like jumping, skipping, throwing, catching, hopping, kicking, running and galloping. Fine motor skills involves controlling small muscles in the hands and wrists. This is achieved by using small objects like handling scissors and writing instruments.Fine motor skills generally follow gross motor development. Physical growth at the infancy stage is rapid. Ther weight of the infant generally doubles over a period of 6 months. The infant grows by 10-12 inches in length( or height) and the the propartions change over a period of two years. The size of the head also decreases.The subcortical areas of brain start developing first followed by cortical areas. At birth, the barin weighs 25% of and adult brain which increases to 80% by puberty. Physical development at childhood is rapid. By the end of second year, most children can standup,walk/run, climb stairs, jump, and skip. From ages 4-5 they develop more speed and agility and posture control. Fine motor skills start developing at this stage. Physical development at adolescence starts with the beginning of puberty and ends with adulthood. The physical age ranges from 12-18 years. At puberty distinctive physiological changes occur, which involve increase in height, weight, sex characteristics, body composition and internal systems. These changes are influenced by changes in hormone activity (growth hormones, thyroid hormones and androgens). Males develop a deeper voice during puberty and females develop breasts and increased hip size start menstruation. Physical development at early adulthood is observed at ages 20-40 years. At this period the physical abilities are at their peak like muscle strength, sensory abilities, cardiac functioning etc. One also starts aging at this period. Age related changes now varies to a great extent depending on the biological factors like molecular and cellular changes and also choice of lifestyle. Aging process starts during early adulthood and is characterized by changes in skin, vision and reproductive capability. Women reach a menopause Physical development at middle age is characterized by failing organs and body functions, wrinled skin, lo.
The three domains of human development are physical, cognitive and p.pdf
The three domains of human development are physical, cognitive and p.pdf
annammalassociates
This is a templet called arrayListType.h The templet class name as arrayListType.Array of different list type is described in this template. arrayListType Data variables are Functions in class arrayListType are class name as arrayListType arrayListType Data variables are Functions in class arrayListType are 8.replace() function is used to replace an element with an element in tthe array.9. 9.retive() function is used to retive the array. 10.move() function is used to move the element from the given location. 11.clearlist() function to clear the array. 12.seqsearch() to search an element in the array sequentiallly. 13.insert() function to insert an element in the array after seaarch. 14.remove() function to remove an elementt from the array . 15.arraylisttype() a consttructor function used to for array type. 16.operator() function used for the operators used by the array Solution This is a templet called arrayListType.h The templet class name as arrayListType.Array of different list type is described in this template. arrayListType Data variables are Functions in class arrayListType are class name as arrayListType arrayListType Data variables are Functions in class arrayListType are 8.replace() function is used to replace an element with an element in tthe array.9. 9.retive() function is used to retive the array. 10.move() function is used to move the element from the given location. 11.clearlist() function to clear the array. 12.seqsearch() to search an element in the array sequentiallly. 13.insert() function to insert an element in the array after seaarch. 14.remove() function to remove an elementt from the array . 15.arraylisttype() a consttructor function used to for array type. 16.operator() function used for the operators used by the array.
This is a templet called arrayListType.hThe templet class name as .pdf
This is a templet called arrayListType.hThe templet class name as .pdf
annammalassociates
the primary purpose for developing transportation models is used to refer to a series of mathematical equations that are used to represent how choices are made when people travel. Travel demand occurs as a result of thousands of individual travelers making individual decisions on how, where and when to travel. These decisions are affected by many factors such as family situations, characteristics of the person making the trip, and the choices (destination, route and mode) available for the trip. Mathematical relationships are used to represent (model) human behavior in making these choices. Models require a series of assumptions in order to work and are limited by the data available to make forecasts. The coefficients and parameters in the model are set (calibrated) to match existing data. Normally, these relationships are assumed to be valid and to remain constant in the future. Solution the primary purpose for developing transportation models is used to refer to a series of mathematical equations that are used to represent how choices are made when people travel. Travel demand occurs as a result of thousands of individual travelers making individual decisions on how, where and when to travel. These decisions are affected by many factors such as family situations, characteristics of the person making the trip, and the choices (destination, route and mode) available for the trip. Mathematical relationships are used to represent (model) human behavior in making these choices. Models require a series of assumptions in order to work and are limited by the data available to make forecasts. The coefficients and parameters in the model are set (calibrated) to match existing data. Normally, these relationships are assumed to be valid and to remain constant in the future..
the primary purpose for developing transportation models is used to .pdf
the primary purpose for developing transportation models is used to .pdf
annammalassociates
The origin of colour in complex ions containing transition metals Complex ions containing transition metals are usually coloured, whereas the similar ions from non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in generating the colour in some way. Remember that transition metals are defined as having partly filled d orbitals. Solution The origin of colour in complex ions containing transition metals Complex ions containing transition metals are usually coloured, whereas the similar ions from non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in generating the colour in some way. Remember that transition metals are defined as having partly filled d orbitals..
The origin of colour in complex ions containing transition metals.pdf
The origin of colour in complex ions containing transition metals.pdf
annammalassociates
a. 0.010 M NaCl pH will be approximately 7 because the solution will be neutral b. 0.010 M NaOH 0.01 M NaOH pOH= -log(0.01) =2 pH +pOH =14 pH = 12 c. 0.010 M NH3 NH3 + H2O NH4(+) + OH- Kb = 1.8*10^-5 = [X]2/(1 - X) the x in denominator can be ignored as the value is much smaller than 1 1.8*10^-5 = [X]2 [OH]=[X]=4.243*10^-3 pOH = -log[OH]=2.37 pH +pOH =14 pH = 11.63 d. 0.010 M malonic acid pka1=2.85,pka2=5.70 concentration doesnot matter for diprotic acids pH= (pka1 + pka2) /2 pH=(2.85+5.70)/2=4.275 Solution a. 0.010 M NaCl pH will be approximately 7 because the solution will be neutral b. 0.010 M NaOH 0.01 M NaOH pOH= -log(0.01) =2 pH +pOH =14 pH = 12 c. 0.010 M NH3 NH3 + H2O NH4(+) + OH- Kb = 1.8*10^-5 = [X]2/(1 - X) the x in denominator can be ignored as the value is much smaller than 1 1.8*10^-5 = [X]2 [OH]=[X]=4.243*10^-3 pOH = -log[OH]=2.37 pH +pOH =14 pH = 11.63 d. 0.010 M malonic acid pka1=2.85,pka2=5.70 concentration doesnot matter for diprotic acids pH= (pka1 + pka2) /2 pH=(2.85+5.70)/2=4.275.
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
annammalassociates
Transition metal elements have atoms or ions with partially filled \'d\' subshells. Solution Transition metal elements have atoms or ions with partially filled \'d\' subshells..
Transition metal elements have atoms or ions with partially filled .pdf
Transition metal elements have atoms or ions with partially filled .pdf
annammalassociates
We know that: The energy of He+ can be calculated as the hydrogen like atom E = - 2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = - 2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ Solution We know that: The energy of He+ can be calculated as the hydrogen like atom E = - 2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = - 2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ.
We know that The energy of He+ can be calculated.pdf
We know that The energy of He+ can be calculated.pdf
annammalassociates
two lone pairs Solution two lone pairs.
two lone pairs Solution .pdf
two lone pairs Solution .pdf
annammalassociates
Recommended
The three domains of human development are physical, cognitive and psychosocial. Physical development: Individual growth varies according to genetics, gender, culture and socioeconomic status. Physical development starts at infancy and can last till late adolescence. It is generally divided into eight stages being infancy; early, mid and late childhood; adolescence; early adulthood; middle age and old age.Specific physical changes occur at each stage of physical development. Physical development concentrates on gross and fine motor skills as well as puberty which includes developing a control over the body, particularly muscles and physical coordination. Gross motor skills involves moving the large muscles in the body like the arms and legs, consciously and deliberately. It also involves balancing and stability with movements like jumping, skipping, throwing, catching, hopping, kicking, running and galloping. Fine motor skills involves controlling small muscles in the hands and wrists. This is achieved by using small objects like handling scissors and writing instruments.Fine motor skills generally follow gross motor development. Physical growth at the infancy stage is rapid. Ther weight of the infant generally doubles over a period of 6 months. The infant grows by 10-12 inches in length( or height) and the the propartions change over a period of two years. The size of the head also decreases.The subcortical areas of brain start developing first followed by cortical areas. At birth, the barin weighs 25% of and adult brain which increases to 80% by puberty. Physical development at childhood is rapid. By the end of second year, most children can standup,walk/run, climb stairs, jump, and skip. From ages 4-5 they develop more speed and agility and posture control. Fine motor skills start developing at this stage. Physical development at adolescence starts with the beginning of puberty and ends with adulthood. The physical age ranges from 12-18 years. At puberty distinctive physiological changes occur, which involve increase in height, weight, sex characteristics, body composition and internal systems. These changes are influenced by changes in hormone activity (growth hormones, thyroid hormones and androgens). Males develop a deeper voice during puberty and females develop breasts and increased hip size start menstruation. Physical development at early adulthood is observed at ages 20-40 years. At this period the physical abilities are at their peak like muscle strength, sensory abilities, cardiac functioning etc. One also starts aging at this period. Age related changes now varies to a great extent depending on the biological factors like molecular and cellular changes and also choice of lifestyle. Aging process starts during early adulthood and is characterized by changes in skin, vision and reproductive capability. Women reach a menopause Physical development at middle age is characterized by failing organs and body functions, wrinled skin, lo.
The three domains of human development are physical, cognitive and p.pdf
The three domains of human development are physical, cognitive and p.pdf
annammalassociates
This is a templet called arrayListType.h The templet class name as arrayListType.Array of different list type is described in this template. arrayListType Data variables are Functions in class arrayListType are class name as arrayListType arrayListType Data variables are Functions in class arrayListType are 8.replace() function is used to replace an element with an element in tthe array.9. 9.retive() function is used to retive the array. 10.move() function is used to move the element from the given location. 11.clearlist() function to clear the array. 12.seqsearch() to search an element in the array sequentiallly. 13.insert() function to insert an element in the array after seaarch. 14.remove() function to remove an elementt from the array . 15.arraylisttype() a consttructor function used to for array type. 16.operator() function used for the operators used by the array Solution This is a templet called arrayListType.h The templet class name as arrayListType.Array of different list type is described in this template. arrayListType Data variables are Functions in class arrayListType are class name as arrayListType arrayListType Data variables are Functions in class arrayListType are 8.replace() function is used to replace an element with an element in tthe array.9. 9.retive() function is used to retive the array. 10.move() function is used to move the element from the given location. 11.clearlist() function to clear the array. 12.seqsearch() to search an element in the array sequentiallly. 13.insert() function to insert an element in the array after seaarch. 14.remove() function to remove an elementt from the array . 15.arraylisttype() a consttructor function used to for array type. 16.operator() function used for the operators used by the array.
This is a templet called arrayListType.hThe templet class name as .pdf
This is a templet called arrayListType.hThe templet class name as .pdf
annammalassociates
the primary purpose for developing transportation models is used to refer to a series of mathematical equations that are used to represent how choices are made when people travel. Travel demand occurs as a result of thousands of individual travelers making individual decisions on how, where and when to travel. These decisions are affected by many factors such as family situations, characteristics of the person making the trip, and the choices (destination, route and mode) available for the trip. Mathematical relationships are used to represent (model) human behavior in making these choices. Models require a series of assumptions in order to work and are limited by the data available to make forecasts. The coefficients and parameters in the model are set (calibrated) to match existing data. Normally, these relationships are assumed to be valid and to remain constant in the future. Solution the primary purpose for developing transportation models is used to refer to a series of mathematical equations that are used to represent how choices are made when people travel. Travel demand occurs as a result of thousands of individual travelers making individual decisions on how, where and when to travel. These decisions are affected by many factors such as family situations, characteristics of the person making the trip, and the choices (destination, route and mode) available for the trip. Mathematical relationships are used to represent (model) human behavior in making these choices. Models require a series of assumptions in order to work and are limited by the data available to make forecasts. The coefficients and parameters in the model are set (calibrated) to match existing data. Normally, these relationships are assumed to be valid and to remain constant in the future..
the primary purpose for developing transportation models is used to .pdf
the primary purpose for developing transportation models is used to .pdf
annammalassociates
The origin of colour in complex ions containing transition metals Complex ions containing transition metals are usually coloured, whereas the similar ions from non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in generating the colour in some way. Remember that transition metals are defined as having partly filled d orbitals. Solution The origin of colour in complex ions containing transition metals Complex ions containing transition metals are usually coloured, whereas the similar ions from non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in generating the colour in some way. Remember that transition metals are defined as having partly filled d orbitals..
The origin of colour in complex ions containing transition metals.pdf
The origin of colour in complex ions containing transition metals.pdf
annammalassociates
a. 0.010 M NaCl pH will be approximately 7 because the solution will be neutral b. 0.010 M NaOH 0.01 M NaOH pOH= -log(0.01) =2 pH +pOH =14 pH = 12 c. 0.010 M NH3 NH3 + H2O NH4(+) + OH- Kb = 1.8*10^-5 = [X]2/(1 - X) the x in denominator can be ignored as the value is much smaller than 1 1.8*10^-5 = [X]2 [OH]=[X]=4.243*10^-3 pOH = -log[OH]=2.37 pH +pOH =14 pH = 11.63 d. 0.010 M malonic acid pka1=2.85,pka2=5.70 concentration doesnot matter for diprotic acids pH= (pka1 + pka2) /2 pH=(2.85+5.70)/2=4.275 Solution a. 0.010 M NaCl pH will be approximately 7 because the solution will be neutral b. 0.010 M NaOH 0.01 M NaOH pOH= -log(0.01) =2 pH +pOH =14 pH = 12 c. 0.010 M NH3 NH3 + H2O NH4(+) + OH- Kb = 1.8*10^-5 = [X]2/(1 - X) the x in denominator can be ignored as the value is much smaller than 1 1.8*10^-5 = [X]2 [OH]=[X]=4.243*10^-3 pOH = -log[OH]=2.37 pH +pOH =14 pH = 11.63 d. 0.010 M malonic acid pka1=2.85,pka2=5.70 concentration doesnot matter for diprotic acids pH= (pka1 + pka2) /2 pH=(2.85+5.70)/2=4.275.
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
annammalassociates
Transition metal elements have atoms or ions with partially filled \'d\' subshells. Solution Transition metal elements have atoms or ions with partially filled \'d\' subshells..
Transition metal elements have atoms or ions with partially filled .pdf
Transition metal elements have atoms or ions with partially filled .pdf
annammalassociates
We know that: The energy of He+ can be calculated as the hydrogen like atom E = - 2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = - 2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ Solution We know that: The energy of He+ can be calculated as the hydrogen like atom E = - 2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = - 2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ.
We know that The energy of He+ can be calculated.pdf
We know that The energy of He+ can be calculated.pdf
annammalassociates
two lone pairs Solution two lone pairs.
two lone pairs Solution .pdf
two lone pairs Solution .pdf
annammalassociates
the temperature will be higher as the pressure is increased. P is directly proportional to T Solution the temperature will be higher as the pressure is increased. P is directly proportional to T.
the temperature will be higher as the pressure is.pdf
the temperature will be higher as the pressure is.pdf
annammalassociates
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides Solution The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides.
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
annammalassociates
replaces OH with COCH3 Solution replaces OH with COCH3.
replaces OH with COCH3 .pdf
replaces OH with COCH3 .pdf
annammalassociates
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 = 9.05 Solution pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 = 9.05.
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
annammalassociates
please post the clear qsn.... i ll help u in answering... thank you.... Solution please post the clear qsn.... i ll help u in answering... thank you.....
please post the clear qsn.... i ll help u in answ.pdf
please post the clear qsn.... i ll help u in answ.pdf
annammalassociates
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3 KClO3+KIO3 -->NO REACTION Solution Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3 KClO3+KIO3 -->NO REACTION.
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
annammalassociates
It\'s to remove the air. This prevents the molecules of air from interfering with the readings. Solution It\'s to remove the air. This prevents the molecules of air from interfering with the readings..
Its to remove the air. This prevents the molecu.pdf
Its to remove the air. This prevents the molecu.pdf
annammalassociates
The conclusion can be summarised as follows: Solution The conclusion can be summarised as follows:.
The conclusion can be summarised as followsSolutionThe conclu.pdf
The conclusion can be summarised as followsSolutionThe conclu.pdf
annammalassociates
The AutoCAD Electrical installation directory structure contains: Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\... Note: The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved to a shared network drive. After you move the \\Libs\\ folder you must modify the path in Support File Search Path in the Options dialog box. The following electrical schematic libraries can be installed: The following libraries are automatically installed: Main executable and static support files at C:\\Program Files\\Autodesk\\AutoCAD {version}\\ The \\ACADE\\ subfolder carries several bitmap files and other static support files. Support files at C:\\Users\\{username}\\AppData... The Support files folder structure carries the support files that have the potential of being altered by the user. The installation program creates a new Autodesk\\AutoCAD Electrical release subfolder entry under the user loginname\\AppData folder. This Application data folder is normally marked as hidden within Windows Explorer and users may need to access and customize these files. The base \\Support\\ folder carries the AutoCAD Electrical .mnl files, icon menu .dat files, and the slide library .slb files referenced by the icon menus. The \\AeToolPalette\\Palettes\\ subfolder structure carries four AutoCAD Electrical specific .atc files. The \\User\\ folder is where AutoCAD Electrical writes customized user settings files, stores temporary files, and maintains the user scratch database files for the projects. This needs to be on a per-logged-in user basis, not shared with other users Data files at C:\\Users\\{username}\\Documents\\Acade {version}\\AeData The AEDATA folder structure carries various database and project drawing files that will be altered by the user. The installation program creates a new ACADE 2015\\subfolder entry under the user login name\\Documents\\ folder. The \\AeData\\ folder carries the wd.env environment settings file plus four subfolders. The four individual subfolders to \\AeData\\ are as follows: \\{language code}\\ subfolder contains two subfolders \\Catalogs\\ and \\Plc\\. \\Catalogs\\ subfolder contains these files: D. Both Engineer are correctJIC1/JIC125USA Standard (Inch units)IEC2/IEC 60617European Standard (MM units)JIS2Japanese Standard (MM units)GB2Chinese Standard (MM units)AS2Australian Standard (MM units)IEEE 315/315AInstitute of Electrical and Electronics Engineers Standard (MM units)NFPANational Fire Protection Association Standard (Inch units) Solution The AutoCAD Electrical installation directory structure contains: Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\... Note: The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved t.
The AutoCAD Electrical installation directory structure containsS.pdf
The AutoCAD Electrical installation directory structure containsS.pdf
annammalassociates
Service that are performed by distributed objects. Objects is the specified task that are performed by the software. Business problems sloved by use of classes: 1.cheap, transparent communication 2.Object identity and lifetime maintained by infrastructure Business problems solved by use of communication: 1.use of heterogeneous platform 2.explicit communication Solution Service that are performed by distributed objects. Objects is the specified task that are performed by the software. Business problems sloved by use of classes: 1.cheap, transparent communication 2.Object identity and lifetime maintained by infrastructure Business problems solved by use of communication: 1.use of heterogeneous platform 2.explicit communication.
Service that are performed by distributed objects.Objects is the s.pdf
Service that are performed by distributed objects.Objects is the s.pdf
annammalassociates
Profits increase by 41% (I just took the Quiz) Solution Profits increase by 41% (I just took the Quiz).
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
annammalassociates
rate = k*x*y*z Solution rate = k*x*y*z.
rate = kxyzSolutionrate = kxyz.pdf
rate = kxyzSolutionrate = kxyz.pdf
annammalassociates
Operations Sales Administrative Depreciation on factory equipment. Advertising manager\'s salary. Depreciation on office equipment Depreciation on factory building Salespersons\' travel expenses Cost of hiring new employees Assembly foreman\'s salary. Salespersons\' salaries Leasing of computer equipment for the Accounting Department Supplies for the Machining Department Advertising supplies used. Electricity for the Assembly Department Supplies for the sales office Lost materials (scrap) in a Machining Department. Sales commissions. Direct labor in the Assembly Department Packing supplies. Supplies for Production Scheduling Cost of repairing parts improperly manufactured in the Machining Department. Payroll fringe benefits for workers in the Shipping Departmen Paint for the Assembly Department. Heat, light, and power for the factory b) Operations Sales Administrative Depreciation on factory equipment.-Unit Level Activity Advertising manager\'s salary.Product Level Depreciation on office equipment Facility Level Depreciation on factory building Unit Level Activity Salespersons\' travel expenses Product Level Cost of hiring new employees Facility Level Assembly foreman\'s salary. Level Activity Batch Level Activity Salespersons\' salaries Product Level Leasing of computer equipment for the Accounting Department Facility Level Supplies for the Machining Department Unit Level Activity Advertising supplies used. Product Level Electricity for the Assembly Department Unit Level Activity Supplies for the sales office Product Level Lost materials (scrap) in a Machining Department. Batch Level Activity Sales commissions. Product Level Direct labor in the Assembly Department Unit Level Activity Packing supplies. Batch Level Activity Batch Level Activity Supplies for Production Scheduling Unit Level Activity Cost of repairing parts improperly manufactured in the Machining Department. Batch Level Activity Payroll fringe benefits for workers in the Shipping Departmen Batch Level Activity Paint for the Assembly Department.Batch Level Activity Heat, light, and power for the factory Unit Level Activity c) Unit Level Activities: Labours Hours,No. of units produced or machine hours Batch level: no of purchase orders,amount of material, no.of setups, no. of customer order, no of customers Product Level:No. of orders, no. of supervision hours,no. of test, no. of test time Facility Level:no. of employees,sqaure foot,labours hours. d) Operations Sales Administrative Depreciation on factory equipment.-Unit Level Activity- Machine hours Advertising manager\'s salary.Product Level no. of orders Depreciation on office equipment Facility Level square foot Depreciation on factory building Unit Level Activity Machine hours Salespersons\' travel expenses Product Level Cost of hiring new employees Facility Level no. of employees Assembly foreman\'s salary. Level Activity Batch Level Activity Salespersons\' salaries Product Level no. of orders Leasing of computer equipment .
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
annammalassociates
moles of base, using molar mass of NaOH: 15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH moles of acid: 0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid the reaction is 1:1 1 NaOH + 1 HNO3 --> NaNO3 + H2O so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC: 0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of the base , which is: 0.3375 moles base ------------ concentrations of all the ions present 0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH / 0.150litres = 2.50 molar NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar Solution moles of base, using molar mass of NaOH: 15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH moles of acid: 0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid the reaction is 1:1 1 NaOH + 1 HNO3 --> NaNO3 + H2O so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC: 0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of the base , which is: 0.3375 moles base ------------ concentrations of all the ions present 0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH / 0.150litres = 2.50 molar NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar.
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
annammalassociates
Microscopic examination usually support s the presence of White blood cells in the urine elements. In case of Urinary tract infection. 4). White blood cells. Solution Microscopic examination usually support s the presence of White blood cells in the urine elements. In case of Urinary tract infection. 4). White blood cells..
Microscopic examination usually support s the presence of White bloo.pdf
Microscopic examination usually support s the presence of White bloo.pdf
annammalassociates
molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10 Solution molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10.
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
annammalassociates
Lung volumes and lung capacity Lung volumes and lung capacities refer to the volume of air associated with different phases of the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung volumes. The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20 breaths per minute in adults. The total amount of air that the lungs can accommodate is divided into four separate volumes and four capacities. Combinations of these volumes are used to designate lung capacities. Lung volume and capacity vary with age, race, height, and gender The following terms describe the various lung (respiratory) volumes: Summing specific lung volumes produces the following lung capacities: In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic bronchitis In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and pulmonary edema. Differences between lung volume and capacity Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume and expiratory volume It varies from 5-6 liters It varies from 3.5-4.5 liters Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume and expiratory volume It varies from 5-6 liters It varies from 3.5-4.5 liters Solution Lung volumes and lung capacity Lung volumes and lung capacities refer to the volume of air associated with different phases of the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung volumes. The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20 breaths per minute in adults. The total amount of air that the lungs can accommodate is divided into four separate volumes and four capacities. Combinations of these volumes are used to designate lung capacities. Lung volume and capacity vary with age, race, height, and gender The following terms describe the various lung (respiratory) volumes: Summing specific lung volumes produces the following lung capacities: In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic bronchitis In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and pulmonary edema. Differences between lung volume and capacity Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume an.
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
annammalassociates
A) The source provides energy, it\'s normally a laser. B) The prism directs the source or the directions of the laser C) The exit slit is where the laser exits after it goes through the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s normally a glass cuvette. E) The detector detects the photons that where excited by the laser. Solution A) The source provides energy, it\'s normally a laser. B) The prism directs the source or the directions of the laser C) The exit slit is where the laser exits after it goes through the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s normally a glass cuvette. E) The detector detects the photons that where excited by the laser..
A) The source provides energy, its normally a l.pdf
A) The source provides energy, its normally a l.pdf
annammalassociates
Answer: The blue colored tracts Ascending tracts are sensory and deliver information to the brain. Solution Answer: The blue colored tracts Ascending tracts are sensory and deliver information to the brain..
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
annammalassociates
Hence I am inclinedto think its A. Solution Hence I am inclinedto think its A..
Hence I am inclinedto think its A.SolutionHenc.pdf
Hence I am inclinedto think its A.SolutionHenc.pdf
annammalassociates
This presentation covers the essential parameters of Unit 2 Operations Processes of the subject Operations & Supply Chain Management. Topics Covered: Volume Variety and Flow. Types of Processes and Operations Systems - Continuous Flow system and intermittent flow systems.Job Production, Batch Production, Assembly line and Continuous Flow, Process and Product Layout. Design of Service Systems, Service Blueprinting.
OSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & Systems
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the temperature will be higher as the pressure is increased. P is directly proportional to T Solution the temperature will be higher as the pressure is increased. P is directly proportional to T.
the temperature will be higher as the pressure is.pdf
the temperature will be higher as the pressure is.pdf
annammalassociates
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides Solution The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides.
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
annammalassociates
replaces OH with COCH3 Solution replaces OH with COCH3.
replaces OH with COCH3 .pdf
replaces OH with COCH3 .pdf
annammalassociates
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 = 9.05 Solution pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 = 9.05.
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
annammalassociates
please post the clear qsn.... i ll help u in answering... thank you.... Solution please post the clear qsn.... i ll help u in answering... thank you.....
please post the clear qsn.... i ll help u in answ.pdf
please post the clear qsn.... i ll help u in answ.pdf
annammalassociates
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3 KClO3+KIO3 -->NO REACTION Solution Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3 KClO3+KIO3 -->NO REACTION.
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
annammalassociates
It\'s to remove the air. This prevents the molecules of air from interfering with the readings. Solution It\'s to remove the air. This prevents the molecules of air from interfering with the readings..
Its to remove the air. This prevents the molecu.pdf
Its to remove the air. This prevents the molecu.pdf
annammalassociates
The conclusion can be summarised as follows: Solution The conclusion can be summarised as follows:.
The conclusion can be summarised as followsSolutionThe conclu.pdf
The conclusion can be summarised as followsSolutionThe conclu.pdf
annammalassociates
The AutoCAD Electrical installation directory structure contains: Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\... Note: The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved to a shared network drive. After you move the \\Libs\\ folder you must modify the path in Support File Search Path in the Options dialog box. The following electrical schematic libraries can be installed: The following libraries are automatically installed: Main executable and static support files at C:\\Program Files\\Autodesk\\AutoCAD {version}\\ The \\ACADE\\ subfolder carries several bitmap files and other static support files. Support files at C:\\Users\\{username}\\AppData... The Support files folder structure carries the support files that have the potential of being altered by the user. The installation program creates a new Autodesk\\AutoCAD Electrical release subfolder entry under the user loginname\\AppData folder. This Application data folder is normally marked as hidden within Windows Explorer and users may need to access and customize these files. The base \\Support\\ folder carries the AutoCAD Electrical .mnl files, icon menu .dat files, and the slide library .slb files referenced by the icon menus. The \\AeToolPalette\\Palettes\\ subfolder structure carries four AutoCAD Electrical specific .atc files. The \\User\\ folder is where AutoCAD Electrical writes customized user settings files, stores temporary files, and maintains the user scratch database files for the projects. This needs to be on a per-logged-in user basis, not shared with other users Data files at C:\\Users\\{username}\\Documents\\Acade {version}\\AeData The AEDATA folder structure carries various database and project drawing files that will be altered by the user. The installation program creates a new ACADE 2015\\subfolder entry under the user login name\\Documents\\ folder. The \\AeData\\ folder carries the wd.env environment settings file plus four subfolders. The four individual subfolders to \\AeData\\ are as follows: \\{language code}\\ subfolder contains two subfolders \\Catalogs\\ and \\Plc\\. \\Catalogs\\ subfolder contains these files: D. Both Engineer are correctJIC1/JIC125USA Standard (Inch units)IEC2/IEC 60617European Standard (MM units)JIS2Japanese Standard (MM units)GB2Chinese Standard (MM units)AS2Australian Standard (MM units)IEEE 315/315AInstitute of Electrical and Electronics Engineers Standard (MM units)NFPANational Fire Protection Association Standard (Inch units) Solution The AutoCAD Electrical installation directory structure contains: Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\... Note: The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved t.
The AutoCAD Electrical installation directory structure containsS.pdf
The AutoCAD Electrical installation directory structure containsS.pdf
annammalassociates
Service that are performed by distributed objects. Objects is the specified task that are performed by the software. Business problems sloved by use of classes: 1.cheap, transparent communication 2.Object identity and lifetime maintained by infrastructure Business problems solved by use of communication: 1.use of heterogeneous platform 2.explicit communication Solution Service that are performed by distributed objects. Objects is the specified task that are performed by the software. Business problems sloved by use of classes: 1.cheap, transparent communication 2.Object identity and lifetime maintained by infrastructure Business problems solved by use of communication: 1.use of heterogeneous platform 2.explicit communication.
Service that are performed by distributed objects.Objects is the s.pdf
Service that are performed by distributed objects.Objects is the s.pdf
annammalassociates
Profits increase by 41% (I just took the Quiz) Solution Profits increase by 41% (I just took the Quiz).
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
annammalassociates
rate = k*x*y*z Solution rate = k*x*y*z.
rate = kxyzSolutionrate = kxyz.pdf
rate = kxyzSolutionrate = kxyz.pdf
annammalassociates
Operations Sales Administrative Depreciation on factory equipment. Advertising manager\'s salary. Depreciation on office equipment Depreciation on factory building Salespersons\' travel expenses Cost of hiring new employees Assembly foreman\'s salary. Salespersons\' salaries Leasing of computer equipment for the Accounting Department Supplies for the Machining Department Advertising supplies used. Electricity for the Assembly Department Supplies for the sales office Lost materials (scrap) in a Machining Department. Sales commissions. Direct labor in the Assembly Department Packing supplies. Supplies for Production Scheduling Cost of repairing parts improperly manufactured in the Machining Department. Payroll fringe benefits for workers in the Shipping Departmen Paint for the Assembly Department. Heat, light, and power for the factory b) Operations Sales Administrative Depreciation on factory equipment.-Unit Level Activity Advertising manager\'s salary.Product Level Depreciation on office equipment Facility Level Depreciation on factory building Unit Level Activity Salespersons\' travel expenses Product Level Cost of hiring new employees Facility Level Assembly foreman\'s salary. Level Activity Batch Level Activity Salespersons\' salaries Product Level Leasing of computer equipment for the Accounting Department Facility Level Supplies for the Machining Department Unit Level Activity Advertising supplies used. Product Level Electricity for the Assembly Department Unit Level Activity Supplies for the sales office Product Level Lost materials (scrap) in a Machining Department. Batch Level Activity Sales commissions. Product Level Direct labor in the Assembly Department Unit Level Activity Packing supplies. Batch Level Activity Batch Level Activity Supplies for Production Scheduling Unit Level Activity Cost of repairing parts improperly manufactured in the Machining Department. Batch Level Activity Payroll fringe benefits for workers in the Shipping Departmen Batch Level Activity Paint for the Assembly Department.Batch Level Activity Heat, light, and power for the factory Unit Level Activity c) Unit Level Activities: Labours Hours,No. of units produced or machine hours Batch level: no of purchase orders,amount of material, no.of setups, no. of customer order, no of customers Product Level:No. of orders, no. of supervision hours,no. of test, no. of test time Facility Level:no. of employees,sqaure foot,labours hours. d) Operations Sales Administrative Depreciation on factory equipment.-Unit Level Activity- Machine hours Advertising manager\'s salary.Product Level no. of orders Depreciation on office equipment Facility Level square foot Depreciation on factory building Unit Level Activity Machine hours Salespersons\' travel expenses Product Level Cost of hiring new employees Facility Level no. of employees Assembly foreman\'s salary. Level Activity Batch Level Activity Salespersons\' salaries Product Level no. of orders Leasing of computer equipment .
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
annammalassociates
moles of base, using molar mass of NaOH: 15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH moles of acid: 0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid the reaction is 1:1 1 NaOH + 1 HNO3 --> NaNO3 + H2O so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC: 0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of the base , which is: 0.3375 moles base ------------ concentrations of all the ions present 0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH / 0.150litres = 2.50 molar NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar Solution moles of base, using molar mass of NaOH: 15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH moles of acid: 0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid the reaction is 1:1 1 NaOH + 1 HNO3 --> NaNO3 + H2O so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC: 0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of the base , which is: 0.3375 moles base ------------ concentrations of all the ions present 0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH / 0.150litres = 2.50 molar NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar.
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
annammalassociates
Microscopic examination usually support s the presence of White blood cells in the urine elements. In case of Urinary tract infection. 4). White blood cells. Solution Microscopic examination usually support s the presence of White blood cells in the urine elements. In case of Urinary tract infection. 4). White blood cells..
Microscopic examination usually support s the presence of White bloo.pdf
Microscopic examination usually support s the presence of White bloo.pdf
annammalassociates
molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10 Solution molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10.
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
annammalassociates
Lung volumes and lung capacity Lung volumes and lung capacities refer to the volume of air associated with different phases of the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung volumes. The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20 breaths per minute in adults. The total amount of air that the lungs can accommodate is divided into four separate volumes and four capacities. Combinations of these volumes are used to designate lung capacities. Lung volume and capacity vary with age, race, height, and gender The following terms describe the various lung (respiratory) volumes: Summing specific lung volumes produces the following lung capacities: In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic bronchitis In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and pulmonary edema. Differences between lung volume and capacity Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume and expiratory volume It varies from 5-6 liters It varies from 3.5-4.5 liters Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume and expiratory volume It varies from 5-6 liters It varies from 3.5-4.5 liters Solution Lung volumes and lung capacity Lung volumes and lung capacities refer to the volume of air associated with different phases of the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung volumes. The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20 breaths per minute in adults. The total amount of air that the lungs can accommodate is divided into four separate volumes and four capacities. Combinations of these volumes are used to designate lung capacities. Lung volume and capacity vary with age, race, height, and gender The following terms describe the various lung (respiratory) volumes: Summing specific lung volumes produces the following lung capacities: In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic bronchitis In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and pulmonary edema. Differences between lung volume and capacity Lung volume Lung capacity It is the total volume of air in the lungs It is the maximum volume of air that can be inhaled and exhaled during forced breathing It is the sum of the vital capacity and residual volume It is the sum of tidal volume, inspiratory reserve volume an.
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
annammalassociates
A) The source provides energy, it\'s normally a laser. B) The prism directs the source or the directions of the laser C) The exit slit is where the laser exits after it goes through the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s normally a glass cuvette. E) The detector detects the photons that where excited by the laser. Solution A) The source provides energy, it\'s normally a laser. B) The prism directs the source or the directions of the laser C) The exit slit is where the laser exits after it goes through the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s normally a glass cuvette. E) The detector detects the photons that where excited by the laser..
A) The source provides energy, its normally a l.pdf
A) The source provides energy, its normally a l.pdf
annammalassociates
Answer: The blue colored tracts Ascending tracts are sensory and deliver information to the brain. Solution Answer: The blue colored tracts Ascending tracts are sensory and deliver information to the brain..
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
annammalassociates
Hence I am inclinedto think its A. Solution Hence I am inclinedto think its A..
Hence I am inclinedto think its A.SolutionHenc.pdf
Hence I am inclinedto think its A.SolutionHenc.pdf
annammalassociates
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httgc7rh9c
Here is the slide show presentation from the Pre-Deployment Brief for HMCS Max Bernays from May 8th, 2024.
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
Esquimalt MFRC
Program code examples (known also as worked examples) play a crucial role in learning how to program. Instructors use examples extensively to demonstrate the semantics of the programming language being taught and to highlight the fundamental coding patterns. Programming textbooks allocate considerable space to present and explain code examples. To make the process of studying code examples more interactive, CS education researchers developed a range of tools to engage students in the study of code examples. These tools include codecasts (codemotion,codecast,elicasts), interactive example explorers (WebEx, PCEX), and tutoring systems (DeepTutor). An important component in all types of worked examples is code explanations associated with specific code lines or code chunks of an example. The explanations connect examples with general programming knowledge explaining the role and function of code fragments or their behavior. In textbooks, these explanations are usually presented as comments in the code or as explanations on the margins. The example explorer tools allow students to examine these explanations interactively. Tutoring systems, which engage students in explaining the code, use these model explanations to check student responses and provide scaffolding. In all these cases, to make a worked example re-usable beyond its presentation in a lecture, the explanations have to be authored by instructors or domain experts i.e., produced and integrated into a specific system. As the experience of the last 10 years demonstrated, these explanations are hard to obtain. Those already collected are usually “locked” in a specific example-focused system and can’t be reused. The purpose of this working group is to support broader re-used of worked examples augmented with explanations. Our current plan is to develop а standard approach to represent explained examples. This approach will enable an example created for any of the existing systems to be explored in a standard format and imported into any other example-focused system. We plan to follow a successful experience of the PEML working group focused on re-using programming exercises.
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ZnS mass ratio = 1.310.642 =2.04 .pdf
1.
Zn/S mass ratio
= 1.31/0.642 =2.04 Solution Zn/S mass ratio = 1.31/0.642 =2.04
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