Its to remove the air. This prevents the molecu.pdf
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It\'s to remove the air. This prevents the molecules of air from interfering with the readings. Solution It\'s to remove the air. This prevents the molecules of air from interfering with the readings..
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The three domains of human development are physical, cognitive and p.pdf
The three domains of human development are physical, cognitive and psychosocial.
Physical development:
Individual growth varies according to genetics, gender, culture and socioeconomic status.
Physical development starts at infancy and can last till late adolescence. It is generally divided
into eight stages being infancy; early, mid and late childhood; adolescence; early adulthood;
middle age and old age.Specific physical changes occur at each stage of physical development.
Physical development concentrates on gross and fine motor skills as well as puberty which
includes developing a control over the body, particularly muscles and physical coordination.
Gross motor skills involves moving the large muscles in the body like the arms and legs,
consciously and deliberately. It also involves balancing and stability with movements like
jumping, skipping, throwing, catching, hopping, kicking, running and galloping.
Fine motor skills involves controlling small muscles in the hands and wrists. This is achieved by
using small objects like handling scissors and writing instruments.Fine motor skills generally
follow gross motor development.
Physical growth at the infancy stage is rapid. Ther weight of the infant generally doubles over a
period of 6 months. The infant grows by 10-12 inches in length( or height) and the the
propartions change over a period of two years. The size of the head also decreases.The
subcortical areas of brain start developing first followed by cortical areas. At birth, the barin
weighs 25% of and adult brain which increases to 80% by puberty.
Physical development at childhood is rapid. By the end of second year, most children can
standup,walk/run, climb stairs, jump, and skip. From ages 4-5 they develop more speed and
agility and posture control. Fine motor skills start developing at this stage.
Physical development at adolescence starts with the beginning of puberty and ends with
adulthood. The physical age ranges from 12-18 years. At puberty distinctive physiological
changes occur, which involve increase in height, weight, sex characteristics, body composition
and internal systems. These changes are influenced by changes in hormone activity (growth
hormones, thyroid hormones and androgens).
Males develop a deeper voice during puberty and females develop breasts and increased hip size
start menstruation.
Physical development at early adulthood is observed at ages 20-40 years. At this period the
physical abilities are at their peak like muscle strength, sensory abilities, cardiac functioning etc.
One also starts aging at this period. Age related changes now varies to a great extent depending
on the biological factors like molecular and cellular changes and also choice of lifestyle. Aging
process starts during early adulthood and is characterized by changes in skin, vision and
reproductive capability. Women reach a menopause
Physical development at middle age is characterized by failing organs and body functions,
wrinled skin, lo.
This is a templet called arrayListType.hThe templet class name as .pdf
This is a templet called arrayListType.h
The templet class name as arrayListType.Array of different list type is described in this template.
arrayListType Data variables are
Functions in class arrayListType are
class name as arrayListType
arrayListType Data variables are
Functions in class arrayListType are
8.replace() function is used to replace an element with an element in tthe array.9.
9.retive() function is used to retive the array.
10.move() function is used to move the element from the given location.
11.clearlist() function to clear the array.
12.seqsearch() to search an element in the array sequentiallly.
13.insert() function to insert an element in the array after seaarch.
14.remove() function to remove an elementt from the array .
15.arraylisttype() a consttructor function used to for array type.
16.operator() function used for the operators used by the array
Solution
This is a templet called arrayListType.h
The templet class name as arrayListType.Array of different list type is described in this template.
arrayListType Data variables are
Functions in class arrayListType are
class name as arrayListType
arrayListType Data variables are
Functions in class arrayListType are
8.replace() function is used to replace an element with an element in tthe array.9.
9.retive() function is used to retive the array.
10.move() function is used to move the element from the given location.
11.clearlist() function to clear the array.
12.seqsearch() to search an element in the array sequentiallly.
13.insert() function to insert an element in the array after seaarch.
14.remove() function to remove an elementt from the array .
15.arraylisttype() a consttructor function used to for array type.
16.operator() function used for the operators used by the array.
the primary purpose for developing transportation models is used to .pdf
the primary purpose for developing transportation models is used to refer to a series of
mathematical equations that are used to represent how choices are made when people travel.
Travel demand occurs as a result of thousands of individual travelers making individual
decisions on how, where and when to travel. These decisions are affected by many factors such
as family situations, characteristics of the person making the trip, and the choices (destination,
route and mode) available for the trip.
Mathematical relationships are used to represent (model) human behavior in making these
choices. Models require a series of assumptions in order to work and are limited by the data
available to make forecasts. The coefficients and parameters in the model are set (calibrated) to
match existing data. Normally, these relationships are assumed to be valid and to remain constant
in the future.
Solution
the primary purpose for developing transportation models is used to refer to a series of
mathematical equations that are used to represent how choices are made when people travel.
Travel demand occurs as a result of thousands of individual travelers making individual
decisions on how, where and when to travel. These decisions are affected by many factors such
as family situations, characteristics of the person making the trip, and the choices (destination,
route and mode) available for the trip.
Mathematical relationships are used to represent (model) human behavior in making these
choices. Models require a series of assumptions in order to work and are limited by the data
available to make forecasts. The coefficients and parameters in the model are set (calibrated) to
match existing data. Normally, these relationships are assumed to be valid and to remain constant
in the future..
The origin of colour in complex ions containing transition metals.pdf
The origin of colour in complex ions containing transition metals
Complex ions containing transition metals are usually coloured, whereas the similar ions from
non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in
generating the colour in some way. Remember that transition metals are defined as having partly
filled d orbitals.
Solution
The origin of colour in complex ions containing transition metals
Complex ions containing transition metals are usually coloured, whereas the similar ions from
non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in
generating the colour in some way. Remember that transition metals are defined as having partly
filled d orbitals..
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
a. 0.010 M NaCl
pH will be approximately 7 because the solution will be neutral
b. 0.010 M NaOH
0.01 M NaOH
pOH= -log(0.01) =2
pH +pOH =14
pH = 12
c. 0.010 M NH3
NH3 + H2O NH4(+) + OH-
Kb = 1.8*10^-5 = [X]2/(1 - X)
the x in denominator can be ignored as the value is much smaller than 1
1.8*10^-5 = [X]2
[OH]=[X]=4.243*10^-3
pOH = -log[OH]=2.37
pH +pOH =14
pH = 11.63
d. 0.010 M malonic acid
pka1=2.85,pka2=5.70
concentration doesnot matter for diprotic acids
pH= (pka1 + pka2) /2
pH=(2.85+5.70)/2=4.275
Solution
a. 0.010 M NaCl
pH will be approximately 7 because the solution will be neutral
b. 0.010 M NaOH
0.01 M NaOH
pOH= -log(0.01) =2
pH +pOH =14
pH = 12
c. 0.010 M NH3
NH3 + H2O NH4(+) + OH-
Kb = 1.8*10^-5 = [X]2/(1 - X)
the x in denominator can be ignored as the value is much smaller than 1
1.8*10^-5 = [X]2
[OH]=[X]=4.243*10^-3
pOH = -log[OH]=2.37
pH +pOH =14
pH = 11.63
d. 0.010 M malonic acid
pka1=2.85,pka2=5.70
concentration doesnot matter for diprotic acids
pH= (pka1 + pka2) /2
pH=(2.85+5.70)/2=4.275.
Transition metal elements have atoms or ions with partially filled .pdf
Transition metal elements have atoms or ions with partially filled \'d\' subshells.
Solution
Transition metal elements have atoms or ions with partially filled \'d\' subshells..
ZnS mass ratio = 1.310.642 =2.04 .pdf
Zn/S mass ratio = 1.31/0.642 =2.04
Solution
Zn/S mass ratio = 1.31/0.642 =2.04.
We know that The energy of He+ can be calculated.pdf
We know that: The energy of He+ can be calculated as the hydrogen like atom E = -
2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = -
2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ
Solution
We know that: The energy of He+ can be calculated as the hydrogen like atom E = -
2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = -
2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ.
Recommended
The three domains of human development are physical, cognitive and p.pdf
The three domains of human development are physical, cognitive and psychosocial.
Physical development:
Individual growth varies according to genetics, gender, culture and socioeconomic status.
Physical development starts at infancy and can last till late adolescence. It is generally divided
into eight stages being infancy; early, mid and late childhood; adolescence; early adulthood;
middle age and old age.Specific physical changes occur at each stage of physical development.
Physical development concentrates on gross and fine motor skills as well as puberty which
includes developing a control over the body, particularly muscles and physical coordination.
Gross motor skills involves moving the large muscles in the body like the arms and legs,
consciously and deliberately. It also involves balancing and stability with movements like
jumping, skipping, throwing, catching, hopping, kicking, running and galloping.
Fine motor skills involves controlling small muscles in the hands and wrists. This is achieved by
using small objects like handling scissors and writing instruments.Fine motor skills generally
follow gross motor development.
Physical growth at the infancy stage is rapid. Ther weight of the infant generally doubles over a
period of 6 months. The infant grows by 10-12 inches in length( or height) and the the
propartions change over a period of two years. The size of the head also decreases.The
subcortical areas of brain start developing first followed by cortical areas. At birth, the barin
weighs 25% of and adult brain which increases to 80% by puberty.
Physical development at childhood is rapid. By the end of second year, most children can
standup,walk/run, climb stairs, jump, and skip. From ages 4-5 they develop more speed and
agility and posture control. Fine motor skills start developing at this stage.
Physical development at adolescence starts with the beginning of puberty and ends with
adulthood. The physical age ranges from 12-18 years. At puberty distinctive physiological
changes occur, which involve increase in height, weight, sex characteristics, body composition
and internal systems. These changes are influenced by changes in hormone activity (growth
hormones, thyroid hormones and androgens).
Males develop a deeper voice during puberty and females develop breasts and increased hip size
start menstruation.
Physical development at early adulthood is observed at ages 20-40 years. At this period the
physical abilities are at their peak like muscle strength, sensory abilities, cardiac functioning etc.
One also starts aging at this period. Age related changes now varies to a great extent depending
on the biological factors like molecular and cellular changes and also choice of lifestyle. Aging
process starts during early adulthood and is characterized by changes in skin, vision and
reproductive capability. Women reach a menopause
Physical development at middle age is characterized by failing organs and body functions,
wrinled skin, lo.
This is a templet called arrayListType.hThe templet class name as .pdf
This is a templet called arrayListType.h
The templet class name as arrayListType.Array of different list type is described in this template.
arrayListType Data variables are
Functions in class arrayListType are
class name as arrayListType
arrayListType Data variables are
Functions in class arrayListType are
8.replace() function is used to replace an element with an element in tthe array.9.
9.retive() function is used to retive the array.
10.move() function is used to move the element from the given location.
11.clearlist() function to clear the array.
12.seqsearch() to search an element in the array sequentiallly.
13.insert() function to insert an element in the array after seaarch.
14.remove() function to remove an elementt from the array .
15.arraylisttype() a consttructor function used to for array type.
16.operator() function used for the operators used by the array
Solution
This is a templet called arrayListType.h
The templet class name as arrayListType.Array of different list type is described in this template.
arrayListType Data variables are
Functions in class arrayListType are
class name as arrayListType
arrayListType Data variables are
Functions in class arrayListType are
8.replace() function is used to replace an element with an element in tthe array.9.
9.retive() function is used to retive the array.
10.move() function is used to move the element from the given location.
11.clearlist() function to clear the array.
12.seqsearch() to search an element in the array sequentiallly.
13.insert() function to insert an element in the array after seaarch.
14.remove() function to remove an elementt from the array .
15.arraylisttype() a consttructor function used to for array type.
16.operator() function used for the operators used by the array.
the primary purpose for developing transportation models is used to .pdf
the primary purpose for developing transportation models is used to refer to a series of
mathematical equations that are used to represent how choices are made when people travel.
Travel demand occurs as a result of thousands of individual travelers making individual
decisions on how, where and when to travel. These decisions are affected by many factors such
as family situations, characteristics of the person making the trip, and the choices (destination,
route and mode) available for the trip.
Mathematical relationships are used to represent (model) human behavior in making these
choices. Models require a series of assumptions in order to work and are limited by the data
available to make forecasts. The coefficients and parameters in the model are set (calibrated) to
match existing data. Normally, these relationships are assumed to be valid and to remain constant
in the future.
Solution
the primary purpose for developing transportation models is used to refer to a series of
mathematical equations that are used to represent how choices are made when people travel.
Travel demand occurs as a result of thousands of individual travelers making individual
decisions on how, where and when to travel. These decisions are affected by many factors such
as family situations, characteristics of the person making the trip, and the choices (destination,
route and mode) available for the trip.
Mathematical relationships are used to represent (model) human behavior in making these
choices. Models require a series of assumptions in order to work and are limited by the data
available to make forecasts. The coefficients and parameters in the model are set (calibrated) to
match existing data. Normally, these relationships are assumed to be valid and to remain constant
in the future..
The origin of colour in complex ions containing transition metals.pdf
The origin of colour in complex ions containing transition metals
Complex ions containing transition metals are usually coloured, whereas the similar ions from
non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in
generating the colour in some way. Remember that transition metals are defined as having partly
filled d orbitals.
Solution
The origin of colour in complex ions containing transition metals
Complex ions containing transition metals are usually coloured, whereas the similar ions from
non-transition metals aren\'t. That suggests that the partly filled d orbitals must be involved in
generating the colour in some way. Remember that transition metals are defined as having partly
filled d orbitals..
a. 0.010 M NaCl pH will be approximately 7 because the solution.pdf
a. 0.010 M NaCl
pH will be approximately 7 because the solution will be neutral
b. 0.010 M NaOH
0.01 M NaOH
pOH= -log(0.01) =2
pH +pOH =14
pH = 12
c. 0.010 M NH3
NH3 + H2O NH4(+) + OH-
Kb = 1.8*10^-5 = [X]2/(1 - X)
the x in denominator can be ignored as the value is much smaller than 1
1.8*10^-5 = [X]2
[OH]=[X]=4.243*10^-3
pOH = -log[OH]=2.37
pH +pOH =14
pH = 11.63
d. 0.010 M malonic acid
pka1=2.85,pka2=5.70
concentration doesnot matter for diprotic acids
pH= (pka1 + pka2) /2
pH=(2.85+5.70)/2=4.275
Solution
a. 0.010 M NaCl
pH will be approximately 7 because the solution will be neutral
b. 0.010 M NaOH
0.01 M NaOH
pOH= -log(0.01) =2
pH +pOH =14
pH = 12
c. 0.010 M NH3
NH3 + H2O NH4(+) + OH-
Kb = 1.8*10^-5 = [X]2/(1 - X)
the x in denominator can be ignored as the value is much smaller than 1
1.8*10^-5 = [X]2
[OH]=[X]=4.243*10^-3
pOH = -log[OH]=2.37
pH +pOH =14
pH = 11.63
d. 0.010 M malonic acid
pka1=2.85,pka2=5.70
concentration doesnot matter for diprotic acids
pH= (pka1 + pka2) /2
pH=(2.85+5.70)/2=4.275.
Transition metal elements have atoms or ions with partially filled .pdf
Transition metal elements have atoms or ions with partially filled \'d\' subshells.
Solution
Transition metal elements have atoms or ions with partially filled \'d\' subshells..
ZnS mass ratio = 1.310.642 =2.04 .pdf
Zn/S mass ratio = 1.31/0.642 =2.04
Solution
Zn/S mass ratio = 1.31/0.642 =2.04.
We know that The energy of He+ can be calculated.pdf
We know that: The energy of He+ can be calculated as the hydrogen like atom E = -
2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = -
2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ
Solution
We know that: The energy of He+ can be calculated as the hydrogen like atom E = -
2p2me4 / n2h2 * Z2 = - 13.6 eV / n2 *Z2 Z = 2 for He atom ; n= 5 given = -13.6 eV / 25 * 4 = -
2.176 eV x1.602 x 10-19 J / eV = 3.48 x 10-19 J = 3.48 x 10-16 kJ.
the temperature will be higher as the pressure is.pdf
the temperature will be higher as the pressure is increased. P is directly
proportional to T
Solution
the temperature will be higher as the pressure is increased. P is directly
proportional to T.
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides
Solution
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides.
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 =
9.05
Solution
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 =
9.05.
please post the clear qsn.... i ll help u in answ.pdf
please post the clear qsn.... i ll help u in answering... thank you....
Solution
please post the clear qsn.... i ll help u in answering... thank you.....
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in
water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3
KClO3+KIO3 -->NO REACTION
Solution
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in
water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3
KClO3+KIO3 -->NO REACTION.
The conclusion can be summarised as followsSolutionThe conclu.pdf
The conclusion can be summarised as follows:
Solution
The conclusion can be summarised as follows:.
The AutoCAD Electrical installation directory structure containsS.pdf
The AutoCAD Electrical installation directory structure contains:
Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\...
Note:
The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel
layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved to a shared
network drive. After you move the \\Libs\\ folder you must modify the path in Support File
Search Path in the Options dialog box.
The following electrical schematic libraries can be installed:
The following libraries are automatically installed:
Main executable and static support files at C:\\Program Files\\Autodesk\\AutoCAD {version}\\
The \\ACADE\\ subfolder carries several bitmap files and other static support files.
Support files at C:\\Users\\{username}\\AppData...
The Support files folder structure carries the support files that have the potential of being altered
by the user. The installation program creates a new Autodesk\\AutoCAD Electrical release
subfolder entry under the user loginname\\AppData folder. This Application data folder is
normally marked as hidden within Windows Explorer and users may need to access and
customize these files.
The base \\Support\\ folder carries the AutoCAD Electrical .mnl files, icon menu .dat files, and
the slide library .slb files referenced by the icon menus.
The \\AeToolPalette\\Palettes\\ subfolder structure carries four AutoCAD Electrical specific .atc
files.
The \\User\\ folder is where AutoCAD Electrical writes customized user settings files, stores
temporary files, and maintains the user scratch database files for the projects. This needs to be on
a per-logged-in user basis, not shared with other users
Data files at C:\\Users\\{username}\\Documents\\Acade {version}\\AeData
The AEDATA folder structure carries various database and project drawing files that will be
altered by the user. The installation program creates a new ACADE 2015\\subfolder entry under
the user login name\\Documents\\ folder.
The \\AeData\\ folder carries the wd.env environment settings file plus four subfolders. The four
individual subfolders to \\AeData\\ are as follows:
\\{language code}\\ subfolder contains two subfolders \\Catalogs\\ and \\Plc\\.
\\Catalogs\\ subfolder contains these files:
D. Both Engineer are correctJIC1/JIC125USA Standard (Inch units)IEC2/IEC 60617European
Standard (MM units)JIS2Japanese Standard (MM units)GB2Chinese Standard (MM
units)AS2Australian Standard (MM units)IEEE 315/315AInstitute of Electrical and Electronics
Engineers Standard (MM units)NFPANational Fire Protection Association Standard (Inch units)
Solution
The AutoCAD Electrical installation directory structure contains:
Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\...
Note:
The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel
layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved t.
Service that are performed by distributed objects.Objects is the s.pdf
Service that are performed by distributed objects.
Objects is the specified task that are performed by the software.
Business problems sloved by use of classes:
1.cheap, transparent communication
2.Object identity and lifetime maintained by infrastructure
Business problems solved by use of communication:
1.use of heterogeneous platform
2.explicit communication
Solution
Service that are performed by distributed objects.
Objects is the specified task that are performed by the software.
Business problems sloved by use of classes:
1.cheap, transparent communication
2.Object identity and lifetime maintained by infrastructure
Business problems solved by use of communication:
1.use of heterogeneous platform
2.explicit communication.
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
Profits increase by 41% (I just took the Quiz)
Solution
Profits increase by 41% (I just took the Quiz).
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
Operations
Sales
Administrative
Depreciation on factory equipment.
Advertising manager\'s salary.
Depreciation on office equipment
Depreciation on factory building
Salespersons\' travel expenses
Cost of hiring new employees
Assembly foreman\'s salary.
Salespersons\' salaries
Leasing of computer equipment for the Accounting Department
Supplies for the Machining Department
Advertising supplies used.
Electricity for the Assembly Department
Supplies for the sales office
Lost materials (scrap) in a Machining Department.
Sales commissions.
Direct labor in the Assembly Department
Packing supplies.
Supplies for Production Scheduling
Cost of repairing parts improperly manufactured in the Machining Department.
Payroll fringe benefits for workers in the Shipping Departmen
Paint for the Assembly Department.
Heat, light, and power for the factory
b)
Operations
Sales
Administrative
Depreciation on factory equipment.-Unit Level Activity
Advertising manager\'s salary.Product Level
Depreciation on office equipment Facility Level
Depreciation on factory building Unit Level Activity
Salespersons\' travel expenses Product Level
Cost of hiring new employees Facility Level
Assembly foreman\'s salary. Level Activity Batch Level Activity
Salespersons\' salaries Product Level
Leasing of computer equipment for the Accounting Department Facility Level
Supplies for the Machining Department Unit Level Activity
Advertising supplies used. Product Level
Electricity for the Assembly Department Unit Level Activity
Supplies for the sales office Product Level
Lost materials (scrap) in a Machining Department. Batch Level Activity
Sales commissions. Product Level
Direct labor in the Assembly Department Unit Level Activity
Packing supplies. Batch Level Activity Batch Level Activity
Supplies for Production Scheduling Unit Level Activity
Cost of repairing parts improperly manufactured in the Machining Department. Batch Level
Activity
Payroll fringe benefits for workers in the Shipping Departmen Batch Level Activity
Paint for the Assembly Department.Batch Level Activity
Heat, light, and power for the factory Unit Level Activity
c) Unit Level Activities: Labours Hours,No. of units produced or machine hours
Batch level: no of purchase orders,amount of material, no.of setups, no. of customer order, no of
customers
Product Level:No. of orders, no. of supervision hours,no. of test, no. of test time
Facility Level:no. of employees,sqaure foot,labours hours.
d)
Operations
Sales
Administrative
Depreciation on factory equipment.-Unit Level Activity- Machine hours
Advertising manager\'s salary.Product Level no. of orders
Depreciation on office equipment Facility Level square foot
Depreciation on factory building Unit Level Activity Machine hours
Salespersons\' travel expenses Product Level
Cost of hiring new employees Facility Level no. of employees
Assembly foreman\'s salary. Level Activity Batch Level Activity
Salespersons\' salaries Product Level no. of orders
Leasing of computer equipment .
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
moles of base, using molar mass of NaOH:
15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH
moles of acid:
0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid
the reaction is 1:1
1 NaOH + 1 HNO3 --> NaNO3 + H2O
so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC:
0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of
the base , which is: 0.3375 moles base
------------
concentrations of all the ions present
0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar
Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH /
0.150litres = 2.50 molar
NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar
Solution
moles of base, using molar mass of NaOH:
15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH
moles of acid:
0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid
the reaction is 1:1
1 NaOH + 1 HNO3 --> NaNO3 + H2O
so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC:
0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of
the base , which is: 0.3375 moles base
------------
concentrations of all the ions present
0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar
Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH /
0.150litres = 2.50 molar
NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar.
Microscopic examination usually support s the presence of White bloo.pdf
Microscopic examination usually support s the presence of White blood cells in the urine
elements.
In case of Urinary tract infection.
4). White blood cells.
Solution
Microscopic examination usually support s the presence of White blood cells in the urine
elements.
In case of Urinary tract infection.
4). White blood cells..
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10
Solution
molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10.
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
Lung volumes and lung capacity
Lung volumes and lung capacities refer to the volume of air associated with different phases of
the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung
volumes.
The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20
breaths per minute in adults. The total amount of air that the lungs can accommodate is divided
into four separate volumes and four capacities. Combinations of these volumes are used to
designate lung capacities. Lung volume and capacity vary with age, race, height, and gender
The following terms describe the various lung (respiratory) volumes:
Summing specific lung volumes produces the following lung capacities:
In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic
bronchitis
In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and
pulmonary edema.
Differences between lung volume and capacity
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume and expiratory volume
It varies from 5-6 liters
It varies from 3.5-4.5 liters
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume and expiratory volume
It varies from 5-6 liters
It varies from 3.5-4.5 liters
Solution
Lung volumes and lung capacity
Lung volumes and lung capacities refer to the volume of air associated with different phases of
the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung
volumes.
The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20
breaths per minute in adults. The total amount of air that the lungs can accommodate is divided
into four separate volumes and four capacities. Combinations of these volumes are used to
designate lung capacities. Lung volume and capacity vary with age, race, height, and gender
The following terms describe the various lung (respiratory) volumes:
Summing specific lung volumes produces the following lung capacities:
In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic
bronchitis
In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and
pulmonary edema.
Differences between lung volume and capacity
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume an.
A) The source provides energy, its normally a l.pdf
A) The source provides energy, it\'s normally a laser. B) The prism directs the
source or the directions of the laser C) The exit slit is where the laser exits after it goes through
the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s
normally a glass cuvette. E) The detector detects the photons that where excited by the laser.
Solution
A) The source provides energy, it\'s normally a laser. B) The prism directs the
source or the directions of the laser C) The exit slit is where the laser exits after it goes through
the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s
normally a glass cuvette. E) The detector detects the photons that where excited by the laser..
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
Answer:
The blue colored tracts
Ascending tracts are sensory and deliver information to the brain.
Solution
Answer:
The blue colored tracts
Ascending tracts are sensory and deliver information to the brain..
Hence I am inclinedto think its A.SolutionHenc.pdf
Hence I am inclinedto think its A.
Solution
Hence I am inclinedto think its A..
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
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Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
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the temperature will be higher as the pressure is.pdf
the temperature will be higher as the pressure is increased. P is directly
proportional to T
Solution
the temperature will be higher as the pressure is increased. P is directly
proportional to T.
The CPSase of multienzyme pyrl-3 is inhibited by .pdf
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides
Solution
The CPSase of multienzyme pyrl-3 is inhibited by a variety of uridine nucleotides.
pH = pKa + log[base][salt] = -log (5.6 10^-10.pdf
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 =
9.05
Solution
pH = pKa + log[base]/[salt] = -log (5.6 * 10^-10) + log 0.17/0.27 = 9.2518 - 0.2 =
9.05.
please post the clear qsn.... i ll help u in answ.pdf
please post the clear qsn.... i ll help u in answering... thank you....
Solution
please post the clear qsn.... i ll help u in answering... thank you.....
Na2S + NaNO3 - No reaction Na2S + KClO3 - No re.pdf
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in
water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3
KClO3+KIO3 -->NO REACTION
Solution
Na2S + NaNO3 -> No reaction Na2S + KClO3 -> No reaction (K2S is soluble in
water) Na2S + Pb(NO3)2 = 2NaNO3 + PbS Na2SO4 + Pb(NO3)2 = PbSO4 + 2NaNO3
KClO3+KIO3 -->NO REACTION.
The conclusion can be summarised as followsSolutionThe conclu.pdf
The conclusion can be summarised as follows:
Solution
The conclusion can be summarised as follows:.
The AutoCAD Electrical installation directory structure containsS.pdf
The AutoCAD Electrical installation directory structure contains:
Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\...
Note:
The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel
layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved to a shared
network drive. After you move the \\Libs\\ folder you must modify the path in Support File
Search Path in the Options dialog box.
The following electrical schematic libraries can be installed:
The following libraries are automatically installed:
Main executable and static support files at C:\\Program Files\\Autodesk\\AutoCAD {version}\\
The \\ACADE\\ subfolder carries several bitmap files and other static support files.
Support files at C:\\Users\\{username}\\AppData...
The Support files folder structure carries the support files that have the potential of being altered
by the user. The installation program creates a new Autodesk\\AutoCAD Electrical release
subfolder entry under the user loginname\\AppData folder. This Application data folder is
normally marked as hidden within Windows Explorer and users may need to access and
customize these files.
The base \\Support\\ folder carries the AutoCAD Electrical .mnl files, icon menu .dat files, and
the slide library .slb files referenced by the icon menus.
The \\AeToolPalette\\Palettes\\ subfolder structure carries four AutoCAD Electrical specific .atc
files.
The \\User\\ folder is where AutoCAD Electrical writes customized user settings files, stores
temporary files, and maintains the user scratch database files for the projects. This needs to be on
a per-logged-in user basis, not shared with other users
Data files at C:\\Users\\{username}\\Documents\\Acade {version}\\AeData
The AEDATA folder structure carries various database and project drawing files that will be
altered by the user. The installation program creates a new ACADE 2015\\subfolder entry under
the user login name\\Documents\\ folder.
The \\AeData\\ folder carries the wd.env environment settings file plus four subfolders. The four
individual subfolders to \\AeData\\ are as follows:
\\{language code}\\ subfolder contains two subfolders \\Catalogs\\ and \\Plc\\.
\\Catalogs\\ subfolder contains these files:
D. Both Engineer are correctJIC1/JIC125USA Standard (Inch units)IEC2/IEC 60617European
Standard (MM units)JIS2Japanese Standard (MM units)GB2Chinese Standard (MM
units)AS2Australian Standard (MM units)IEEE 315/315AInstitute of Electrical and Electronics
Engineers Standard (MM units)NFPANational Fire Protection Association Standard (Inch units)
Solution
The AutoCAD Electrical installation directory structure contains:
Symbol Libraries at C:\\Users\\Public\\Documents\\Autodesk\\Acade {version}\\Libs\\...
Note:
The symbol library subfolder, \\Libs\\, carries various AutoCAD Electrical schematic and panel
layout symbol libraries. The \\Libs\\ folder structure can be easily copied and moved t.
Service that are performed by distributed objects.Objects is the s.pdf
Service that are performed by distributed objects.
Objects is the specified task that are performed by the software.
Business problems sloved by use of classes:
1.cheap, transparent communication
2.Object identity and lifetime maintained by infrastructure
Business problems solved by use of communication:
1.use of heterogeneous platform
2.explicit communication
Solution
Service that are performed by distributed objects.
Objects is the specified task that are performed by the software.
Business problems sloved by use of classes:
1.cheap, transparent communication
2.Object identity and lifetime maintained by infrastructure
Business problems solved by use of communication:
1.use of heterogeneous platform
2.explicit communication.
Profits increase by 41 (I just took the Quiz)SolutionProfits .pdf
Profits increase by 41% (I just took the Quiz)
Solution
Profits increase by 41% (I just took the Quiz).
OperationsSalesAdministrativeDepreciation on factory equipment.pdf
Operations
Sales
Administrative
Depreciation on factory equipment.
Advertising manager\'s salary.
Depreciation on office equipment
Depreciation on factory building
Salespersons\' travel expenses
Cost of hiring new employees
Assembly foreman\'s salary.
Salespersons\' salaries
Leasing of computer equipment for the Accounting Department
Supplies for the Machining Department
Advertising supplies used.
Electricity for the Assembly Department
Supplies for the sales office
Lost materials (scrap) in a Machining Department.
Sales commissions.
Direct labor in the Assembly Department
Packing supplies.
Supplies for Production Scheduling
Cost of repairing parts improperly manufactured in the Machining Department.
Payroll fringe benefits for workers in the Shipping Departmen
Paint for the Assembly Department.
Heat, light, and power for the factory
b)
Operations
Sales
Administrative
Depreciation on factory equipment.-Unit Level Activity
Advertising manager\'s salary.Product Level
Depreciation on office equipment Facility Level
Depreciation on factory building Unit Level Activity
Salespersons\' travel expenses Product Level
Cost of hiring new employees Facility Level
Assembly foreman\'s salary. Level Activity Batch Level Activity
Salespersons\' salaries Product Level
Leasing of computer equipment for the Accounting Department Facility Level
Supplies for the Machining Department Unit Level Activity
Advertising supplies used. Product Level
Electricity for the Assembly Department Unit Level Activity
Supplies for the sales office Product Level
Lost materials (scrap) in a Machining Department. Batch Level Activity
Sales commissions. Product Level
Direct labor in the Assembly Department Unit Level Activity
Packing supplies. Batch Level Activity Batch Level Activity
Supplies for Production Scheduling Unit Level Activity
Cost of repairing parts improperly manufactured in the Machining Department. Batch Level
Activity
Payroll fringe benefits for workers in the Shipping Departmen Batch Level Activity
Paint for the Assembly Department.Batch Level Activity
Heat, light, and power for the factory Unit Level Activity
c) Unit Level Activities: Labours Hours,No. of units produced or machine hours
Batch level: no of purchase orders,amount of material, no.of setups, no. of customer order, no of
customers
Product Level:No. of orders, no. of supervision hours,no. of test, no. of test time
Facility Level:no. of employees,sqaure foot,labours hours.
d)
Operations
Sales
Administrative
Depreciation on factory equipment.-Unit Level Activity- Machine hours
Advertising manager\'s salary.Product Level no. of orders
Depreciation on office equipment Facility Level square foot
Depreciation on factory building Unit Level Activity Machine hours
Salespersons\' travel expenses Product Level
Cost of hiring new employees Facility Level no. of employees
Assembly foreman\'s salary. Level Activity Batch Level Activity
Salespersons\' salaries Product Level no. of orders
Leasing of computer equipment .
moles of base, using molar mass of NaOH 15.0g NaOH @ 40.0gmol = .pdf
moles of base, using molar mass of NaOH:
15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH
moles of acid:
0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid
the reaction is 1:1
1 NaOH + 1 HNO3 --> NaNO3 + H2O
so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC:
0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of
the base , which is: 0.3375 moles base
------------
concentrations of all the ions present
0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar
Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH /
0.150litres = 2.50 molar
NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar
Solution
moles of base, using molar mass of NaOH:
15.0g NaOH @ 40.0g/mol = 0.375 moles of NaOH
moles of acid:
0.1500 litres @ 0.250moles/litre= 0.0375 moles of acid
the reaction is 1:1
1 NaOH + 1 HNO3 --> NaNO3 + H2O
so it uses up all of 0.0375 moles of acid and only destroys 10% of the Base, so it is still BASIC:
0.375 moles of NaOH - 0.0375 moles destroyed by the moles of acid .... & leaves behind 90% of
the base , which is: 0.3375 moles base
------------
concentrations of all the ions present
0.3375 moles base left over, releases 0.3375 moles of OH- /0.150 litres... OH- = 2.25 molar
Na + was not destroyed, it was a spectator ion ... Na+ stays the same @ 0.375 moles of NaOH /
0.150litres = 2.50 molar
NO3- was not destroyed, it was a spectator ion ... NO3- stays the same @ 0.250 molar.
Microscopic examination usually support s the presence of White bloo.pdf
Microscopic examination usually support s the presence of White blood cells in the urine
elements.
In case of Urinary tract infection.
4). White blood cells.
Solution
Microscopic examination usually support s the presence of White blood cells in the urine
elements.
In case of Urinary tract infection.
4). White blood cells..
molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10
Solution
molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10.
Lung volumes and lung capacityLung volumes and lung capacities ref.pdf
Lung volumes and lung capacity
Lung volumes and lung capacities refer to the volume of air associated with different phases of
the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung
volumes.
The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20
breaths per minute in adults. The total amount of air that the lungs can accommodate is divided
into four separate volumes and four capacities. Combinations of these volumes are used to
designate lung capacities. Lung volume and capacity vary with age, race, height, and gender
The following terms describe the various lung (respiratory) volumes:
Summing specific lung volumes produces the following lung capacities:
In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic
bronchitis
In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and
pulmonary edema.
Differences between lung volume and capacity
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume and expiratory volume
It varies from 5-6 liters
It varies from 3.5-4.5 liters
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume and expiratory volume
It varies from 5-6 liters
It varies from 3.5-4.5 liters
Solution
Lung volumes and lung capacity
Lung volumes and lung capacities refer to the volume of air associated with different phases of
the respiratory cycle. Lung volumes are directly measured; lung capacities are inferred from lung
volumes.
The average human respiratory rate is 30-60 breaths per minute at birth, decreasing to 12-20
breaths per minute in adults. The total amount of air that the lungs can accommodate is divided
into four separate volumes and four capacities. Combinations of these volumes are used to
designate lung capacities. Lung volume and capacity vary with age, race, height, and gender
The following terms describe the various lung (respiratory) volumes:
Summing specific lung volumes produces the following lung capacities:
In obstructive lung disorders include asthma and other COPDs, such as emphysema and chronic
bronchitis
In restrictive lung disorders include pulmonary fibrosis, adult respiratory distress syndrome, and
pulmonary edema.
Differences between lung volume and capacity
Lung volume
Lung capacity
It is the total volume of air in the lungs
It is the maximum volume of air that can be inhaled and exhaled during forced breathing
It is the sum of the vital capacity and residual volume
It is the sum of tidal volume, inspiratory reserve volume an.
A) The source provides energy, its normally a l.pdf
A) The source provides energy, it\'s normally a laser. B) The prism directs the
source or the directions of the laser C) The exit slit is where the laser exits after it goes through
the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s
normally a glass cuvette. E) The detector detects the photons that where excited by the laser.
Solution
A) The source provides energy, it\'s normally a laser. B) The prism directs the
source or the directions of the laser C) The exit slit is where the laser exits after it goes through
the sample. Guided into the detector. D) The sample container holds the sample in place. It\'s
normally a glass cuvette. E) The detector detects the photons that where excited by the laser..
AnswerThe blue colored tractsAscending tracts are sensory and d.pdf
Answer:
The blue colored tracts
Ascending tracts are sensory and deliver information to the brain.
Solution
Answer:
The blue colored tracts
Ascending tracts are sensory and deliver information to the brain..
Hence I am inclinedto think its A.SolutionHenc.pdf
Hence I am inclinedto think its A.
Solution
Hence I am inclinedto think its A..
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molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf
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