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molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10
Solution
molar mass of InF3 =171.82g/mol
mass solubility =4.0e-2g/100mL=0.4g/L
molar solubility=0.4g/(171.82g/mol)=2.33e-3M
For the dissociation of InF3 in water, we have the chem formula
InF3 (s) ---- In3+ (aq)+ 3F- (aq)
Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s
Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10

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molar mass of InF3 =171.82gmolmass solubility =4.0e-2g100mL=0.4g.pdf

  • 1. molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10 Solution molar mass of InF3 =171.82g/mol mass solubility =4.0e-2g/100mL=0.4g/L molar solubility=0.4g/(171.82g/mol)=2.33e-3M For the dissociation of InF3 in water, we have the chem formula InF3 (s) ---- In3+ (aq)+ 3F- (aq) Assume molar solubility=s, so at equilibrium, [In3+]=s, [F-]=3s Ksp=(s)(3s)3=27s4=27*(2.33e-3M)4=7.93e-10