moles NH4NO3 = 2.57 g /80.04 g/mol=0.0321 moles H2O = 4 x 0.0321 /2= 0.0642 moles O2 = 0.0321/2 =0.0161 moles N2 = 0.0321 total moles = 0.112 so p = 0.112 x 0.08206 x 520 K/ 4.50=1.06 atm Solution moles NH4NO3 = 2.57 g /80.04 g/mol=0.0321 moles H2O = 4 x 0.0321 /2= 0.0642 moles O2 = 0.0321/2 =0.0161 moles N2 = 0.0321 total moles = 0.112 so p = 0.112 x 0.08206 x 520 K/ 4.50=1.06 atm.