a) Replace the 2 V source in the circuit in (Figure 1) , and calculate ? o for the source value ?6V.
Express your answer to three significant figures and include the appropriate units.
b) Replace the 2 V source in the circuit in the figure, and calculate ? o for the source value ?3.5V.
Express your answer to three significant figures and include the appropriate units.
a) Replace the 2 V source in the circuit in (Figure 1) , and calculate ?o for the source value ?6V. Express your answer to three significant figures and include the appropriate units. b) Replace the 2 V source in the circuit in the figure, and calculate ?o for the source value ?3.5V. Express your answer to three significant figures and include the appropriate units.
Solution
it is an inverting amplifier
so output=(-12/4)*source voltage
a)source voltage=-6 volt
output=-6*(-3)=18 volts
but as the constraint voltages are +15 volt and -15 volts, the op-amp will be saturated and output will be clipped at 15 volts
b)source voltage=-3.5 volts
output=-3.5*(-3)=10.5 volts
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a) Replace the 2 V source in the circuit in (Figure 1) - and calculate.docx
1. a) Replace the 2 V source in the circuit in (Figure 1) , and calculate ? o for the source value ?6V.
Express your answer to three significant figures and include the appropriate units.
b) Replace the 2 V source in the circuit in the figure, and calculate ? o for the source value
?3.5V.
Express your answer to three significant figures and include the appropriate units.
a) Replace the 2 V source in the circuit in (Figure 1) , and calculate ?o for the source value ?6V.
Express your answer to three significant figures and include the appropriate units. b) Replace the
2 V source in the circuit in the figure, and calculate ?o for the source value ?3.5V. Express your
answer to three significant figures and include the appropriate units.
Solution
it is an inverting amplifier
so output=(-12/4)*source voltage
a)source voltage=-6 volt
output=-6*(-3)=18 volts
but as the constraint voltages are +15 volt and -15 volts, the op-amp will be saturated and output
will be clipped at 15 volts
b)source voltage=-3.5 volts
output=-3.5*(-3)=10.5 volts
