Find the solution to the differential equation:
dz/dt = 4tez
that passes through the origin.
z= ?
Solution
dz/e^z = 4tdt or, -1/e^z = 2t^2 + c since y passes through the origin, so it satisfies
(0,0) or, c = -1 so,e^(-z) = 1- 2t^2 taking ln on both sides so, -z = ln(1- 2t^2) so, z = ln(1/(1-
2t^2)).
Z Score,T Score, Percential Rank and Box Plot Graph
Find the square roots of the complex number [-80-18i ] and solve the.pdf
1. Find the square roots of the complex number [-80-18i ] and solve the following quadratic
equation.
[4z^2+(16i-4)z+(65+10i) = 0]
Solution
Let
[sqrt(-80-18i)=a+ib]
squaring both side
[-80-18i=a^2-b^2+2abi]
coparing real and magnary parts both side
[a^2-b^2=-80]
[2ab=-18]
But
[(a^2+b^2)^2=(a^2-b^2)^2+4a^2b^2]
[(a^2+b^2)=(-80)^2+(-18)^2]
[=6400+324=6724]
[a^2+b^2=+-82]
Now solve
[a^2-b^2=-80]
[a^2+b^2=+-82]
[If]
[a^2-b^2=-80]
[a^2+b^2=82]
[Then]
[a=+-1 and b=+-9]
[if]
[a^2-b^2=-80]
[a^2+b^2=-82]
[a=+-9 and b=+-1]
[Thus]
[sqrt(-80-18i)=+-1+-9i]
[or]
[sqrt(-80-18i)=+-9+-i]
[4z^2+(16i-4)z+(65+10i)=0]