not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I\'m thinking I could figure itout not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I\'m thinking I could figure itout Solution since 5 has an order of 6, wouldn\'t 5^5 be the most you canreduce it in mod 7?, whereas 6^5 is congruent to 6(mod7) since itsorder is 2.

1. not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm
thinking I could figure itout
not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm
thinking I could figure itout
Solution
since 5 has an order of 6, wouldn't 5^5 be the most you canreduce it in mod 7?, whereas 6^5 is
congruent to 6(mod7) since itsorder is 2