Suppose 14 students have tickets for a concert. Three students (Bob, Jim, and Tom) own cars and will provide transportation to the concert. Bob\'s car has room for three passengers (nondrivers), while the cars owned by Jim and Tom each has room for four passengers. In how many different ways can the 11 passengers be loaded into the cars? At the concert hall the students are seated together in a row. If they take their seats in random order, find the probability that the three students who drove their cars have adjoining seats. Solution a) 11C3 * 8C4* 4C4 b) favourable case = 3! * 11! total case = 14! probability = 3!* 11! / 14!.