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Probability Theory
1. Random Experiment: If in each trail an experiment conducted
identical conditions, the outcome is not unique, but may be one
possible outcomes, then such an experiment is called a
under
of the
random
experiment.
Example: Throwing a die, a pack of cards.
2. Sample space: The set of all possible outcomes of an experiment. It is
denoted by “𝑺”.
3. Trial: Any particular performance of a random experiment is called a trial
and outcome or combination of outcomes are termed as events.
Example: Tossing of a coin: {H, T}
4. Exhaustive events or cases: The total number of possible outcomes of a
random experiments is known as the exhaustive events or cases.
5. Favourable Events or Cases: The number of cases favourable to an event in a
trail is the number of outcomes which entail the happening of the event.
Example: In drawing a card from a pack of cards the number of cases
favourable to drawing of an ace is 4,
for drawing a spade card is 13 and
for drawing a red card is 26.
6. Mutually Exclusive events: Events are said to be mutually exclusive or
incompatible if the happening of any one of them precludes the happening of all the
others, i.e., no two or more of them can happen simultaneously in the same trail.
7. Equally likely events: Outcomes of trail are said to be equally likely if taking into
consideration all the relevant evidences, there is no reason to expect one in
preference to the others.
8. Independent Events: Several events are said to be independent if the happening
(non-happening) of an event is not affected by the supplementary knowledge
concerning the occurrence of any number of remaining events.
Statistical Definition
If a random experiment or trail results in ‘𝒏’ exhaustive, mutually
exclusive and equally likely outcomes(or cases), out of which ‘𝒎’ are
favourable to the occurrence of an event 𝑬, then the probability ‘p’ of
occurrence of 𝐸, denoted by 𝑷(𝑬), is given by:
𝑝 = 𝑃 𝐸 =
𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑣𝑜𝑢𝑟𝑎𝑏𝑙𝑒 𝑐𝑎𝑠𝑒𝑠
𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑒𝑥ℎ𝑎𝑢𝑠𝑡𝑖𝑣𝑒 𝑐𝑎𝑠𝑒𝑠
=
𝑚
𝑛
(i) Since 𝑚 ≥ 0, 𝑛 ≥ 0 𝑎𝑛𝑑 𝑚 ≤ 𝑛
𝑃 𝐸 ≥ 0 𝑎𝑛𝑑 𝑃 𝐸 ≤ 1 ⟹ 0 ≤ 𝑃 𝐸 ≤ 1
(ii) 𝑃 𝐸 + 𝑃 𝐸
̅ = 1
Axiomatic Probability
𝑃 𝐴 is the probability function defined on a 𝝈 −field 𝐵 of events if the
following properties or axioms hold:
1. For each 𝐴 ∈ B, 𝑃(𝐴) is defined, is real and 𝑃(𝐴) ≥ 0. (Axiom of non-negativity)
2. P(S) = 1 (Axiom of certainty)
3. If {𝐴𝑛} is any finite or infinite sequence of disjoint events in 𝐵, then
𝑖=1 𝑖
=1
𝑃(∪𝑛 𝐴𝑖) = ∑𝑛 𝑃(𝐴𝑖) (Axiom of additivity)
4. The set function 𝑃 defined on 𝝈 −field 𝐵, taking its values in the real line and
satisfying the above three axioms is called the probability measure.
Algebra of Events
For eventsAand B,
̅ =
𝐴 − 𝐵 =
= {𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑜𝑟 𝜔 ∈ 𝐵}
= {𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑎𝑛𝑑 𝜔 ∈ 𝐵}
{𝜔 ∈ 𝑆: 𝜔 ∉ 𝐴}
{𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑏𝑢𝑡 𝜔 ∉ 𝐵}
(i) 𝐴 𝖴 𝐵
(ii) 𝐴 ∩ 𝐵
(iii) 𝐴
(iv)
(v)
(vi)
𝐴 ⊂ 𝐵 𝑓𝑜𝑟 𝑒𝑣𝑒𝑟𝑦 𝜔 ∈ 𝐴, 𝜔 ∈ 𝐵
𝐴 = 𝐵 if and only if A and B have same elements,𝑖. 𝑒. , 𝐴 ⊂ 𝐵 and B ⊂ 𝐴
(vii) 𝐴 and 𝐵 disjoint events (mutually exclusive) ⟹ 𝐴 ∩ 𝐵 = Φ (𝑛𝑢𝑙𝑙 𝑠𝑒𝑡)
(viii)𝐴 𝖴 𝐵 can be denoted by 𝐴 + 𝐵 if Aand B are disjoint events.
(ix) A ∆ B denotes those 𝜔 belonging to exactly one ofAand B, i.e.,
𝐴 ∆ 𝐵 = 𝐴̅ 𝐵 𝖴 𝐴 𝐵
̅ = 𝐴̅ 𝐵 + 𝐴 𝐵
̅ (disjoint events)
Theorems on Probability of Events
Addition Theorem of Probability for two events:
P A 𝖴 B = P A + P B − P A ∩ B
Addition Theorem of Probability for 𝑛-events:
𝑖
=1
P(∪𝑛 𝐴𝑖) = ∑𝑛 𝑃(𝐴𝑖) − ∑ ∑ 𝑃(𝐴𝑖 ∩ 𝐴𝑗) +…+ (−1)𝑛−1𝑃(𝐴1 ∩ 𝐴2 ∩ ⋯ 𝐴𝑛)
𝑖=1
Example
A class in Mathematics subject consists of 6 men and 4 women. An exam is given and the
students are ranked according to their performance. Assuming that no two students
obtain the same score, (a) how many different rankings are possible? (b) If all rankings are
considered equally likely, what is the probability that women receive the top 4 scores?
Solution:
Example:
A box containing 6-white and 5 black balls. If 3 balls are drawn randomly from
the box, what is the probability that one of the drawn balls is white and the other
two are black balls?
Example
A system composed of n separate components is said to be a parallel system if
it functions when at least one of the components functions. For such a system,
if component i, independent of other components, functions with probability 𝐩𝒊
, 𝑖 = 1, . . . , 𝑛, what is the probability the system functions?
Conditional Probability
𝑃(𝐴|𝐵) = 𝑃(𝐴∩𝐵)
𝑃(𝐵)
; 𝑃 𝐵 > 0
𝑃(𝐵|𝐴) = 𝑃(𝐴∩𝐵)
𝑃(𝐴)
; 𝑃(𝐴) > 0
If Aand B are independent, 𝑃 𝐴 𝐵 = 𝑃(𝐴)
𝑃(𝐵|𝐴) = 𝑃(𝐵)
Multiplication theorem of Probability :
𝑃(𝐴 ∩ 𝐵) = 𝑃(𝐵) ∙ 𝑃(𝐴|𝐵)
𝑃(𝐵 ∩ 𝐴) = 𝑃(𝐴) ∙ 𝑃(𝐵|𝐴)
For n events, 𝑃 𝐴1 ∩ 𝐴2 ∩ ⋯ … . 𝐴𝑛 = 𝑃(𝐴1) 𝑃 𝐴2 𝐴1 ×
P 𝐴3 𝐴1∩ 𝐴2 … … × 𝑃 𝐴𝑛 | 𝐴1 ∩ 𝐴2 ∩ ⋯ … . 𝐴𝑛−1
Example
An urn contains 5 defective (that immediately fail when put in use), 10 partially
defective (that fail after a couple of hours of use) and 25 acceptable transistors.
A transistor is chosen at random from the urn and put into use. If it does not
immediately fail, what is the probability it is acceptable?
Bayes Theorem of Probability:
Theorem: If 𝑬𝟏, 𝑬𝟐, … . . , 𝑬𝒏 are mutually disjoint events with 𝑷 𝑬𝒊 ≠ 𝟎,
𝑖 = 1, 2, … . 𝑛 , then for any arbitrary event 𝑨 which is a subset of
𝒊=𝟏
∪𝒏
𝑬𝒊 such that 𝑷 𝑨 > 𝟎, we have
𝑖
𝑃(𝐸 |𝐴) =
𝑃(𝐸𝑖) 𝑃(𝐴|𝐸𝑖)
𝑖
=1
∑𝑛
𝑃(𝐸𝑖) 𝑃(𝐴|𝐸𝑖)
; 𝑖 = 1,2, … … . , 𝑛
Example
In answering a question on a multiple-choice test, a student either knows the
answer or she guesses. Let p be the probability that she knows the answer and
1−p the probability that she guesses. Assume that a student who guesses at the
answer will be correct with probability 1/m, where m is the number of multiple-
choice alternatives. What is the conditional probability that a student knew the
answer to a question given that she answered it correctly?
Example
A laboratory blood test is 99 percent effective in detecting a certain disease
when it is, in fact, present. However, the test also yields a “false positive”
result for 1 percent of the healthy persons tested. (That is, if a healthy person is
tested, then, with probability .01, the test result will imply he or she has the
disease.) If .5 percent of the population actually has the disease, what is the
probability a person has the disease given that his test result is positive?

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01_Module_1-ProbabilityTheory.pptx

  • 2. 1. Random Experiment: If in each trail an experiment conducted identical conditions, the outcome is not unique, but may be one possible outcomes, then such an experiment is called a under of the random experiment. Example: Throwing a die, a pack of cards. 2. Sample space: The set of all possible outcomes of an experiment. It is denoted by “𝑺”. 3. Trial: Any particular performance of a random experiment is called a trial and outcome or combination of outcomes are termed as events. Example: Tossing of a coin: {H, T} 4. Exhaustive events or cases: The total number of possible outcomes of a random experiments is known as the exhaustive events or cases.
  • 3. 5. Favourable Events or Cases: The number of cases favourable to an event in a trail is the number of outcomes which entail the happening of the event. Example: In drawing a card from a pack of cards the number of cases favourable to drawing of an ace is 4, for drawing a spade card is 13 and for drawing a red card is 26. 6. Mutually Exclusive events: Events are said to be mutually exclusive or incompatible if the happening of any one of them precludes the happening of all the others, i.e., no two or more of them can happen simultaneously in the same trail. 7. Equally likely events: Outcomes of trail are said to be equally likely if taking into consideration all the relevant evidences, there is no reason to expect one in preference to the others. 8. Independent Events: Several events are said to be independent if the happening (non-happening) of an event is not affected by the supplementary knowledge concerning the occurrence of any number of remaining events.
  • 4. Statistical Definition If a random experiment or trail results in ‘𝒏’ exhaustive, mutually exclusive and equally likely outcomes(or cases), out of which ‘𝒎’ are favourable to the occurrence of an event 𝑬, then the probability ‘p’ of occurrence of 𝐸, denoted by 𝑷(𝑬), is given by: 𝑝 = 𝑃 𝐸 = 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑣𝑜𝑢𝑟𝑎𝑏𝑙𝑒 𝑐𝑎𝑠𝑒𝑠 𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑒𝑥ℎ𝑎𝑢𝑠𝑡𝑖𝑣𝑒 𝑐𝑎𝑠𝑒𝑠 = 𝑚 𝑛 (i) Since 𝑚 ≥ 0, 𝑛 ≥ 0 𝑎𝑛𝑑 𝑚 ≤ 𝑛 𝑃 𝐸 ≥ 0 𝑎𝑛𝑑 𝑃 𝐸 ≤ 1 ⟹ 0 ≤ 𝑃 𝐸 ≤ 1 (ii) 𝑃 𝐸 + 𝑃 𝐸 ̅ = 1
  • 5. Axiomatic Probability 𝑃 𝐴 is the probability function defined on a 𝝈 −field 𝐵 of events if the following properties or axioms hold: 1. For each 𝐴 ∈ B, 𝑃(𝐴) is defined, is real and 𝑃(𝐴) ≥ 0. (Axiom of non-negativity) 2. P(S) = 1 (Axiom of certainty) 3. If {𝐴𝑛} is any finite or infinite sequence of disjoint events in 𝐵, then 𝑖=1 𝑖 =1 𝑃(∪𝑛 𝐴𝑖) = ∑𝑛 𝑃(𝐴𝑖) (Axiom of additivity) 4. The set function 𝑃 defined on 𝝈 −field 𝐵, taking its values in the real line and satisfying the above three axioms is called the probability measure.
  • 6. Algebra of Events For eventsAand B, ̅ = 𝐴 − 𝐵 = = {𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑜𝑟 𝜔 ∈ 𝐵} = {𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑎𝑛𝑑 𝜔 ∈ 𝐵} {𝜔 ∈ 𝑆: 𝜔 ∉ 𝐴} {𝜔 ∈ 𝑆: 𝜔 ∈ 𝐴 𝑏𝑢𝑡 𝜔 ∉ 𝐵} (i) 𝐴 𝖴 𝐵 (ii) 𝐴 ∩ 𝐵 (iii) 𝐴 (iv) (v) (vi) 𝐴 ⊂ 𝐵 𝑓𝑜𝑟 𝑒𝑣𝑒𝑟𝑦 𝜔 ∈ 𝐴, 𝜔 ∈ 𝐵 𝐴 = 𝐵 if and only if A and B have same elements,𝑖. 𝑒. , 𝐴 ⊂ 𝐵 and B ⊂ 𝐴 (vii) 𝐴 and 𝐵 disjoint events (mutually exclusive) ⟹ 𝐴 ∩ 𝐵 = Φ (𝑛𝑢𝑙𝑙 𝑠𝑒𝑡) (viii)𝐴 𝖴 𝐵 can be denoted by 𝐴 + 𝐵 if Aand B are disjoint events. (ix) A ∆ B denotes those 𝜔 belonging to exactly one ofAand B, i.e., 𝐴 ∆ 𝐵 = 𝐴̅ 𝐵 𝖴 𝐴 𝐵 ̅ = 𝐴̅ 𝐵 + 𝐴 𝐵 ̅ (disjoint events)
  • 7. Theorems on Probability of Events Addition Theorem of Probability for two events: P A 𝖴 B = P A + P B − P A ∩ B Addition Theorem of Probability for 𝑛-events: 𝑖 =1 P(∪𝑛 𝐴𝑖) = ∑𝑛 𝑃(𝐴𝑖) − ∑ ∑ 𝑃(𝐴𝑖 ∩ 𝐴𝑗) +…+ (−1)𝑛−1𝑃(𝐴1 ∩ 𝐴2 ∩ ⋯ 𝐴𝑛) 𝑖=1
  • 8. Example A class in Mathematics subject consists of 6 men and 4 women. An exam is given and the students are ranked according to their performance. Assuming that no two students obtain the same score, (a) how many different rankings are possible? (b) If all rankings are considered equally likely, what is the probability that women receive the top 4 scores? Solution:
  • 9. Example: A box containing 6-white and 5 black balls. If 3 balls are drawn randomly from the box, what is the probability that one of the drawn balls is white and the other two are black balls?
  • 10. Example A system composed of n separate components is said to be a parallel system if it functions when at least one of the components functions. For such a system, if component i, independent of other components, functions with probability 𝐩𝒊 , 𝑖 = 1, . . . , 𝑛, what is the probability the system functions?
  • 11. Conditional Probability 𝑃(𝐴|𝐵) = 𝑃(𝐴∩𝐵) 𝑃(𝐵) ; 𝑃 𝐵 > 0 𝑃(𝐵|𝐴) = 𝑃(𝐴∩𝐵) 𝑃(𝐴) ; 𝑃(𝐴) > 0 If Aand B are independent, 𝑃 𝐴 𝐵 = 𝑃(𝐴) 𝑃(𝐵|𝐴) = 𝑃(𝐵)
  • 12. Multiplication theorem of Probability : 𝑃(𝐴 ∩ 𝐵) = 𝑃(𝐵) ∙ 𝑃(𝐴|𝐵) 𝑃(𝐵 ∩ 𝐴) = 𝑃(𝐴) ∙ 𝑃(𝐵|𝐴) For n events, 𝑃 𝐴1 ∩ 𝐴2 ∩ ⋯ … . 𝐴𝑛 = 𝑃(𝐴1) 𝑃 𝐴2 𝐴1 × P 𝐴3 𝐴1∩ 𝐴2 … … × 𝑃 𝐴𝑛 | 𝐴1 ∩ 𝐴2 ∩ ⋯ … . 𝐴𝑛−1
  • 13. Example An urn contains 5 defective (that immediately fail when put in use), 10 partially defective (that fail after a couple of hours of use) and 25 acceptable transistors. A transistor is chosen at random from the urn and put into use. If it does not immediately fail, what is the probability it is acceptable?
  • 14. Bayes Theorem of Probability: Theorem: If 𝑬𝟏, 𝑬𝟐, … . . , 𝑬𝒏 are mutually disjoint events with 𝑷 𝑬𝒊 ≠ 𝟎, 𝑖 = 1, 2, … . 𝑛 , then for any arbitrary event 𝑨 which is a subset of 𝒊=𝟏 ∪𝒏 𝑬𝒊 such that 𝑷 𝑨 > 𝟎, we have 𝑖 𝑃(𝐸 |𝐴) = 𝑃(𝐸𝑖) 𝑃(𝐴|𝐸𝑖) 𝑖 =1 ∑𝑛 𝑃(𝐸𝑖) 𝑃(𝐴|𝐸𝑖) ; 𝑖 = 1,2, … … . , 𝑛
  • 15. Example In answering a question on a multiple-choice test, a student either knows the answer or she guesses. Let p be the probability that she knows the answer and 1−p the probability that she guesses. Assume that a student who guesses at the answer will be correct with probability 1/m, where m is the number of multiple- choice alternatives. What is the conditional probability that a student knew the answer to a question given that she answered it correctly?
  • 16. Example A laboratory blood test is 99 percent effective in detecting a certain disease when it is, in fact, present. However, the test also yields a “false positive” result for 1 percent of the healthy persons tested. (That is, if a healthy person is tested, then, with probability .01, the test result will imply he or she has the disease.) If .5 percent of the population actually has the disease, what is the probability a person has the disease given that his test result is positive?