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Maxwell’s Equations: Application of Stokes and Gauss’ theorem
The object of this write up is to derive the so-called Maxwell’s
equation in electro-dynamics from laws given in your Physics class.
Maxwell’s form of electro-dynamic equations are more convenient the
resulting Partial Differential Equations (PDE) can be solved in many
cases(1)
This allows, for instance, calculation of the electro-magnetic
wave propagation caused by an oscillating dipole built out of a wire
loop carrying alternating current. It also allows calculation of electric
and magnetic fields without simplifying assumptions you have see in
your physics class.
1. Gauss’ Law for Electric Field in differential form
Take a region in space having a smooth charge density ρ(x, y, z).
Then, according to Gauss’ Law that you learn in Physics, the electric
field E satisfies:
S
E · dS =
q
ǫ0
(1)
where q is the charge enclosed within the region with closed boundary
S. Since charge is distributed all over the region, with density ρ, the
total charge within S is
q =
E
ρ dV, (2)
where E is the solid region inside S. Therefore, equation (1) becomes,
S
E · dS =
1
ǫ0 E
ρ dV (3)
However, since there are no point charges inside E by assumption,
E has continuous partial derivatives and we obtain from divergence
Theorem and (3):
E
div EdV =
S
E · dS =
1
ǫ0 E
ρ dV (4)
Therefore, for any region E, it follows that
E
div E −
ρ
ǫ0
dV = 0
We divide the expression above by V , the volume of E, and take the
limit V → 0 to obtain
div E −
ρ
ǫ0
= 0 , or div E =
ρ
ǫ0
(4)
(1)
You will learn how to find solutions to PDEs if you took a course in PDEs.
1
2
Equation (4) is Gauss’ law in differential form, and is first of Maxwell’s
four equations.
2. Gauss’ Law for magnetic fields in differential form
We learn in Physics, for a magetic field B, the magnetic flux through
any closed surface is zero because there is no such thing as a magnetic
charge (i.e. monopole). Whenever, there is a north pole, you have a
south pole in a magnetic field. So,
S
B · dS = 0 (5)
With the same steps as for the case of electric field, except B replaces
E and ρ is replaced by 0, it follows from (5) that
div B = 0 (6)
This is Maxwell’s second equation, or Gauss’ law for magnetic field in
differential form.
3. Faraday’s law
We also learn in Physics that if you take a loop and calculate the
rate of change of magnetic flux through a near closed loop (imagine
we keep the circuit open slightly), it is equal to the induced potential
difference Vi, i.e.
Vi =
d
dt S
B · dS , (7)
where S is the surface enclosed by C and oriented positively with re-
spect to the C. On the otherhand, potential difference is the is the
work done to bringing a point test charge from one end of the loop to
another, and is therefore given by
Vi = −
C
E · dr (8)
Therefore, we obtain Faraday’s law in the form
C
E · dr = −
d
dt S
B · dS , = −
S
∂B
∂t
· dS , (8)
Using Stokes Theorem, we obtain
C
E · dr =
S
curl E · dS (9)
Therefore, it follows from (8) that
S
curl E +
∂B
∂t
· dS = 0
3
Dividing the above answer by A, which is the area of S and taking the
limit A → 0 with S chosen to be a planar surface with normal n, we
derive(2)
n · curl E +
∂B
∂t
= 0
Since this is true for any orientation of loop C, and therefore for any
choice of direction for n, it follows that
curl E +
∂B
∂t
= 0 (10)
This is Faraday’s law in differential form, or Maxwell’s third equation.
4. Ampere’s law and correction: Maxwell’s fourth
equation
You learn Ampere’s law in Physics, which states that the loop inte-
gral of the magnetic field B is related to the current I enclosed by the
loop C:
C
B · dr = µ0I (11)
Let’s assume that the current is distibuted across the cross-section of
the loop, with current density j. This density is a vector since it has
a direction attached to it (the direction of current flow). So, the total
current I enclosed by C is
I =
S
j · dS (12)
Therefore, Ampere’s law becomes:
C
B · dr =
S
µ0j · dS, (13)
where S is a surface whose boundary is C. Using Stokes’ Theorem on
the left hand side of (13), we obtain
S
{curl B − µ0j} · dS = 0
Since this is true for arbitrary S, by shrinking C to smaller and smaller
loop around a fixed point and dividing by the area of S, we obtain in
a manner that should be familiar by now:
n · {curl B − µ0j} = 0.
(2)This process is similar to that done in class when we derived the physical
meaning of curl F
4
Since this is true for any orientation of loop C, and therefore for any
direction of n, it follow that
curl B = µ0j (14)
This is Ampere’s law in differential form.
However, equation (14) is not quite correct as Maxwell noted a lack
of symmetry between electric and magnetic field in equations (10) and
(14) in a region where current density j = 0. He postulated that similar
to a changing magnetic field causing an electric field, a changing electric
field should also cause a magnetic field. With Maxwell’s correction
equation (14) is replaced by
curl B = µ0 j + ǫ0
∂E
∂t
(15)
This is the fourth of Maxwell’s equations.
It is to be noted that µ0ǫ0 = 1
c2 , where c is the speed of light. So, the
term in (15) that Ampere’s law (14) does not include is µ0ǫ0
∂E
∂t
, which
is small under conditions when Ampere’s law was tested. However,
this is not the case for electro-magnetic radiation and the correction
by Maxwell is extremely important.

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Maxwell

  • 1. Maxwell’s Equations: Application of Stokes and Gauss’ theorem The object of this write up is to derive the so-called Maxwell’s equation in electro-dynamics from laws given in your Physics class. Maxwell’s form of electro-dynamic equations are more convenient the resulting Partial Differential Equations (PDE) can be solved in many cases(1) This allows, for instance, calculation of the electro-magnetic wave propagation caused by an oscillating dipole built out of a wire loop carrying alternating current. It also allows calculation of electric and magnetic fields without simplifying assumptions you have see in your physics class. 1. Gauss’ Law for Electric Field in differential form Take a region in space having a smooth charge density ρ(x, y, z). Then, according to Gauss’ Law that you learn in Physics, the electric field E satisfies: S E · dS = q ǫ0 (1) where q is the charge enclosed within the region with closed boundary S. Since charge is distributed all over the region, with density ρ, the total charge within S is q = E ρ dV, (2) where E is the solid region inside S. Therefore, equation (1) becomes, S E · dS = 1 ǫ0 E ρ dV (3) However, since there are no point charges inside E by assumption, E has continuous partial derivatives and we obtain from divergence Theorem and (3): E div EdV = S E · dS = 1 ǫ0 E ρ dV (4) Therefore, for any region E, it follows that E div E − ρ ǫ0 dV = 0 We divide the expression above by V , the volume of E, and take the limit V → 0 to obtain div E − ρ ǫ0 = 0 , or div E = ρ ǫ0 (4) (1) You will learn how to find solutions to PDEs if you took a course in PDEs. 1
  • 2. 2 Equation (4) is Gauss’ law in differential form, and is first of Maxwell’s four equations. 2. Gauss’ Law for magnetic fields in differential form We learn in Physics, for a magetic field B, the magnetic flux through any closed surface is zero because there is no such thing as a magnetic charge (i.e. monopole). Whenever, there is a north pole, you have a south pole in a magnetic field. So, S B · dS = 0 (5) With the same steps as for the case of electric field, except B replaces E and ρ is replaced by 0, it follows from (5) that div B = 0 (6) This is Maxwell’s second equation, or Gauss’ law for magnetic field in differential form. 3. Faraday’s law We also learn in Physics that if you take a loop and calculate the rate of change of magnetic flux through a near closed loop (imagine we keep the circuit open slightly), it is equal to the induced potential difference Vi, i.e. Vi = d dt S B · dS , (7) where S is the surface enclosed by C and oriented positively with re- spect to the C. On the otherhand, potential difference is the is the work done to bringing a point test charge from one end of the loop to another, and is therefore given by Vi = − C E · dr (8) Therefore, we obtain Faraday’s law in the form C E · dr = − d dt S B · dS , = − S ∂B ∂t · dS , (8) Using Stokes Theorem, we obtain C E · dr = S curl E · dS (9) Therefore, it follows from (8) that S curl E + ∂B ∂t · dS = 0
  • 3. 3 Dividing the above answer by A, which is the area of S and taking the limit A → 0 with S chosen to be a planar surface with normal n, we derive(2) n · curl E + ∂B ∂t = 0 Since this is true for any orientation of loop C, and therefore for any choice of direction for n, it follows that curl E + ∂B ∂t = 0 (10) This is Faraday’s law in differential form, or Maxwell’s third equation. 4. Ampere’s law and correction: Maxwell’s fourth equation You learn Ampere’s law in Physics, which states that the loop inte- gral of the magnetic field B is related to the current I enclosed by the loop C: C B · dr = µ0I (11) Let’s assume that the current is distibuted across the cross-section of the loop, with current density j. This density is a vector since it has a direction attached to it (the direction of current flow). So, the total current I enclosed by C is I = S j · dS (12) Therefore, Ampere’s law becomes: C B · dr = S µ0j · dS, (13) where S is a surface whose boundary is C. Using Stokes’ Theorem on the left hand side of (13), we obtain S {curl B − µ0j} · dS = 0 Since this is true for arbitrary S, by shrinking C to smaller and smaller loop around a fixed point and dividing by the area of S, we obtain in a manner that should be familiar by now: n · {curl B − µ0j} = 0. (2)This process is similar to that done in class when we derived the physical meaning of curl F
  • 4. 4 Since this is true for any orientation of loop C, and therefore for any direction of n, it follow that curl B = µ0j (14) This is Ampere’s law in differential form. However, equation (14) is not quite correct as Maxwell noted a lack of symmetry between electric and magnetic field in equations (10) and (14) in a region where current density j = 0. He postulated that similar to a changing magnetic field causing an electric field, a changing electric field should also cause a magnetic field. With Maxwell’s correction equation (14) is replaced by curl B = µ0 j + ǫ0 ∂E ∂t (15) This is the fourth of Maxwell’s equations. It is to be noted that µ0ǫ0 = 1 c2 , where c is the speed of light. So, the term in (15) that Ampere’s law (14) does not include is µ0ǫ0 ∂E ∂t , which is small under conditions when Ampere’s law was tested. However, this is not the case for electro-magnetic radiation and the correction by Maxwell is extremely important.