Required 1. Briefly describe different computer controls available .pdf

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Required: 1. Briefly describe different computer controls available to an organization. a. Identify how these controls help to maintain system security and reduce risk. b. Do companies need a formal internal policy that addresses security violations? Why/why not? c. Consider what type of actions a company should take against employees that circumvent computer Solution Security Controls: Administrative Controls, Technical or Logical Controls, Physical Controls The constituents of Security: Vulnerability, Threat, Risk, Exposure, Countermeasure or Safeguard The data vendor grants access needs or may choose to give this function to business unit managers. And it is the data owner who will contract with security violations pertaining to the data he is liable for defending. Subjects that should be measured when developing a security policy: Classification Controls: Qualitative Risk Analysis Techniques:.

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For our discussion question, we focus on recent trends in security technologies and security operations. Staying current with various security tools is an important characteristic of a proficient security manager. One method to discover new technologies is to attend security related conferences and network with other security professionals about current and trending best practices. For your discussion question, choose two relevant and recent physical security technologies and describe them. As part of your detailed description, provide: 1) Specific information about the technology\'s function and application; 2) The type of facilities that the technology would be best suited for; 3) The assets that the technology would best be used to protect; 4) The likely vulnerabilities that the technology would best address; 5) Methods in which the technology would be integrated with other technologies; 6) The number and type of personnel that will need to be committed to the operation of the technology; 7) Special considerations for policies and procedures to fully implement the technology; and 8) A likely budget needed to implement the technology. If you are impressed with a particular security technology that your organization uses, share it. Include any relevant hyperlinks and attach any pictures if applicable. Here are some security categories of technologies that you may select. Please make sure your posting covers a specific technology rather than a broad category: Intrusion Detection Screening Technologies Access Control Technologies Assessment/Surveillance Technologies Communications Technologies Central Control Technologies Security Lighting Make certain that you do not duplicate another student\'s contribution. You can select a “different” technology from the same category. Solution Information Security management is a process of defining the security controls in order to protect the information assets. Security Program The first action of a management program to implement information security is to have a security program in place. Though some argue the first act would be to gain some real \"proof of concept\" \"explainable thru display on the monitor screen\" security knowledge. Start with maybe understanding where OS passwords are stored within the code inside a file within a directory. If you don\'t understand Operating Systems at the root directory level maybe you should seek out advice from somebody who does before even beginning to implement security program management and objectives. Security Program Objectives Protect the company and its assets. Manage Risks by Identifying assets, discovering threats and estimating the risk Provide direction for security activities by framing of information security policies, procedures, standards, guidelines and baselines Information Classification Security Organization and Security Education Security Management Responsibilities Determining objectives, scope, policies,re expected to be accomplished fr.

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In today’s time, where businesses heavily depend on technology for their daily operations, the danger of cyberattacks is a big concern. Companies need to have a solid plan in place to manage the risks associated with cybersecurity. This means taking the necessary steps to protect sensitive data and systems from bad guys who want to cause harm. In this article, we’ll explain why cybersecurity risk management is so important and share some practical strategies to help you keep your digital assets safe. So, let’s dive in and explore how you can protect your business from cyber threats!

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Healthcare becomes one of major economic and social problems around the world. Also security and privacy challenges in the healthcare sector is a growing issue , The psychology and sociology of information technology users in healthcare sector have problems to raise awareness about cyber security issues and the efforts that do aim to protect patient health do not equal the efforts that do to protect healthcare systems and records from daily cyber threats. Recent events have made clear that hackers will find opportunities to exploit flaws in the way healthcare organizations try to manage patient data with wrong mission and outdated approach, so it will lead to data protection failure. Healthcare organizations have lack of budget especially for information technology infrastructure and lack of staff training and monitoring systems to enhance information flow inside and outside organizations, also healthcare industry facing lack of talent who can improve systems security and thinking like hackers. It's possible to decrease gap between industry and healthcare organizations by increasing awareness about security issues depend on correct mission which focusing on patient records and health , In addition to modern approach that can detect advanced threats.

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Assignment Content After reviewing the material your group has prepared so far, the management team has returned with a list of five specific concerns. They include: Access control Security enterprise Impact of implementing a change management system Mitigation Risk management Management has asked you to address concerns with a visual presentation. Address concerns by providing the following information: An overview of the access control Required mitigation steps for each concern Prioritize concerns Concerns with vendor relations from the enterprise security standpoint Description of how the organization can apply risk management principles in its efforts Description of iterative maintenance effort, including audits and frequency Include at least two references formatted according to APA guidelines. Present the information in one of the following ways: A detailed chart along with a brief 1- to 2-page executive summary explaining the decisions made A 12- to 14-slide multimedia-rich presentation with speaker notes Wk 2 - Security Vulnerability Report [due Mon] Assignment Content A security vulnerability report identifies the areas of the organization that are at risk of losing data, outages, etc. Typically, organizations categorize the report to focus on specific areas and highlight the level of risk per area. Based on the vulnerability report, organizations are able to plan appropriately for budgeting and resource improvements. Write a 2½- to 3 ½-page security vulnerability report in Microsoft Word based on the organization you chose in Week 1. An internal review of your organization was previously conducted and found the following vulnerabilities: A formal Password Policy has not been developed that meets your organization’s regulatory requirements. The organization only uses single factor authentication using weak passwords. Vulnerability Severity: High Impact: Threats could easily guess weak passwords allowing unauthorized access. Software configuration management does not exist on your organization’s production servers. There are different configurations on each server and no operating system patching schedule. Vulnerability Severity: Moderate Impact: With ad hoc configuration management, the organization could inadvertently or unintentionally make changes to the servers that could cause a self-imposed denial of service. An Incident Response Plan has not been developed. There is not a formal process for responding to a security incident. Vulnerability Severity: High Impact: In the event of a security incident, an ad hoc process could allow the security incident to get worse and spread throughout the network; the actual attack may not be recognized or handled in a timely manner giving the attacker more time to expand the attack. Consider people, processes, and technology that can be exploited by the source of a threat. Include recommended countermeasures to mitigate the impacts and r.

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Consider a binary search tree T with nodes containing the four fields key, left, right, p. and ht, where key is an integer, left, and right are pointers to the two subtrees, p is a pointer to the parent of the node, and ht is the height of the node (the maximum length of a path from this node to a leaf). Design an algorithm for a procedure insert (T, x) that inserts to a binary searches tree T a new node x (whose key is not in the tree yet), and updates lit fields accordingly. The function should work in O(h) time, where h is the length of the access path. Solution Algorithm is implemented in C: struct node { int key; struct node *left, *right; }; //function to create a new BST node struct node *new_Node(int item) { struct node *tem = (struct node *)malloc(sizeof(struct node)); tem->key = item; tem->left = tem->right = NULL; return tem; } /INSERT PROCEDURE /* Given key in BST,function to insert a new node. */ struct node* insert(struct node* T, int x) { /* If tree is empty then return a new node */ if (T == NULL) return new_Node(x); /* else, repeat down the tree */ if (x < T->x) T->left = insert(T->left, x); else if (key > node->key) T->right = insert(T->right, x); return T; }.

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Based on the article Why It Is Time to Look Beyond Algal Genes in Photosynthetic Slugs By: Cessa Rauch1, Jan de Vries 1, Sophie Rommel2, Laura E. Rose2, Christian Woehle3, Gregor Christa1, Elise M. Laetz4, Heike Wa ¨gele4, Aloysius G.M. Tielens5,6, Jo ¨rg Nickelsen7, Tobias Schumann8, Peter Jahns8, and Sven B. Gould1,* Answer this: --> It has been argued that the reason for detection of such a small amount of mRNA (the read count) of lateral gene transfer origin in the slug cells is due to only very few cells containing plastids. Do you agree with this argument? Why or why not? --> The authors present several alternative reasons for the stability of plastids within the slug cells. Describe two of these reasons. Solution 1. No, we donot agree with the argument. Through LGT from algae to slugs has similar RNA sequence,supported by genome sequence of slug DNA, failed to give an evidence for such LGT events later on. So by this, it is clear that there is no proof that the evolution of kleptoplasty in photosynthetic slugs involves LGT events, where they depend purely on nuclear genes. In some of the photosynthetic slugs, plastids sequestered from algae can continue to photosynthesize for weeks, or even months, in the absence of algal nuclei. Therefore, in conclusion, some isolated algal plastids are by nature more robust than those of land plants and there is no evidence that any of these require the expression of slug genes of algal origin. 2. Plastids have effective photoprotection mechanisms. Slugs acquiring robust plastids will not automatically retain them long-term and endure starvation. Slugs are physiologically adapted and require to retain them functionally..

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Compare/contrast the following classes of hormones by identifying three similarities and four differences among/between them. In addition, be able to list several specific examples of each. AMINE vs. PEPTIDE vs. STEROID Solution Three similarities between the three hormones- 1. Being hormones, the site of synthesis and the site of action of all the three hormones are different. 2. They are all organic molecules and rich in carbon and hydrogen. 3. They are all released directly into the blood stream. Differences Peptide Steroid Amine Composition Made of few to many amino acids(3-200), synthesized from mRNA Derived from cholesterol (from pregnenolone, a steroid precursor) Derived from amino acids tyrosine or tryptophan Solubility in lipid bilayer Not soluble soluble Not soluble Nature Hydrophillic with cell surface receptors( except- thyroid hormones are lipid soluble) Lipophillic with intracellular receptors Hydrophillic with cell surface receptors Mode of Action Through secondary messengers like cAMP, cGMP etc by cascading effect Once inside the cell it binds DNA and modifies transcription Through binding to beta adrenergic receptors, by secondary messengers (signal transduction) or calcium or phosphoinositides Examples ADH, calcitonin, Insulin, Pituitary Hormones (LH,FSH, ACTH, TSH,GH) Estrogen, Progesterone, testosterone, cortisol Epinephrine, nor epinephrine, melatonin, dopamine Peptide Steroid Amine Composition Made of few to many amino acids(3-200), synthesized from mRNA Derived from cholesterol (from pregnenolone, a steroid precursor) Derived from amino acids tyrosine or tryptophan Solubility in lipid bilayer Not soluble soluble Not soluble Nature Hydrophillic with cell surface receptors( except- thyroid hormones are lipid soluble) Lipophillic with intracellular receptors Hydrophillic with cell surface receptors Mode of Action Through secondary messengers like cAMP, cGMP etc by cascading effect Once inside the cell it binds DNA and modifies transcription Through binding to beta adrenergic receptors, by secondary messengers (signal transduction) or calcium or phosphoinositides Examples ADH, calcitonin, Insulin, Pituitary Hormones (LH,FSH, ACTH, TSH,GH) Estrogen, Progesterone, testosterone, cortisol Epinephrine, nor epinephrine, melatonin, dopamine.

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Why does the incidence of acute disease decrease with age? Solution Incidence of acute diseases decrease with age because the body which is through all the worst times have gained enough resistance though the immunity decreases with age still the body will be ready to fight with acute infections and go over that due to the resistance developed in course of lifetime. i hope this is a brief answer and would help you. Thank you.

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White eye color in Drosophila was discovered to be sex linked by Thomas Hunt Morgan, who observed that: White eye color in Drosophila was discovered to be sex linked by Thomas Hunt Morgan, who observed that:A. reciprocal crosses produced different results, which is not true for most autosomal traits.B. the inheritance pattern depended on the sex of the individuals.C. the white- eyed flies were sterile, in contrast to the red-eyed flies.D. A and B.E. All of the above statements apply. Solution The answer is D. A and B. A. reciprocal crosses produced different results, which is not true for most autosomal traits. B. the inheritance pattern depended on the sex of the individuals..

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Which of the following protons would you NOT expect to find embedded in the cytoplasmic membrane of any bacteria? Primary active transport proteins. ATP synthase. Enzyme I complex of the Group translocation system. Basel body protein rings of flagella. Which of the following is true? Both photosystem I and photosystem II rely on light bombarding chlorophyll. Photosystem II donates electrons to photosystem I in a linear electron transport chain. Photosystem I only (not photosystem II) directly produces NADPH utilized for the Calvin cycle. All of the above are true. None of the above are true. Which one of these prokaryotic characteristics can\'t co-exist in a single cell? Mesospheric and acidophil. Aero-tolerant and basophilic. Thermophiles and psychrophilic. Fermentative and Anaerobic. If a population of 4 bacterial cells in log phase, how many cells can we expect to see in an hour\'s time if the cell has a generation time of 30 minutes? 8 cells. 16 cells. 64 cells. 128 cells. The classification of ribosomes in bacteria would be: Ribosomes are proteins and bacteria contain 70s versions. Ribosomes are proteins and bacteria contain 80s versions. Ribosomes are membrane lipids and bacteria contain 70s versions. Ribosomes are membrane lipids and bacteria contain 80s versions. Where do The Calvin Cycle and Glycolysis converge? Only after the \"prep step\" once acetyl CoA is formed, leading to the Calvin Cycle Only when NADH is utilized in the electron transport chain At Glyceraldehyde 3 Phosphate. None of the above are correct. Solution 8.a primary active transport proteins The basal body of a bacterial flagellum is a rod and a system of rings embedded in the cell envelope.Gram-negative flagella usually have an L ring in the plane of the lipopolysaccharide in the outer membrane,a periplasmic P ring in the plane of the peptidoglycan around the flagellar rod and a M S ring that is located within and above the cytoplasmic membrane.A ,C ring extends into the cytoplasm. Enzyme I transfers phosphate from PEP to HPr.PEP group translocation is a distinct method used by bacteria for sugar uptake where the source of energy is from phosphoenolpyruvate (PEP).It is known as multicomponent system that always involves enzymes of the plasma membrane and those in the cytoplasm. ATP synthase is located within the thylakoid membrane and the inner mitochondrial membrane in bacteria. 9.d all are true. In photosystem I energy is absorbed by a pair of P700 chlrophyll a molecules raise to an excited energy level.From there they pass onto FeS4,then onto ferrodoxin,and finally onto ferrodoxin- NADP reductase.After 2 electrons have reduced ferrodoxin-NADP reductase they are transferred to NADP+ reducing it to NADPH and a H+.Photosystem II works with Photosystem I and two series of enzymes imbedded in the thylakoid membrane to transfer energy from the form of light to that stored in chemical bands and gradients which the plant can use in a process called noncyclic photophosph.

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Which of these characteristics distinguishes angiosperms from other seed plants? roots Which of these characteristics distinguishes angiosperms from other seed plants?flowersseedstracheids roots Solution 1. Only angiosperms bear true fruit and have flowers. 2.sporophyte and gametophyte generations, swimming sperm and desiccation tolerance 3. monocots (ie cereals) 4. mechanical support (in form of stem and root anchored to the soil) 5. the diploid gametophyte 6. Pollen grains contain the male gametes of gymnosperms, and seeds contain the female gametes called ovules..

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Which of the following is MOST responsible for maintaining the double-stranded structure of DNA? A. Attractive interactions between positively charged purines and negatively charged pyrimidines. B. Hydrogen bonding between the 3\'-OH of deoxyribose and purine and pyrimidine ring nitrogens. C. Hydrophobic interactions between contiguous base pairs and hydrogen bonding between complementary bases on opposite strands. D. Interactions between the phosphate groups in separate chains. E. Hydrophilic interactions between the pentoses in separate chains. Solution A. Attractive interactions between positively charged purines and negatively charged pyrimidines. Explanation- Attractive interactions between partial positive charge on purines and partial negative charge on pyrimidines is responsible for maintaining stability of DNA. Hydrogen bonds in the DNA strands are individually weak but are collectively strong. These bonds between complementary base pairs stabilize the helical structure of DNA. Adenine is paired through two hydrogen bonds with thymine. Guanidine is paired through three hydrogen bonds with cytosine..

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What are the role of environmental factors on transpiration and how plants defend themselves against water loss? What are the role of environmental factors on transpiration and how plants defend themselves against water loss? Solution Role of environmental factors on transpiration 1. Relative humidity The loss of water vapour from stomata occurs by simple diffusion. When the atmosphere is very humid, the rate of loss of water vapour is lowered. Wind: When the wind velocity is high, rate of transpiration also increases. Temperature: Warm air hold more water vapour so the rate of loss of water increases with increase in temperature. Light: Opening and closing of stomata is regulated by light. More light result in high degree of transpiration. Soil water content: When there is less water content in the soil , the leaf droops / get dehydrated making the stomata to close resulting in less rate of transpiration. Carbon dioxide concentration When the concentration is high, stomata closes resulting in low rate of transpiration and vice versa. Plants defense mechanism against water loss Plants require water for it\'s survival. So it will have to regulate water loss ( especially during drought) . Several leaf adaptations help to combat water loss. Leaf arrangements play important role, transversely arranged leaves loss more water than perpendicularly arranged ones. Other anatomical features of the leaves such as sunken/vestigial stomata and closely arranged mesophyll cells reduces transpiration. Presence of hair, cuticle(waxy) , gums, mucilage etc on leaf surface help reducing transpiration. During drought, plant hormone abscisic acid play an important role by closing the stomata reducing water loss..

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What is the need for a shadow page table? (One or two brief sentences please) Solution Virtualization allows multiple operating system instances to run concurrently on a single computer. Virtualization is the creation of a virtual rather than actual version of something, such as an operating system, a server, a storage device or network resources. Virtualization is where the framework divides the resource into one or more execution environments Even something as simple as partitioning a hard drive is considered virtualization because you take one drive and partition it to create two separate hard drives. Types of virtualization: Storage virtualization: is the pooling of physical storage from multiple network storage devices into what appears to be a single storage device Data virtualization: is abstracting the traditional technical details of data and data management, such as location, performance or format.. Network virtualization: is a method of combining the available resources in a network by splitting up the available bandwidth into channels, each of which is independent from the others. Server virtualization: the partitioning a physical server into smaller virtual servers. Shadow Tables are objects used to improve the way machines, networks and programs handle information. Shadow page tables are used by the hypervisor to keep track of the state in which the guest thinks its page tables should be. The guest can\'t be allowed access to the hardware page tables because then it would essentially have control of the machine. So, the hypervisor keeps the \"real\" mappings guest virtual -> host physical in the hardware when the relevant guest is executing, and keeps a representation of the page table..

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What step of protein synthesis is shown in the figure? elongation stage of transcription termination stage of translation mRNA processing elongation stage of translation initiation stage of transcription Solution elongation stage of transcription Explanation: newly synthesized mRNA separates from the DNA template as the RNA plymerase continues elongation. multiple RNA plymerases transcribe simultaneously..

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Some commercial airplanes recirculate approximately 50% of the cabin air in order to increase fuel efficiency. The researchers studied 1096 airline passengers, among which some traveled on airplanes that recirculated air and others traveled on planes that did not recirculate air. Of the 515 passengers who flew on planes that did not recirculate air, 106 reported post-flight respiratory symptoms, while 112 of the 581 passengers on planes that did recirculate air reported such symptoms. Is there sufficient evidence to conclude that the proportion of passengers with post- flight respiratory symptoms differs for planes that do and do not recirculate air? Test the appropriate hypotheses using a = 0.05. You may assume that it is reasonable to regard these two samples as being independently selected and as representative of the two populations of interest. (Use a statistical computer package to calculate the P-value. Use Pdo not recirculate - Pdo recirculate- Round your test statistic to two decimal places and your P-value to four decimal places.) Solution Null , There Is No Significance between them Ho: p1 = p2 Alternate , There Is Significance between them H1: p1 != p2 Test Statistic Sample 1 : X1 =106, n1 =515, P1= X1/n1=0.206 Sample 2 : X2 =112, n2 =581, P2= X2/n2=0.193 Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2) P^=0.199 Q^ Value For Proportion= 1-P^=0.801 we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2)) Zo =(0.206-0.193)/Sqrt((0.199*0.801(1/515+1/581)) Zo =0.54 | Zo | =0.54 Critical Value The Value of |Z | at LOS 0.05% is 1.96 We got |Zo| =0.54 & | Z | =1.96 Make Decision Hence Value of |Zo | < | Z | and Here we Do not Reject Ho P-Value: Two Tailed ( double the one tail ) -Ha : ( P != 0.5403 ) = 0.589 Hence Value of P0.05 < 0.589,Here We Do not Reject Ho No sufficient evidence to condude that the proportion of passengers with post-flight respratory symptoms differs for planes that do and do not recirculate air ANS: Z = 0.54 P = 0.589.

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Please convert the following C code to assembly Y86 int i,j; ..... if (i >j) { i= i+5; } else { i=0; j++; } Solution Answer: MIPS Assembly Language Code : .zero 1 main: push rbp mov rbp, rsp mov eax, DWORD PTR [rbp-4] cmp eax, DWORD PTR [rbp-8] jle .L2 add DWORD PTR [rbp-4], 5 jmp .L3 .L2: mov DWORD PTR [rbp-4], 0 add DWORD PTR [rbp-8], 1 .L3: mov eax, 0 pop rbp ret __static_initialization_and_destruction_0(int, int): push rbp mov rbp, rsp sub rsp, 16 mov DWORD PTR [rbp-4], edi mov DWORD PTR [rbp-8], esi cmp DWORD PTR [rbp-4], 1 jne .L7 cmp DWORD PTR [rbp-8], 65535 jne .L7 mov edi, OFFSET FLAT:std::__ioinit call std::ios_base::Init::Init() mov edx, OFFSET FLAT:__dso_handle mov esi, OFFSET FLAT:std::__ioinit mov edi, OFFSET FLAT:std::ios_base::Init::~Init() call __cxa_atexit .L7: nop leave ret push rbp mov rbp, rsp mov esi, 65535 mov edi, 1 call __static_initialization_and_destruction_0(int, int) pop rbp ret.

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