2. Proposition 1โข To construct an equilateral triangle on a given finite
straight-line.
โข Step for construction
Describe the circle BCD with centre A and radius AB.
Again describe the circle ACE with centre B and radius BA.
Join the straight lines CA and CB from the point C at which the circles cut one another to
the points A and B
3. Proof
Statements Reason
AB = AC โต ๐ด ๐๐ ๐กโ๐ ๐๐๐๐ก๐๐ ๐๐ ๐กโ๐ ๐๐๐๐๐๐๐ถ๐ท๐ต
BA = BC โต ๐ต ๐๐ ๐กโ๐ ๐๐๐๐ก๐๐ ๐๐ ๐กโ๐ ๐๐๐๐๐๐ ๐ถ๐ด๐ธ
โ ๐ด๐ถ = ๐ถ๐ต โต ๐ด๐ต = ๐ด๐ถ ๐๐๐ ๐๐๐ ๐ ๐ด๐ต = ๐ต๐ถ ๐๐๐
Things equal to the same thing are
also equal to one another
AB = AC = BC โต ๐ด๐ต = ๐ด๐ถ, ๐ต๐ด = ๐ต๐ถ ๐ด๐๐ท ๐ด๐ถ = ๐ถ๐ต
Thus, the triangle ABC is equilateral, and has been constructed on the given finite
straight-line AB.
Q.E.F