The distance between two successive minimize of a transverse wave is 3.31 m. Five crests of the wave pass a given along the direction of travel every 13.4 s. Find the frequency of the wave. Find the wave speed. Solution a) Time period of the wave is T = 13.4 / 4.5 = 2.977 s frequency of the wave is f = 1 / T = 0.335 Hz b) speed of wave is v = 2 d / T = 2( 3.31 m ) / 2.977 s = 2.223 m/s.