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Lecture 9: Operational Amplifiers
Today, we will introduce our first integrated circuit element:
the operational amplifier.
The operational amplifier,
or op-amp, has three terminals*:
 V+ is called the non-inverting input terminal.
 V- is called the inverting input terminal.
 VO is called the output terminal.
* There are actually more connections to the device that are not
shown. The device connects to a power supply, which is
needed for proper operation, as well as ground.
+

V+
V
V0
I-V Relationship
 The I-V relationship for the op-amp is complicated, since it
has multiple terminals.
 The op-amp can be modeled using the following circuit:
 You can simply replace the op-amp symbol with the above
circuit for analysis.
 However, the above model is only valid when VO is within a
certain range.
+

+

V0
AV1
+

V1
Ri
Circuit Model in linear region
Ro
Rails and Saturation
 The output VO must lie within a range determined by the
supply voltages, which are not shown.
 It will limit or “clip” if VO attempts to exceed the
boundaries. We call the limits of the output the “rails”.
 In the linear region, the op-amp
output voltage VO is equal to the
gain A times the voltage across
the input terminals.
 You can “blindly” use
the linear region model,
and check if the output
exceeds a rail. If so,
the output is equal to that rail voltage.
Slope is A
V0


 V
V
lower rail
upper rail
Example: Voltage Follower
 Find the output voltage. Assume the rails are not exceeded.
V0
+

VIN
+

+

V0
AV1
-
+
V1
Ri
Ro
VIN
i
1
o
1
o
R
V
R
AV
V


o
IN
1 V
V
V 

IN
o
i
o
i
o V
R
R
)
1
A
(
R
R
A
V




Ideal Op-Amp Assumptions
 While we can always use our circuit model for the linear
region, it is complicated.
 Ri is usually very large.
 RO is usually very small.
 A is usually very large
(like 103 to 106).
 Thus, we can make the following ideal assumptions for
easier, but still pretty accurate, analysis:
 Assume A = ∞.
 Assume Ri = ∞.
 Assume Ro = 0 W
+

+

V0
AV1
+

V1
Ri
Circuit Model
Ro
Ideal Op-Amp Model
Our idealized op-amp follows these rules within the linear region:
 Rule 1: V+ - V- = 0.
 Why? If the output voltage is limited by rails, and the gain A is
very large, then V+ - V- must be very small.
 Rule 2: No current goes in/out of the input terminals.
 Why? V+ - V- is very small and Ri is very large.
 Remember current can go into/out the output terminal.
 Why? There are connections not shown, and the current comes
from those connections.
+

V+
V
V0 +

+

V0
AV1
+

V1
Ri
Ro
Example: Voltage Follower
V0
+

VIN
 Find the output voltage. Assume the rails are not exceeded.
VO = VIN
+

Utility of Voltage Follower
 Suppose I have a voltage coming out of a digital circuit.
 I want to apply the voltage to “turn on” some device that
requires high power (the device “drains” a substantial amount
of current).
 Digital circuits usually cannot provide much current; they are
designed for low power consumption.
 If we put a voltage follower between the digital circuit and the
load, the voltage follower replicates the desired voltage, and
can also provide current through its power supply.
Digital
Circuit
Op-Amp Circuits
 Op-Amp circuits usually take some input voltage and perform
some “operation” on it, yielding an output voltage.
 Some tips on how to find the output, given the input:
Step 1: KVL around input loop (involves Vin and op-amp inputs)
Use Rule 1: V+-V- = 0
Step 2: Find the current in the feedback path
Use Rule 2: No current into/out of op-amp inputs
Step 3: KVL around output loop (involves Vo and feedback path)
Remember current can flow in/out op-amp output
Example: Inverting Amplifier
V0
+

R1 R2
VIN
Input Loop
Feedback Path
Output Loop
IN
V
1
R
2
R
o
V 

V1
V0
+

V3
V2
RF
R1
R2
R3
3
3
F
2
2
F
1
1
F
0 V
R
R
V
R
R
V
R
R
V 



Example: Inverting Summing Amplifier
Non-inverting Amplifier
IN
V
1
R
2
R
1
o
V 









R1
R2
VIN
Vo
Important Points
 The amplifier output voltage does not depend on the “load”
(what is attached to the output).
 The “form” of the output voltage (the signs of the scaling
factors on the input voltages, for example) depends on the
amplifier circuit layout.
 To change the values (magnitudes) of scaling factors, adjust
resistor values.
 Input voltages which are attached to the + (non-inverting)
amplifier terminal get positive scaling factors.
 Inputs attached to the – (inverting) terminal get negative
scaling factors.
 You can use these principles to design amplifiers which
perform a particular function on the input voltages.
Example: Voltage Divider
 Suppose I want to use the following circuit to supply a
certain fraction of VIN to whatever I attach.
 What is VO if nothing
is attached?
 What is VO if a 1 kW
resistor is attached?
 This circuit clearly does
not supply the same voltage
to any attached load.
What could I add to the circuit so that it will supply the
same fraction of VIN to any attached device?
VIN
1 kW
1 kW
+
VO
_
Example
 Design a circuit whose output is the sum of two
input voltages.
Example
 Design a circuit whose output is the average of
two input voltages.

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lecture9.ppt

  • 1. Lecture 9: Operational Amplifiers Today, we will introduce our first integrated circuit element: the operational amplifier. The operational amplifier, or op-amp, has three terminals*:  V+ is called the non-inverting input terminal.  V- is called the inverting input terminal.  VO is called the output terminal. * There are actually more connections to the device that are not shown. The device connects to a power supply, which is needed for proper operation, as well as ground. +  V+ V V0
  • 2. I-V Relationship  The I-V relationship for the op-amp is complicated, since it has multiple terminals.  The op-amp can be modeled using the following circuit:  You can simply replace the op-amp symbol with the above circuit for analysis.  However, the above model is only valid when VO is within a certain range. +  +  V0 AV1 +  V1 Ri Circuit Model in linear region Ro
  • 3. Rails and Saturation  The output VO must lie within a range determined by the supply voltages, which are not shown.  It will limit or “clip” if VO attempts to exceed the boundaries. We call the limits of the output the “rails”.  In the linear region, the op-amp output voltage VO is equal to the gain A times the voltage across the input terminals.  You can “blindly” use the linear region model, and check if the output exceeds a rail. If so, the output is equal to that rail voltage. Slope is A V0    V V lower rail upper rail
  • 4. Example: Voltage Follower  Find the output voltage. Assume the rails are not exceeded. V0 +  VIN +  +  V0 AV1 - + V1 Ri Ro VIN i 1 o 1 o R V R AV V   o IN 1 V V V   IN o i o i o V R R ) 1 A ( R R A V    
  • 5. Ideal Op-Amp Assumptions  While we can always use our circuit model for the linear region, it is complicated.  Ri is usually very large.  RO is usually very small.  A is usually very large (like 103 to 106).  Thus, we can make the following ideal assumptions for easier, but still pretty accurate, analysis:  Assume A = ∞.  Assume Ri = ∞.  Assume Ro = 0 W +  +  V0 AV1 +  V1 Ri Circuit Model Ro
  • 6. Ideal Op-Amp Model Our idealized op-amp follows these rules within the linear region:  Rule 1: V+ - V- = 0.  Why? If the output voltage is limited by rails, and the gain A is very large, then V+ - V- must be very small.  Rule 2: No current goes in/out of the input terminals.  Why? V+ - V- is very small and Ri is very large.  Remember current can go into/out the output terminal.  Why? There are connections not shown, and the current comes from those connections. +  V+ V V0 +  +  V0 AV1 +  V1 Ri Ro
  • 7. Example: Voltage Follower V0 +  VIN  Find the output voltage. Assume the rails are not exceeded. VO = VIN
  • 8. +  Utility of Voltage Follower  Suppose I have a voltage coming out of a digital circuit.  I want to apply the voltage to “turn on” some device that requires high power (the device “drains” a substantial amount of current).  Digital circuits usually cannot provide much current; they are designed for low power consumption.  If we put a voltage follower between the digital circuit and the load, the voltage follower replicates the desired voltage, and can also provide current through its power supply. Digital Circuit
  • 9. Op-Amp Circuits  Op-Amp circuits usually take some input voltage and perform some “operation” on it, yielding an output voltage.  Some tips on how to find the output, given the input: Step 1: KVL around input loop (involves Vin and op-amp inputs) Use Rule 1: V+-V- = 0 Step 2: Find the current in the feedback path Use Rule 2: No current into/out of op-amp inputs Step 3: KVL around output loop (involves Vo and feedback path) Remember current can flow in/out op-amp output
  • 10. Example: Inverting Amplifier V0 +  R1 R2 VIN Input Loop Feedback Path Output Loop IN V 1 R 2 R o V  
  • 13. Important Points  The amplifier output voltage does not depend on the “load” (what is attached to the output).  The “form” of the output voltage (the signs of the scaling factors on the input voltages, for example) depends on the amplifier circuit layout.  To change the values (magnitudes) of scaling factors, adjust resistor values.  Input voltages which are attached to the + (non-inverting) amplifier terminal get positive scaling factors.  Inputs attached to the – (inverting) terminal get negative scaling factors.  You can use these principles to design amplifiers which perform a particular function on the input voltages.
  • 14. Example: Voltage Divider  Suppose I want to use the following circuit to supply a certain fraction of VIN to whatever I attach.  What is VO if nothing is attached?  What is VO if a 1 kW resistor is attached?  This circuit clearly does not supply the same voltage to any attached load. What could I add to the circuit so that it will supply the same fraction of VIN to any attached device? VIN 1 kW 1 kW + VO _
  • 15. Example  Design a circuit whose output is the sum of two input voltages.
  • 16. Example  Design a circuit whose output is the average of two input voltages.