Muhammed Fuad Rashid Petroleum Engineering Department at Koya Universiy Fluid Mechanics Laboratory 2020

1. Table of Content: -
Title Page No.
Aim of the experiment 3
Introduction 3
Experiment procedure
4
Calculation 5
discussion 7

2. Aim of the experiment:-
Measuring the fluid flow rate.
Introduction:-
The basic Hydraulics Bench and the various ancillary modules available
form a comprehensive laboratory facility which enables a detailed
Mechanics of Fluids Laboratory. The hydraulics bench unit provides the
basic services for the pumping and volumetric measurement of the water
supply with which all the additional accessories and experiments are used.
The working surface of the unit is in fiberglass, molded to provide a
recessed area on which to mount experiments. An integral weir tank is
provided along with a volumetric measuring tank. The measuring tank is
stepped to enable for accurate measuring of both high and low flow rates.
A level indicator allows convenient read out of the flow. The measuring
tank discharges into a fiberglass sump tank via a valve. Overflow pipe is
provided. An electric motor drives a submersible motor driven pump
which delivers water to the outlet at the working surface for connection to
the individual experiments.
1- Volumetric measuring tank with
channel
2-Remote sight gauge
3- Sliding valve
4- Sump tank
5- Drain cock
6- Submersible motor driven
pump
7- Water supply for accessories
with pump
8- Flow control valve
9- Overflow pipe
10- Switch box
11- Discharge cap
12- Water supply connection for
accessories without pump

3. Experiment procedure
* Turn on the pump.
* Set the stop watch to zero.
* Close the valve at the bottom of the volumetric tank, wait until
the liquid
reaches a value of 10 liters and at the same start the watch.
* After the liquid reached a value of 20 liters stop the watch.
* Read off and note the measurement time and the high value of
water in tank.
Table of readings
No. V
(liter)
t
(s)
1 10 23.7
2 10 16.01
3 10 12.86

4. Calculation: -
No.1/ 1L=0.001m3
-Volume flow rate t
V
Q 
7.23
01.0
Q
=0.000422 m3/s
-Mass Flow rate Qm 
m=1000*0.000442
m=0.421941 kg/s
- Weight flow rate gQW 
W
=1000*9.81*0.000442
W
= 4.139241 N/s
NO.2
-Volume flow rate t
V
Q 
=0.000246 m3/s
-Mass Flow rate Qm 
m=1000*0.000246
m=0.6246 kg/s
- Weight flow rate gQW 
W
=1000*9.81*0.000442
W
= 6.12374 N/s
01.16
01.0
Q

5. No.3
Volume flow rate t
V
Q 
86.12
01.0
Q =0.000777 m3
/s
-Mass Flow rate Qm 
m=1000*0.000777
m=0.7776 kg/s
- Weight flow rate gQW 
W
=1000*9.81*0.000777
W
= 7.6283 N/s
Table of Calculating: -
No. V
(m3
)
t
(s)
Q
(
s
m3
)
m
(
s
kg
)
W
(
s
N
)
1 10 23.7 0.000422 0.421941 4.139241
2 10 16.01 0.000246 0.6246 6.12374
3 10 12.86 0.000777 0.7776 7.6283

6. Discussion: -
Q1/ Draw the relation between Q & m , then find the slop of the
relation?
A/
0.4
0.45
0.5
0.55
0.6
0.65
0.7
0.75
0.8
0.0004 0.00045 0.0005 0.00055 0.0006 0.00065 0.0007 0.00075 0.0008
Volume flow rate (Q)
MassFlowrate(m)

7. Q2/ Draw the relation between Q & W
, then find the slop
of the relation?
A/
Q3- What do you understand by the slops above?
A/ By increasing volume flow rate, the mass flow rate
will increase and the time will decrease.
0.4
0.45
0.5
0.55
0.6
0.65
0.7
0.75
0.8
0.0004 0.00045 0.0005 0.00055 0.0006 0.00065 0.0007 0.00075 0.0008
Volume flow rate (Q)
WeightFlowrate(W)