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Holt Geometry
2-5 Algebraic Proof2-5 Algebraic Proof
Holt Geometry
Warm UpWarm Up
Lesson PresentationLesson Presentation
Lesson QuizLesson Quiz
Holt Geometry
2-5 Algebraic Proof
Warm Up
Solve each equation.
1. 3x + 5 = 17
2. r – 3.5 = 8.7
3. 4t – 7 = 8t + 3
4.
5. 2(y – 5) – 20 = 0
x = 4
r = 12.2
n = –38
y = 15
t = –
5
2
Holt Geometry
2-5 Algebraic Proof
Review properties of equality and use
them to write algebraic proofs.
Identify properties of equality and
congruence.
Objectives
Holt Geometry
2-5 Algebraic Proof
proof
Vocabulary
Holt Geometry
2-5 Algebraic Proof
A proof is an argument that uses logic, definitions,
properties, and previously proven statements to show
that a conclusion is true.
An important part of writing a proof is giving
justifications to show that every step is valid.
Holt Geometry
2-5 Algebraic Proof
Holt Geometry
2-5 Algebraic Proof
The Distributive Property states that
a(b + c) = ab + ac.
Remember!
Holt Geometry
2-5 Algebraic Proof
Solve the equation 4m – 8 = –12. Write a
justification for each step.
Example 1: Solving an Equation in Algebra
4m – 8 = –12 Given equation
+8 +8 Addition Property of Equality
4m = –4 Simplify.
m = –1 Simplify.
Division Property of Equality
Holt Geometry
2-5 Algebraic Proof
Check It Out! Example 1
t = –14 Simplify.
Solve the equation . Write a justification
for each step.
Given equation
Multiplication Property of Equality.
Holt Geometry
2-5 Algebraic Proof
Example 2: Problem-Solving Application
What is the temperature in degrees Fahrenheit F
when it is 15°C? Solve the equation F = C + 32
for F and justify each step.
9
5
Holt Geometry
2-5 Algebraic Proof
Example 2 Continued
11 Understand the Problem
The answer will be the temperature in
degrees Fahrenheit.
List the important information:
C = 15
Holt Geometry
2-5 Algebraic Proof
22 Make a Plan
Substitute the given information into the
formula and solve.
Example 2 Continued
Holt Geometry
2-5 Algebraic Proof
Solve33
F = 27 + 32 Simplify.
F = 59 Simplify.
Given equation
Substitution Property of Equality
F = 59°
Example 2 Continued
Holt Geometry
2-5 Algebraic Proof
Look Back44
Check your answer by substituting it back
into the original formula.
59 = 59
?
Example 2 Continued
Holt Geometry
2-5 Algebraic Proof
Check It Out! Example 2
What is the temperature in degrees Celsius C when
it is 86°F? Solve the equation C = (F – 32) for C
and justify each step.
5
9
Holt Geometry
2-5 Algebraic Proof
11 Understand the Problem
The answer will be the temperature in
degrees Celsius.
List the important information:
F = 86
Check It Out! Example 2 Continued
Holt Geometry
2-5 Algebraic Proof
22 Make a Plan
Substitute the given information into the
formula and solve.
Check It Out! Example 2 Continued
Holt Geometry
2-5 Algebraic Proof
Solve33
C = 30 Simplify.
Given equation
Substitution Property of Equality
Simplify.
Check It Out! Example 2 Continued
C = 30°
Holt Geometry
2-5 Algebraic Proof
Look Back44
Check your answer by substituting it back
into the original formula.
30 = 30 
Check It Out! Example 2 Continued
?
Holt Geometry
2-5 Algebraic Proof
Like algebra, geometry also uses numbers, variables,
and operations. For example, segment lengths and
angle measures are numbers. So you can use these
same properties of equality to write algebraic proofs in
geometry.
A B
AB represents the length AB, so you can think of
AB as a variable representing a number.
Helpful Hint
Holt Geometry
2-5 Algebraic Proof
Write a justification for each step.
Example 3: Solving an Equation in Geometry
NO = NM + MO
4x – 4 = 2x + (3x – 9) Substitution Property of Equality
Segment Addition Post.
4x – 4 = 5x – 9 Simplify.
–4 = x – 9
5 = x Addition Property of Equality
Subtraction Property of Equality
Holt Geometry
2-5 Algebraic Proof
Check It Out! Example 3
Write a justification for each step.
x = 11
Subst. Prop. of Equality8x° = (3x + 5)° + (6x – 16)°
8x = 9x – 11 Simplify.
–x = –11 Subtr. Prop. of Equality.
Mult. Prop. of Equality.
∠ Add. Post.m∠ABC = m∠ABD + m∠DBC
Holt Geometry
2-5 Algebraic Proof
You learned in Chapter 1 that segments with
equal lengths are congruent and that angles with
equal measures are congruent. So the Reflexive,
Symmetric, and Transitive Properties of Equality
have corresponding properties of congruence.
Holt Geometry
2-5 Algebraic Proof
Holt Geometry
2-5 Algebraic Proof
Numbers are equal (=) and figures are congruent
(≅).
Remember!
Holt Geometry
2-5 Algebraic Proof
Identify the property that justifies each
statement.
A. ∠QRS ≅ ∠QRS
B. m∠1 = m∠2 so m∠2 = m∠1
C. AB ≅ CD and CD ≅ EF, so AB ≅ EF.
D. 32° = 32°
Example 4: Identifying Property of Equality and
Congruence
Symm. Prop. of =
Trans. Prop of ≅
Reflex. Prop. of =
Reflex. Prop. of ≅.
Holt Geometry
2-5 Algebraic Proof
Check It Out! Example 4
Identify the property that justifies each
statement.
4a. DE = GH, so GH = DE.
4b. 94° = 94°
4c. 0 = a, and a = x. So 0 = x.
4d. ∠A ≅ ∠Y, so ∠Y ≅ ∠A
Sym. Prop. of =
Reflex. Prop. of =
Trans. Prop. of =
Sym. Prop. of ≅
Holt Geometry
2-5 Algebraic Proof
Lesson Quiz: Part I
Solve each equation. Write a justification for
each step.
1.
z – 5 = –12 Mult. Prop. of =
z = –7 Add. Prop. of =
Given
Holt Geometry
2-5 Algebraic Proof
Lesson Quiz: Part II
Solve each equation. Write a justification for
each step.
2. 6r – 3 = –2(r + 1)
Given
6r – 3 = –2r – 2
8r – 3 = –2
Distrib. Prop.
Add. Prop. of =
6r – 3 = –2(r + 1)
8r = 1 Add. Prop. of =
Div. Prop. of =
Holt Geometry
2-5 Algebraic Proof
Lesson Quiz: Part III
Identify the property that justifies each
statement.
3. x = y and y = z, so x = z.
4. ∠DEF ≅ ∠DEF
5. AB ≅ CD, so CD ≅ AB.
Trans. Prop. of =
Reflex. Prop. of ≅
Sym. Prop. of ≅

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Holt Geometry 2-5 Algebraic Proof Lesson

  • 1. Holt Geometry 2-5 Algebraic Proof2-5 Algebraic Proof Holt Geometry Warm UpWarm Up Lesson PresentationLesson Presentation Lesson QuizLesson Quiz
  • 2. Holt Geometry 2-5 Algebraic Proof Warm Up Solve each equation. 1. 3x + 5 = 17 2. r – 3.5 = 8.7 3. 4t – 7 = 8t + 3 4. 5. 2(y – 5) – 20 = 0 x = 4 r = 12.2 n = –38 y = 15 t = – 5 2
  • 3. Holt Geometry 2-5 Algebraic Proof Review properties of equality and use them to write algebraic proofs. Identify properties of equality and congruence. Objectives
  • 4. Holt Geometry 2-5 Algebraic Proof proof Vocabulary
  • 5. Holt Geometry 2-5 Algebraic Proof A proof is an argument that uses logic, definitions, properties, and previously proven statements to show that a conclusion is true. An important part of writing a proof is giving justifications to show that every step is valid.
  • 7. Holt Geometry 2-5 Algebraic Proof The Distributive Property states that a(b + c) = ab + ac. Remember!
  • 8. Holt Geometry 2-5 Algebraic Proof Solve the equation 4m – 8 = –12. Write a justification for each step. Example 1: Solving an Equation in Algebra 4m – 8 = –12 Given equation +8 +8 Addition Property of Equality 4m = –4 Simplify. m = –1 Simplify. Division Property of Equality
  • 9. Holt Geometry 2-5 Algebraic Proof Check It Out! Example 1 t = –14 Simplify. Solve the equation . Write a justification for each step. Given equation Multiplication Property of Equality.
  • 10. Holt Geometry 2-5 Algebraic Proof Example 2: Problem-Solving Application What is the temperature in degrees Fahrenheit F when it is 15°C? Solve the equation F = C + 32 for F and justify each step. 9 5
  • 11. Holt Geometry 2-5 Algebraic Proof Example 2 Continued 11 Understand the Problem The answer will be the temperature in degrees Fahrenheit. List the important information: C = 15
  • 12. Holt Geometry 2-5 Algebraic Proof 22 Make a Plan Substitute the given information into the formula and solve. Example 2 Continued
  • 13. Holt Geometry 2-5 Algebraic Proof Solve33 F = 27 + 32 Simplify. F = 59 Simplify. Given equation Substitution Property of Equality F = 59° Example 2 Continued
  • 14. Holt Geometry 2-5 Algebraic Proof Look Back44 Check your answer by substituting it back into the original formula. 59 = 59 ? Example 2 Continued
  • 15. Holt Geometry 2-5 Algebraic Proof Check It Out! Example 2 What is the temperature in degrees Celsius C when it is 86°F? Solve the equation C = (F – 32) for C and justify each step. 5 9
  • 16. Holt Geometry 2-5 Algebraic Proof 11 Understand the Problem The answer will be the temperature in degrees Celsius. List the important information: F = 86 Check It Out! Example 2 Continued
  • 17. Holt Geometry 2-5 Algebraic Proof 22 Make a Plan Substitute the given information into the formula and solve. Check It Out! Example 2 Continued
  • 18. Holt Geometry 2-5 Algebraic Proof Solve33 C = 30 Simplify. Given equation Substitution Property of Equality Simplify. Check It Out! Example 2 Continued C = 30°
  • 19. Holt Geometry 2-5 Algebraic Proof Look Back44 Check your answer by substituting it back into the original formula. 30 = 30  Check It Out! Example 2 Continued ?
  • 20. Holt Geometry 2-5 Algebraic Proof Like algebra, geometry also uses numbers, variables, and operations. For example, segment lengths and angle measures are numbers. So you can use these same properties of equality to write algebraic proofs in geometry. A B AB represents the length AB, so you can think of AB as a variable representing a number. Helpful Hint
  • 21. Holt Geometry 2-5 Algebraic Proof Write a justification for each step. Example 3: Solving an Equation in Geometry NO = NM + MO 4x – 4 = 2x + (3x – 9) Substitution Property of Equality Segment Addition Post. 4x – 4 = 5x – 9 Simplify. –4 = x – 9 5 = x Addition Property of Equality Subtraction Property of Equality
  • 22. Holt Geometry 2-5 Algebraic Proof Check It Out! Example 3 Write a justification for each step. x = 11 Subst. Prop. of Equality8x° = (3x + 5)° + (6x – 16)° 8x = 9x – 11 Simplify. –x = –11 Subtr. Prop. of Equality. Mult. Prop. of Equality. ∠ Add. Post.m∠ABC = m∠ABD + m∠DBC
  • 23. Holt Geometry 2-5 Algebraic Proof You learned in Chapter 1 that segments with equal lengths are congruent and that angles with equal measures are congruent. So the Reflexive, Symmetric, and Transitive Properties of Equality have corresponding properties of congruence.
  • 25. Holt Geometry 2-5 Algebraic Proof Numbers are equal (=) and figures are congruent (≅). Remember!
  • 26. Holt Geometry 2-5 Algebraic Proof Identify the property that justifies each statement. A. ∠QRS ≅ ∠QRS B. m∠1 = m∠2 so m∠2 = m∠1 C. AB ≅ CD and CD ≅ EF, so AB ≅ EF. D. 32° = 32° Example 4: Identifying Property of Equality and Congruence Symm. Prop. of = Trans. Prop of ≅ Reflex. Prop. of = Reflex. Prop. of ≅.
  • 27. Holt Geometry 2-5 Algebraic Proof Check It Out! Example 4 Identify the property that justifies each statement. 4a. DE = GH, so GH = DE. 4b. 94° = 94° 4c. 0 = a, and a = x. So 0 = x. 4d. ∠A ≅ ∠Y, so ∠Y ≅ ∠A Sym. Prop. of = Reflex. Prop. of = Trans. Prop. of = Sym. Prop. of ≅
  • 28. Holt Geometry 2-5 Algebraic Proof Lesson Quiz: Part I Solve each equation. Write a justification for each step. 1. z – 5 = –12 Mult. Prop. of = z = –7 Add. Prop. of = Given
  • 29. Holt Geometry 2-5 Algebraic Proof Lesson Quiz: Part II Solve each equation. Write a justification for each step. 2. 6r – 3 = –2(r + 1) Given 6r – 3 = –2r – 2 8r – 3 = –2 Distrib. Prop. Add. Prop. of = 6r – 3 = –2(r + 1) 8r = 1 Add. Prop. of = Div. Prop. of =
  • 30. Holt Geometry 2-5 Algebraic Proof Lesson Quiz: Part III Identify the property that justifies each statement. 3. x = y and y = z, so x = z. 4. ∠DEF ≅ ∠DEF 5. AB ≅ CD, so CD ≅ AB. Trans. Prop. of = Reflex. Prop. of ≅ Sym. Prop. of ≅