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UNIDAD 1
Tarea 3. Realizar las siguientes divisiones de polinomios aplicando la división
sintética
3𝑥4
− 2𝑥3
+ 𝑥2
+ 15𝑥 + 4 ÷ (3𝑥 + 4)
Igualamos a cero el divisor 3𝑥 + 4 = 0 𝑦 𝑜𝑏𝑡𝑒𝑛𝑒𝑚𝑜𝑠 𝑙𝑜 𝑠𝑖𝑔𝑢𝑖𝑒𝑛𝑡𝑒
𝑥 = −
4
3
Colocamos la parte numérica del polinomio en orden
descendiente de acuerdo a los exponentes.
3 − 2 + 1 + 15 + 4 Multiplico el primer término (3) ( −
4
3
) da -6
−4 + 8 − 12 − 4 −
4
3
Multiplico −6 −
4
3
y obtenemos +8
3 − 6 + 9 + 3 0 Multiplico (+9) −
4
3
nos queda -12
Multiplico (+3) −
4
3
se obtiene -4
Restamos, el resultado es cero
Ahora al resultado le colocamos la variable X, restándole una unidad al exponente
del polinomio original que tiene exponente (4). Entonces nos quedara un nuevo
polinomio con exponente (3)
3𝑥3
− 6𝑥2
+ 9𝑥 + 3 Ahora divido todo entre el valor del primer término
que es (3)
3𝑥3
− 6𝑥2
+ 9𝑥 + 3 ÷ 3 Y obtenemos lo siguiente
𝑥3
− 2𝑥2
+ 3𝑥 + 1 Resultado de la división sintética
UNIDAD 1 TAREA 3
COMPROBACION GEOGEBRA

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División sintética de polinomios

  • 1. UNIDAD 1 Tarea 3. Realizar las siguientes divisiones de polinomios aplicando la división sintética 3𝑥4 − 2𝑥3 + 𝑥2 + 15𝑥 + 4 ÷ (3𝑥 + 4) Igualamos a cero el divisor 3𝑥 + 4 = 0 𝑦 𝑜𝑏𝑡𝑒𝑛𝑒𝑚𝑜𝑠 𝑙𝑜 𝑠𝑖𝑔𝑢𝑖𝑒𝑛𝑡𝑒 𝑥 = − 4 3 Colocamos la parte numérica del polinomio en orden descendiente de acuerdo a los exponentes. 3 − 2 + 1 + 15 + 4 Multiplico el primer término (3) ( − 4 3 ) da -6 −4 + 8 − 12 − 4 − 4 3 Multiplico −6 − 4 3 y obtenemos +8 3 − 6 + 9 + 3 0 Multiplico (+9) − 4 3 nos queda -12 Multiplico (+3) − 4 3 se obtiene -4 Restamos, el resultado es cero Ahora al resultado le colocamos la variable X, restándole una unidad al exponente del polinomio original que tiene exponente (4). Entonces nos quedara un nuevo polinomio con exponente (3) 3𝑥3 − 6𝑥2 + 9𝑥 + 3 Ahora divido todo entre el valor del primer término que es (3) 3𝑥3 − 6𝑥2 + 9𝑥 + 3 ÷ 3 Y obtenemos lo siguiente 𝑥3 − 2𝑥2 + 3𝑥 + 1 Resultado de la división sintética
  • 2. UNIDAD 1 TAREA 3 COMPROBACION GEOGEBRA