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Consider the function below and investigate on the values of 𝑓(π‘₯) for
the given values of π‘₯.
𝒇 𝒙 =
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
Table A Table B
1.Basedonthetable, whatis impliedonthedomainof 𝑓(π‘₯)?
Table A Table B
2. Howwould youdescribethevalues ofthe independent
variableπ‘₯onTableA?onTableB?
Table A Table B
3. Whatseems tobethevalue of 𝑓(π‘₯)asπ‘₯approaches tothe
valueof 1?
Table A Table B
4.Whatwillhappentothevalue of 𝑓(π‘₯)ifπ‘₯ =1?
𝒇 𝟏 =
πŸπŸ‘ βˆ’ 𝟏𝟐
𝟏 βˆ’ 𝟏
𝒇 𝟏 =
𝟏 βˆ’ 𝟏
𝟎
𝒇 𝟏 =
𝟎
𝟎
𝒇 𝟏 = π’Šπ’π’…π’†π’•π’†π’“π’Žπ’Šπ’π’‚π’•π’†
Take note:
indeterminate becomes a hole in a graph
𝒇 𝒙 =
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
Illustrate a limit of a function (STEM_BC11LC-IIIa-1).
Consider a function f(𝒙). Consider a constant 𝒄 which the
variable 𝒙 will approach (𝒄 may or may not be in the domain
of 𝒇).
The limit, to be denoted by 𝑳, is the unique real value that 𝒇(
𝒙) will approach as 𝒙 approaches 𝒄. In symbols, we write this
process as
This is read as β€œThe limit of 𝒇(𝒙) as 𝒙 approaches 𝒄 is 𝑳.”
π₯𝐒𝐦
𝒙→𝒄
𝒇 𝒙 = 𝑳
1. Table of Values
2. Graph
𝒇 𝒙 =
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
π₯𝐒𝐦
𝒙→𝒄
𝒇 𝒙 = 𝑳 π₯𝐒𝐦
π’™β†’πŸ
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝑳
Find the limit of the function, as x approaches 1.
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝑳 π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝑳
β€œThe limit of f(x) as x approaches
1 from the left”
β€œThe limit of f(x) as x approaches
1 from the right”
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝑳
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
x < 1 f(x)
0.25
0.81
0.9801
0.99980001
0.9999800001
x > 1 f(x)
2.25
1.21
1.0201
1.002001
1.002001
π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝑳
π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
0.5
0.9
0.99
0.999
0.9999
1.5
1.1
1.01
1.001
1.0001
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏 π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
Left-hand Limit: Right-hand
Limit:
Conclusion:
Since the left-hand and right-hand limits are
equal, therefore,
π₯𝐒𝐦
π’™β†’πŸ
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
π₯𝐒𝐦
π’™β†’πŸβˆ’
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
π₯𝐒𝐦
π’™β†’πŸ+
π’™πŸ‘
βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
Left-hand Limit:
Right-hand
Limit:
π₯𝐒𝐦
π’™β†’πŸ
π’™πŸ‘ βˆ’ π’™πŸ
𝒙 βˆ’ 𝟏
= 𝟏
The limit is the unique real
value that 𝒇(𝒙) will approach
as 𝒙 approaches 𝒄.
π₯𝐒𝐦
𝒙→𝒄
𝒇 𝒙 = 𝑳
π₯𝐒𝐦
π’™β†’π’„βˆ’
𝒇 𝒙 π₯𝐒𝐦
𝒙→𝒄+
𝒇 𝒙
Left-hand Limit Right-hand
Limit
Judgment:
 If both left-hand and right-
hand limits are EQUAL,
the limit exist, which is L
(value).
 If both left-hand and right-
hand limits are NOT
EQUAL, the limit does not
exist (DNE).
𝒇 𝒙 = 𝟏 + πŸ‘π’™
π₯𝐒𝐦
𝒙→𝒄
𝒇 𝒙 = 𝑳 π₯𝐒𝐦
π’™β†’πŸ
(𝟏 + πŸ‘π’™) = 𝑳
Find the limit of the function, as x approaches 2.
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝟏 + πŸ‘π’™) = 𝑳 π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™) = 𝑳
β€œThe limit of f(x) as x approaches
2 from the left”
β€œThe limit of f(x) as x approaches
2 from the right”
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝟏 + πŸ‘π’™) π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™)
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝟏 + πŸ‘π’™) = 𝑳
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝟏 + πŸ‘π’™) = πŸ•
x < 2 f(x)
6.1
6.7
6.85
6.997
6.9997
x > 2 f(x)
8.5
7.3
7.03
7.003
7.0003
π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™) = 𝑳
π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™) = πŸ•
1.7
1.9
1.95
1.999
1.9999
2.5
2.1
2.01
2.001
2.0001
Table A Table B
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝒙 + πŸ‘π’™) = πŸ• π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™) = πŸ•
Left-hand Limit: Right-hand
Limit:
Conclusion:
Since the left-hand and right-hand limits are
equal, therefore,
π₯𝐒𝐦
π’™β†’πŸ
(𝟏 + πŸ‘π’™) = πŸ•
π₯𝐒𝐦
π’™β†’πŸβˆ’
(𝟏 + πŸ‘π’™) = πŸ•
π₯𝐒𝐦
π’™β†’πŸ+
(𝟏 + πŸ‘π’™) = πŸ•
Left-hand Limit:
Right-hand
Limit:
π₯𝐒𝐦
π’™β†’πŸ
(𝟏 + πŸ‘π’™) = πŸ•
Using the graph, find the limit of the function as x
approaches from the following values.
1. π‘₯ = βˆ’1
2. π‘₯ = 3
3. π‘₯ = βˆ’3.75
4. π‘₯ = 1
5. π‘₯ = 5
1. Form a circle with your group mates.
2. Prepare your pens and calculators.
3. As you received the material from the
teacher, provide the necessary answer.
4. If you are already done answering, give
the material to the teacher.
5. Prepare your group for a presentation
later.
π’ˆ 𝒙 =
π’™πŸ
βˆ’ πŸπ’™
𝒙 βˆ’ 𝟐
𝒉 𝒙 = 𝒙 + 𝟏
𝒓 𝒙 = π’™πŸ βˆ’ πŸ’
𝒇 𝒙 =
𝟏
𝒙
WhatdowemeanbytheLimitofaFunction?
HowcanwefindtheLimit ofaFunction?
Isitimportanttofindfirsttheleft-hand and
right-handlimits beforestatingtheanswerof
the ?
lim
π‘₯→𝑐
𝑓(π‘₯)
Directions: Get 1 whole yellow paper per group. Copy
and answer only. Do not include the graph in your
paper.
A. Construct two tables of values to find the .
B. Consider the function 𝑓(π‘₯) whose graph is given below.
1.
2.
3.
4.
5.
lim
π‘₯β†’1
(π‘₯3
+2π‘₯)
lim
π‘₯β†’βˆ’3
𝑓 π‘₯ =
lim
π‘₯β†’1
𝑓 π‘₯ =
lim
π‘₯β†’3
𝑓 π‘₯ =
lim
π‘₯β†’2
𝑓 π‘₯ =
lim
π‘₯β†’4
𝑓 π‘₯ =
Directions: Get 1 whole yellow paper per group. Copy
and answer only. Do not include the graph in your
paper.
A. Construct two tables of values to
find the
B. Consider the function 𝑓(π‘₯) whose
graph is given below.
1.
2.
3.
4.
5.
lim
π‘₯β†’1
(π‘₯3+2π‘₯)
lim
π‘₯β†’βˆ’3
𝑓 π‘₯ =
lim
π‘₯β†’1
𝑓 π‘₯ =
lim
π‘₯β†’2
𝑓 π‘₯ =
lim
π‘₯β†’6
𝑓 π‘₯ =
lim
π‘₯β†’4
𝑓 π‘₯ =
Arceo, Carlene Perpetua P., Richard S. Lemence, Oreste Jr. M. Ortega, and Louie John D.
Vallejo. (2016). Teaching Guide For Senior High School Basic Calculus. Diliman,
Quezon City: Comission on Higher Education
CREDITS: This presentation template was created by Slidesgo,
including icons by Flaticon, infographics & images by Freepik.
THANKS
Do you have any questions?
youremail@freepik.com
+91 620 421 88
yourwebsite.com
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1-LIMIT-OF-A-FUNCTION.pptx

  • 1.
  • 2. Consider the function below and investigate on the values of 𝑓(π‘₯) for the given values of π‘₯. 𝒇 𝒙 = π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 Table A Table B
  • 3. 1.Basedonthetable, whatis impliedonthedomainof 𝑓(π‘₯)? Table A Table B
  • 4. 2. Howwould youdescribethevalues ofthe independent variableπ‘₯onTableA?onTableB? Table A Table B
  • 5. 3. Whatseems tobethevalue of 𝑓(π‘₯)asπ‘₯approaches tothe valueof 1? Table A Table B
  • 6. 4.Whatwillhappentothevalue of 𝑓(π‘₯)ifπ‘₯ =1? 𝒇 𝟏 = πŸπŸ‘ βˆ’ 𝟏𝟐 𝟏 βˆ’ 𝟏 𝒇 𝟏 = 𝟏 βˆ’ 𝟏 𝟎 𝒇 𝟏 = 𝟎 𝟎 𝒇 𝟏 = π’Šπ’π’…π’†π’•π’†π’“π’Žπ’Šπ’π’‚π’•π’† Take note: indeterminate becomes a hole in a graph 𝒇 𝒙 = π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏
  • 7. Illustrate a limit of a function (STEM_BC11LC-IIIa-1).
  • 8. Consider a function f(𝒙). Consider a constant 𝒄 which the variable 𝒙 will approach (𝒄 may or may not be in the domain of 𝒇). The limit, to be denoted by 𝑳, is the unique real value that 𝒇( 𝒙) will approach as 𝒙 approaches 𝒄. In symbols, we write this process as This is read as β€œThe limit of 𝒇(𝒙) as 𝒙 approaches 𝒄 is 𝑳.” π₯𝐒𝐦 𝒙→𝒄 𝒇 𝒙 = 𝑳
  • 9. 1. Table of Values 2. Graph
  • 10. 𝒇 𝒙 = π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 π₯𝐒𝐦 𝒙→𝒄 𝒇 𝒙 = 𝑳 π₯𝐒𝐦 π’™β†’πŸ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝑳 Find the limit of the function, as x approaches 1. π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝑳 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝑳 β€œThe limit of f(x) as x approaches 1 from the left” β€œThe limit of f(x) as x approaches 1 from the right”
  • 11. π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝑳 π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 x < 1 f(x) 0.25 0.81 0.9801 0.99980001 0.9999800001 x > 1 f(x) 2.25 1.21 1.0201 1.002001 1.002001 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝑳 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 0.5 0.9 0.99 0.999 0.9999 1.5 1.1 1.01 1.001 1.0001
  • 12. π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 Left-hand Limit: Right-hand Limit: Conclusion: Since the left-hand and right-hand limits are equal, therefore, π₯𝐒𝐦 π’™β†’πŸ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏
  • 13. π₯𝐒𝐦 π’™β†’πŸβˆ’ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 π₯𝐒𝐦 π’™β†’πŸ+ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏 Left-hand Limit: Right-hand Limit: π₯𝐒𝐦 π’™β†’πŸ π’™πŸ‘ βˆ’ π’™πŸ 𝒙 βˆ’ 𝟏 = 𝟏
  • 14. The limit is the unique real value that 𝒇(𝒙) will approach as 𝒙 approaches 𝒄. π₯𝐒𝐦 𝒙→𝒄 𝒇 𝒙 = 𝑳 π₯𝐒𝐦 π’™β†’π’„βˆ’ 𝒇 𝒙 π₯𝐒𝐦 𝒙→𝒄+ 𝒇 𝒙 Left-hand Limit Right-hand Limit Judgment:  If both left-hand and right- hand limits are EQUAL, the limit exist, which is L (value).  If both left-hand and right- hand limits are NOT EQUAL, the limit does not exist (DNE).
  • 15. 𝒇 𝒙 = 𝟏 + πŸ‘π’™ π₯𝐒𝐦 𝒙→𝒄 𝒇 𝒙 = 𝑳 π₯𝐒𝐦 π’™β†’πŸ (𝟏 + πŸ‘π’™) = 𝑳 Find the limit of the function, as x approaches 2. π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝟏 + πŸ‘π’™) = 𝑳 π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) = 𝑳 β€œThe limit of f(x) as x approaches 2 from the left” β€œThe limit of f(x) as x approaches 2 from the right”
  • 16. π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝟏 + πŸ‘π’™) π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝟏 + πŸ‘π’™) = 𝑳 π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝟏 + πŸ‘π’™) = πŸ• x < 2 f(x) 6.1 6.7 6.85 6.997 6.9997 x > 2 f(x) 8.5 7.3 7.03 7.003 7.0003 π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) = 𝑳 π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) = πŸ• 1.7 1.9 1.95 1.999 1.9999 2.5 2.1 2.01 2.001 2.0001 Table A Table B
  • 17. π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝒙 + πŸ‘π’™) = πŸ• π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) = πŸ• Left-hand Limit: Right-hand Limit: Conclusion: Since the left-hand and right-hand limits are equal, therefore, π₯𝐒𝐦 π’™β†’πŸ (𝟏 + πŸ‘π’™) = πŸ•
  • 18. π₯𝐒𝐦 π’™β†’πŸβˆ’ (𝟏 + πŸ‘π’™) = πŸ• π₯𝐒𝐦 π’™β†’πŸ+ (𝟏 + πŸ‘π’™) = πŸ• Left-hand Limit: Right-hand Limit: π₯𝐒𝐦 π’™β†’πŸ (𝟏 + πŸ‘π’™) = πŸ•
  • 19. Using the graph, find the limit of the function as x approaches from the following values. 1. π‘₯ = βˆ’1 2. π‘₯ = 3 3. π‘₯ = βˆ’3.75 4. π‘₯ = 1 5. π‘₯ = 5
  • 20. 1. Form a circle with your group mates. 2. Prepare your pens and calculators. 3. As you received the material from the teacher, provide the necessary answer. 4. If you are already done answering, give the material to the teacher. 5. Prepare your group for a presentation later.
  • 21. π’ˆ 𝒙 = π’™πŸ βˆ’ πŸπ’™ 𝒙 βˆ’ 𝟐 𝒉 𝒙 = 𝒙 + 𝟏 𝒓 𝒙 = π’™πŸ βˆ’ πŸ’ 𝒇 𝒙 = 𝟏 𝒙
  • 23. Directions: Get 1 whole yellow paper per group. Copy and answer only. Do not include the graph in your paper. A. Construct two tables of values to find the . B. Consider the function 𝑓(π‘₯) whose graph is given below. 1. 2. 3. 4. 5. lim π‘₯β†’1 (π‘₯3 +2π‘₯) lim π‘₯β†’βˆ’3 𝑓 π‘₯ = lim π‘₯β†’1 𝑓 π‘₯ = lim π‘₯β†’3 𝑓 π‘₯ = lim π‘₯β†’2 𝑓 π‘₯ = lim π‘₯β†’4 𝑓 π‘₯ =
  • 24. Directions: Get 1 whole yellow paper per group. Copy and answer only. Do not include the graph in your paper. A. Construct two tables of values to find the B. Consider the function 𝑓(π‘₯) whose graph is given below. 1. 2. 3. 4. 5. lim π‘₯β†’1 (π‘₯3+2π‘₯) lim π‘₯β†’βˆ’3 𝑓 π‘₯ = lim π‘₯β†’1 𝑓 π‘₯ = lim π‘₯β†’2 𝑓 π‘₯ = lim π‘₯β†’6 𝑓 π‘₯ = lim π‘₯β†’4 𝑓 π‘₯ =
  • 25. Arceo, Carlene Perpetua P., Richard S. Lemence, Oreste Jr. M. Ortega, and Louie John D. Vallejo. (2016). Teaching Guide For Senior High School Basic Calculus. Diliman, Quezon City: Comission on Higher Education
  • 26. CREDITS: This presentation template was created by Slidesgo, including icons by Flaticon, infographics & images by Freepik. THANKS Do you have any questions? youremail@freepik.com +91 620 421 88 yourwebsite.com Please keep this slide for attribution