This word problem is about a triangle whose perimeter is 47 miles. Since it\'s asking to find the length of each side, then there are 3 unknowns. So here\'s what we do: Let the variables S1 be the length of side 1 in miles, S2 be the length of side 2 in miles, and S3 be the length of side 3 in miles. Now, the next thing to do with these variables is to set up equations that follow the word problem. Here they are as follows: S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than twice the 2nd side (represented by 2*S2). S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side. Next, since we have more than one unknown, we should express one equation in terms of one variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that we express the other variable equations of S1 and S3 in terms of S2. Here\'s how it goes: S1=(2*S2)-5 as S1 is already expressed in terms of S2 S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2. =(2*S2)-5+2 I combined like terms. =(2*S2)-3. Now that I have expressed both S1 and S3 in terms of S2, I can plug those equations into that for the triangle perimeter: [(2*S2)-5]+S2+[(2*S2)-3]=47 (2*S2)-5+S2+(2*S2)-3=47 Again, I combined like terms. (5*S2)-8=47 +8=+8 I added 8 on both sides of the equation to eliminate -8 on the left side. 5*S2=55 5*S2/5=55/5 S2=11 S1=(2*11)-5=22-5=17 Now that I have found the value of S2, I can plug it into the S1 equation. S3=17+2=19 Now that I have found the value of S1, I can plug it into the S3 equation. So now here are the lengths of each side of the triangle. Side 1 is 17 miles, side 2 is 11 miles, and side 3 is 19 miles. Solution This word problem is about a triangle whose perimeter is 47 miles. Since it\'s asking to find the length of each side, then there are 3 unknowns. So here\'s what we do: Let the variables S1 be the length of side 1 in miles, S2 be the length of side 2 in miles, and S3 be the length of side 3 in miles. Now, the next thing to do with these variables is to set up equations that follow the word problem. Here they are as follows: S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than twice the 2nd side (represented by 2*S2). S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side. Next, since we have more than one unknown, we should express one equation in terms of one variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that we express the other variable equations of S1 and S3 in terms of S2. Here\'s how it goes: S1=(2*S2)-5 as S1 is already expressed in terms of S2 S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2. =(2*S2)-5+2 I combined l.

1. This word problem is about a triangle whose perimeter is 47 miles. Since it's asking to find the
length of each side, then there are 3 unknowns. So here's what we do:
Let the variables S1 be the length of side 1 in miles,
S2 be the length of side 2 in miles,
and S3 be the length of side 3 in miles.
Now, the next thing to do with these variables is to set up equations that follow the word
problem. Here they are as follows:
S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides
S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than
twice the 2nd side (represented by 2*S2).
S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side.
Next, since we have more than one unknown, we should express one equation in terms of one
variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that
we express the other variable equations of S1 and S3 in terms of S2. Here's how it goes:
S1=(2*S2)-5 as S1 is already expressed in terms of S2
S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2.
=(2*S2)-5+2 I combined like terms.
=(2*S2)-3.
Now that I have expressed both S1 and S3 in terms of S2, I can plug those equations into that for
the triangle perimeter:
[(2*S2)-5]+S2+[(2*S2)-3]=47
(2*S2)-5+S2+(2*S2)-3=47 Again, I combined like terms.
(5*S2)-8=47
+8=+8 I added 8 on both sides of the equation to eliminate -8 on the left side.
5*S2=55
5*S2/5=55/5
S2=11
S1=(2*11)-5=22-5=17 Now that I have found the value of S2, I can plug it into the S1 equation.
S3=17+2=19 Now that I have found the value of S1, I can plug it into the S3 equation.
So now here are the lengths of each side of the triangle. Side 1 is 17 miles, side 2 is 11 miles, and
side 3 is 19 miles.
Solution
This word problem is about a triangle whose perimeter is 47 miles. Since it's asking to find the

2. length of each side, then there are 3 unknowns. So here's what we do:
Let the variables S1 be the length of side 1 in miles,
S2 be the length of side 2 in miles,
and S3 be the length of side 3 in miles.
Now, the next thing to do with these variables is to set up equations that follow the word
problem. Here they are as follows:
S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides
S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than
twice the 2nd side (represented by 2*S2).
S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side.
Next, since we have more than one unknown, we should express one equation in terms of one
variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that
we express the other variable equations of S1 and S3 in terms of S2. Here's how it goes:
S1=(2*S2)-5 as S1 is already expressed in terms of S2
S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2.
=(2*S2)-5+2 I combined like terms.
=(2*S2)-3.
Now that I have expressed both S1 and S3 in terms of S2, I can plug those equations into that for
the triangle perimeter:
[(2*S2)-5]+S2+[(2*S2)-3]=47
(2*S2)-5+S2+(2*S2)-3=47 Again, I combined like terms.
(5*S2)-8=47
+8=+8 I added 8 on both sides of the equation to eliminate -8 on the left side.
5*S2=55
5*S2/5=55/5
S2=11
S1=(2*11)-5=22-5=17 Now that I have found the value of S2, I can plug it into the S1 equation.
S3=17+2=19 Now that I have found the value of S1, I can plug it into the S3 equation.
So now here are the lengths of each side of the triangle. Side 1 is 17 miles, side 2 is 11 miles, and
side 3 is 19 miles.