1. Create a file name with DiffEqn.m with the following codefuncti.pdf

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1. Create a file name with DiffEqn.m with the following code function dx=DiffEqn(t,x) m=10; k=100; b=1; x1=x(1); x2=x(2); dx1=x2; dx2=(1/m)*(-k*x1-b*x2); dx=[dx1;dx2]; 2. Create another file for running the differential equation with all the given conditions. %using ode solver we can solve the given differential equation. [t,x]=ode45(@DiffEqn,[1,100],[10,0]); %plotting the final result t vs dx/dt plot(t,x(:,1)); Solution 1. Create a file name with DiffEqn.m with the following code function dx=DiffEqn(t,x) m=10; k=100; b=1; x1=x(1); x2=x(2); dx1=x2; dx2=(1/m)*(-k*x1-b*x2); dx=[dx1;dx2]; 2. Create another file for running the differential equation with all the given conditions. %using ode solver we can solve the given differential equation. [t,x]=ode45(@DiffEqn,[1,100],[10,0]); %plotting the final result t vs dx/dt plot(t,x(:,1));.

1. Create a file name with DiffEqn.m with the following code
function dx=DiffEqn(t,x)
m=10;
k=100;
b=1;
x1=x(1);
x2=x(2);
dx1=x2;
dx2=(1/m)*(-k*x1-b*x2);
dx=[dx1;dx2];
2. Create another file for running the differential equation with all the given conditions.
%using ode solver we can solve the given differential equation.
[t,x]=ode45(@DiffEqn,[1,100],[10,0]);
%plotting the final result t vs dx/dt
plot(t,x(:,1));
Solution
1. Create a file name with DiffEqn.m with the following code
function dx=DiffEqn(t,x)
m=10;
k=100;
b=1;
x1=x(1);
x2=x(2);
dx1=x2;
dx2=(1/m)*(-k*x1-b*x2);
dx=[dx1;dx2];
2. Create another file for running the differential equation with all the given conditions.
%using ode solver we can solve the given differential equation.
[t,x]=ode45(@DiffEqn,[1,100],[10,0]);

%plotting the final result t vs dx/dt
plot(t,x(:,1));

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The metal will undergo oxidation forming metal ion and releasing electron K ==============> K+ + e- HCl will dissociate into HCl =============> H+ + Cl- This H+ will get reduced to hydrogen gas by taking the electron released by the metal. H+ + e- =========> H2 (gas) Then the metal ion will combine with chloride forming metal chloride K+ + Cl- ====> Kcl The over all reaction would be K + HCl =====> Kcl + H2 [not balanced] Note: when metal react with acid, it will form metal salt releasing hydrogen gas] Solution The metal will undergo oxidation forming metal ion and releasing electron K ==============> K+ + e- HCl will dissociate into HCl =============> H+ + Cl- This H+ will get reduced to hydrogen gas by taking the electron released by the metal. H+ + e- =========> H2 (gas) Then the metal ion will combine with chloride forming metal chloride K+ + Cl- ====> Kcl The over all reaction would be K + HCl =====> Kcl + H2 [not balanced] Note: when metal react with acid, it will form metal salt releasing hydrogen gas].

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Static Keyword Static is a keyword in C++ used to give special characteristics to an element. Static elements are allocated storage only once in a program lifetime in static storage area. And they have a scope till the program lifetime. Static Keyword can be used with following, Static variable in functions Static Class Objects Static member Variable in class Static Methods in class Static variables inside Functions Static variables when used inside function are initialized only once, and then they hold there value even through function calls. These static variables are stored on static storage area , not in stack. void counter() { static int count=0; cout << count++; } int main(0 { for(int i=0;i<5;i++) { counter(); } } Output : 0 1 2 3 4 Let\'s se the same program\'s output without using static variable. void counter() { int count=0; cout << count++; } int main(0 { for(int i=0;i<5;i++) { counter(); } } Output : 0 0 0 0 0 If we do not use static keyword, the variable count, is reinitialized everytime when counter() function is called, and gets destroyed each time when counter() functions ends. But, if we make it static, once initialized count will have a scope till the end of main() function and it will carry its value through function calls too. If you don\'t initialize a static variable, they are by default initialized to zero. Static class Objects Static keyword works in the same way for class objects too. Objects declared static are allocated storage in static storage area, and have scope till the end of program. Static objects are also initialized using constructors like other normal objects. Assignment to zero, on using static keyword is only for primitive datatypes, not for user defined datatypes. class Abc { int i; public: Abc() { i=0; cout << \"constructor\"; } ~Abc() { cout << \"destructor\"; } }; void f() { static Abc obj; } int main() { int x=0; if(x==0) { f(); } cout << \"END\"; } Output : constructor END destructor You must be thinking, why was destructor not called upon the end of the scope of if condition. This is because object was static, which has scope till the program lifetime, hence destructor for this object was called when main() exits. Static data member in class Static data members of class are those members which are shared by all the objects. Static data member has a single piece of storage, and is not available as separate copy with each object, like other non- static data members. Static member variables (data members) are not initialied using constructor, because these are not dependent on object initialization. Also, it must be initialized explicitly, always outside the class. If not initialized, Linker will give error. class X { static int i; public: X(){}; }; int X::i=1; int main() { X obj; cout << obj.i; // prints value of i } Once the definition for static data member is made, user cannot redefine it. Though, arithmetic operations can be performed on it. Static Member Functions These functions work for the .

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Water is a polar inorganic solvent. Benzene is a nonpolar organic solvent. The solvents will generally dissolve solutes with similar polarity (with certain exceptions). CaCO3 - insoluble in water, insoluble in benzene CaCO3 is a polar ionic compound that is insoluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. NaNO3 - soluble in water, insoluble in benzene NaNO3 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. K2SO4 - soluble in water, insoluble in benzene K2SO4 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. Petroleum jelly - insoluble in water, soluble in benzene Petroleum jelly is a paraffin and a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene. Butane - insoluble in water, soluble in benzene Butane is a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene. Acetone - soluble in water, soluble in benzene Acetone is a polar organic compound. Thus it is soluble in both water and benzene. Solution Water is a polar inorganic solvent. Benzene is a nonpolar organic solvent. The solvents will generally dissolve solutes with similar polarity (with certain exceptions). CaCO3 - insoluble in water, insoluble in benzene CaCO3 is a polar ionic compound that is insoluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. NaNO3 - soluble in water, insoluble in benzene NaNO3 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. K2SO4 - soluble in water, insoluble in benzene K2SO4 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in nonpolar organic solvents like benzene. Petroleum jelly - insoluble in water, soluble in benzene Petroleum jelly is a paraffin and a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene. Butane - insoluble in water, soluble in benzene Butane is a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene. Acetone - soluble in water, soluble in benzene Acetone is a polar organic compound. Thus it is soluble in both water and benzene..

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Isomers which have their atoms connected in the same sequence but differ in the way the atoms are oriented in space - i.e. the difference between two stereoisomers lies only in the three dimensional arrangement of atoms. since Cis-3-hexene to trans-3-hexene differs in three dimensional arrangement of atoms and arrangement is same in 2D space , they are stereo isomers Solution Isomers which have their atoms connected in the same sequence but differ in the way the atoms are oriented in space - i.e. the difference between two stereoisomers lies only in the three dimensional arrangement of atoms. since Cis-3-hexene to trans-3-hexene differs in three dimensional arrangement of atoms and arrangement is same in 2D space , they are stereo isomers.

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1. 1. Create a file name with DiffEqn.m with the following code function dx=DiffEqn(t,x) m=10; k=100; b=1; x1=x(1); x2=x(2); dx1=x2; dx2=(1/m)*(-k*x1-b*x2); dx=[dx1;dx2]; 2. Create another file for running the differential equation with all the given conditions. %using ode solver we can solve the given differential equation. [t,x]=ode45(@DiffEqn,[1,100],[10,0]); %plotting the final result t vs dx/dt plot(t,x(:,1)); Solution 1. Create a file name with DiffEqn.m with the following code function dx=DiffEqn(t,x) m=10; k=100; b=1; x1=x(1); x2=x(2); dx1=x2; dx2=(1/m)*(-k*x1-b*x2); dx=[dx1;dx2]; 2. Create another file for running the differential equation with all the given conditions. %using ode solver we can solve the given differential equation. [t,x]=ode45(@DiffEqn,[1,100],[10,0]);

2. %plotting the final result t vs dx/dt plot(t,x(:,1));