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Compounding More than
One a Year
Lesson Outline
1. Compounding more than once a year
2. Maturity value, interest, and present value
when compound interest is computed more
than once a year.
Sometimes interest may be computed more
than once a year. Consider the following
example.
Given a principal of 10,000, which of the
following options will yield greater interest after
5 years:
A. Earn an annual interest rate of 2% at the
end of the year, or
B. Earn an annual interest rate of 2% in two
portions – 1% after 6 months, and 1% after
another 6 months?
Solution
Option A: interest is compounded annually
Time (t) in
years
Principal = 10,000
Annual interest rate = 2%, compounded annually
Amount at the end of the year
1 10,000 x 1.02 = 10,200
2 10,200 x 1.02 = 10, 404
3 10, 404 x 1.02 = 10,612.08
4 10,612.08 x 1.02 = 10,824.32
5 10,824.32 x 1.02 = 11, 040.81
Solution
Option B: interest is compounded semi-annually, or every 6
months Time (t)
in years
Principal = 10,000, Annual Interest rate = 2%, compounded
semi-annually
Amount at the end of the year
Β½ 10,000 x 1.01 = 10, 100
1 10, 100 x 1.01 = 10, 201
1 Β½ 10, 201 x 1.01 = 10, 303.01
2 10, 303.01 x 1.01 = 10,406.04
2 Β½ 10,406.04 x 1.01 = 10,510.10
3 10,510.10 x 1.01 = 10,615.20
3 Β½ 10,615.20 x 1.01 = 10,721.35
4 10,721.35 x 1.01 = 10828.56
4 Β½ 10,828.56 x 1.01 = 10,936.85
5 10,936.85 x 1.01 = 10,046.22
What option will you choose? A or B?
Option B will give the higher interest after 5 years.
If all else is equal, a more frequent compounding
will result in a higher interest, which is why Option
B gives higher interest than Option A.
The investment scheme in Option B introduces
new concepts because interest is compounded
twice a year, the conversion period is 6 months,
and the frequency of conversion is 2. As the
investment runs for 5 years, the total number of
conversion periods is 10. the nominal rate is 2%
and the rate of interest for each conversion period
is 1%. These terms are generally define in the next
slide.
Frequency of conversion (m) – number of conversion periods in
one year
Conversion or interest period – time between successive
conversions of interest
Total number of conversion periods n
n = mt = (frequency of conversion) x (time in years)
Nominal rate (β…ˆ π’Ž ) – annual rate of interest
Rate (j) of interest for each conversion period
𝑗 =
β…ˆ π‘š
π‘š
=
π‘Žπ‘›π‘›π‘’π‘Žπ‘™ π‘Ÿπ‘Žπ‘‘π‘’ π‘œπ‘“ π‘–π‘›π‘‘π‘’π‘Ÿπ‘’π‘ π‘‘
π‘“π‘Ÿπ‘’π‘žπ‘’π‘’π‘›π‘π‘¦ π‘œπ‘“ π‘π‘œπ‘›π‘£π‘’π‘Ÿπ‘ π‘–π‘œπ‘›
Definition of Terms

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Compounding More than One a Year.pptx

  • 2. Lesson Outline 1. Compounding more than once a year 2. Maturity value, interest, and present value when compound interest is computed more than once a year.
  • 3. Sometimes interest may be computed more than once a year. Consider the following example.
  • 4. Given a principal of 10,000, which of the following options will yield greater interest after 5 years: A. Earn an annual interest rate of 2% at the end of the year, or B. Earn an annual interest rate of 2% in two portions – 1% after 6 months, and 1% after another 6 months?
  • 5. Solution Option A: interest is compounded annually Time (t) in years Principal = 10,000 Annual interest rate = 2%, compounded annually Amount at the end of the year 1 10,000 x 1.02 = 10,200 2 10,200 x 1.02 = 10, 404 3 10, 404 x 1.02 = 10,612.08 4 10,612.08 x 1.02 = 10,824.32 5 10,824.32 x 1.02 = 11, 040.81
  • 6. Solution Option B: interest is compounded semi-annually, or every 6 months Time (t) in years Principal = 10,000, Annual Interest rate = 2%, compounded semi-annually Amount at the end of the year Β½ 10,000 x 1.01 = 10, 100 1 10, 100 x 1.01 = 10, 201 1 Β½ 10, 201 x 1.01 = 10, 303.01 2 10, 303.01 x 1.01 = 10,406.04 2 Β½ 10,406.04 x 1.01 = 10,510.10 3 10,510.10 x 1.01 = 10,615.20 3 Β½ 10,615.20 x 1.01 = 10,721.35 4 10,721.35 x 1.01 = 10828.56 4 Β½ 10,828.56 x 1.01 = 10,936.85 5 10,936.85 x 1.01 = 10,046.22
  • 7. What option will you choose? A or B?
  • 8. Option B will give the higher interest after 5 years. If all else is equal, a more frequent compounding will result in a higher interest, which is why Option B gives higher interest than Option A.
  • 9. The investment scheme in Option B introduces new concepts because interest is compounded twice a year, the conversion period is 6 months, and the frequency of conversion is 2. As the investment runs for 5 years, the total number of conversion periods is 10. the nominal rate is 2% and the rate of interest for each conversion period is 1%. These terms are generally define in the next slide.
  • 10. Frequency of conversion (m) – number of conversion periods in one year Conversion or interest period – time between successive conversions of interest Total number of conversion periods n n = mt = (frequency of conversion) x (time in years) Nominal rate (β…ˆ π’Ž ) – annual rate of interest Rate (j) of interest for each conversion period 𝑗 = β…ˆ π‘š π‘š = π‘Žπ‘›π‘›π‘’π‘Žπ‘™ π‘Ÿπ‘Žπ‘‘π‘’ π‘œπ‘“ π‘–π‘›π‘‘π‘’π‘Ÿπ‘’π‘ π‘‘ π‘“π‘Ÿπ‘’π‘žπ‘’π‘’π‘›π‘π‘¦ π‘œπ‘“ π‘π‘œπ‘›π‘£π‘’π‘Ÿπ‘ π‘–π‘œπ‘› Definition of Terms