Shear force and Bending moment calculations

1. RHS
2m
MA: 1o0x8)
8m
(-100x 6)
-100x 2
.= 4 800+800O
Fag ShEoN Force
RA RB 00 KN.
Shea foace Calculoh ons
LHS
f.D.S.Pa
RHS
SF JuGt lef Ho A =
0 1
C+) (-)(-) +
SE atJuS RI9ht to
point A =
A)1OoC
Left
iest tO poio C O00N FOC Bendun9 mom
SE a JuS Ri9nt 4o POInt C G100-(00)
LHS 1RHS
O1CN
91aJUS Left+0 Point D +100-100
C (- (-) +)
O lC
CE C JuS+ RN to Poihi D AIO0
ST GF JUS Left Fo Point B Olo0 t LHS RHS
B e n d i n 9 momeni ColCulatiOns BM)
BM a P A MA 00x 8 t 100x 6+ 100 2 (a)-
800 + 600 +2OG
CNM.
SMO Pt C l c
G
Prof.D
200 tNm)
+ 1O0 x 2
C+)
Clocr wise
N a
aw
(+)
Pt D D (00n2
an ctocdc
wise
-(200 Nm
S'a

2. 100 N
O0 1CN
D
2m
PA 100 t
2m
loo lN D .
rof.D SE ot Bm
+
secion
Daauw
ab ove
Befe line
SFO 100 bN
Belowhe
(00 v.
Bee lin&
Prot
200 Nm 200 laNm
3
BMD
Pawe
o

3. (3 t (6 CN
(RA)2 m (RB)
2m 2 m
SFD BMD
Sim Pl7
Suppot Beo
RA+RB 346
O calculohHons Of PeaChOnho
Bm cuea9e
RA/1RB O.
B Ct POin A O
Ma 0.
M +RD X6-6G-32
+RB6 6xu-3x2O.
6RB 24-6
RB
awa
5 CN
RA+RB 3 6
RR+5 = 36
RA G N
w a r

4. 6 tv
h
LHS
2m
RHS
DSPawa
2) Shea for Ce Calcwlah ons
2m t
C+) (-) -)
(RB:5 y
SFat juSE Ri9hB +0 Point A t9 k
SF O JUS Left 4o Point C + tr.
SF Ot JUS+ Ri9ht t0 Point C: t 4-3
SE
at JUSt 1etto PointD - 3
EN.
SE ot JUS+ R9ht fo Poin D 5 w
SF at JUSt teft +0 POint B =-5 N.
S.Pawa
Pawar
rof.D
ProfD
S

5. 6 N
3 CN
B
A
2
-2m
2m
PA-GA
+= cboue
beloO
B
(SED 5 tN 5 lcns