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Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 1 of 24
PHILIP DUTTON
UNIVERSITY OF WINDSOR
DEPARTMENT OF CHEMISTRY AND
BIOCHEMISTRY
TENTH EDITION
GENERAL CHEMISTRY
Principles and Modern Applications
PETRUCCI HERRING MADURA BISSONNETTE
Chemical
Reactions 4
Chemical Compounds
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 2 of 24
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 3 of 24
4-1 Chemical Reactions and Chemical
Equations
As reactants are converted to products we observe:
Color change
Precipitate formation
Gas evolution
Heat absorption or evolution
Chemical evidence may be necessary.
Precipitation of silver chromate
Figure 4-1
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 4 of 24
Evidence of a chemical reaction
Figure 4-2
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 5 of 24
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 6 of 24
Chemical Reactions
Nitrogen monoxide + oxygen nitrogen dioxide→
Step 1: Write the reaction using chemical symbols.
NO + O2 NO→ 2
Step 2: Balance the chemical equation.
2 1 2
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 7 of 24
Molecular Representation
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 8 of 24
Balancing Equations
Never introduce extraneous atoms to balance.
NO + O2 → NO2 + O
Never change a formula for the purpose of balancing an
equation.
NO + O2 → NO3
An equation can be balanced only by adjusting the
coefficients of formulas.
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 9 of 24
Balancing Equation Strategy
Balance elements that occur in only one compound
on each side first.
Balance free elements last.
Balance unchanged polyatomics (or other groups of
atoms) as groups.
Fractional coefficients are acceptable and can be
cleared at the end by multiplication.
States of Matter
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 10 of 24
(g) gas (l) liquid (s) solid
Thus, the equation for combustion of triethylene glycol can be
written as
2 C6H14O4(l) + 15 O2(g) 12 CO2(g) + 14 H2O(l)
Another commonly used symbol for reactants or products
dissolved in water is
(aq) aqueous solution
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 11 of 24
4-2 Chemical Equations and Stoichiometry
Stoichiometry includes all the quantitative
relationships involving:
atomic and formula masses
chemical formulas.
chemical equations
• Mole ratio or stoichiometric factor
is a central conversion factor.
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 12 of 24
KEEP IN MIND
that it is important to
include units and to work
from a balanced chemical
equation when solving
stoichiometry problems.
A generalized stoichiometry diagram
Figure 4-3
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 13 of 24
The reaction of 2 Al(s) 6 HCl(aq) 2 AlCl3(aq) 3 H2(g)
Figure 4-4
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 14 of 24
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 15 of 24
4-3 Chemical Reactions in Solution
Close contact between atoms, ions and molecules
necessary for a reaction to occur.
Solvent
We will usually use aqueous (aq) solution.
Solute
A material dissolved by the solvent.
Molarity
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 16 of 24
Molarity (M) =
Volume of solution (L)
Amount of solute (mol solute)
If 0.440 mol of urea is dissolved in enough water to make
1.000 L of solution the concentration is:
curea =
1.000 L
0.440 mol urea
= 0.440 M CO(NH2)2
C =
V
n
Solution Dilution
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 17 of 24
Figure 4-6
Visualizing the dilution of a solution
Mi × Vi = ni
Mi × Vi Mf × Vf
= nf = Mf × Vf
M =
n
V
Mi × Vi
Mf =
Vf
= Mi
Vi
Vf
Preparation of 0.250 M K2Cr2O7 —Example 4-9 illustrated
Figure 4-5
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 18 of 24
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 19 of 24
4-4 Determining Limiting Reagent
The reactant that is completely consumed
determines the quantities of the products formed.
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 20 of 24
Theoretical yield is the expected yield from a reactant.
Actual yield is the amount of product actually produced.
Percent yield = × 100%
Actual yield
Theoretical Yield
4-5 Other Practical Matters in Reaction
Stoichiometry
Theoretical, Actual and Percent Yield
Theoretical, Actual and Percent Yield
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 21 of 24
actual yield = theoretical yield
quantitative
Side reactions reduce the percent yield.
By-products are formed by side reactions.
Consecutive Reactions, Simultaneous
Reactions and Overall Reactions
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 22 of 24
Multistep synthesis is often unavoidable.
Reactions carried out in sequence are called
consecutive reactions.
When substances react independently and at the
same time the reaction is a simultaneous
reaction.
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 23 of 24
Overall Reactions and Intermediates
The Overall Reaction is a chemical equation that
expresses all the reactions occurring in a single
overall equation.
An intermediate is a substance produced in one step
and consumed in another during a multistep
synthesis.
Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 24 of 24
End of Chapter Questions
Initial problem solving is linear and often
based on memorizing solutions for particular
situations.
Answer
a
b
c

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Ch04lecture 150104200419-conversion-gate01

  • 1. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 1 of 24 PHILIP DUTTON UNIVERSITY OF WINDSOR DEPARTMENT OF CHEMISTRY AND BIOCHEMISTRY TENTH EDITION GENERAL CHEMISTRY Principles and Modern Applications PETRUCCI HERRING MADURA BISSONNETTE Chemical Reactions 4
  • 2. Chemical Compounds Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 2 of 24
  • 3. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 3 of 24 4-1 Chemical Reactions and Chemical Equations As reactants are converted to products we observe: Color change Precipitate formation Gas evolution Heat absorption or evolution Chemical evidence may be necessary.
  • 4. Precipitation of silver chromate Figure 4-1 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 4 of 24
  • 5. Evidence of a chemical reaction Figure 4-2 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 5 of 24
  • 6. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 6 of 24 Chemical Reactions Nitrogen monoxide + oxygen nitrogen dioxide→ Step 1: Write the reaction using chemical symbols. NO + O2 NO→ 2 Step 2: Balance the chemical equation. 2 1 2
  • 7. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 7 of 24 Molecular Representation
  • 8. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 8 of 24 Balancing Equations Never introduce extraneous atoms to balance. NO + O2 → NO2 + O Never change a formula for the purpose of balancing an equation. NO + O2 → NO3 An equation can be balanced only by adjusting the coefficients of formulas.
  • 9. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 9 of 24 Balancing Equation Strategy Balance elements that occur in only one compound on each side first. Balance free elements last. Balance unchanged polyatomics (or other groups of atoms) as groups. Fractional coefficients are acceptable and can be cleared at the end by multiplication.
  • 10. States of Matter Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 10 of 24 (g) gas (l) liquid (s) solid Thus, the equation for combustion of triethylene glycol can be written as 2 C6H14O4(l) + 15 O2(g) 12 CO2(g) + 14 H2O(l) Another commonly used symbol for reactants or products dissolved in water is (aq) aqueous solution
  • 11. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 11 of 24 4-2 Chemical Equations and Stoichiometry Stoichiometry includes all the quantitative relationships involving: atomic and formula masses chemical formulas. chemical equations • Mole ratio or stoichiometric factor is a central conversion factor.
  • 12. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 12 of 24 KEEP IN MIND that it is important to include units and to work from a balanced chemical equation when solving stoichiometry problems.
  • 13. A generalized stoichiometry diagram Figure 4-3 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 13 of 24
  • 14. The reaction of 2 Al(s) 6 HCl(aq) 2 AlCl3(aq) 3 H2(g) Figure 4-4 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 3Slide 14 of 24
  • 15. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 15 of 24 4-3 Chemical Reactions in Solution Close contact between atoms, ions and molecules necessary for a reaction to occur. Solvent We will usually use aqueous (aq) solution. Solute A material dissolved by the solvent.
  • 16. Molarity Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 16 of 24 Molarity (M) = Volume of solution (L) Amount of solute (mol solute) If 0.440 mol of urea is dissolved in enough water to make 1.000 L of solution the concentration is: curea = 1.000 L 0.440 mol urea = 0.440 M CO(NH2)2 C = V n
  • 17. Solution Dilution Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 17 of 24 Figure 4-6 Visualizing the dilution of a solution Mi × Vi = ni Mi × Vi Mf × Vf = nf = Mf × Vf M = n V Mi × Vi Mf = Vf = Mi Vi Vf
  • 18. Preparation of 0.250 M K2Cr2O7 —Example 4-9 illustrated Figure 4-5 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 18 of 24
  • 19. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 19 of 24 4-4 Determining Limiting Reagent The reactant that is completely consumed determines the quantities of the products formed.
  • 20. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 20 of 24 Theoretical yield is the expected yield from a reactant. Actual yield is the amount of product actually produced. Percent yield = × 100% Actual yield Theoretical Yield 4-5 Other Practical Matters in Reaction Stoichiometry Theoretical, Actual and Percent Yield
  • 21. Theoretical, Actual and Percent Yield Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 21 of 24 actual yield = theoretical yield quantitative Side reactions reduce the percent yield. By-products are formed by side reactions.
  • 22. Consecutive Reactions, Simultaneous Reactions and Overall Reactions Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 22 of 24 Multistep synthesis is often unavoidable. Reactions carried out in sequence are called consecutive reactions. When substances react independently and at the same time the reaction is a simultaneous reaction.
  • 23. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 23 of 24 Overall Reactions and Intermediates The Overall Reaction is a chemical equation that expresses all the reactions occurring in a single overall equation. An intermediate is a substance produced in one step and consumed in another during a multistep synthesis.
  • 24. Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 4Slide 24 of 24 End of Chapter Questions Initial problem solving is linear and often based on memorizing solutions for particular situations. Answer a b c

Editor's Notes

  1. In this chapter, you will learn how to deduce and write chemical formulas and how to use the information incorporated into chemical formulas. The chapter ends with an overview of the relationship between names and formulas—chemical nomenclature.
  2. Scanning electron microscope image of sodium chloride crystals. Chemical compounds, their formulas, and their names are topics discussed in this chapter.
  3. When aqueous solutions of silver nitrate and potassium chromate are mixed, the disappearance of the distinctive yellow color of chromate ion and the appearance of the red-brown solid, silver chromate, provide physical evidence of a reaction.
  4. (a) Evolution of a gas: When a copper penny reacts with nitric acid, the red-brown gas NO2 is evolved. (b) Evolution of heat: When iron gauze (steel wool) is ignited in an oxygen atmosphere, evolved heat and light provide physical evidence of a reaction.
  5. Consider the reaction of colorless nitrogen monoxide with oxygen to give brown nitrogen dioxide. The arrow represents a reaction proceeding Replace the words with chemical symbols
  6. The solution cannot be prepared just by adding 12.1 g K2Cr2O7(s) to 250.0 mL water. Instead, (a) the weighed quantity of K2Cr2O7(s) is first added to a clean, dry 250 mL volumetric flask; (b) the K2Cr2O7(s) is dissolved in less than 250 mL of water; and (c) the flask is filled to the 250.0 mL calibration mark by the careful addition (dropwise) of the remaining water.