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Today’s learning
• Mathematical description of texture
Mathematical Description of Texture
• Texture of a single phase polycrystalline material is
defined by orientation distribution function (ODF).
• ODF describes the volume fraction of crystallites having
the orientation of the crystal axis with reference to a fixed
coordinate system (RD, TD, ND)
by volume dV(g) = f(g)dg; g = g(1, , 2 )
V
by number dN(g) = f(g)dg; dg = 1 Sin  d d1 d2
N 82
• Parameters of Orientation “g”,
g = [g i j] = {1, , 2 } = {hkl}<uvw>
Orientation matrix Euler angle Crystal direction
Assumption:
• ODF can be fitted by a series expansion with suitable
mathematical functions. These functions are Spherical
Harmonic functions.
• Therefore, ODF f(g) can be completely described by
the series expansion coefficients `Cl
mn´.
• The goal is to obtain the coefficients `Cl
mn´.
• The experimental texture is measured in the form of
pole figures
• The information from pole figure must be transformed
to compute the ODF.
• The procedure of doing so is called “pole figure
inversion”. In this procedure, the pole figure is also
expressed in terms of spherical harmonic function
whose value is known for all possible orientations on
the pole figure and finally the coefficients are
calculated. This is done as follows:
In a pole figure, the position of a given
pole on the sphere is characterised in
terms of 2 angles:
(1) The rotation of the pole around
the polar axis
(2) The azimuth of the pole
azimuth of
the pole
For rolled sheet geometry,
the orientation of a cubic
crystal is defined as
= 0 for ND
= 0 for RD
Let us recall the previously learnt description of a pole figure.
How can we express pole figures mathematically?
rotation of
the pole
around the
polar axis
(100) Poles of a
cubic crystal in
the stereographic
projection
A pole which is defined by a direction y, e.g. (, ) in a given 2D pole
figure Ph(y) corresponds to a region in the 3D ODF which contains
all possible rotations with angle  about this direction y in the pole
figure. This is described by the following equation
Representation of
the fundamental
equation of pole
figure inversion in
a (100) pole figure
where, y = {, }; g = {1, , 2}
RD
TD



[001]
100
010
where Fn
l are series expansion coefficients, and
Kn
l(y) are the spherical harmonic function
• Pole figure is characterized by two angles (,). The
expansion expression for pole figure is expressed in
terms of spherical harmonic function Kl
n(y). This is
as follows:
• The two-dimensional series expansion coefficient Fn
l
and the Cl
mn coefficients are related through the
following expression
 Usually several pole figures Ph are required to calculate
the ODF.
 Lower the symmetry of crystal structure, higher
number of pole figures are required.
 For cubic crystal structure, 3-4 pole figures are
desirable
 For hexagonal crystal structure, 6 pole figures are
required
 For orthorhombic crystal structure , 7 pole figures
are a must.
 The size and shape of the Euler space depends on the
combination of specimen symmetry and crystal
symmetry.
A typical three dimensional orientation distribution
function plot appears like follows:
This Euler space is for a
hexagonal metal.
Therefore, it is not a
symmetrical. The 2
axis ranges from 0-60
degree while the other
two axes have their
range 0-90 degree. In a
cubic material, all the
three axes are 0-90
degrees, therefore the
Euler space is a perfect
cube.
• Euler space for Cubic materials with the main
orientations depicted
• It is, however, not convenient to read orientations, that
is the orientation coordinates {1, , 2}, therefore the
Euler space is sliced at certain angular intervals along
one of the axes and the slices are spread on the sheet
Goss
Brass
Cu
S
Goss
Brass
1
2

Goss
Brass
0
90
90
Courtesy: R. Madhavan
• The spread cuts look
like this figure 
• By identifying the
maxima locations in
the cut-sections, one
can obtain {1, , 2},
from which the texture
component (hkl)[uvw]
can be computed.
Courtesy: R. Madhavan
Representation of 3D ODF in 2D
Section (at some angular interval) the 3D euler space along
ϕ2 or any of ϕ1, ϕ , ϕ2
In the representation the Euler space is sectioned along ϕ2 and
most relevant sections are displayed
ϕ1
ϕ
Φ2=0º Φ2=45º Φ2=65º
Cu
{112}<111>
Bs
{110}<211>
S
{123}<634>
Bs
{110}<211>
• Standard charts are available with (hkl)[uvw] computed for
various ({1, , 2}
• By matching the position of maxima with the corresponding
location in the chart, it is possible to identify the texture
component (hkl)[uvw]
The ODF section 2 = 45
The orientation of crystallites
represented in the given ODF section
• By this way, it is easier to visualize the crystallite
orientation as follows.

1



1
Courtesy: R.K. Ray
1. How it is different to represent the orientations in ODF than in a pole
figure?
2. How to calculate ODFs?
3. What all the advantages to plot ODF for the orientations?
4. Plot a representative fibre in ODF.
5. How to represent 3D ODF in 2D?
Questions

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p.pdf

  • 1. Today’s learning • Mathematical description of texture
  • 2. Mathematical Description of Texture • Texture of a single phase polycrystalline material is defined by orientation distribution function (ODF). • ODF describes the volume fraction of crystallites having the orientation of the crystal axis with reference to a fixed coordinate system (RD, TD, ND) by volume dV(g) = f(g)dg; g = g(1, , 2 ) V by number dN(g) = f(g)dg; dg = 1 Sin  d d1 d2 N 82 • Parameters of Orientation “g”, g = [g i j] = {1, , 2 } = {hkl}<uvw> Orientation matrix Euler angle Crystal direction
  • 3. Assumption: • ODF can be fitted by a series expansion with suitable mathematical functions. These functions are Spherical Harmonic functions.
  • 4. • Therefore, ODF f(g) can be completely described by the series expansion coefficients `Cl mn´. • The goal is to obtain the coefficients `Cl mn´. • The experimental texture is measured in the form of pole figures • The information from pole figure must be transformed to compute the ODF. • The procedure of doing so is called “pole figure inversion”. In this procedure, the pole figure is also expressed in terms of spherical harmonic function whose value is known for all possible orientations on the pole figure and finally the coefficients are calculated. This is done as follows:
  • 5. In a pole figure, the position of a given pole on the sphere is characterised in terms of 2 angles: (1) The rotation of the pole around the polar axis (2) The azimuth of the pole azimuth of the pole For rolled sheet geometry, the orientation of a cubic crystal is defined as = 0 for ND = 0 for RD Let us recall the previously learnt description of a pole figure. How can we express pole figures mathematically? rotation of the pole around the polar axis (100) Poles of a cubic crystal in the stereographic projection
  • 6. A pole which is defined by a direction y, e.g. (, ) in a given 2D pole figure Ph(y) corresponds to a region in the 3D ODF which contains all possible rotations with angle  about this direction y in the pole figure. This is described by the following equation Representation of the fundamental equation of pole figure inversion in a (100) pole figure where, y = {, }; g = {1, , 2} RD TD    [001] 100 010
  • 7. where Fn l are series expansion coefficients, and Kn l(y) are the spherical harmonic function • Pole figure is characterized by two angles (,). The expansion expression for pole figure is expressed in terms of spherical harmonic function Kl n(y). This is as follows: • The two-dimensional series expansion coefficient Fn l and the Cl mn coefficients are related through the following expression
  • 8.  Usually several pole figures Ph are required to calculate the ODF.  Lower the symmetry of crystal structure, higher number of pole figures are required.  For cubic crystal structure, 3-4 pole figures are desirable  For hexagonal crystal structure, 6 pole figures are required  For orthorhombic crystal structure , 7 pole figures are a must.  The size and shape of the Euler space depends on the combination of specimen symmetry and crystal symmetry.
  • 9. A typical three dimensional orientation distribution function plot appears like follows: This Euler space is for a hexagonal metal. Therefore, it is not a symmetrical. The 2 axis ranges from 0-60 degree while the other two axes have their range 0-90 degree. In a cubic material, all the three axes are 0-90 degrees, therefore the Euler space is a perfect cube.
  • 10. • Euler space for Cubic materials with the main orientations depicted • It is, however, not convenient to read orientations, that is the orientation coordinates {1, , 2}, therefore the Euler space is sliced at certain angular intervals along one of the axes and the slices are spread on the sheet Goss Brass Cu S Goss Brass 1 2  Goss Brass 0 90 90 Courtesy: R. Madhavan
  • 11. • The spread cuts look like this figure  • By identifying the maxima locations in the cut-sections, one can obtain {1, , 2}, from which the texture component (hkl)[uvw] can be computed. Courtesy: R. Madhavan
  • 12. Representation of 3D ODF in 2D Section (at some angular interval) the 3D euler space along ϕ2 or any of ϕ1, ϕ , ϕ2 In the representation the Euler space is sectioned along ϕ2 and most relevant sections are displayed ϕ1 ϕ Φ2=0º Φ2=45º Φ2=65º Cu {112}<111> Bs {110}<211> S {123}<634> Bs {110}<211>
  • 13. • Standard charts are available with (hkl)[uvw] computed for various ({1, , 2} • By matching the position of maxima with the corresponding location in the chart, it is possible to identify the texture component (hkl)[uvw]
  • 14. The ODF section 2 = 45 The orientation of crystallites represented in the given ODF section • By this way, it is easier to visualize the crystallite orientation as follows.  1    1 Courtesy: R.K. Ray
  • 15. 1. How it is different to represent the orientations in ODF than in a pole figure? 2. How to calculate ODFs? 3. What all the advantages to plot ODF for the orientations? 4. Plot a representative fibre in ODF. 5. How to represent 3D ODF in 2D? Questions