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Hukum Aljabar Untuk
Ekspresi Reguler
oleh kelompok 1
2022
Anggota Kelompok
1. Azzah Shaffiyah (2065061001)
2. Beltra Saura Rahmadan (2015061029)
3. Muhamad Ferdian Hidayat (2015061030)
4. Muhammad Rizky Rifaldi (2055061002)
5. Rahmad Romadhoni (2015061033)
6. Zaki Taufiqurrachman (2015061034)
• Sebuah bahasa dinyatakan
memiliki ekspresi regular jika
terdapat Finite State Automata
(FSA) yang dapat menerimanya.
Ekspresi Reguler
• Bahasa-bahasa yang diterima
oleh FSA bisa dinyatakan secara
sederhana dengan ekspresi
regular (regular expression).
bisa tidak muncul,
bisa juga muncul
berhingga kali
ER : ab*cc, 010*, a*d
berarti minimal
muncul satu kali
ER : a⁺d
union
ER : a * ∪b * , (a ∪b) *,01 * + 0
konkatenansi
Biasanya tanpa ditulis
titiknya, misal ab, berarti
sama dengan a.b
Notasi Reguler
* + + U
atau .(titik)
Sifat Komutatif
dan Asosiatif
Identitas dan
Anihilator
Hukum
Distributif
01
03
Hukum Aljabar Ekspresi Reguler
Hukum
Idempoten
04
02
01. Sifat Komutatif
dan Asosiatif
• Sifat Komutatif
Dapat membalik urutan operand-operand nya
dan tetap memperoleh hasil akhir yang sama.
Memungkinkan kita untuk mengelompokkan
operand nya Ketika operator dikenakan dua kali.
• Sifat Asosiatif
Sifat Komutatif & Asosiatif
yang berlaku pada ER
1) A + B = B + A
Hukum ini (hukum komutatif untuk gabungan) menyatakan
bahwa kita dapat melakukan gabungan dua bahasa
tersebut, baik dengan urutan seperti di sebelah kiri ‘=‘
maupun seperti di sebelah kanan ‘=‘
2) (A + B ) + C = A + ( B + C )
Hukum ini (hukum asosiatif untuk gabungan) menyatakan bahwa kita dapat
melakukan gabungan pada tiga bahasa, baik dengan mengambil gabungan dua
bahasa pertama terlebih dahulu maupun dengan mengambil gabungan dau
bahasa terakhir.
3) ( AB ) C = A ( BC )
Hukum ini ( hukum asosiatif untuk penyambungan/concatenation) menyatakan
bahwa kita dapat merenteng tuga bahasa dengan menyambung dua bahasa
pertama terlebih dahulu atau dua bahasa terakhir terlebih dahulu.
Hukum : AB = BA tidak berlaku dalam ekspresi regular
Contoh : ekspresi regular 01 dan 10
Ekspresi tersebut berturut-turut melambangkan bahasa {01} dan {10}.
Ekspresi 0 untuk A dan 1 untuk B tidak dapat disubstitusi.
Karena bahasanya berbeda, aka hukum AB = BA tidak berlaku.
02. Identidas dan Anihilator
a) Identitas suatu operator
Nilai yang sedemikian sehingga Ketika dikenakan pada identitas dan suatu
nilai lain, maka hasilnya nilai lain lagi.
Contoh :
0 adalah identitas untuk penjumlahan, karena
0 + ꭓ = ꭓ + 0 = ꭓ
1 adalah identitas untuk perkalian, karena
1 x ꭓ = ꭓ x 1 = ꭓ
b) Anihilator untuk suatu operator
Nilai yang sedemikian sehingga Ketika operator tersebut dikenakan pada
annihilator dan suatu nilai lain, hasilnya adalah annihilator.
Contoh :
0 adalah annihilator untuk perkalian, karena
0 x ꭓ = ꭓ x 0 = 0
Hukum identitas dan annihilator
yang berlaku pada ER
1) θ + L = L + θ = L
Hukum ini menegaskan bahwa θ adalah identitas untuk
operasi gabungan.
2) ϵ L = L ϵ = L
Hukum ini menegaskan bahwa ϵ adalah identitas untuk
operasi concatenation.
3) θ L = L θ = θ
Hukum ini menegaskan bahwa θ adalah annihilator untuk
operasi concatenation.
03. Hukum Distributif
Hukum distributive melibatkan dua operator, dan menyatakan
bahwa salah satu operator dapat dipaksa untuk dikenakan pada
tiap-tiap argument operator lain secara individual.
Contoh :
Hukum distributive perkalian atas penjumlahan
ꭓ x ( y + z ) = ( ꭓ x y ) + ( ꭓ x z )
Hukum distributive yang
berlaku pada ER
1) A ( M + N ) = AM + AN
Hukum ini adalah hukum distributive kiri
concatenation terhadap gabungan (union).
2) ( M + N ) A = MA + NA
Hukum ini adalah hukum distributive kanan
concatenation terhadap gabungan (union).
Gabungan dan irisan adalah contoh sederhana
operator idempotent.
04. Hukum Idempoten
Suatu Operator dikatakan idempotent jika hasil
penerapannya pada dua nilai yang sama sebagai
argument adalah nilai itu sendiri.
Operator aritmatika biasa tidak bersifat idempotent ;
ꭓ + ꭓ ≠ ꭓ dan ꭓ x ꭓ ≠ ꭓ
Gabungan dan irisan adalah contoh sederhana
operator idempotent.
Hukum idempotent yang
berlaku pada ER
1) L + L = L
Hukum ini (hukum idempoten untuk gabungan)
menyatakan bahwa jika kita mengambil
gabungan dari dua ekspresi yang identic, kita
dapat mengganti keduanya dengan satu Salinan
ekspresi tersebut.
Contoh Soal
1. Diberikan ekspresi regular 0 + 01*.
Penyelesaian :
Ekspresi tersebut dapat disederhanakan menggunakan hukum-hukum
aljabar dalam ekspresi regular:
0 + 01*
= 0ε + 01* dari (2b)
= 0(ε + 1*) dari (3a), distributif kiri
= 01* karena ε + R = R
Contoh Soal
2. (L + M )* = (L*M*)*
Penyelesaian :
 Untuk menunjukkan kesamaan tersebut, ganti variabel L dan M berturut-turut
dengan symbol a dan b, sehingga diperoleh ekspresi regular (a+b)* dan (a*b*)*.
 Kedua ekspresi regular tersebut menyatakan bahasa dengan semua string dari a
dan b.
 Dengan demikian, kesamaan (L + M )* = (L*M*)* benar.
Contoh Soal
3. L* = L*L*
Penyelesaian :
 Untuk menunjukkan kesamaan tersebut, ganti
variabel L dengan simbol a, sehingga diperoleh
ekspresi regular a* dan a*a*.
 Kedua ekspresi regular tersebut menyatakan
bahasa dengan semua string dari a.
 Dengan demikian, kesamaan L* =L*L* benar.
Contoh Soal
4. L + ML = (L + M)L
Penyelesaian :
 Untuk menunjukkan kesamaan tersebut, ganti
variabel L dan M berturut-turut dengan simbol a
dan b, sehingga diperoleh ekspresi regular a+ba
dan (a+b)a.
 Kedua ekspresi regular tersebut menyatakan
Bahasa yang berbeda.
 Untuk menunjukkan hal tersebut, pilih aa dalam
bahasa dari ekspresi regular (a+b)a, tapi tidak
dalam bahasa dari ekspresi regular a+ba.
 Dengan demikian, kesamaan L + ML = (L + M)L
salah
Contoh Soal
Thank
You
Some percentages
40%
Saturn
Saturn is a gas giant and
has several rings
60%
Venus
Venus is the second
planet from the Sun
A picture is
worth a
thousand
words
Some percentages
Mercury
It’s the smallest planet
of them all
Venus
Venus is the second
planet from the Sun
Jupiter
Jupiter is the biggest
planet of them all
Saturn
It’s composed of
hydrogen and helium
Mars
Mars is actually a very
cold place
Neptune
It’s the farthest planet
from the Sun
Algebraic expressions
Algebraic operations
Venus
Venus is the second
planet from the Sun
Jupiter
Jupiter is the biggest
planet of them all
Mars
Despite being red,
Mars is a cold place
Saturn
Saturn is a gas giant
and has several rings
A picture always
reinforces the
concept
Images reveal large amounts of data, so
remember: use an image instead of a long text.
Your audience will appreciate it
This is a map
Latin America
Venus has a beautiful name
and is the second planet
from the Sun
Europe
Despite being red, Mars is
actually a cold place. It’s full
of iron oxide dust
Steps to tackle equations
01
Read
problem
Venus is the
second planet
from the Sun
02
Identify
unknown
Jupiter is the
biggest planet of
them all
03
Approach
equation
Despite being
red, Mars is a
cold place
04
Solve
equation
Saturn is a gas
giant and has
several rings
05
Answer
question
Mercury is the
smallest planet of
them all
X - 5 = 3
Example of an equation
Unknown
Jupiter is the biggest
planet of them all
First member
Saturn is composed of
hydrogen and helium
Second member
Neptune is very far away
from Earth
Activities
● A number increased by 8 equals 22. What number is it? --
● Maria's age increased by 7 equals 15. How old is Maria? --
● Double a number equals 46. Find that number --
● If half of Marta's age is equal to 10, how old is Marta? --
● The triple of a number decreased by 1 is equal to 20. Find that number --
Do these exercises
Solve: Result
7 x 4 --
6 x 8 --
3 x 9 --
5 x 5 --
4 x 8 --
Solve: Result
3 x 6 --
2 x 8 --
9 x 2 --
7 x 9 --
2 x 6 --
Practical exercise
Exercise A
Venus has a beautiful
name and is the second
planet from the Sun
Exercise B
Despite being red, Mars
is actually a cold place.
It’s full of iron oxide dust
Result
--
Result
--
Interpretation exercise
Interpret a multiplication equation as a comparison, for example:
35 = 5 × 7 35 is 5 times as
many as 7
7 times as many
as 5
Comparison A
Despite being red, Mars is
a very cold place
Comparison B
Saturn is a gas giant and
has several rings
Interpret
Neptune is the farthest
planet from the Sun
Multiples
Observe and match:
Multiples of 5
Multiples of 9
Multiples of 6
Multiples of 8
Multiples of 7
Multiples of 4
12, 18, 24, 30
16, 24, 32, 40
15, 20, 25, 30
18, 27, 36,45
14, 28, 35, 42
28, 36, 40, 44
Important concepts
Factors
Jupiter is the biggest
planet of them all
Hexagons
Saturn is a gas giant
and has several rings
Equality
Neptune is very far
away from us
Logarithm
Ceres is located in
the asteroid belt
Binomial
Mercury is the
smallest planet
Cube
Venus is the second
planet from the Sun
Digit
Mars is actually a
very cold place
Exponent
Earth is the planet
where we live on
Desktop
software
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Assignment 1_Kelompok 1_2.pptx

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Assignment 1_Kelompok 1_2.pptx

  • 1. Hukum Aljabar Untuk Ekspresi Reguler oleh kelompok 1 2022
  • 2. Anggota Kelompok 1. Azzah Shaffiyah (2065061001) 2. Beltra Saura Rahmadan (2015061029) 3. Muhamad Ferdian Hidayat (2015061030) 4. Muhammad Rizky Rifaldi (2055061002) 5. Rahmad Romadhoni (2015061033) 6. Zaki Taufiqurrachman (2015061034)
  • 3. • Sebuah bahasa dinyatakan memiliki ekspresi regular jika terdapat Finite State Automata (FSA) yang dapat menerimanya. Ekspresi Reguler • Bahasa-bahasa yang diterima oleh FSA bisa dinyatakan secara sederhana dengan ekspresi regular (regular expression).
  • 4. bisa tidak muncul, bisa juga muncul berhingga kali ER : ab*cc, 010*, a*d berarti minimal muncul satu kali ER : a⁺d union ER : a * ∪b * , (a ∪b) *,01 * + 0 konkatenansi Biasanya tanpa ditulis titiknya, misal ab, berarti sama dengan a.b Notasi Reguler * + + U atau .(titik)
  • 5. Sifat Komutatif dan Asosiatif Identitas dan Anihilator Hukum Distributif 01 03 Hukum Aljabar Ekspresi Reguler Hukum Idempoten 04 02
  • 6. 01. Sifat Komutatif dan Asosiatif • Sifat Komutatif Dapat membalik urutan operand-operand nya dan tetap memperoleh hasil akhir yang sama. Memungkinkan kita untuk mengelompokkan operand nya Ketika operator dikenakan dua kali. • Sifat Asosiatif
  • 7. Sifat Komutatif & Asosiatif yang berlaku pada ER 1) A + B = B + A Hukum ini (hukum komutatif untuk gabungan) menyatakan bahwa kita dapat melakukan gabungan dua bahasa tersebut, baik dengan urutan seperti di sebelah kiri ‘=‘ maupun seperti di sebelah kanan ‘=‘
  • 8. 2) (A + B ) + C = A + ( B + C ) Hukum ini (hukum asosiatif untuk gabungan) menyatakan bahwa kita dapat melakukan gabungan pada tiga bahasa, baik dengan mengambil gabungan dua bahasa pertama terlebih dahulu maupun dengan mengambil gabungan dau bahasa terakhir. 3) ( AB ) C = A ( BC ) Hukum ini ( hukum asosiatif untuk penyambungan/concatenation) menyatakan bahwa kita dapat merenteng tuga bahasa dengan menyambung dua bahasa pertama terlebih dahulu atau dua bahasa terakhir terlebih dahulu.
  • 9. Hukum : AB = BA tidak berlaku dalam ekspresi regular Contoh : ekspresi regular 01 dan 10 Ekspresi tersebut berturut-turut melambangkan bahasa {01} dan {10}. Ekspresi 0 untuk A dan 1 untuk B tidak dapat disubstitusi. Karena bahasanya berbeda, aka hukum AB = BA tidak berlaku.
  • 10. 02. Identidas dan Anihilator a) Identitas suatu operator Nilai yang sedemikian sehingga Ketika dikenakan pada identitas dan suatu nilai lain, maka hasilnya nilai lain lagi. Contoh : 0 adalah identitas untuk penjumlahan, karena 0 + ꭓ = ꭓ + 0 = ꭓ 1 adalah identitas untuk perkalian, karena 1 x ꭓ = ꭓ x 1 = ꭓ
  • 11. b) Anihilator untuk suatu operator Nilai yang sedemikian sehingga Ketika operator tersebut dikenakan pada annihilator dan suatu nilai lain, hasilnya adalah annihilator. Contoh : 0 adalah annihilator untuk perkalian, karena 0 x ꭓ = ꭓ x 0 = 0
  • 12. Hukum identitas dan annihilator yang berlaku pada ER 1) θ + L = L + θ = L Hukum ini menegaskan bahwa θ adalah identitas untuk operasi gabungan. 2) ϵ L = L ϵ = L Hukum ini menegaskan bahwa ϵ adalah identitas untuk operasi concatenation. 3) θ L = L θ = θ Hukum ini menegaskan bahwa θ adalah annihilator untuk operasi concatenation.
  • 13. 03. Hukum Distributif Hukum distributive melibatkan dua operator, dan menyatakan bahwa salah satu operator dapat dipaksa untuk dikenakan pada tiap-tiap argument operator lain secara individual. Contoh : Hukum distributive perkalian atas penjumlahan ꭓ x ( y + z ) = ( ꭓ x y ) + ( ꭓ x z )
  • 14. Hukum distributive yang berlaku pada ER 1) A ( M + N ) = AM + AN Hukum ini adalah hukum distributive kiri concatenation terhadap gabungan (union). 2) ( M + N ) A = MA + NA Hukum ini adalah hukum distributive kanan concatenation terhadap gabungan (union). Gabungan dan irisan adalah contoh sederhana operator idempotent.
  • 15. 04. Hukum Idempoten Suatu Operator dikatakan idempotent jika hasil penerapannya pada dua nilai yang sama sebagai argument adalah nilai itu sendiri. Operator aritmatika biasa tidak bersifat idempotent ; ꭓ + ꭓ ≠ ꭓ dan ꭓ x ꭓ ≠ ꭓ Gabungan dan irisan adalah contoh sederhana operator idempotent.
  • 16. Hukum idempotent yang berlaku pada ER 1) L + L = L Hukum ini (hukum idempoten untuk gabungan) menyatakan bahwa jika kita mengambil gabungan dari dua ekspresi yang identic, kita dapat mengganti keduanya dengan satu Salinan ekspresi tersebut.
  • 17. Contoh Soal 1. Diberikan ekspresi regular 0 + 01*. Penyelesaian : Ekspresi tersebut dapat disederhanakan menggunakan hukum-hukum aljabar dalam ekspresi regular: 0 + 01* = 0ε + 01* dari (2b) = 0(ε + 1*) dari (3a), distributif kiri = 01* karena ε + R = R
  • 18. Contoh Soal 2. (L + M )* = (L*M*)* Penyelesaian :  Untuk menunjukkan kesamaan tersebut, ganti variabel L dan M berturut-turut dengan symbol a dan b, sehingga diperoleh ekspresi regular (a+b)* dan (a*b*)*.  Kedua ekspresi regular tersebut menyatakan bahasa dengan semua string dari a dan b.  Dengan demikian, kesamaan (L + M )* = (L*M*)* benar.
  • 19. Contoh Soal 3. L* = L*L* Penyelesaian :  Untuk menunjukkan kesamaan tersebut, ganti variabel L dengan simbol a, sehingga diperoleh ekspresi regular a* dan a*a*.  Kedua ekspresi regular tersebut menyatakan bahasa dengan semua string dari a.  Dengan demikian, kesamaan L* =L*L* benar.
  • 20. Contoh Soal 4. L + ML = (L + M)L Penyelesaian :  Untuk menunjukkan kesamaan tersebut, ganti variabel L dan M berturut-turut dengan simbol a dan b, sehingga diperoleh ekspresi regular a+ba dan (a+b)a.  Kedua ekspresi regular tersebut menyatakan Bahasa yang berbeda.  Untuk menunjukkan hal tersebut, pilih aa dalam bahasa dari ekspresi regular (a+b)a, tapi tidak dalam bahasa dari ekspresi regular a+ba.  Dengan demikian, kesamaan L + ML = (L + M)L salah
  • 23. Some percentages 40% Saturn Saturn is a gas giant and has several rings 60% Venus Venus is the second planet from the Sun
  • 24. A picture is worth a thousand words Some percentages
  • 25. Mercury It’s the smallest planet of them all Venus Venus is the second planet from the Sun Jupiter Jupiter is the biggest planet of them all Saturn It’s composed of hydrogen and helium Mars Mars is actually a very cold place Neptune It’s the farthest planet from the Sun Algebraic expressions
  • 26. Algebraic operations Venus Venus is the second planet from the Sun Jupiter Jupiter is the biggest planet of them all Mars Despite being red, Mars is a cold place Saturn Saturn is a gas giant and has several rings
  • 27. A picture always reinforces the concept Images reveal large amounts of data, so remember: use an image instead of a long text. Your audience will appreciate it
  • 28. This is a map Latin America Venus has a beautiful name and is the second planet from the Sun Europe Despite being red, Mars is actually a cold place. It’s full of iron oxide dust
  • 29. Steps to tackle equations 01 Read problem Venus is the second planet from the Sun 02 Identify unknown Jupiter is the biggest planet of them all 03 Approach equation Despite being red, Mars is a cold place 04 Solve equation Saturn is a gas giant and has several rings 05 Answer question Mercury is the smallest planet of them all
  • 30. X - 5 = 3 Example of an equation Unknown Jupiter is the biggest planet of them all First member Saturn is composed of hydrogen and helium Second member Neptune is very far away from Earth
  • 31. Activities ● A number increased by 8 equals 22. What number is it? -- ● Maria's age increased by 7 equals 15. How old is Maria? -- ● Double a number equals 46. Find that number -- ● If half of Marta's age is equal to 10, how old is Marta? -- ● The triple of a number decreased by 1 is equal to 20. Find that number --
  • 32. Do these exercises Solve: Result 7 x 4 -- 6 x 8 -- 3 x 9 -- 5 x 5 -- 4 x 8 -- Solve: Result 3 x 6 -- 2 x 8 -- 9 x 2 -- 7 x 9 -- 2 x 6 --
  • 33. Practical exercise Exercise A Venus has a beautiful name and is the second planet from the Sun Exercise B Despite being red, Mars is actually a cold place. It’s full of iron oxide dust Result -- Result --
  • 34. Interpretation exercise Interpret a multiplication equation as a comparison, for example: 35 = 5 × 7 35 is 5 times as many as 7 7 times as many as 5 Comparison A Despite being red, Mars is a very cold place Comparison B Saturn is a gas giant and has several rings Interpret Neptune is the farthest planet from the Sun
  • 35. Multiples Observe and match: Multiples of 5 Multiples of 9 Multiples of 6 Multiples of 8 Multiples of 7 Multiples of 4 12, 18, 24, 30 16, 24, 32, 40 15, 20, 25, 30 18, 27, 36,45 14, 28, 35, 42 28, 36, 40, 44
  • 36. Important concepts Factors Jupiter is the biggest planet of them all Hexagons Saturn is a gas giant and has several rings Equality Neptune is very far away from us Logarithm Ceres is located in the asteroid belt Binomial Mercury is the smallest planet Cube Venus is the second planet from the Sun Digit Mars is actually a very cold place Exponent Earth is the planet where we live on
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