Logarithm for class IX and X. it is very difficult question.

1. 1) In log Multiply change into Addition
2) In log Divide change into subtraction
3) In log we never find power
4) Characteristics = value – 1
5) log 1 = 0
6) log 10 = 1
Key point of logarithm
LOGARITHM

2. EXERCISE 3.6
 Find the value of the following by using logarithms:

3. EXERCISE 3.6
 Find the value of the following by using logarithms:

4. EXERCISE 3.6
 Find the value of the following by using logarithms:

7. EXERCISE 3.6
 Find the value of the following by using logarithms:

8. Mean Difference
Mentissa

9. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8)

11. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)

12. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)
2 (1.9355) + (1.5725) – (2.7716)

13. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)
2 (1.9355) + (1.5725) – (2.7716)
3.871 + 1.5725 – 2.7716

14. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)
2 (1.9355) + (1.5725) – (2.7716)
3.871 + 1.5725 – 2.7716
5.4435 – 2.7716

15. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)
2 (1.9355) + (1.5725) – (2.7716)
3.871 + 1.5725 – 2.7716
5.4435 – 2.7716
2.6719
For Antilog
.6719

16. Mentissa
Mean Difference

17. EXERCISE 3.6
 Find the value of the following by using logarithms:
2 (1.9355 + 0) + (1.5717 + 8) – (2.7716 + 0)
2 (1.9355) + (1.5725) – (2.7716)
3.871 + 1.5725 – 2.7716
5.4435 – 2.7716
2.6719
For Antilog
.6719
4688 + 10
469.8 answer