The document discusses the design of machine elements. It covers factors governing design, general design procedures, stresses in bolts, nuts and keys, and design of cylinder cover bolts. Key points covered include:
1) The factors governing machine element design include strength, cost, reliability, shape, size, friction, corrosion and more.
2) General design procedures include identifying needs, analyzing forces, selecting materials, determining sizes, and producing detailed drawings.
3) Stresses in bolted connections from initial tightening, external loads, and combined loads are analyzed. Formulas to calculate bolt sizes based on allowable stresses are presented.
4) The design of cylinder cover bolts involves calculating the pitch
IMPLICATIONS OF THE ABOVE HOLISTIC UNDERSTANDING OF HARMONY ON PROFESSIONAL E...
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Machine Design Elements Guide
1. COURSE CODE : 5021
MODULE-1
DESIGN OF MACHINE ELEMENTS
1
2. 1.1.0 Understand the factors governing the Design of Machine elements
1.1.1 List the factors governing the design
1.1.2 Define the general procedure for design
1.1.3 Illustrate the methods of design ā analytical and empirical
1.1.4 Explain design stress, working stress and factor of safety
1.2.0 Design of Bolts, Nuts and Keys using analytical and empirical methods
1.2.1 Define the important terms used in screw threads
1.2.2 List the standard dimensions of screw threads and empirical formulae
1.2.3 Explain the designation of screw threads
1.2.4 Identify the stresses due to static loading, initial stresses and stresses due to
external forces, stresses due to combined forces
1.2.5 Estimate the size of the screw from above stresses
1.2.6 Design cylinder covers
1.2.7 Simple problems related to design of cylinder covers
1.2.8 Explain the bolts of uniform strength
EXPECTEDOUTCOMES
2
3. 1.2.9 Classify the various types of keys
1.2.10 Determine the proportions of sunk key
1.2.11 Calculate the strength of rectangular sunk key and square sunk key
1.2.12 Select the key size using empirical proportions, simple problems
1.3.0 Analyze the working efficiencyof screw jack
1.3.1 Determine the effort, torque required and efficiencyof a square threaded
screw jack with collar and without collar fiction
1.3.2 Calculate the maximum efficiencyof a square threaded screw
1.3.3 Describe overhauling and self locking
1.3.4 Calculate the efficiency of self locking screw jack
EXPECTEDOUTCOMES
3
4. 4
TEXT BOOKS
1.A text book of Machine Design - R.S. Khurmi and J.K. Gupta
2.A text book of Theory of Machines- R.S. Khurmi and J.K. Gupta
3.A text book of Strengthof Materials- Dr. R.K. Bansal
REFERENCE
1.A Text book of Automobile Engineering - T.R. Bangerand Nathu Singh
2.Machine Design - Dr. Sadhu Singh.
3.Design of Machine elements M.R.Thomas.
TEXT BOOKS AS PER SYLLABUS
5. 5
INTRODUCTION
Machineis a mechanical device consistingof interrelatedparts thatmodifies force or
motionin order to perform useful work by consuming some form of energy . The
interrelatedpartsare called machine elements.
Design of machine element is the process of determining the size, shape and material of
machine elements by consideringthe forces and motions experienced by the elements.
6. 6
The machine design may be classified as follows :
1. Adaptivedesign.
ā¢Adaptationof existingdesigns.
ā¢The designer only makes minor modification in the existingdesigns.
ā¢Ordinarytechnical trainingis sufficient . No special knowledge or skill needed
2.Developmentdesign.
ā¢Modifythe existing designs into a new idea by adoptinga new material or different
methodof manufacture.
ā¢Startsfromthe existingdesign, but the final productmay differ from the original
product.
ā¢Needs considerable scientifictraining and design ability
3.New design.
ā¢ Needs lot of research,technicalability and creative thinking.
ā¢The designs, depending upon the methods used, may be classified as follows :
(a) Rational design - Depends upon mathematicalformulae of principle of mechanics.
(b) Empirical design - Depends upon empirical formulae based on past experience.
TYPES OF MACHINE DESIGN
9. 9
DESIGN STRESS, WORKING STRESS AND FACTOR OF SAFETY
DesignStress
It is the maximum stressto which the componentis designed. That is it is the stress used in
mathematicalcalculationof the required size of the component.
WorkingStress
It is the stress actually developed in the component under working condition.
Factorof Safety
Itis the ratio of the ultimate stress to the design stress.
11. 11
Major (nominal)diameter
This is the largestdiameter of a screw thread, touchingthe crestson an external thread or
the rootsof an internal thread.
Minor(core) diameter
This is the smallest diameter of a screw thread, touchingthe roots or core of an external
thread(root or core diameter) thread (root or core diameter) or the crests of an internal
thread.
Pitchdiameter
This is the diameter of an imaginary cylinder, passing throughthe threads at the points
where the thread width is equal to the space between the threads.
Pitch
Itis the distancemeasured parallel to the axis, between correspondingpointson adjacent
screwthreads.
IMPORTANT TERMS USED IN SCREW THREADS cont...
12. 12
Lead
Itis the distancea screw advancesaxially in one turn.
Flank
Flankis the straightportion of the surface, on either side of the screw thread.
Crest
Itis the peak edge of a screw thread, that connectsthe adjacentflanks at the top.
Root
Itis the bottomedge of the thread that connectsthe adjacentflanks at the bottom.
Threadangle
This is the angle included between the flanks of the thread, measured in an axial plane.
IMPORTANT TERMS USED IN SCREW THREADS cont...
13. 13
FORMS OF SCREW THREADS
BritishStandard Whitworth(B.S.W.) thread
This type of thread has V-form and thread
angle of 55Ā°.The crest and roots are rounded
of to avoid sharp cornerswhich reduces
stressconcentration. Thistypeof thread is
used for general engineering purpose
Britishassociation(B.A.) thread
This type of thread has V-form and thread
angle of 47.5Ā°.The crest and roots are rounded
of to avoid sharp cornerswhich reduces stress
concentration.Thistype of thread is used for
precisionwork such as in electrical fittingsand
instruments.
14. 14
FORMS OF SCREW THREADS cont...
Americannationalstandardthread
This thread is also known as Sellerās thread. It
is similar to V thread and has flat crestsand
roots.It has thread angle of 60Ā°.The flat crest
canwithstandmore rough usage than sharp V-
threads.These threadsare used for general
purposese.g. on bolts, nuts,screws and
tappedholes.
ISOMetricthread
This thread is also known as Unified national
threador Unified thread.It has a V form and
threadangle of 60Ā°.It has flat crestsand
curved roots.The flat crest can withstandmore
roughusage. These threads are used for
generalpurposes.
15. 15
FORMS OF SCREW THREADS cont...
Squarethread
This thread has a square form This type of
threadsare used in machine tools and screw
jacketc.
Acmethread
This thread is a modificationof square thread
and has thread angle of 29Ā°.These threads are
strongerthansquare threads and used in
power transmission.These threadsare used in
lead screw of lathe.
16. 16
Buttressthread
Itis used for transmissionof power in one
directiononly. This thread units the advantage
of both square and V-threads.It has a low
frictionalresistancecharacteristicsofthe
squarethread and have the same strengthas
thatof V-thread.The spindles of bench vices
are usually provided with buttressthread..
FORMS OF SCREW THREADS cont...
Knucklethread
Itis a modification of square thread.It has rounded
topand bottom.These threads are used for rough
and ready work. They are usually found on railway
carriagecouplings,hydrants,necksof glass bottles
and large moulded insulatorsused in electrical
trade.
17. 17
DESIGNATION OF SCREW THREADS
ā¢The designation of screw thread is based on Indian standards,IS: 4218(PartIV). The size
of the screw thread is designated by the letter `M' followed by the major diameter and
pitchin mm, the two being separatedby the sign X.
M DiameterXPitch
Example:
M8 X 1.25
M12 X 1.75
M12 X 1.25
ā¢If no pitchis mentioned, it shall mean that coarse pitchis selected.
Example:
M12
M12 X 1.25indicate a fine pitch screw thread.
18. 18
DESIGNATION OF SCREW THREADS cont...
ā¢Fora complete designation,class of fit should also be mentioned. There are mainly three
classesof fits.
1.Close fit ā 5H/4h
2.Mediumfit ā 6H/6g
3.Freefit ā 7H/8g
Example:
M10 X 1.25-4h
M10 X 1.25-7H
M14 X 1.5 ā 6H/6g
Etc
ā¢If no informationabout class of fit is given a medium fit is assumed.
19. 19
STANDARD DIMENSIONS OF SCREW THREADS
ā¢The standarddimensions of screw thread are based on Indian standards,IS: 4218(PartIII).
Corediameter,dc = 0.84d
Where,
d is the major diameter.
20. 20
STRESSES IN SCREWED FASTENING DUE TO STATIC LOADING
ā¢The following stresses in screwed fasteningdue to staticloading are important.
1.Initial stressesdue to tightening
2.Stressesdue to external forces
3.Stressdue to combined forces
The following stresses are developed in a screw fastener while tightening.
ā¢Tensile stressdue to stretchingof bolt
ā¢Torsionalshear stressduring tightening
ā¢Bendingstress
ā¢Shearstress acrossthe threads
ā¢Compressionor crushing stresson threads
21. 21
INITIAL STRESSES DUE TO TIGHTENING
Tensilestressdue to stretchingof bolt
The initial tensile force in a bolt due to tighteningis calculatedby following relation. This
relationis developed based on experiments.
Pi = 2840dN
Where,
Pi = Initial tension in a bolt , in N
d = Nominal diameter of bolt, in mm.
Tensile stressdeveloped,
Where,
Core diameter, dc = 0.84d
22. 22
INITIAL STRESSES DUE TO TIGHTENING cont...
Torsionalshear stress during tightening
The torsional shear stress is developed due to the frictional resistancebetween the threads
of screw and nut during tightening.
The torsional shear stress is calculatedusing the torsionequation.
Torsionalshear stress,
Where,
T = Torque applied
dc = Minor or core diameter of the thread.
23. 23
INITIAL STRESSES DUE TO TIGHTENING cont...
Bendingstress
If the surfaces under the head or nut are not perfectly perpendicular to the bolt axis, then
the bolt will be subjectedto bending action. The bending stress(Ļb) induced in the shank
of the bolt is given by
24. 24
INITIAL STRESSES DUE TO TIGHTENING cont...
Shearstress across the threads
The threads tend to shear off about its roots .
The average thread shearing stressfor the bolt is
The average thread shearing stressfor the nut is
Where,
P = applied load
dc = Minor or core diameter of the thread.
d = Nominal diameter of nut.
b = Width of the thread section at the root.
n = number of threadsin engagement.
25. 25
INITIAL STRESSES DUE TO TIGHTENING cont...
Compressionor crushingstress on threads
The compression or crushing stress between the threads (Ļc) is obtained by using the
relation
Where,
P = applied load
dc = Minor or corediameter of the thread.
d = Nominal diameter of nut.
n = number of threadsin engagement.
26. 26
STRESSES IN SCREWED FASTENING DUE TO EXTERNAL LOADING
ā¢The following stresses in screwed fasteningdue to staticloading are important.
1.Tensile stresses
2.Shear Stresses
3.Combined tensile and shear stress
27. 27
STRESSES DUE TO EXTERNAL LOADING cont...
Tensilestressdue to externalload
The tensile stressdue to external load in bolt is,
If ānā number of bolts are resistingthe applied load then the tensile stress developed in
each bolt is,
Where,
P = applied external load
Core diameter, dc = 0.84d
d = Nominal diameter of bolt
Design of bolt based on material tensile allowable
If P is the applied load, ļ³ta is the allowable material tensile stressand n is the number of
boltsresisting the applied load, then the size of the bolt is calculatedas
28. 28
STRESSES DUE TO EXTERNAL LOADING cont...
Shearstress due to externalload
The shear stressdue to external load in bolt is,
If ānā number of bolts are resistingthe applied load then the tensile stress developed in
each bolt is,
Where,
P = applied external load
d = Nominal diameter of bolt
Design of bolt based on material tensile allowable
If P is the applied load, ļ³sa is the allowable material tensile stressand n is the number of
boltsresisting the applied load, then the size of the bolt is calculatedas
29. 29
STRESSES DUE TO EXTERNAL LOADING cont...
Combinedtensionand shear stress
When the bolt is subjectedto both tension and shear loads, then the diameter of the shank
of the bolt is obtained from the shear load and thatof threaded part from the tensile load.
Outof these the largestdiameter is consideredand stresses due to combined load should
be checked for the following principal stresses.
Maximumprincipal shear stress,
Maximumprincipal tensile stress,
30. 30
PROBLEMS
M1.P1)Twomachine componentsare connectedtogethertightly by a M24bolt. Calculate
the tensile stressinduces in the bolt due to initial tightening.
Nominaldiameter of the bolt, d = 24mm
Initial load, Pi = 2840dN = 2840x 24 = 68160N
Core diameter of the bolt, dc = 0.84d= 0.84x 24 = 20.16mm
Tensile stressdeveloped, where,
31. 31
PROBLEMS contā¦
M1.P2)Amachine weighing 9kN has to be provided with an eye bolt for lifting purpose.
Findthe diameter of the bolt if the permissible stresson the bolt is 20N/mm2.
32. 32
PROBLEMS contā¦
M1.P3)Amachine weighing 25kNhas to be provided with an steel eye bolt for lifting
purpose.Find the diameter of the bolt if the ultimate tensile strengthof steel is 480N/mm2.
Consider a factorof safety of 6 in the design. (2018OCTOBER 7 Marks)
33. 33
PROBLEMS contā¦
M1.P4)Twoscrews for a pipe hanger must hold a tensile load of 10kN.Calculate the most
suitablesize of screw.Take the working stress in tension is 45MPa. (2019APRIL6 Marks)
34. 34
PROBLEMS contā¦
M1.P5)Ageneratorweighing 20kN is to be provided with an eye bolt in the housing for
liftingpurposes. Find the size of bolts if it is made of C- 40 steel. If the ultimate tensile
strengthofC- 40 steel is 600MPa and the factorof safety is 6 ? (2018APRIL6 Marks)
36. 36
PROBLEMS contā¦
M1.P6)Aneye bolt carries a tensile load of 18kN.Find the size of the bolt, if the tensile
stressis not to exceed 100 MPa.?(2018APRIL7 Marks)
38. 38
M1.P7)Twoshafts are connected by means of a flange coupling to transmittorque of
210N-m. The flange of the coupling are fastenedby four bolts of the same material at a
radiusof 50 mm. Find the size of the bolts, if the allowable shear stressfor the bolt
materialis 40 MPa.(2018APRIL 7 marks)
PROBLEMS contā¦
42. 42
The bolts or studs, cylinder cover plate and cylinder flange may be designed as discussed
below:
Pitchcircle diameter, Dp = D + 2t + 3d1
Outsidediameter of the cover, Do = Dp + 3d1 = D + 2t + 6d1
Where,
D = Diameter of the cylinder
d1= Diameter of the hole for bolt or stud
t = Thickness of the cylinder wall
Where,
n = number of bolts
DESIGN OF CYLINDER COVER BOLTS cont...
43. 43
Assumptionsfor design of cylindercoverbolt
ā¢Initialstresses in bolts due to tighteningare neglected.
ā¢The effect of gasket is neglected
ā¢Totalload due to the pressure inside the cylinder is equally shared by the bolts.
ā¢There is no stressconcentrationon the threads.
DESIGN OF CYLINDER COVER BOLTS cont...
44. 44
Designof bolts or studs
Let,
D = Diameter of the cylinder
p = Pressure in the cylinder
dc = Core diameter of the bolts or studs
n = Number of bolts or studs
Ļtb = Permissible tensile stressfor the bolt or stud material
Then,
Upwardforceacting on the cylinder cover,
This force is resistedby n number of bolts or studs provided on the cover
Fromthe above two equations
DESIGN OF CYLINDER COVER BOLTS cont...
45. 45
ā¢Fromthe above equation, the number of bolts or studsmay be obtained, if the size of the
bolt or stud is known and vice-versa.
ā¢If the value of n as obtained from the above relation is odd or a fraction,then next higher
even number is adopted.
ā¢A bolt or a stud less than 16mm diameter should never be used.
ā¢The circular pitch should be between and
DESIGN OF CYLINDER COVER BOLTS cont...
46. 46
PROBLEMS contā¦
M1.P8)Theeffective diameter of a cylinder is 0.5mand the highestpressure of steam
actingon the cylinder head is 1.2MPa.Allowable stressin tension of bolt material is 35MPa.
If the cylinder head is held by 10 bolts, find the size of the bolts. (2018APRIL8 Marks)
47. 47
PROBLEMS contā¦
M1.P9)Acylinder cover of a steam engine is secured by 12 studs.The cylinder is 0.3m
diameterand has a steampressure of 1.2 N/mm2gauge.Calculate the diameter of the
studs,assumingthe permissible stress to be 30 N/mm2. (2017OCTOBER8 Marks)
49. 49
PROBLEMS contā¦
M1.P10) Inasteam engine the maximum steam pressure is 1 N/mm2 absolute and back
pressureis 0.015N/mm2 absolute. The cylinder diameter is 300mm. Determine the
diameterof the screwed end of the piston rod, when the allowable stressis 45 N/mm2 in
tension.(2018OCTOBER8 marks)
51. 51
PROBLEMS contā¦
M1.P11) Asteamengine cylinder has an effective diameter of 340mm and the maximum
steampressure actingon the cylinder cover is 1.25N/mm2. Calculate the number and size
of studs required to fix the cylinder cover, assuming the permissible stressin the studs as
30Mpa.(2019OCTOBER8marks)
57. 57
BOLTS OF UNIFORM STRENGTH
ā¢In an ordinary bolt, the stressin the threaded part of the bolt will be higher than thatin
the shank since the core diameter is less than the shank diameter. Hence the threaded
portionmay fracturebecause of its small length.
ā¢If the shank of the bolt is turned down to a diameter equal or even slightly less than the
corediameter of the thread (dc), then shank of the bolt will undergo a higher stress.
ā¢The bolt, in this way, becomes strongerand lighter and known as bolts of uniform strength.
ā¢An alternative method of obtainingthe bolts of uniform strengthis, an axial hole is drilled
throughthe head as far as the thread portion such thatthe area of the shank becomes
equal to the root area of the thread.
Let,
dh = Diameter of the hole
d = Major diameter of the thread
dc = Root or core diameter of the thread
Ordinarybolt
Reduced Shank Boltwith axial hole
58. 58
STRESSED DUE TO COMBINED INITIAL AND EXTERNAL LOAD
ā¢The resultantload due to initial load and external load is given by
P = P1 + kP2
Where,
P1 = Initial load
P2 = External load
k = stiffnessconstant,
Kb = stiffness of bolt
Kp = stiffnessof connectedparts
ā¢Forgasketed jointswith soft material the value of k =1
ā¢Formetal to metal contactjointsthe value of k = 0
ā¢Forall other types of joints the value of k is between 0 and 1
59. 59
KEYS
ā¢A key is a machine element inserted between the shaft and pulley or shaftand gear to
connectthese together in order to prevent relative motion between them.
ā¢Keysare used as temporaryfasteningsand are subjectedto considerablecrushing and
shearingstresses.
ā¢A keyway is a slot or recess in a shaft and hub of the pulley to accommodatea key.
ā¢The following types of keys are important
1.Sunk keys
2.Saddle keys
3.Tangent keys
4.Round keys
5.Splines
60. 60
SUNK KEYS
ā¢The sunk keys requires keyway in the shaft and in the hub. The sunk keys are of the
followingtypes:
1.Rectangularsunkkey
The usual proportionsof this key are :
Width of key, w = d / 4
thicknessof key, t = 2w / 3 = d / 6
Where,
d = Diameter of the shaft or diameter of the hole in the hub.
2.Squaresunk key
The only difference between a rectangularsunk key and a square sunk key is that its width
and thickness are equal, i.e.
w = t = d / 4
3.Gib-headkey
Itis a rectangularsunk key with a head at one end known
as gib head. It is usually provided to facilitatethe removal
of key.
61. 61
SUNK KEYS cont...
4.Featherkey
A key attachedto one member of the
connectedtorquetransmittingmembers and
which permits relative axial movement is known
as feather key. It is a special type of parallel key
which transmitsa turning moment and also
permitsaxial movement. It is fastened either to
the shaft or hub.
5.Woodruffkey
Itis a semi circulardisc having similar keyway. A
woodruffkey is capable of tilting in the keyway
so can be easily adjusted.This key is largely used
in machine tool and automobile construction.
62. 62
SADDLE KEYS
ā¢The saddle keys are of the following two types :
1.Flat saddle key
2.Hollow saddle key
A flat saddle key is a key which needs a keyway in the hub and is flat on the shaft. It is likely
toslip round the shaft under load. Therefore it is used for comparativelylight loads.
A hollow saddle keyās face which touches shaft is shaped to fit the curved surfaceof the
shaft.Since hollow saddle keys hold on by friction, these are suitable for light loads.
Flatsaddle key Hollowsaddlekey
63. 63
TANGENTKEYS
The tangentkeys are fitted in pair at an angle. Each key is to withstandtorsionin one
directiononly. These are used in heavy duty shafts.
64. 64
ROUND KEYS
The round keys, are circular in section and fit into holes drilled partly in the shaft and partly
in the hub. They have the advantagethattheir keyways may be drilled and reamed after the
matingparts have been assembled. Round keys are usually considered to be most
appropriateforlow power drives.
65. 65
SPLINES
Sometimes,keys are made integralwith the shaft.Such shafts are known as splined shafts.
These shafts usually have four, six, ten or sixteen splines. The splined shafts are relatively
strongerthanshafts having a single keyway. The splined shaftsare used when the forceto
be transmittedis large in proportionto the size of the shaft as in automobile transmission
and sliding gear transmissions.
66. 66
STRENGTHOF RECTANGULAR SUNK KEY AND SQUARE SUNK KEY
Let
T = Torque transmittedby the shaft
F= Tangential force actingat the circumference of the shaft
d = Diameter of shaft
l = Lengthof key
w = Width of key
t = Thickness of key
Ļ = Shear stressesfor the material of key
Ļc = crushing stressesfor the material of key
l
w
t
67. 67
STRENGTHOF RECTANGULAR SUNK KEY AND SQUARE SUNK KEY
Due to the power transmittedby the shaft,the key may fail due to shearing or crushing.
Consideringshearing of the key, the tangentialshearing force acting at the circumferenceof
the shaft,
F= Area resistingshearing Ć Shear stress= l Ć w Ć Ļ
ā“ Torque transmittedby the shaft,
Consideringcrushing of the key, the tangentialcrushing force actingat the circumference
of the shaft,
ā“ Torque transmittedby the shaft,
68. 68
STRENGTHOF RECTANGULAR SUNK KEY AND SQUARE SUNK KEY
The key is equally strongin shearing and crushing,if
The permissible crushing stressfor the key material should be atleast twice the permissible
shearingstress for equal width and thickness.
69. 69
In order to find the length of the key to transmitfull power of the shaft,the shearing
strengthofthe key is equal to the torsional shear strengthof the shaft.
Shearingstrengthof key,
Torsionalshear strengthof the shaft,
Equatingthese two equations
Bytaking w = d/4
If the key material is same as that of the shaft,
Lengthof key,
STRENGTHOF RECTANGULAR SUNK KEY AND SQUARE SUNK KEY
71. 71
PROBLEMS contā¦
M1.P12) A40mm diameter shaft is subjectedto a tangentialforce of 20kN around it's
circumference.Determine the size of key. The allowable shear stress in key is 60 N/mm2.
(2018OCTOBER7marks)
73. 73
PROBLEMS contā¦
M1.P13) Asteelshaft has a diameter, of 25 mm. The shaftrotatesat a speed of 600rpm
and transmits7 kW through a gear.Design a suitable key for the gear. The allowable shear
and crushingstress for the material of the key can be taken as 60MPaand 120MPa
respectively.Assume the same material for both shaftand key. (2019OCTOBER8 marks)
76. 76
PROBLEMS contā¦
M1.P14) Arectangularsunkkey of 75 mm long , 14mm wide and 10 mm thick has to
transmit1200N-mtorque from a 50mm diameter solid shaft. Determine if the designed
lengthis sufficient to transmitthe torque if the allowable shear strengthand crushing
strengthofthe key material are 80Mpaand 180Mparespectively.
78. 78
PROBLEMS contā¦
M1.P15) Ashaftof 50mm diameter is transmitting150kW at 3000rpm. If a key of length
75mm,width 16mm and thickness 10mm is used, calculateinduced shear stressand
crushingstressin the key.
80. 80
ā¢The power screws are used to convertrotary motion into translatorymotion. Power
screwsare used in lathes,screw jacks,vices, testing machines, presses etc.
ā¢In power screws, the relative motion between screw and nut can be following types.
1.The nut moves axially againstthe resisting axial force while the screw rotatesin
its bearings.
2.The screw rotatesand moves axially againstthe resisting forcewhile the nut is
stationary.
3.The nut rotateswhile the screw moves axially with no rotation.
ā¢Followingare the three types of screw threadsmostly used for power screws
1.Squarethread
2.Acme thread
3.Buttressthread
POWER SCREWS
81. 81
ā¢Screwjack is a device used wherever thereis a need to lift or hold heavy loads.
ā¢Screwjack convertrotationalmotion into linear motion.
ā¢A screw jack consistsof a vertical screw with a table mounted on its top, which screws
intoa threaded hole (act as nut) in a stationarysupport frame.
ā¢Itworks on the principle same as thatof incline plane.
ā¢Itutilizes the property of a screw thread providing a mechanical advantagei.e. it can
be used to amplify force.
SCREW JACK
82. 82
SCREW JACK contā¦
Ps
Effort requiredto raisethe load
If T is the torquerequired to raise the load then,
T = P x L
P x L = Ps x dm/2
Where,
P = Effort applied at the end of the handle
L = length of handle
Ps = imaginary force acting at mean
circumferenceof the screw.
dm = Mean diameter of the screw
dm = (d+dc)/2
dm = dc+0.5p
dm = d-0.5p
d = Nominal diameter of the screw
dc = Core diameter of the screw
p = Pitch of the screw
83. 83
Ī± = Helix angle
tanĪ± = n p / Ļ dm
Where,
p = Pitch of the screw
n = number of starts
Forsingle startthread,n = 1
Fordouble startthread,n = 2 etc..
Development of a screw thread
SCREW JACK contā¦
84. 84
SCREW JACK- TORQUE REQUIRED TO RAISE LOAD
ā¢Screwjack works on the principle same as that of incline plane.
W = Load to be lifted
Ps = Effortapplied at the circumference of the screw
PF = Frictionalload
Ī± = Helix angle
Ī¼= Coefficient of friction between the screw and nut
Ī¼= tan Ļ, where Ļ is the friction angle
Effortto be applied at circumferenceof the screw to lift the load, Ps = W tan(Ļ + Ī±)
Torqueto be applied at circumference of the screw to lift the load, T = Ps dm /2
T = W tan(Ļ + Ī±)dm /2
85. 85
SCREW JACK- TORQUE REQUIRED TO LOWER LOAD
W = Load to be lifted
Ps = Effortapplied at the circumference of the screw
PF = Frictionalload
Ī± = Helix angle
Ī¼= Coefficient of friction between the screw and nut
Ī¼= tan Ļ, where Ļ is the friction angle
Effortto be applied at circumferenceof the screw to lower the load, Ps = W tan(Ļ - Ī±)
Torqueto be applied at circumference of the screw to lower the load, T = Ps dm /2
T = W tan(Ļ - Ī±)dm /2
86. To prevent the rotationof the load a collar is provided at the top of the screw head. Collar
frictiontakes place at the contactsurfacebetween screw head and collar.
Let,
Ī¼c= Coefficient of friction between the screw head and collar
R1 = Internal radius of bearing surface of collar in mm
R2 = External radius of bearing surfaceof collar in mm
Meanradius considering uniform wear,
Meanradius considering uniform pressure,
Collar friction torque, Tc = Ī¼ c WR
Torqueto be applied at circumference of the screw to lift the load consideringcollar friction
T = Ps dm /2 + Tc
T = W tan(Ļ + Ī±)(dm /2) + Ī¼ c WR
Torqueto be applied at circumference of the screw to lower the load considering collar
friction
T = Ps dm /2 + Tc
T = W tan(Ļ - Ī±)(dm /2) + Ī¼ c WR
86
SCREW JACK- TORQUE REQUIRED CONSIDERING COLLAR FRICTION
87. 87
SCREW JACK- EFFICIENCY
The efficiency of screw jack is defined as the ratio between the ideal effort(i.e. the effort
requiredto move the load, neglecting friction) to the actual effort(i.e. the effortrequired to
move the load taking friction into account).
Actualeffort,P = W tan(Ļ + Ī±)
Where,
Ī± = Helix angle, Ļ = frictionangle
Ideal effortis the effort required to move the load, neglecting friction.
Ideal effort,Po = W tan Ī±
The efficiency of a screw jack is independent of the load raised.
88. 88
SCREW JACK- EFFICIENCY CONSIDERING COLLAR FRICTION
Consideringcollar friction,
Actualtorque,T = Pdm /2 + Ī¼ c WR
Ideal torque,To = Podm /2
Where,
P = Actual effort,Po = Ideal effort,dm = Mean diameter of the screw
Ī¼c= Coefficient of friction between the screw head and collar
R = Mean radius
89. 89
SCREW JACK- MAXIMUM EFFICIENCY
The efficiency of screw jack is given as
Multiplyingthe numeratorand denominator by 2,
The efficiency given by the above equation will be maximum when sin (2Ī± + Ļ) is maximum,
i.e. when
sin (2Ī± + Ļ) = 1
Means,2Ī±+ Ļ = 90Ā°
ā“ 2Ī± = 90Ā° ā Ļ
Ī±= 45Ā°ā Ļ / 2
Maximumefficiency of screw jack,
90. 90
SCREW JACK- OVER HAULING AND SELF LOCKING
The effort to be applied at circumferenceof the screw to lower the load, Ps = W tan(Ļ - Ī±)
The torque to be applied at circumference of screw to lower the load, T = W tan(Ļ - Ī±)dm /2
Where,
W = Load to be lifted, dm = Mean diameter of the screw
Ī± = Helix angle, Ļ = frictionangle
In the above expression, if Ļ < Ī±, then torque required to lower the load will be negative.In
otherwords, the load will startmoving downward without the applicationof any torque. Such
a condition is known as over hauling of screws.
If however, Ļ > Ī±, the torque required to lower the load will be positive, indicating thatan
effortis applied to lower the load. Such a screw is known as self locking screw.In other words,
a screw will be self locking if the friction angle is greaterthan helix angle.
The efficiency of a self locking screw is less than 50%.
If the efficiency of a screw jack is 50% the screw is at the point of reversal.
If the efficiency is more than 50% the screw jack is overhauling.
91. 91
PROBLEMS contā¦
M1.P16) Ascrewjack having square threads of 50 mm mean diameter and 12.5mm pitch is
operatedby a 500 mm long hand lever Coefficient of friction at the thread is 0.1.
1.Findthe Efficiency of screw jack.
2.CheckWhether it is self locking or overhauling
3.Determinethe forceneeded to be applied at the end of the lever to lift the load
of 20kN. (2017OCTOBER8 marks)
94. 94
PROBLEMS contā¦
M1.P17) Findtheforce to be applied at the end of one meter long handle of a screw jack so
thata load of 7 kN is lifted with constantvelocity.The screw is square threaded having a
pitchof 16mm and root diameter 50mm.The coefficient of friction between the screw and
nutis 0.16. (2018APRIL 8 marks)
96. 96
PROBLEMS contā¦
M1.P18) Aload of 2500N is to be raised by a screw jack with a screw of 75 mm mean
diameterand pitch of 12 mm. Find the efficiency of the screw jack,if the coefficient of
frictionof screw and nut is 0.075.(2018OCTOBER8 marks)
98. 98
PROBLEMS contā¦
M1.P19) Aload of 10000Nis to be raised by a screw jack with a square threaded double
startscrewof 75mm mean diameter and pitch of 10 mm. Find the efficiency of the screw
jack,if the coefficientof friction of screw and nut is 0.1.
100. 100
PROBLEMS contā¦
M1.P20) Aturnbuckle is used to tighten a wire rope. The threads are single right and left
hand and square in section.The outside diameter of the screw is 40 mm and the pitch is 8.5
mm. The coefficientof friction between the screwsand nuts is 0.15.What torque on the
turnbuckle is necessary, if the rope is to be tightened to a tension of 8 kN ?
(2018APRIL9 marks)
102. 102
PROBLEMS contā¦
M1.P21) Anelectricmotor driven power screw moves a nut in a horizontalplane againsta
forceof 75kNat a speed of 300mm/min.The screw has a single square thread of 6mm pitch
on a major diameter of 40 mm. The coefficientof friction at screw threads is 0.1.Estimate
power of the motor. (2019OCTOBER7 marks)
105. 105
PROBLEMS contā¦
M1.P22) Ascrewjack having square threaded screw of pitchof 16mm and nominal
diameter50mm. The coefficientof friction between the screw and nut is 0.16and screw
and collar is 0.18.The outside and inside diameter of collar is 80 mm and 50 mm
respectively.Find the forceto be applied at the end of one meter long handle of a screw
jackso thata load of 7 kN is lifted with constantvelocity considering
I. Uniformwear at collar
II. Uniformpressure at collar