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1
Find the momentum of
(a) a 10.0-MeV gamma ray;
(b) a 25-keV X ray;
(c) a 1.0-μm infrared photon;
(d) a 150-MHz radio-wave photon.
Express the momentum in kg·m/s and eV/c.
Helping Tools
No.1
2
No.2
3
No.3
4
No.4
5
Solution
(a)
6
7 7 19
12
10.0 10 10
10 10 1.602 10
1.602 10
E MeV X eV
eV X X J
X J
−
−
= =
= =
=
6
8 8
7 7 12
12
20
8
20 21
10 10 1.602 10
1.602 10
,
3.00 10 3.00 10
.
0.534 10 .
3.00 10
. .
0.534 10 5.34 10
E
Also p
m m
c c X X
s s
N m
X N s
m
X
s
e
kg m kg m
X X
s s
V eV X J
X −
− −
−
−
= = = =
= =
= =
7
(b)
19
19 15
3
25.0 k 25.0 10
25000 25000 1.602 10 J
=40050X10 J=4.00X10 J
E eV X eV
eV X X −
− −
= =
= =
8
8
15
15
8
23
8
23 23
25000 25000 4.00 10
4.00
,
3.00 10 3.00 10
.
1.333 10 .
3.00 10
. .
1.333 10 1.333
10
10
E
Also p
m m
c c X X
s s
N m
X N s
m
X
s
e
kg m kg m
X X
s
V V X
s
e J
X −
−
−
−
−
= = = =
= =
= =
9
(c)
6
34 34
6 6
28 28
1.0 1.0 10
6.626 10 J. 6.626 10 N.m.
1.0 10 1.0 10
.
6.626 10 . 6.626 10
m X m
h X s X s
p
X m X m
kg m
X N s X
s
 

−
− −
− −
− −
= =
= = =
= =
10
6
15
9
6
8
9
1
1.0 1.0 10
4.136 10 eV. .
4.136 10
1.0 10
2.998 10
.
4.136 10
12.399728 10 1.2399728 1.2
m X m
h X s eV s
p X
X m m
m
X
eV s s
X X
m c
eV eV eV
X
c c c
 

−
−
−
−
−
−
= =
= = =
=
= = 
11
(d)
15 6
9 7
4.136 10 . 150 10
620.4 10 6.204 10
hf X eV sX X Hz
p
c c
X eV X eV
c c
−
− −
= =
= =
12
15 6
9 7
7 19
8
34 34
34
4.136 10 . 150 10
620.4 10 6.204 10
6.204 10 1.602 10
2.99792458 10
.
3.315 10 3.315 10 .
.
3.315 10
hf X eV sX X Hz
p
c c
X eV X eV
c c
X X X J
m
X
s
J s
X X N s
m
kg m
X
s
−
− −
− −
− −
−
= =
= =
=
= =
=
The End

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Photoelectric Effect.pdf

  • 1. 1 Find the momentum of (a) a 10.0-MeV gamma ray; (b) a 25-keV X ray; (c) a 1.0-μm infrared photon; (d) a 150-MHz radio-wave photon. Express the momentum in kg·m/s and eV/c. Helping Tools No.1
  • 5. 5 Solution (a) 6 7 7 19 12 10.0 10 10 10 10 1.602 10 1.602 10 E MeV X eV eV X X J X J − − = = = = =
  • 6. 6 8 8 7 7 12 12 20 8 20 21 10 10 1.602 10 1.602 10 , 3.00 10 3.00 10 . 0.534 10 . 3.00 10 . . 0.534 10 5.34 10 E Also p m m c c X X s s N m X N s m X s e kg m kg m X X s s V eV X J X − − − − − = = = = = = = =
  • 7. 7 (b) 19 19 15 3 25.0 k 25.0 10 25000 25000 1.602 10 J =40050X10 J=4.00X10 J E eV X eV eV X X − − − = = = =
  • 8. 8 8 15 15 8 23 8 23 23 25000 25000 4.00 10 4.00 , 3.00 10 3.00 10 . 1.333 10 . 3.00 10 . . 1.333 10 1.333 10 10 E Also p m m c c X X s s N m X N s m X s e kg m kg m X X s V V X s e J X − − − − − = = = = = = = =
  • 9. 9 (c) 6 34 34 6 6 28 28 1.0 1.0 10 6.626 10 J. 6.626 10 N.m. 1.0 10 1.0 10 . 6.626 10 . 6.626 10 m X m h X s X s p X m X m kg m X N s X s    − − − − − − − = = = = = = =
  • 10. 10 6 15 9 6 8 9 1 1.0 1.0 10 4.136 10 eV. . 4.136 10 1.0 10 2.998 10 . 4.136 10 12.399728 10 1.2399728 1.2 m X m h X s eV s p X X m m m X eV s s X X m c eV eV eV X c c c    − − − − − − = = = = = = = = 
  • 11. 11 (d) 15 6 9 7 4.136 10 . 150 10 620.4 10 6.204 10 hf X eV sX X Hz p c c X eV X eV c c − − − = = = =
  • 12. 12 15 6 9 7 7 19 8 34 34 34 4.136 10 . 150 10 620.4 10 6.204 10 6.204 10 1.602 10 2.99792458 10 . 3.315 10 3.315 10 . . 3.315 10 hf X eV sX X Hz p c c X eV X eV c c X X X J m X s J s X X N s m kg m X s − − − − − − − − = = = = = = = = The End