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Chemical Bonding
and
Molecular Structure
By: Navneet singh
class 11(sa1 Ot)
04/09/2015 Bonding and Structure 1
04/09/2015 Bonding and Structure 2
Chemical Bonding
and
Molecular Structure
• Ionic vs. covalent bonding
• Molecular orbitals and the covalent bond (Ch. 10)
• Valence electron Lewis dot structures
octet vs. non-octet
resonance structures
formal charges
• VSEPR - predicting shapes of molecules
• Bond properties
polarity, bond order, bond strength
04/09/2015 Bonding and Structure 3
Chemical Bonding
Problems and questions —
• How is a molecule or polyatomic
ion held together?
• Why are atoms distributed at
strange angles?
• Why are molecules not flat?
• Can we predict the structure?
• How is structure related to
chemical and physical properties?
04/09/2015 Bonding and Structure 4
Most bonds are somewhere in between.
Forms of Chemical Bonds
• There are 2 extreme forms of connecting
or bonding atoms:
• Ionic—complete transfer of electrons
from one atom to another
• Covalent—electrons shared between
atoms
04/09/2015 Bonding and Structure 5
IonicIonic
BondsBonds
Ionic compounds
- essentially complete electron
transfer from an element of low
IE (metal) to an element of high
electron affinity (EA) (nonmetal)
Na(s) + 1/2 Cl2(g) → Na+
+ Cl-
→ NaCl (s)
- NON-DIRECTIONAL bonding
via Coulomb (charge) interaction
- primarily between metals
(Grps 1A, 2A and transition metals)
and nonmetals (esp O and halogens)
04/09/2015 Bonding and Structure 6
Covalent Bonding
Covalent bond is the sharing of the VALENCE
ELECTRONS of each atom in a bond
Recall: Electrons are divided between core
and valence electrons.
ATOM core valence
Na 1s2
2s2
2p6
3s1
[Ne] 3s1
Br [Ar] 3d10
4s2
4p5
[Ar] 3d10
4s2
4p5
Br Br
04/09/2015 Bonding and Structure 7
Valence Electrons1A1A
2A2A 3A3A 4A4A 5A5A 6A6A 7A7A
8A8A
Number of valence electrons is
equal to the Group number.
04/09/2015 Bonding and Structure 8
Covalent Bonding
The bond arises from the mutual attraction of
2 nuclei for the same electrons.
HB+ HA
HB
HA
A covalent bond is a balance
of attractive and repulsive forces.
6_H2bond.mov
04/09/2015 Bonding and Structure 9
Bond Formation
A bond can result from a “head-to-head” overlap
of atomic orbitals on neighboring atoms.
H H Cl
••
•
•
••
Cl
••
•
•
••
+
Overlap of H (1s) and Cl (2p)
This type of overlap places bonding electrons in a
MOLECULAR ORBITAL along the line between
the two atoms and forms a SIGMA BOND (σ).
04/09/2015 Bonding and Structure 10
Sigma Bond Formation by Orbital Overlap
••↑ ••
sigma bond ( σ)
↓↑↑+
HH
Two s Atomic Orbitals (A.O.s) overlap to form
an sσ (sigma) Molecular Orbital (M.O.)
6_H2pot.mov
04/09/2015 Bonding and Structure 11
Sigma Bond Formation by Orbital Overlap
••↑ ••
sigma bond ( σ)
↓↑↑+
HH
↑↓
↑↑
Two s A.O.s overlap to
from an s σ M.O.
Similarly, two p A.O.s
can overlap end-on to
from a pσ M.O.
e.g.
F2
04/09/2015 Bonding and Structure 12
ElectronElectron
Distribution inDistribution in
MoleculesMolecules
• Electron distribution
is depicted with
Lewis electron
dot structures
• Electrons are
distributed as:
• shared or BOND
PAIRS and
• unshared or LONE
PAIRS.
G. N. Lewis
1875 - 1946
04/09/2015 Bonding and Structure 13
Bond and Lone Pairs
• Electrons are distributed as shared or BOND
PAIRS and unshared or LONE PAIRS.
••
H Cl
••
•
•
This is a LEWIS ELECTRON DOT structure.
shared or bond pair
Unshared or
lone pair (LP)
04/09/2015 Bonding and Structure 14
• This observation is called the OCTET RULE
Rules of Lewis StructuresRules of Lewis Structures
• No. of valence electrons of an atom =
Group number
• Except for H
(and atoms of 3rd and higher periods),
#Bond Pairs + #Lone Pairs = 4
• For Groups 5A-7A (N - F),
no. of BOND PAIRS = 8 - group No.
• For Groups 1A-4A (Li - C),
no. of BOND PAIRS = group number
04/09/2015 Bonding and Structure 15
2. Count valence electrons
H = 1 and N = 5
Total = (3 x 1) + 5
= 8 electrons or
1. Decide on the central atom; never H.
Central atom is atom of lowest affinity for electrons.
In ammonia, N is central
Building a Dot Structure
Ammonia, NH3
4 pairs
04/09/2015 Bonding and Structure 16
4. Remaining electrons form
LONE PAIRS to complete
octet as needed.
3. Form a sigma bond
between the central atom
and surrounding atoms.
H H
H
N
Building a Dot Structure
H
••
H
H
N
3 BOND PAIRS and 1 LONE PAIR.
Note that N has a share in 4 pairs (8 electrons), while
each H shares 1 pair.
04/09/2015 Bonding and Structure 17
Step 2. Count valence electrons
S = 6
3 x O = 3 x 6 = 18
Negative charge = 2
TOTAL = 6 + 18 + 2 = 26 e-
or 13 pairs
Step 1. Central atom = S
10 pairs of electrons are left.
Sulfite ion, SO3
2-
Step 3. Form sigma bonds
O O
O
S
04/09/2015 Bonding and Structure 18
Remaining pairs become lone pairs,
first on outside atoms
then on central atom.
Sulfite ion, SO3
2-
(2)
Each atom is surrounded by an octet of electrons.
•
• O O
O
S
••
••
•• ••
••
••
•
•
•
•
•
•
NOTE - must add formal charges (O-
, S+
) for complete dot diagram
04/09/2015 Bonding and Structure 19
Carbon Dioxide, CO2
1. Central atom = __C____
2. Valence electrons = _16_ or _8_ pairs
3. Form sigma bonds.
O OC
•
• O OC•• ••
••••
•
•
This leaves __6__ pairs.
4. Place lone pairs on outer atoms.
04/09/2015 Bonding and Structure 20
•
• O OC•• ••
••••
•
•
Carbon Dioxide, CO2 (2)
4. Place lone pairs on outer atoms.
•
• O OC•• ••
••••
•
•
•
• O OC•• ••
•
•
The second bonding pair forms a pi (π) bond.
5. To give C an octet, form DOUBLE BONDS
between C and O.
04/09/2015 Bonding and Structure 21
SO3
H2CODouble and even
triple bonds are
commonly
observed for C,
N, P, O, and S
•
• O OC•• ••
•
•
C2F4
04/09/2015 Bonding and Structure 22
Sulfur Dioxide, SO2
1. Central atom = S
2. Valence electrons = 6 + 2*6 = 18 electrons
or 9 pairs•
• O OS••
••
••
••••
•
•
•
• O OS••
••
••
••••
•
•
bring in
left pair
OR bring in
right pair
3. Form pi (π) bond so that S has an octet
— note that there are two ways of doing this.
04/09/2015 Bonding and Structure 23
Sulfur Dioxide, SO2
•
• O OS••
••
••
••••
•
•
bring in
left pair
OR bring in
right pair
•
• O OS••
••
••
••
•
•
•
• O OS••
••
••
••
•
•
Equivalent structures
called:
RESONANCE
STRUCTURES
The proper Lewis structure
is a HYBRID of the two.
A BETTER representation of SO2
is made by forming 2 double bonds
O = S = O
Each atom has
- OCTET
- formal charge = 0
Bonding and Structure 24
Urea (NHUrea (NH22))22COCO
1. Number of valence electrons = 24 e-
2. Draw sigma bonds.
CN N H
HH
H
O
4. Place remaining electron pairs on oxygen
3. Complete C atom octet with double bond.
CN N H
HH
H
O
Leaves 24 - 14 = 10 e- pairs.
and nitrogen atoms.
04/09/2015 Bonding and Structure 25
Violations of the Octet Rule
Usually occurs with:
Boron
BF3
SF4
elements of higher periods.
04/09/2015 Bonding and Structure 26
Boron Trifluoride
• Central atom = B
• Valence electrons = 3 + 3*7 = 24
or electron pairs = 12
• Assemble dot structure
F••
•
•
••
F
F
B
••
••
•
•
•
•
•
•
•
•
The B atom has a share
in only 6 electrons (or 3
pairs). B atom in many
molecules is electron
deficient.
04/09/2015 Bonding and Structure 27
Sulfur Tetrafluoride, SF4
• Central atom = S
• Valence electrons = 6 + 4*7 = 34 e-
or 17 pairs.
• Form sigma bonds and distribute
electron pairs.
F
••
•
•
••
F
F
S
••
••
•
•
•
•
•
• F••
••
••
••
••
5 pairs around the S5 pairs around the S
atom. A commonatom. A common
occurrence outside theoccurrence outside the
2nd period.2nd period.
04/09/2015 Bonding and Structure 28
Formal charge = Group no.
- 1/2 (no. bond electrons)
- (no. of LP electrons)
Formal Atom Charges
• Atoms in molecules often bear a charge (+ or -).
• The most important dominant resonance structure
of a molecule is the one with formal charges
as close to 0 as possible.
04/09/2015 Bonding and Structure 29
04 - (1/ 2)(8) - 0 =
6 - (1/ 2)(4) - 4 = 0
Carbon Dioxide, CO2
At OXYGEN
O C O
•
•
• •
•
•
• •
At CARBON
04/09/2015 Bonding and Structure 30
C atom
charge is 0.
6 - (1/ 2)(6) - 2 = +1
6 - (1/ 2)(2) - 6 = -1
Carbon Dioxide, CO2 (2)
O C O
•
•
• •
•
•
• •
An alternate Lewis structure is:
AND the corresponding
resonance form
+
O C O
•
•
• •
•
•
• •
+
04/09/2015 Bonding and Structure 31
• REALITY: Partial charges calculated
by CAChe molecular modeling
system (on CD-ROM).
+1.46
-0.73 -0.73
Carbon Dioxide, CO2 (3)
Which is the predominant resonance structure?
O C O
•
•
• •
•
•
• •
OR
O C O
•
•
• •
•
•
• •
O C O
•
•
• •
•
•
• •
+
+
Answer ?
Form without formal charges is
BETTER - no +ve charge on O
04/09/2015 Bonding and Structure 32
Boron Trifluoride, BF3
F••
•
•
••
F
F
B
••
••
•
•
•
•
•
•
•
•
What if we form a B—F double
bond to satisfy the B atom octet?
04/09/2015 Bonding and Structure 33
Boron Trifluoride, BF3 (2)
• To have +1 charge on F, with
its very high electron affinity is
not good. -ve charges best
placed on atoms with high EA.
• Similarly -1 charge on B is bad
• NOT important Lewis structure
fc = 7 - 2 - 4 = +1 Fluorine
F••
••
F
F
B
••
••
•
•
•
•
•
•
•
•
fc = 3 - 4 - 0 = -1 Boron
+
04/09/2015 Bonding and Structure 34
A. S=C=N
Thiocyanate ion, (SCN)
-
Which of three possible resonance structures
is most important?
-0.52 -0.32-0.16
Calculated partial charges
ANSWER:
C > A > B
C. S-C N
B. S=C - N
Thank yo u
allfo r watching .
Subm issio n to : Ms
Navde e p Kaur
04/09/2015 Bonding and Structure 35

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chemical bonding and molecular orbitals

  • 1. Chemical Bonding and Molecular Structure By: Navneet singh class 11(sa1 Ot) 04/09/2015 Bonding and Structure 1
  • 2. 04/09/2015 Bonding and Structure 2 Chemical Bonding and Molecular Structure • Ionic vs. covalent bonding • Molecular orbitals and the covalent bond (Ch. 10) • Valence electron Lewis dot structures octet vs. non-octet resonance structures formal charges • VSEPR - predicting shapes of molecules • Bond properties polarity, bond order, bond strength
  • 3. 04/09/2015 Bonding and Structure 3 Chemical Bonding Problems and questions — • How is a molecule or polyatomic ion held together? • Why are atoms distributed at strange angles? • Why are molecules not flat? • Can we predict the structure? • How is structure related to chemical and physical properties?
  • 4. 04/09/2015 Bonding and Structure 4 Most bonds are somewhere in between. Forms of Chemical Bonds • There are 2 extreme forms of connecting or bonding atoms: • Ionic—complete transfer of electrons from one atom to another • Covalent—electrons shared between atoms
  • 5. 04/09/2015 Bonding and Structure 5 IonicIonic BondsBonds Ionic compounds - essentially complete electron transfer from an element of low IE (metal) to an element of high electron affinity (EA) (nonmetal) Na(s) + 1/2 Cl2(g) → Na+ + Cl- → NaCl (s) - NON-DIRECTIONAL bonding via Coulomb (charge) interaction - primarily between metals (Grps 1A, 2A and transition metals) and nonmetals (esp O and halogens)
  • 6. 04/09/2015 Bonding and Structure 6 Covalent Bonding Covalent bond is the sharing of the VALENCE ELECTRONS of each atom in a bond Recall: Electrons are divided between core and valence electrons. ATOM core valence Na 1s2 2s2 2p6 3s1 [Ne] 3s1 Br [Ar] 3d10 4s2 4p5 [Ar] 3d10 4s2 4p5 Br Br
  • 7. 04/09/2015 Bonding and Structure 7 Valence Electrons1A1A 2A2A 3A3A 4A4A 5A5A 6A6A 7A7A 8A8A Number of valence electrons is equal to the Group number.
  • 8. 04/09/2015 Bonding and Structure 8 Covalent Bonding The bond arises from the mutual attraction of 2 nuclei for the same electrons. HB+ HA HB HA A covalent bond is a balance of attractive and repulsive forces. 6_H2bond.mov
  • 9. 04/09/2015 Bonding and Structure 9 Bond Formation A bond can result from a “head-to-head” overlap of atomic orbitals on neighboring atoms. H H Cl •• • • •• Cl •• • • •• + Overlap of H (1s) and Cl (2p) This type of overlap places bonding electrons in a MOLECULAR ORBITAL along the line between the two atoms and forms a SIGMA BOND (σ).
  • 10. 04/09/2015 Bonding and Structure 10 Sigma Bond Formation by Orbital Overlap ••↑ •• sigma bond ( σ) ↓↑↑+ HH Two s Atomic Orbitals (A.O.s) overlap to form an sσ (sigma) Molecular Orbital (M.O.) 6_H2pot.mov
  • 11. 04/09/2015 Bonding and Structure 11 Sigma Bond Formation by Orbital Overlap ••↑ •• sigma bond ( σ) ↓↑↑+ HH ↑↓ ↑↑ Two s A.O.s overlap to from an s σ M.O. Similarly, two p A.O.s can overlap end-on to from a pσ M.O. e.g. F2
  • 12. 04/09/2015 Bonding and Structure 12 ElectronElectron Distribution inDistribution in MoleculesMolecules • Electron distribution is depicted with Lewis electron dot structures • Electrons are distributed as: • shared or BOND PAIRS and • unshared or LONE PAIRS. G. N. Lewis 1875 - 1946
  • 13. 04/09/2015 Bonding and Structure 13 Bond and Lone Pairs • Electrons are distributed as shared or BOND PAIRS and unshared or LONE PAIRS. •• H Cl •• • • This is a LEWIS ELECTRON DOT structure. shared or bond pair Unshared or lone pair (LP)
  • 14. 04/09/2015 Bonding and Structure 14 • This observation is called the OCTET RULE Rules of Lewis StructuresRules of Lewis Structures • No. of valence electrons of an atom = Group number • Except for H (and atoms of 3rd and higher periods), #Bond Pairs + #Lone Pairs = 4 • For Groups 5A-7A (N - F), no. of BOND PAIRS = 8 - group No. • For Groups 1A-4A (Li - C), no. of BOND PAIRS = group number
  • 15. 04/09/2015 Bonding and Structure 15 2. Count valence electrons H = 1 and N = 5 Total = (3 x 1) + 5 = 8 electrons or 1. Decide on the central atom; never H. Central atom is atom of lowest affinity for electrons. In ammonia, N is central Building a Dot Structure Ammonia, NH3 4 pairs
  • 16. 04/09/2015 Bonding and Structure 16 4. Remaining electrons form LONE PAIRS to complete octet as needed. 3. Form a sigma bond between the central atom and surrounding atoms. H H H N Building a Dot Structure H •• H H N 3 BOND PAIRS and 1 LONE PAIR. Note that N has a share in 4 pairs (8 electrons), while each H shares 1 pair.
  • 17. 04/09/2015 Bonding and Structure 17 Step 2. Count valence electrons S = 6 3 x O = 3 x 6 = 18 Negative charge = 2 TOTAL = 6 + 18 + 2 = 26 e- or 13 pairs Step 1. Central atom = S 10 pairs of electrons are left. Sulfite ion, SO3 2- Step 3. Form sigma bonds O O O S
  • 18. 04/09/2015 Bonding and Structure 18 Remaining pairs become lone pairs, first on outside atoms then on central atom. Sulfite ion, SO3 2- (2) Each atom is surrounded by an octet of electrons. • • O O O S •• •• •• •• •• •• • • • • • • NOTE - must add formal charges (O- , S+ ) for complete dot diagram
  • 19. 04/09/2015 Bonding and Structure 19 Carbon Dioxide, CO2 1. Central atom = __C____ 2. Valence electrons = _16_ or _8_ pairs 3. Form sigma bonds. O OC • • O OC•• •• •••• • • This leaves __6__ pairs. 4. Place lone pairs on outer atoms.
  • 20. 04/09/2015 Bonding and Structure 20 • • O OC•• •• •••• • • Carbon Dioxide, CO2 (2) 4. Place lone pairs on outer atoms. • • O OC•• •• •••• • • • • O OC•• •• • • The second bonding pair forms a pi (π) bond. 5. To give C an octet, form DOUBLE BONDS between C and O.
  • 21. 04/09/2015 Bonding and Structure 21 SO3 H2CODouble and even triple bonds are commonly observed for C, N, P, O, and S • • O OC•• •• • • C2F4
  • 22. 04/09/2015 Bonding and Structure 22 Sulfur Dioxide, SO2 1. Central atom = S 2. Valence electrons = 6 + 2*6 = 18 electrons or 9 pairs• • O OS•• •• •• •••• • • • • O OS•• •• •• •••• • • bring in left pair OR bring in right pair 3. Form pi (π) bond so that S has an octet — note that there are two ways of doing this.
  • 23. 04/09/2015 Bonding and Structure 23 Sulfur Dioxide, SO2 • • O OS•• •• •• •••• • • bring in left pair OR bring in right pair • • O OS•• •• •• •• • • • • O OS•• •• •• •• • • Equivalent structures called: RESONANCE STRUCTURES The proper Lewis structure is a HYBRID of the two. A BETTER representation of SO2 is made by forming 2 double bonds O = S = O Each atom has - OCTET - formal charge = 0
  • 24. Bonding and Structure 24 Urea (NHUrea (NH22))22COCO 1. Number of valence electrons = 24 e- 2. Draw sigma bonds. CN N H HH H O 4. Place remaining electron pairs on oxygen 3. Complete C atom octet with double bond. CN N H HH H O Leaves 24 - 14 = 10 e- pairs. and nitrogen atoms.
  • 25. 04/09/2015 Bonding and Structure 25 Violations of the Octet Rule Usually occurs with: Boron BF3 SF4 elements of higher periods.
  • 26. 04/09/2015 Bonding and Structure 26 Boron Trifluoride • Central atom = B • Valence electrons = 3 + 3*7 = 24 or electron pairs = 12 • Assemble dot structure F•• • • •• F F B •• •• • • • • • • • • The B atom has a share in only 6 electrons (or 3 pairs). B atom in many molecules is electron deficient.
  • 27. 04/09/2015 Bonding and Structure 27 Sulfur Tetrafluoride, SF4 • Central atom = S • Valence electrons = 6 + 4*7 = 34 e- or 17 pairs. • Form sigma bonds and distribute electron pairs. F •• • • •• F F S •• •• • • • • • • F•• •• •• •• •• 5 pairs around the S5 pairs around the S atom. A commonatom. A common occurrence outside theoccurrence outside the 2nd period.2nd period.
  • 28. 04/09/2015 Bonding and Structure 28 Formal charge = Group no. - 1/2 (no. bond electrons) - (no. of LP electrons) Formal Atom Charges • Atoms in molecules often bear a charge (+ or -). • The most important dominant resonance structure of a molecule is the one with formal charges as close to 0 as possible.
  • 29. 04/09/2015 Bonding and Structure 29 04 - (1/ 2)(8) - 0 = 6 - (1/ 2)(4) - 4 = 0 Carbon Dioxide, CO2 At OXYGEN O C O • • • • • • • • At CARBON
  • 30. 04/09/2015 Bonding and Structure 30 C atom charge is 0. 6 - (1/ 2)(6) - 2 = +1 6 - (1/ 2)(2) - 6 = -1 Carbon Dioxide, CO2 (2) O C O • • • • • • • • An alternate Lewis structure is: AND the corresponding resonance form + O C O • • • • • • • • +
  • 31. 04/09/2015 Bonding and Structure 31 • REALITY: Partial charges calculated by CAChe molecular modeling system (on CD-ROM). +1.46 -0.73 -0.73 Carbon Dioxide, CO2 (3) Which is the predominant resonance structure? O C O • • • • • • • • OR O C O • • • • • • • • O C O • • • • • • • • + + Answer ? Form without formal charges is BETTER - no +ve charge on O
  • 32. 04/09/2015 Bonding and Structure 32 Boron Trifluoride, BF3 F•• • • •• F F B •• •• • • • • • • • • What if we form a B—F double bond to satisfy the B atom octet?
  • 33. 04/09/2015 Bonding and Structure 33 Boron Trifluoride, BF3 (2) • To have +1 charge on F, with its very high electron affinity is not good. -ve charges best placed on atoms with high EA. • Similarly -1 charge on B is bad • NOT important Lewis structure fc = 7 - 2 - 4 = +1 Fluorine F•• •• F F B •• •• • • • • • • • • fc = 3 - 4 - 0 = -1 Boron +
  • 34. 04/09/2015 Bonding and Structure 34 A. S=C=N Thiocyanate ion, (SCN) - Which of three possible resonance structures is most important? -0.52 -0.32-0.16 Calculated partial charges ANSWER: C > A > B C. S-C N B. S=C - N
  • 35. Thank yo u allfo r watching . Subm issio n to : Ms Navde e p Kaur 04/09/2015 Bonding and Structure 35