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The value of x and y can be solve by
using five solution or processes
method. This include:
   1. Elimination
   2. Substitution
   3. Comparison
   4. Graphing
   5. Determinants
   Solving a system of two linear equation in
    variables x and y using the Determinants.
** To find a determinant you must
have        a S QUA R E
M A T R I X !! **
Finding a 2 x 2 determinant:
   a   b
   c   d

Find the determinant :

   -5 -7
  11   8
Finding a 3 x 3 determinant :
 a1 b1 c1     b2 c2      a2 c2   a2 b2
 a2 b2 c2     b3 c3      a3 c3   a3 b3

 a3 b3 c3
Find the determinant :
 3   2   1     2 3       1 3     1 2
               3 1       3 1     3 3
 1   2   3
 3   3   1
2x+3y = 4              X=?
 x + 2y = -7            Y=?

a1 = 2 ;   b1 = 3   ;   c1= 4
a2 = 1 ;   b2 = 2 ; c2 = -7
S O L U TF o r
         I
O c1 :b1 x
  N            4 3
  c2 b2         -7 2       8 – (-21)     29
          =            =               =      = 29
 a1 b1          2 3         4-3           1

 a2 b2          1 2
          For
          y
 a1 c1          2 4
 a2 c2          1 -7       -14 – 4       -18
          =            =               =     = -18
 a1 b1          2 3         4-3           1

 a2 b2          1 2
X = 29, Y = -18


2x + 3y = 4        X + 2y = -7
2(29) + 3(-18) =   29 + 2(-18) =
4 – 54 = 4
58                 -7 + (-36) = -7
                   29
4=4                -7 = -7
Determinants

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Determinants

  • 1.
  • 2.
  • 3.
  • 4. The value of x and y can be solve by using five solution or processes method. This include: 1. Elimination 2. Substitution 3. Comparison 4. Graphing 5. Determinants  Solving a system of two linear equation in variables x and y using the Determinants.
  • 5. ** To find a determinant you must have a S QUA R E M A T R I X !! **
  • 6. Finding a 2 x 2 determinant: a b c d Find the determinant : -5 -7 11 8
  • 7. Finding a 3 x 3 determinant : a1 b1 c1 b2 c2 a2 c2 a2 b2 a2 b2 c2 b3 c3 a3 c3 a3 b3 a3 b3 c3 Find the determinant : 3 2 1 2 3 1 3 1 2 3 1 3 1 3 3 1 2 3 3 3 1
  • 8. 2x+3y = 4 X=? x + 2y = -7 Y=? a1 = 2 ; b1 = 3 ; c1= 4 a2 = 1 ; b2 = 2 ; c2 = -7
  • 9. S O L U TF o r I O c1 :b1 x N 4 3 c2 b2 -7 2 8 – (-21) 29 = = = = 29 a1 b1 2 3 4-3 1 a2 b2 1 2 For y a1 c1 2 4 a2 c2 1 -7 -14 – 4 -18 = = = = -18 a1 b1 2 3 4-3 1 a2 b2 1 2
  • 10. X = 29, Y = -18 2x + 3y = 4 X + 2y = -7 2(29) + 3(-18) = 29 + 2(-18) = 4 – 54 = 4 58 -7 + (-36) = -7 29 4=4 -7 = -7