1. The equivalent capacitance of capacitors in series is equal to the reciprocal of the sum of the reciprocals of the individual capacitances. 2. For the given circuit with Cr = 3C, C2 = C, and C3 = 5C, the equivalent capacitance is C/(3 + 1/5 + 1) = C/4 Farads. 3. For the given circuit with Cr = 2.5μF, C2 = 5μF, and C3 = 10μF, the equivalent capacitance is 1/(1/2.5 + 1/5 + 1/10) = 6.2μF.

1. 1. Derlve the equation for capacitors in series. Jint:
A parallel place capacitor is constructed by filling
charge ls conserved, energy is conserved the space between two square plates with three
2. Cr = 3C, Cz = C, and Cs = SC. What is the dielectric materials. Find an expression of the
equivalent cap'abitance of the circuit shown below
equivalent capacitance of the system in terms of
in terms of C? the plate area A, d, kr, kzand ke.
f I
-T
d/2
t
d
I
t_
3, Find the equivalent capacitance of the circuit
shown below lf
Gr = 2.50lrF
l'---ttz;
Cz = 5.00 pF B. a.) What is the equivalent capacitance
9q: 10.0 pF of the circuit?
b.) Calculate the charge on each capacitor
if Vao = 10V
c.) Calculate the potentialdifference on each
capacitor
r.F
6.20 p"F I
H
"*-J H
For numbers 4 to 6, refer to the figure below
9. a.) What is the equivalent capacitance of the
network between points a and b?
4. Find the equivalent capacitahce
b.) Calculate the charge on each capacitor
5. Find the potentialdifference across each capacitor
c.) Calculate the potential difference on each
lf AVeu = 10V
capacitor
6. Find the charge on each capacitor
C1 = 65 = 8.4 ttF
C2=C3=C4=4.2uF
4.0 trtF
Van = 22OV
6.0 pF