2. A BAR OF DIFFERENT LENGTH AND DIAMETER GIVEN IN THIS TYPE OF PROBLEMS
AND ALL ARE SUBJECTED TO SAME LOADING.HERE WE HAVE FIND OUT THE TOTAL
STRAIN OR CHANGE IN LENGTH BY USING SIMPLE EQUATIONS.
FORCE=P
L1 L2 L3
D1 D2 D3FORCE=P
L1
L2
L3
FORCE=P
D1
D2
D3
321 DLDLDLDL
TOTAL CHANGE IN LEGTH=SUM OF THE CHANGE IN LENGTH IN ALL BARS
33
3
3
EA
PL
DL
11
1
1
EA
PL
DL
22
2
2
EA
PL
DL
3.
4.
5.
6. WE CAN DRAW THE FREE BODY DIAGRAMS OF EACH SECTIONS.
AND ALSO CAN DIVIDE THE LOAD IN EQUILIBRIUM CONDITIONS.
33
3
3
EA
PL
DL
11
1
1
EA
PL
DL
22
2
2
EA
PL
DL
