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Answer is Highlighted in Red. I don't understand why it is the answer so can you ste by step
explain what each part of the code is doing?
Solution
#include<iostream>
#include<string>
using namespace std;
public bool isPermutation(String str1,String str2) {
if(str1.size()!= str2.size()) return false;
else continue;
int i,counts[10];
for(i =0;i<str1.size();i++)
counts[str1[i] –‘0’] ++;   //Increment the least significant bit
for(i=0;i<str2.size();i++)
counts[str2[i] – ‘0’]--;  // decrement the least significant bit
for(i=0;i<10;i++) {
if(counts[i]!=0) return false;Â Â // if any count is different ,it is not a permutation
else return true;Â Â // counts are identical, was a permutation
}
}
int main() {
String s1,String s2;
cout << “enter string1―;
cin>>s1;
cout<<end1;
cout << “Enter string2―;
cin>>s2;
cout<<end1;
isPermutation(s1,s2);
if(isPermutation(s1,s2)) {
cout<<”Strings are permutations” <<end1;
else cout <<”Strings are not Permutations” << end1;
}
return 0;
}

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Answer is Highlighted in Red- I don-'t understand why it is the answer (1).docx

  • 1. Answer is Highlighted in Red. I don't understand why it is the answer so can you ste by step explain what each part of the code is doing? Solution #include<iostream> #include<string> using namespace std; public bool isPermutation(String str1,String str2) { if(str1.size()!= str2.size()) return false; else continue; int i,counts[10]; for(i =0;i<str1.size();i++) counts[str1[i] –‘0’] ++;   //Increment the least significant bit for(i=0;i<str2.size();i++) counts[str2[i] – ‘0’]--;  // decrement the least significant bit for(i=0;i<10;i++) { if(counts[i]!=0) return false;  // if any count is different ,it is not a permutation else return true;  // counts are identical, was a permutation } }
  • 2. int main() { String s1,String s2; cout << “enter string1―; cin>>s1; cout<<end1; cout << “Enter string2―; cin>>s2; cout<<end1; isPermutation(s1,s2); if(isPermutation(s1,s2)) { cout<<”Strings are permutations” <<end1; else cout <<”Strings are not Permutations” << end1; } return 0; }