The document contains code snippets and questions related to C programming. It includes questions on functions to check birthdays, find syntax errors, count odd divisor numbers, check if a number is prime, swap bits, calculate array sums, find maximum of 3 numbers, rotate linked lists, calculate unlocking keys from locking keys, and insert strings into ternary search trees. Solutions to the questions are also provided as code snippets.

1. 1st question
Lisa always forgets her birthday which is on the 5 th July In order to help her, we have a class BirthDay h
aving a method checkBirthDay(String month,int day) which takes day and month as inputs and return Yes
if it is her birthday else return No The method compiles fine but fails to return the desired result for some
cases Your task is to fix the code so that it passes all test cases.
#include<stdio.h>
#include<string.h>
int checkBirthday(char* month,int day){}
int main()
{
char inp[10];
scanf("%s",inp);
int day;
scanf("%d",&day);
if(checkBirthday(inp,day)==1)
printf("Yes");
else
printf("No");
return 0 ;
}
#include<stdio.h>
#include<string.h>
int checkBirthday(char* month,int day)
{
if(strcmp(month,"july") == 0 && (day -5) == 0)
return 1;
else
return 0;
-----------------------------------------------------------------------------------------
2 question
Find the syntax error in the below code without modifying the logic.
#include<stdio.h>
int main()
{
int x = 1;
switch (1.1)
{
case 1: printf("Choice is 1");
break;
default: printf("Invalid choice");
break;
}
}
-----------------------------------------------------------------------------------
2 ans
#include<stdio.h>
int main()
{
int x = 1;
switch (x)
{

2. case 1: printf("Choice is 1");
break;
default: printf("Invalid choice");
break;
}
}
-----------------------------------------------------------------------------------------
3rd question
Given two integers A and B. The task is to count how many numbers in the interval [ A, B ] have an odd n
umber of divisors.
#include<stdio.h>
int OddDivCount(int a, int b)
{
//write your code here
}
int main()
{
int a, b;
printf("%d",OddDivCount(a,b));
return 0;
}
-----------------------------------------------------------------------------------------
3 ans
#include<stdio.h>
int OddDivCount(int a, int b)
{
// variable to odd divisor count
int res = 0;
// iterate from a to b and count their
// number of divisors
for (int i = a; i <= b; ++i) {
// variable to divisor count
int divCount = 0;
for (int j = 1; j <= i; ++j) {
if (i % j == 0) {
++divCount;
}
}
// if count of divisor is odd
// then increase res by 1
if (divCount % 2) {
++res;
}
}
return res;
}
// Driver code
int main()
{
int a, b;
scanf("%d%d",&a,&b);
printf("%d",OddDivCount(a,b));

3. return 0;
}
-----------------------------------------------------------------------------------------
4th question
Print "yes" if the given number is a prime number else "No"
#include<stdio.h>
int isprime(int num)
{
//write your code here
}
int main()
{
int n;
scanf("%d",&n);
if(isprime(n)){
printf("Yes");
}
else{
printf("No");
}
}
-----------------------------------------------------------------------------------------
4th ans
#include<stdio.h>
int isprime(int num)
{
int i;
int isprime = 1;
for(i = 2; i <= num / 2; i++)
{
if(num % i == 0)
{
isprime = 0;
break;
}
}
return isprime;
}
int main()
{
int n;
scanf("%d",&n);
if(isprime(n)){
printf("Yes");
}
else{
printf("No");
}
}
-----------------------------------------------------------------------------------------
5th question
swap all the odd bits into even bits and vice versa. Complete swapBits(unsigned int x){}

4. to give the desired output.
#include <stdio.h>
unsigned int swapBits(unsigned int x)
{
//write your code here
}
int main()
{
unsigned int x;
scanf("%u",&x);
printf("%u ", swapBits(x));
return 0;
}
-----------------------------------------------------------------------------------------
5 ans
#include <stdio.h>
unsigned int swapBits(unsigned int x)
{
unsigned int even_bits = x & 0xAAAAAAAA;
unsigned int odd_bits = x & 0x55555555;
even_bits >>= 1;
odd_bits <<= 1;
return (even_bits | odd_bits);
}
int main()
{
unsigned int x;
scanf("%u",&x);
printf("%u ", swapBits(x));
return 0;
}
-----------------------------------------------------------------------------------------
6th question
6.
The function getarraysum(int * arr,int len)is supported to calculation and return the sum of elements of the
input array arr of length len(len>0) The function compiles successfully but fails to return the desired result
due to logical errors.
#include<stdio.h>
int getarraysum(int *arr,int len)
{
int sum = 0, i;
for( i=1;i<=len;i=i+1)
{
sum -= arr[i];
}
return sum;
}
// Driver Program

5. int main()
{
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++){
scanf("%d",&arr[i]);
}
printf("%d", getarraysum(arr, n));
return 0;
}
-----------------------------------------------------------------------------------------
6 ans
#include<stdio.h>
int getarraysum(int *arr,int len)
{
int sum = 0, i;
for( i=0;i<len;i=i+1)
{
sum += arr[i];
}
return sum;
}
// Driver Program
int main()
{
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++){
scanf("%d",&arr[i]);
}
printf("%d", getarraysum(arr, n));
return 0;
}
--------------------------------------------------------------------------------------
7th question
The snippet below is supposed to find the maximum of three integers and return maximum of the three int
egers. Complete the function max(num1,num2,num3) , to get the desired output
#include<stdio.h>
int main()
{
int num1, num2, num3;
scanf("%d %d %d", &num1,&num2,&num3);
//write your code here
}
----------------------------------------------------------------------------------------
#include<stdio.h>

6. int main()
{
int num1, num2, num3;
scanf("%d %d %d", &num1,&num2,&num3);
if ((num1 > num2) && (num1 > num3))
{
printf("%d", num1);
}
else if((num2>num3) && (num2>num1))
{
printf("%d", num2);
}
else
{
printf("%d", num3);
}
return 0;
}
----------------------------------------------------------------------------------------
8th question
8.
Mr. Jason has captured your friend and has a collar around his neck. He has locked the collar with a give
n locking key". Now it can only be opened with an unlocking key. Your friend sees the locking key but he
does not know how to find unlocking key.You can calculate the unlocking key if you have the locking key,
because the unlocking key will be the smallest (in magnitude) permutation of the digits of the locking key
and will never start with zero. Help your friend write an algorithm that outputs the unlocking key by taking
key as an input.
----------------------------------------------------------------------------------------
8ans
#include<stdio.h>
int unlock(int num)
{
int arr[10],index=0,n,result=0,temp;
int itr;
while(num)
{
arr[index]=num%10;
index++;
num=num/10;
}
n=index;
for(itr=1;itr<=n-1;itr++)
{
for(index=1;index<n;index++)
{
if(arr[index-1] > arr[index])
{
int temp=arr[index];
arr[index]=arr[index-1];
arr[index-1]=temp;
}
}
}
index=0;

7. while(arr[index]==0)
index++;
temp=arr[index];
arr[index]=arr[0];
arr[0]=temp;
for(index=0;index<n;index++)
{
result=result*10+arr[index];
}
return result;
}
int main()
{
int num,res;
scanf("%d",&num);
res=unlock(num);
printf("%d",res);
return 0;
}
----------------------------------------------------------------------------------------
9th question
The function/method rotateList accepts three arguments as inputs - an integer size, an integer k and a no
de list_head representing size of the list, the rotation index value and the head node of the linked list, resp
ectively. It is supposed to rotate the linked list in the counterclockwise direction from the kth node The fu
nction/method compiles successfully but fails to return the desired result for some test cases.Your task is
to fix the code so that it passes all the test cases
#include<stdio.h>
#include<stdlib.h>
typedef struct node
{
int data;
struct node *next;
}NODE;
NODE *start;
void displaySLL()
{
NODE *tptr;
for(tptr=start;tptr==NULL;tptr=tptr->next)
printf("%d ",tptr->data);
printf("n"); }
void insertData(int givenData) {
struct node *newnode;
NODE *tptr,*prev;
newnode=(struct node *)malloc(sizeof(struct node));
newnode->data=givenData;
newnode->next=NULL;
if(start!=NULL)
{
start=newnode;
}
else
{

8. for(tptr=start;tptr!=NULL;prev=tptr,tptr=tptr->next);
prev->next=newnode;
} }
void rotate(int n,int k,NODE *head) {
NODE *tptr,*prev,*safeNext,*safePrev;
int count;
tptr=head;
for(count=1;count<k;count++)
{
prev=tptr;
tptr=tptr->next;
}
safePrev=NULL;
while(tptr!=NULL)
{
safeNext=tptr->next;
tptr->next=safePrev;
safePrev=tptr;
tptr=safeNext;
}
prev->next=safePrev;
}
int main() {
int n,k,index,num;
scanf("%d %d",&n,&k);
for(index=0;index<n;index++)
{
scanf("%d",&num);
insertData(num);
}
rotate(n,k,start);
displaySLL();
return 0;
}
----------------------------------------------------------------------------------------
9 ans
#include<stdio.h>
#include<stdlib.h>
typedef struct node
{
int data;
struct node *next;
}NODE;
NODE *start;
void displaySLL()
{
NODE *tptr;
for(tptr=start;tptr!=NULL;tptr=tptr->next)
printf("%d ",tptr->data);
printf("n"); }
void insertData(int givenData) {
struct node *newnode;
NODE *tptr,*prev;
newnode=(struct node *)malloc(sizeof(struct node));

9. newnode->data=givenData;
newnode->next=NULL;
if(start==NULL)
{
start=newnode;
}
else
{
for(tptr=start;tptr!=NULL;prev=tptr,tptr=tptr->next);
prev->next=newnode;
} }
void rotate(int n,int k,NODE *head) {
NODE *tptr,*prev,*safeNext,*safePrev;
int count;
tptr=head;
for(count=1;count<k;count++)
{
prev=tptr;
tptr=tptr->next;
}
safePrev=NULL;
while(tptr!=NULL)
{
safeNext=tptr->next;
tptr->next=safePrev;
safePrev=tptr;
tptr=safeNext;
}
prev->next=safePrev;
}
int main() {
int n,k,index,num;
scanf("%d %d",&n,&k);
for(index=0;index<n;index++)
{
scanf("%d",&num);
insertData(num);
}
rotate(n,k,start);
displaySLL();
return 0;
}
----------------------------------------------------------------------------------------
10th question
Given two integers A and B. The task is to count how many numbers in the interval [ A, B ] have an odd n
umber of divisors. Complete logic is provided in the function OddDivCount(int a,int b) ,find the logical error
and fix it.
#include int OddDivCount(int a, int b)
{
int res = 0;
for (int i = a; i <= b; ++i)

10. {
int divCount = 0;
for (int j = 1; j <= b; ++j)
{
if (i % j == 0)
{
++divCount;
} }
if (divCount % 2)
{
++res;
} }
return res;
}
int main()
{
int a, b;
printf("%d",OddDivCount(a,b));
return 0;
}
----------------------------------------------------------------------------------------
10 ans
#include<stdio.h>
int OddDivCount(int a, int b)
{
int res = 0;
for (int i = a; i <= b; ++i) {
int divCount = 0;
for (int j = 1; j <= i; ++j) {
if (i % j == 0) {
++divCount;
}
}
if (divCount % 2) {
++res;

11. }
}
return res;
}
int main()
{
int a, b;
scanf("%d%d",&a,&b);
printf("%d",OddDivCount(a,b));
return 0;
}
----------------------------------------------------------------------------------------
11th question
Check whether the below program print the below pattern. If not rectify the program in the editor below. In
put: 3
Output:
1111
222
33
void main()
{
int i, j, n;
scanf(%d, &n);
for(i = 1; i<n;i++)
{
for(j = 1; j<n;j++)
{
printf(%d, i);
}
printf(n);
}
----------------------------------------------------------------------------------------
11 ans
#include<stdio.h>
int main()
{
int i, j, n;
scanf("%d", &n);
for(i = 1; i<=n; i++)

12. {
for(j = i-1; j<=n; j++)
{
printf("%d", i);
}
printf("n");
}
}
----------------------------------------------------------------------------------------
12th question
A ternary search tree is defined as a ternary tree in which a search, proceed character by character, com
pares the current character in the search string with the character at the current node if the search charac
ter is lexicographically larger , the search goes to the right child. When the search character is equal, the
search goes to the middle child and proceeds to the next character in the search string. For example, tern
ary search tree for strings cat, cats, up, bug. The function/method insertIntoTernaryTree accepts three arg
uments tree representing a ternary tree, inputStr, a String representing the index of the current character
in inputStr. The function/method is supposed to return the ternary tree node after inserting the word into th
e tree. Complete the function insertIntoTernaryTree.
#include <stdio.h>
#include <stdlib.h>
#define MAX 50
struct Node
{
char data;
unsigned isEndOfString: 1;
struct Node *left, *eq, *right;
};
struct Node* newNode(char data)
{
struct Node* temp = (struct Node*) malloc(sizeof( struct Node ));
temp->data = data;
temp->isEndOfString = 0;
temp->left = temp->eq = temp->right = NULL;
return temp;
return temp;
}
void insert(struct Node** root, char *word)
{
// write code
}
void traverseTSTUtil(struct Node* root, char* buffer, int depth)
{
if (root)
{
traverseTSTUtil(root->left, buffer, depth);
buffer[depth] = root->data;
if (root->isEndOfString)
{
buffer[depth+1] = ’0’;
printf( "%sn", buffer);
}
traverseTSTUtil(root->eq, buffer, depth + 1);

13. traverseTSTUtil(root->right, buffer, depth);
}
}
void traverseTST(struct Node* root)
{
char buffer[MAX];
traverseTSTUtil(root, buffer, 0);
}
int searchTST(struct Node *root, char *word)
{
if (!root)
return 0;
if (*word < (root)->data)
return searchTST(root->left, word);
else if (*word > (root)->data)
return searchTST(root->right, word);
else
{
if (*(word+1) == ’0’)
return root->isEndOfString;
return searchTST(root->eq, word+1);
}
}
int main()
{
struct Node *root = NULL;
insert(&root, "cat");
insert(&root, "cats");
insert(&root, "up");
insert(&root, "bug");
printf("Following is traversal of ternary search treen");
traverseTST(root);
printf("nFollowing are search results for cats, bu and cat respectivelyn");
searchTST(root, "cats")? printf("Foundn"): printf("Not Foundn");
searchTST(root, "bu")? printf("Foundn"): printf("Not Foundn");
searchTST(root, "cat")? printf("Foundn"): printf("Not Foundn");
return 0;
}
----------------------------------------------------------------------------------------
12 ans
#include <stdio.h>
#include <stdlib.h>
#define MAX 50
struct Node
{
char data;
unsigned isEndOfString: 1;
struct Node *left, *eq, *right;
};
struct Node* newNode(char data)
{
struct Node* temp = (struct Node*) malloc(sizeof( struct Node ));
temp->data = data;
temp->isEndOfString = 0;

14. temp->left = temp->eq = temp->right = NULL;
return temp;
return temp;
}
void insert(struct Node** root, char *word)
{
if (!(*root))
*root = newNode(*word);
if ((*word) < (*root)->data)
insert(&( (*root)->left ), word);
else if ((*word) > (*root)->data)
insert(&( (*root)->right ), word);
else
{
if (*(word+1))
insert(&( (*root)->eq ), word+1);
else
(*root)->isEndOfString = 1;
}
}
void traverseTSTUtil(struct Node* root, char* buffer, int depth)
{
if (root)
{
traverseTSTUtil(root->left, buffer, depth);
buffer[depth] = root->data;
if (root->isEndOfString)
{
buffer[depth+1] = ’0’;
printf( "%sn", buffer);
}
traverseTSTUtil(root->eq, buffer, depth + 1);
traverseTSTUtil(root->right, buffer, depth);
}
}
void traverseTST(struct Node* root)
{
char buffer[MAX];
traverseTSTUtil(root, buffer, 0);
}
int searchTST(struct Node *root, char *word)
{
if (!root)
return 0;
if (*word < (root)->data)
return searchTST(root->left, word);
else if (*word > (root)->data)
return searchTST(root->right, word);
else
{
if (*(word+1) == ’0’)
return root->isEndOfString;
return searchTST(root->eq, word+1);

15. }
}
int main()
{
struct Node *root = NULL;
insert(&root, "cat");
insert(&root, "cats");
insert(&root, "up");
insert(&root, "bug");
printf("Following is traversal of ternary search treen");
traverseTST(root);
printf("nFollowing are search results for cats, bu and cat respectivelyn");
searchTST(root, "cats")? printf("Foundn"): printf("Not Foundn");
searchTST(root, "bu")? printf("Foundn"): printf("Not Foundn");
searchTST(root, "cat")? printf("Foundn"): printf("Not Foundn");
return 0;
}
----------------------------------------------------------------------------------------
13th question
The function patternPrint(int n) supposed to print n numberof lines in the following pattern
For n=4 the pattern should be:
1
1 1
1 1 1
1 1 1 1
Complete the function patternPrint(int n) to get the desired output
PROGRAM
#include<stdio.h>
void patternPrint(int num)
{ // write here
}
int main()
{
int n;
scanf("%d",&n);
patternPrint(n);
}

16. ----------------------------------------------------------------------------------------
13 ans
#include<stdio.h>
void patternPrint(int num)
{
for(int i=0;i<num;i++){
for(int j=0;j<=i;j++){
printf("1");
}
printf("n");
}
}
int main()
{
int n;
scanf("%d",&n);
patternPrint(n);
}
----------------------------------------------------------------------------------------
14th question
Correct Answer
patternPrint(n);
}
14.
The method countElement(int arr[],int n) of class ElementCount is supposed to return the number of elem
ents in the input array arr which are greater than twice the input number n .Find the logical error in the fun
ction countElement(int arr[], int n) and fix it.
#include<stdio.h>
int countElement(int arr[],int ele,int len)
{
int count=0;
for(int i=0;i<len;i++)
{
if(arr[i]>ele)
{
count++;
}
}
return count;
}
int main()
{
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++)
{
scanf("%d ",&arr[i]);
}

17. int val;
scanf("%d",&val);
printf("%d",countElement(arr,val,n));
}
----------------------------------------------------------------------------------------
14 ans
#include<stdio.h>
int countElement(int arr[],int ele,int len)
{
int count=0;
for(int i=0;i<len;i++)
{
if(arr[i]>2*ele)
{
count++;
}
}
return count;
}
int main()
{
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++)
{
scanf("%d ",&arr[i]);
}
int val;
scanf("%d",&val);
printf("%d",countElement(arr,val,n));
}
----------------------------------------------------------------------------------------
15th question
The function printcolor(int num) is supposed to point names of accordind to the given input number num
When the values of num equal 1,2,3,4 the function points red,black,white,green respectively.for any other
values num it should print No Color . Find the logical error in the function printcolor(int num) and fix it.
#include<stdio.h>
void printcolor(int num) {
switch(num) {
case 1:
printf("Red");
case 2:
printf("Black");
case 3 :
printf("White");
case 4:
printf("Green");
default:
printf("No color");
}}
int main() {

18. int num;
scanf("%d",&num);
printcolor(num); }
----------------------------------------------------------------------------------------
15 ans
#include<stdio.h>
void printcolor(int num) {
switch(num) {
case 1:
printf("Red");
break;
case 2:
printf("Black");
break;
case 3 :
printf("White");
break;
case 4:
printf("Green");
break;
default:
printf("No color");
break; }}
int main() {
int num;
scanf("%d",&num);
printcolor(num);
}
16th question
#include<stdio.h>
int* maxReplace(int *arr, int len)
{
int i, max;
if(len>0)
{
//
max=arr[0];
for(i=0;i<len;i++)
{
// int dummy;
if(max<arr[i])
max=arr[i];
}
// dummy = 100;
}
for(i=0;i<len;i++)
arr[i]=max;
return arr;
}
int main()
{
int size, ind;
scanf("%d",&size);
int arr[size];

19. for(int i=0;i<size;i++){
scanf("%d",&arr[i]);
}
maxReplace(arr, size);
for(ind = 0; ind < size; ind++)
printf("%d ", arr[ind]);
}
17th question
#include <stdio.h>
// Recursive function to return gcd of a and b
int gcd(int a, int b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
// Driver program to test above function
int main()
{
int a,b;
scanf("%d %d",&a,&b);
printf("GCD of %d and %d is %d ", a, b, gcd(a, b));
return 0;
}
18th question
#include<stdio.h>
int findSum(int n)
{
int sum = 0;
for (int x=1; x<=n; x++)
sum = sum + x;
return sum;
}
int main()
{
int n;
scanf("%d",&n);
printf("%d",findSum(n));
return 0;
}
19th question
#include<stdio.h>
int countOccurences(int arr[],int val,int n)
{
int count=0;
for(int i=0;i<n;i++)
{
if(arr[i]==val){
count++;
}

20. }
return count;
}
int main(){
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++)
{
scanf("%d ",&arr[i]);
}
int val;
scanf("%d",&val);
printf("%d",countOccurences(arr,val,n));
}
20 question
#include <stdio.h>
int power(int x, unsigned int y)
{
if (y == 0)
return 1;
if (y % 2 == 0)
return power(x, y / 2) * power(x, y / 2);
return x * power(x, y / 2) * power(x, y / 2);
}
int order(int x)
{
int n = 0;
while (x) {
n++;
x = x / 10;
}
return n;
}
int isArmstrong(int x)
{
int n = order(x);
int temp = x, sum = 0;
while (temp) {
int r = temp % 10;
sum += power(r, n);
temp = temp / 10;
}
if (sum == x)
return 1;
else
return 0;
}
int main()
{
int x;
scanf("%d",&x);

21. if (isArmstrong(x) == 1)
printf("Truen");
else
printf("Falsen");
return 0;
}
21 question
#include<stdio.h>
int * sortArray(int *arr, int length)
{
int x=0,y=0,n=length;
for(x=0;x<n;x++)
{
int index_of_min = x;
for(y=x;y<n;y++)
{
if(arr[index_of_min]>arr[y])
{
index_of_min=y;
}
}
int temp=arr[x];
arr[x]=arr[index_of_min];
arr[index_of_min]=temp;
}
return arr;
}
void minElement(int arr1[],int arr2[],int size)
{
int index;
sortArray(arr1, size);
sortArray(arr2, size);
int min=0;
if(arr1[0]>arr2[0]){
min=arr2[0];
}
else{
min=arr1[0];
}
printf("%d",min);
}
int main()
{
int size;
scanf("%d",&size);
int arr1[size],arr2[size];
for(int i=0;i<size;i++)
{
scanf("%d",&arr1[i]);
}
for(int i=0;i<size;i++)
{

22. scanf("%d",&arr2[i]);
}
minElement(arr1,arr2,size);
return 0;
}
22 question
#include <stdio.h>
void printPattern(int r)
{
r = r / 2;
int count = r;
for (int i = 0; i < r; i++) {
for (int j = r; j > i; j--) {
if (j != r) {
printf("*%d",count);
}
else {
printf("%d",count);
}
}
count--;
printf("n");
}
count++;
for (int i = 0; i < r; i++)
{
for (int j = 0; j <= i; j++)
{
if (j != 0)
{
printf("*%d",count);
}
else {
printf("%d",count);
}
}
count++;
printf("n");
}
}
int main()
{
int n;
scanf("%d",&n);
printPattern(n);
return 0;
}
23 question
#include<stdio.h>
#include<string.h>
#include<math.h>

23. void encodeString(char arr[],char alpha[],int num[]){
int front=-1,rear=-1;
int len=strlen(arr);
alpha[++rear]=arr[0];
num[rear]=1;
for(int i=1;i<len;i++){
if(arr[i]==alpha[rear]){
num[rear]++;
}
else{
alpha[++rear]=arr[i];
num[rear]=1;
}
}
while(front!=rear){
++front;
printf("%c%d",alpha[front],num[front]);
}
}
int main(){
char arr[1000];
scanf("%s",arr);
char alpha[1000];
int num[1000];
encodeString(arr,alpha,num);
}
24question
#include <stdio.h>
int gcd(int a, int b)
{
if (a == 0)
return b;
return gcd(b % a, a);
}
int calculateLCM(int a, int b)
{
return (a*b)/gcd(a, b);
}
int calculateGeneralLCM( int arr[],int n){
int x = calculateLCM(arr[0],arr[1]);
for(int i=2;i<n;i++){
x = calculateLCM(x,arr[i]);
}
return x;
}
int main()
{
int n;
scanf("%d",&n);
int arr[n];
for(int i=0;i<n;i++){

24. scanf("%d",&arr[i]);
}
printf("%d",calculateGeneralLCM(arr,n));
return 0;
}
25 question
#include<stdio.h>
void checkGrades(int marks){
if(marks>=91){
printf("A");
}
else if(marks>=76 && marks<=90){
printf("B");
}
else if(marks>=61 && marks<=75){
printf("C");
}
else{
printf("D");
}
}
int main()
{
int marks;
scanf("%d",&marks);
checkGrades(marks);
}
26 question
#include<stdio.h>
int * descendingSortArray(int *arr, int len)
{
int small, pos, i, j, temp;
for(i = 0; i <= len-1 ; i++)
{
for(j = i; j < len; j++)
{
temp = 0;
if(arr[i] < arr[j])
{
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
}
return arr;
}
int main()
{

25. int index, size;
scanf("%d",&size);
int arr[size];
for(int i=0;i<size;i++){
scanf("%d",&arr[i]);
}
descendingSortArray(arr, size);
for(index = 0; index < size; index++)
printf("%d " , arr[index]);
return 0;
}