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CPLT assignment 1 Vedant Vyas.pdf
1. Unit - I
Assingmert
Pout A..
1. Nhat usa (omputeu
-Tanish
Acomputexusian electronie deuice thct
manipulatesinformotion, ohdota
has th abilit
th ability o toeetieve
and process dato Th tem
compute" wa Sigina guen to
humauns wtho þesm Áumeticl
callati uingmehaniial
calulataxs tomptesae
2ltite five chactersticd
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Date
many kieldyike banking meciçne
finnui edueation wit inaAed
Asi Five choOtenstC&
9amputer ?
Tt tesþonds to a spe citicset
instrutin npropet monnt
It conexete a þrerecoded it
instruet
in.(A rogmam)
that
an electtonic deuice
lates informatisn 0r datu
2. Tt has tha
retieve
@ The majo
&tobage
Remebes'a powzs e
2what wscyclic
chatactenstics b
w
proe&s date
gi
Lambuteh canbe dassified into
speec, Qccuey diligene
venseility ulicblityansisteney
momshu Statagecapity
Atylie icodeus
ode
to
ocle2
Lode w0
line ah bloCk ode thot hy
propety thetiay yitsh
codewomd yelie cocdes
gesatt Sthng
th
goutontion
Dato
Tanishq
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matric That speifies
censtructs the codew0
Useul for
erfO detectiÇn and
colecl beceuse thay hawe
howe
algebic Sthuetuhe th aLow
effiient operatigns A ycie
ccun be deined hy
or a genato
hw
the
to
r i s
3. 4
whatis nen Impact
and hape
electrostatie chemical o
technology
Ans: Nem- Impact inteny oLon't use ouny
dËtect contoet
moing
These ptintet a De
noiiy gclon't hawemerhanical
5.Find 16s compliment of A92 ?
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betuweenimkibbn
lesse
A 9 2
-Tanishq
Date
56 D
þatstocanduet printìng
Nan Tpat printes þhmt images
and chaactehsithaut any er
phyaicalcontot betueen
primting mechcinism and
Comjaliment.
?
56 D
inkjet
56E
Ams Step 4 we obtaun the I5.S cerpliment
hetadeimalnunbe by
Subthacting each dipit the
th
the
Step 2 : Add iA to s'sempliment to
Obtuin6's
YLAn Imþact riatee
4. Partr B
Ans MEMORY HreRARcHY
Tanish
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Date
1 what us memoryhieohy
the00rking 6 antho unit by
a duitable dioam
disc
éxplain.
abaut arhangna
difftent kinc ib storage deyice u
Lomute balec on tha ig2
and cLessi dpeed and the
olesthyplay napplicatibn
phocesiingThcpblicatibn
maig hunpses
ahieveefiient apootign'
the mem0y t0
oces timehle
apeecling4 upoþenatien Jhese
hioxchiesin a dystem'y
egteh, ach
memsymaunemoy, magneti
A Conto uni heceives data prem
the seh and tan.slote ut nto
entisl ignal that ase dbseqyuertl
deiueeV totha centhaeprocessOr
Jhu hocessor ß7 the compute
then instuelathe assaciateA
what oetisns
5. lo00000DD
28)6
t
o
m controlbus.
Lontro Si
g
ncu
oithin
PU rosignd
88
Lontro ynut
pate
Page No.
:
Tani
s
hq
246
2352
0
2
2 70Yo
( 16-9.
t C6:-15)+
Cl
6 40), l6 t24
o t
2
2140D8o
CAFA)2),.
conueKtthe follouwinginto Binay
?
22814
Reqjster.
ciaguem
Uut
ontro
t
h
e CPU
Lemyute ahe
TOsthution
N
clependent
Unt funtöny peoned
mcunujcctuhehto
Because cPu aehi tectue diffes
ft
Block
to al
o
Ansi
6. (201)’ (?
2 2 o
2
(8°1)t (8:0 t (84):tot 448
2
2
2
28
3
1
J
3 Exþloun BCD code
-Tanish
binany enHding
enhding uhue
digit in
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with txmple
Date
Ans: Binhy code deimal o Bco, s
anttn þrocess for oueiimg
decimal humbes into thiih bìnay
eayuivalents
This enoding' c£n be cen
eith 4-bt
4-bit s ttd)
0T g- bit
deumal number
bits
i
7. Ans:
Explcin Psimauy memory,
memsy with
8xumple
misy
memhy Tt ws diretly acesi ble
þrocessox CRURnay
Tanishq
Paçe tio
and eonday
deuicebaemahehen.sive
thanseLondabtorage deuice
mamahuy deuices sedfor primcy
mumyic
Qccesibe
emisnductQ
mcçn memnyex
cache mnshy Pronn Eprtm etc
Exteunce mern0y
SECDNDARY MEMoRY’It wb þmansnt
Rom Rorm
tha CPUThise
eas expensive theun prlmeuy mmaht
horcl cisk, flapPY disket
8. 4- Explaun
Pot
ASCIT Code. find AscL
2
value o4 A-G and ag?
AnsiAs cIlCAmnican Standcudc0de fox
infomatigm /ntehchung) sthu
msit Lonn chaacte encodng
-tom,t otett data iin
cempute and n the internt
TnStoundad AscI encodec
data, theie ae uniapue uales
ko 98 iphabatic namiic
speiiaadeiHonalchanactehs
A) 65
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Date
cothl codes hactense
ASA enodng induoleuuphes
to gbasicuntuatign
B) 66
anish
D) 68
ASCa todes f0 the hauctes
E) 69
TheeASCI codes aHe deimal
eeserdahian
A to G oe
9. A) oob000
B)oo0000 1D
D) olo0olo0
E).oLo0alo
Tho AScLVolues
let
b) 48
d) oo
)o2
03
0
Tanishq
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Date|
10. the
with exmþle ?
@Exþlaun
þositive
Jhe
the
Inthe binay supresentation e4
numbeA the mast
bìnchy
eX
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Date
Tanishq
hemanin bitshepredent
magnitëde onumber in
2S Comþliment
for ex Bìnay upresenttign
tho decimel numbes s is go
absolte volue
To Repredent megotivemumbers
wsing tuo's ZompBimmen the
Jhoi
MSG
epredent the
Temaniung bit
magnitude to the numben'a
in bìngy
Inuentall bits oo
Add t1
For ex! Let' conaiden
fomfor ex:
oleimay no.Sit binasy
Tepresentatien is loll fo fnd
t's tuD's cAmbliert
11. coole
Exþlaun Gtuy cocde ond..excess -3
In
-Tanishq
Ansikay code i hay coclealso kneusn s
letd bìnguycode
fields
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binau umunc ystemwhe
tun cendeutvevae ciAfea
hit ckcyCode
Date
numheh
and digitol- to - analo onuesters.
ìncuding tele ommunication
odeduch th adiacenI
cocdes dliffe y ny one bit.
Thus fnopety Stuin.
etrors cuihg
digital
Jhe
adueing
ttunsitos betueenneutiye
XS-3 s atbtz code,
sy comþlementy bingny
coded decimol CBcD) ode T us
wsed to SapreAent deimal digits in
dyste cand calulatoA
excess3 code is ceived by
adding3 to tha deima
12. aigit andthan epreaertinig
the saAuLt in 4-bit binay
fom, Tn the excesS-3code
fach de imal digit ftorm
Lanuentthe follbanng
codeintot
ey code
hncy
clesigv&d
that each binay code s9
the bincy epesentttien
the deima wau us 3,
binca
Paga No.:
steh Ii opy the leyt mot bit bg
binaruy
222
-Tanishq
Oto 9
4- buk
So 9y code0LL.
Step 2 Potming xOR tin
X0R
14. Ans:
3. ) Exþlaun fized point numbexytern
anol flocting poimt number dyite,
duitabe erample?
(a)
)
with
dystem
bits ae
ficLed bint numbel dyeHen In a
ted poi numboi
alocated tor
þaut and sepate set
pant dhe haitiom
ited henct
Tanishq
fited-poi
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allocated for thi ctioncl
ho binohy
izedpoint dystem
the integ
To Lonvent
mbeh to
bits
eXcnle to illustote tha
thename
Ch ed point
to itsde unmo) ea uvalent,
follou the Stebs
4 conuent /tegeh hat to de iml
Add deaimal vaes of idega
ctien al ht
15. Luhoe elemnthawe
floating foinl numbes ytermiAfloating
pojmt numhL dystem us
Evauate the following
-Tanish
i) lo000001 - 1L’(?),
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l|Lo0 lo
Date
ngatie thae numbeh with
'cleeimal poimt
the