ecet 375 week 6 homework new,ecet 375 week 6 ilab exploring internet protocol hierarchy and ethernet layers new,devry ecet 375 week 6 tutorial,devry ecet 375 week 6 assignment,devry ecet 375 week 6 help

1. DEVRY ECET 375 Week 6 Homework NEW
Check this A+ tutorial guideline at
http://www.uopassignments.com/ecet-375-
devry/ecet-375-week-6-homework-recent
For more classes visit
http://www.uopassignments.com
Chapter 20-Questions
Pg-652-654
20-1: What is the primary purpose of using
subnetting?
20-2: List and describe several reasons why
network designers create subnetting.
20-3: Explain the differences between default
masksandsubnet masks.
20-7: Explain the reasons for using supernetting.
Chapter 20-Problems
20-1: What is the default mask for the network
address 139.100.0.0?
a.255.0.0.0
b.255.255.255.0
c.255.255.0.0

2. d.255.255.255.255
20-2: Using the default mask, how many hosts can
the classful network 109.0.0.0 support?
20-7: How many hosts can be supported on a
classful class B network with the following
subnetmask: 255.255.224.0?
20-9: You have a host IP address of 40.150.73.10
and a subnet mask 255.248.0.0:
20-15: Determine the subnet addresses and subnet
masks for a business network with the classful
class C address 204.238.7.0 with six departments
having separate subnetworks with the following
numbers of hosts:
20-23: A small business has been assigned a
classless network address 210.38.4.0.
20-24: Determine the following for the network
specified in problem 20-23:
Chapter 21-Questions
Pg-700-702
21-3: What is the primary purpose of the address
resolution protocol (ARP)?
Chapter 21-Problems
21-3: Determine the contents of the first byte of an
IP header if the IP protocol is IPv4 and the header
has 40 bytes of options.
21-6: Determine the length of an ICMP data field
for Ethernet frame that is carrying an IP datagram

3. with a 28-byte header and an eight-byte ICMP
header and the Ethernet data field is 600 bytes
long.
21-7: Use the following network analyzer display
of an ARP packet to answer the following
questions:
0000 00 07 08 00 06 04 00 02 00 00 BD 41 2A 1C
C1 98
0010 A0 14 00 00 40 A3 B1 CC C1 98 0F 10
21-8: Use the following network analyzer display
of an IP packet to answer the following questions:
0000 45 28 13 82 01 A2 21 34 F3 01 43 A1 C0 99
4A 01
0010 99 4A 0C -- -- -- -- -- -- -- -- -- -- -- -- --
21-11: A maximum-length data gram carrying
65,536 bytes can be transported over a WAN with
a maximum packet length of 292 bytes, which
includes the 20-byte IP header. Determine…