1. Frequency

2. Voltage

3. Current

5. Example:
Find the power loading in kilowatts of a three phase,
415 V, 50 Hz alternator rated at 150 kVA at 0.8
power factor, if when fully loaded the load has a
power factor of: (a) 0.8 and (b) 0.6.

6. The machine is rated at 150 kVA and 0.8 power
factor, so at this load;
Power output = 150 x 0.8 = 120 kW.

7. At 0.6 power factor;
Power output = 150 x 0.6 = 90 kW.
Note: in both cases the current flowing will be
the full load current value.